第 18 课时 几何初步及平行线、相线 第 19 课时 三角形 第 20 课时...
DESCRIPTION
第三单元 函数及其图象. 第 18 课时 几何初步及平行线、相线 第 19 课时 三角形 第 20 课时 全等三角形 第 21 课时 等腰三角形 第 22 课时 直角三角形与勾股定理 第 23 课时 相似三角形 第 24 课时 相似三角形的应用 第 25 课时 锐角三角函数 第 26 课时 解直角三角形及其应用. 第四单元 三角形. 第 18 课时 ┃ 几何初步及平行线、相交线. 第 18 课时 几何初步及平行线、相交线. 考点聚焦. 第 18 课时 ┃ 考点聚焦. 考点 1 三种基本图形 —— 直线、射线、线段. 一. 线段. - PowerPoint PPT PresentationTRANSCRIPT
-
181920 21 22 23 24 25 26
-
18
-
18 1
________________ ________
-
2 18
1__________________2______ ________ (1)(2)
-
3 18
1 n ________ 2 n() ________ 3 n______ 4 n________ 5 n ________
eq \f(nn1,2)
eq \f(nn1,2)
eq \f(nn1,2)
eq \f(nn1,2)
eq \f(n2n2,2)
-
4 18
-
5 18
-
6 18
-
7 18
-
18 1. 2. 1 [2012] 181ABCDOOMAOCBOD76BOM() A38 B104 C142 D144181C
-
18
[] AOCAOM180
BOD76AOCBOD76.
OMAOC
AOMeq \f(1,2)AOCeq \f(1,2)7638
BOM180AOM18038142.
C.
-
123 2 [2011] 3635________14325 [] 180363514325. 18
-
90180.18
-
1. 2. 3. 3 182ABCDAPCPABPCD18218
-
APC PAB PCD APC360(PAB PCD) APCPAB PCD APCPCDPAB. APC PAB PCD. PPEABAAPE. ABCDPECDCCPE PAEPCDAPECPE APC PAB PCD.
18
-
19
-
19 1
-
2 19
1
eq \b\lc\{(\a\vs4\al\co1(,\b\lc\{(\a\vs4\al\co1(,))))
2
eq \b\lc\{(\a\vs4\al\co1(,\b\lc\{(\a\vs4\al\co1(,))))
-
3 19
-
4 180 360 19
-
5 19
-
6 19
-
19 1. 2. 3. 1 [2012] 3 cm4 cm7 cm9 cm() A1 B2 C3 D4B
-
[] B 347349 379479 379479 B.19
-
1. 2. 2 [2012] 191ABC DEABACB50.ABCDEAA1BDA1________
19180 19
-
[] DEBCADEB50ADEA1DEBDA11802B80.19
-
19
-
1. 2. 19 3 [2012] 192ACDABCABCACDA1A1BCA1CDA2An1BCAn1CDAn. A.(1)A1________ (2)An________192
eq \f(,2)
eq \f(,2n)
-
19
[] (1)A1BCeq \f(1,2)ABCA1CDeq \f(1,2)ACDACDAABCA1CDA1BCA1
-
19
(2)(1)A2eq \f(1,2)
A1BABCA1CACD
A1BCeq \f(1,2)ABCA1CDeq \f(1,2)ACD.
ACDAABCA1CDA1BCA1,
eq \f(1,2)(AABC)A1BCA1A1eq \f(1,2)A.
AA1eq \f(,2)A2eq \f(1,2)A1eq \f(1,2)eq \f(1,2)eq \f(,22)
Aneq \f(,2n).
-
19
-
20
-
20 1
________ ________ (1) (2)
-
2 20
-
3 ASA AAS SAS HL 20
-
4 20
-
20 1. SSSASAAASSASHL2. 1 [2012] 201ABAE12B EBCED.201
-
121BAD2BADBACEAD.BACEAD
BACEADBCED. [] 12EADBACABAEBEASAABCAEDBCED.20
-
1() 2 320
-
1. 2. 3 2 [2012] 202ABCDBCADADEFCEBF.BDFCDE________()20220
-
DEDF(CEBFECDDBFDECDFB) BDFCDE BDFCDE.20
-
[] EDCBDFDCDBDEDF(CEBFECDDBFDECDFB)20
-
()20
-
12 3 [2012] ac. ABCBCaABc ABC. 20320
-
21
-
21 1 1
____ ____1(________) 2________ (1)(2)(3)(4)(5)(6)(7)
-
2 21
-
3 60 3 21
-
4 21
-
5 21
-
21 1. 2. 3. ().
-
1 211ABCABACADBCABCBGADEEFABF. EFED.ABACADBCADBC.BGABCEFABEFED. [] ADBCEFAB21121
-
(1) (2) 21
-
2 [2011] 212ABCBDCEOOBOC. (1)ABC (2)OBAC21221
-
(1)OBOCOBCOCB.BDCEBDCCEB90.BCCBBDCCEB (AAS)DCBEBC, ABAC.ABC (2)OBAC AO. BDCCEBDCEB. OBOCODOE. ADOAEO90AOAOADOAEO(HL) DAOEAO OBAC
21
-
[] (1)BDCCEB DCBEBC (2)AOHLADOAEODAOEAO21
-
(1)(2)(3)21
-
1. 2. C 21
3 [2012] ABCADBCDADeq \f(1,2)BCABC()
A45 B75
C4575 D60
-
21
[] BACBAC
(1)ABACADBCBDCDeq \f(1,2)BCADB90.
ADeq \f(1,2)BCADBDB45ABC45
(2)ACBCADBCADC90.
ADeq \f(1,2)BCADeq \f(1,2)ACC30.
CABBeq \f(180C,2)75
ABC75.
ABC4575.
C.
-
21
-
4 [2011] ABCEABDCBEDEC213.AEDB21321
- (1) EAB214AEDB AE________DB(>
- (2) AEDBAE________DB(>
-
ABCABCACBBAC60ABBCAC.EFBCAEFAFE60BACAEFAEAFEFABAEACAFBECF.ABCEDBBED60ACBECBFCE60EDECEDBECBBEDFCE.DBEEFC120DBEEFCDBEFAEBD.21
-
ABCABCACB60ABD120.ABCEDBBEDACBECBACEEDECEDBECBBEDACE.FEBCAEFAFE60BACAEFEFC180ACB120ABD.EFCDBEDBEF.AEFEFAEAEDB.21
-
(3) ABCEABDBCEDEC.ABC1AE2CD()
13. 21
-
6021
-
1221
-
21521
5 (a)(b)(c)1.(a)(b)(c)
(1)48
(2)10
(3)2eq \r(,2)6
-
(a)(b)(c)21
[] (1)484(2)102eq \r(5)(3)2eq \r(2)62eq \r(2)
-
. 21
-
22
-
22 1
________ (1) (2)30 ______________ (3) ______________ (1) (2)
-
2 a2b2c2 a2b2c2 22
-
3 22
-
4 22
-
5 1()()() 2________ 3________ 22
-
22 1. 2.
-
D 22122
1 [2011] 453 cm30221()
A3 cm B6 cm
C3eq \r(2) cm D. 6eq \r(2) cm
-
22
[] AADBDD
AB2AD236(cm)ABCACeq \r(2)AB6eq \r(2) cm.
-
(1) (2) (3)22
-
1. 2. 2 222()AC1 (1) (2)AB4BC4CC15 (3)B122222
-
22
(1)ACC1A1ABC1D1.
AC1AC1.
(2)A1B1C1
l1eq \r(42452)eq \r(97).
BB1C1
l2eq \r(44252)eq \r(89).
l1>l2l2eq \r(89).
(3)B1EAC1E
B1Eeq \f(B1C1,AC1)AA1eq \f(4,\r(89))5eq \f(20,89)
eq \r(89)
B1eq \f(20,89)
eq \r(89).
-
22
-
D 22
3 [2012] 2343451eq \r(3)2.()
A B
C D
-
22
[]
22321342
324252
12(eq \r(3))222
.
D.
-
22
-
23
-
23 1 abcd
abcd____________
-
2 adbc b2ac 23
(1)eq \f(a,b)eq \f(c,d)________
(2)adbc(abcd0)eq \f(a,b)______
eq \f(a,b)eq \f(b,c)________bac
eq \f(a,b)eq \f(c,d)eq \f(ab,b)______
eq \f(c,d)
eq \f(cd,d)
-
3 23
eq \f(AC,AB)eq \f(BC,AC)
eq \f(\r(51),2)(0.618)
-
4 23
-
5 23
-
6 23
-
23 12 1 [2012] 231PABPAPB.S1PAS2ABPBS1________S2.()231
-
[] PABPAPB PA2PBAB. S1PAS2ABPB S1PA2S2PBAB S1S2.23
-
123 2 232ABCADEBADCAEABCADE. (1)() (2)23223
-
23
(1)ABCADEABDACE.
(2)ABCADE.
BADCAE
BADDACCAEDAC
BACDAE.
ABCADE
ABCADE.
ABDACE.
ABCADE
eq \f(AB,AD)eq \f(AC,AE).BADCAE
ABDACE.
-
23
[] (1)ABCADEABDACE.
(2)BACDAEABCADEABCADEABCADEeq \f(AB,AD)eq \f(AC,AE)ABDACE.
-
23
-
1 2 323
-
23323
3 233ABCDEFABACBCDEBCDFAC.eq \f(AD,BD)eq \f(2,3)SABCaDFCE
-
23
DEBC
ADEABC.
eq \f(AD,BD)eq \f(2,3)eq \f(AD,AB)eq \f(2,5)
SADESABC425SADEeq \f(4,25)a.
SBDFeq \f(9,25)a.
SDFCESABCSBDFSADEeq \f(12,25)a.
-
23
SADES1SBDFS2
SABCSeq \r(S1)eq \r(S2)eq \r(S).
-
24
-
24 1
(1)(2)(3)(4)
-
2 24
-
24
-
1 [2012] 241DEFABDFDEBDE40 cmEF20 cmDFAC1.5 mCD8 mAB________m.2415.5 24
-
24
[] DEFBCD90DD
DEFDCB
eq \f(BC,EF)eq \f(DC,DE).
DE40 cm0.4 mEF20 cm0.2 mCD8 m
eq \f(BC,0.2)eq \f(8,0.4)
BC4 m
ABACBC1.545.5(m)
-
24224
2 [2011] 242ABCADBCBC40 cmAD30 cmHGHE2EFGHEFBCGHACABADHGM.
(1)eq \f(AM,AD)eq \f(HG,BC)
(2)EFGH
-
24
(1)EFGH
EFGHAHGABC.
HAGBACAHGABC
eq \f(AM,AD)eq \f(HG,BC).
(2)(1)eq \f(AM,AD)eq \f(HG,BC).HExHG2x
AMADDMADHE30x
eq \f(30x,30)eq \f(2x,40)x122x24.
EFGH2(1224)72(cm)
-
[] (1)AHGABC (2)HExHG2x24
-
243D 24
[2011] 243ABCABACDEABACGFBCDEFGDE2 cmAC ()
A3eq \r(3) cm B4 cm
C2eq \r(3) cm D2eq \r(5) cm
-
24
-
3244ABCDMNDMNCABCDAB4. (1)AD (2)DMNCABCD24424
-
24
(1)MNABMDeq \f(1,2) ADeq \f(1,2)BC.
DMNCABCDeq \f(DM,AB)eq \f(MN,BC)
eq \f(1,2)AD2AB2
AB4AD4eq \r(2).
(2)DMNCABCDeq \f(DM,AB)eq \f(\r(2),2).
-
25
-
25 1
RtABCC90ABcBCaACbA
A
sinAeq \f(A,)
________
cosAeq \f(A,)
________
tanAeq \f(A,A)
________
eq \f(a,c)
eq \f(b,c)
eq \f(a,b)
-
2 1 25
eq \f(1,2)
eq \f(1,2)
eq \f(\r(3),2)
eq \f(\r(3),2)
eq \f(\r(3),3)
eq \f(\r(2),2)
eq \f(\r(2),2)
eq \r(3)
-
3 01 () () 25
eq \f(sinA,cosA)tanA
-
25 1. 2. 3.
-
251B 25
1 [2012] 251ABCsinA()
A.eq \f(1,2) B.eq \f(\r(5),5) C.eq \f(\r(10),10) D.eq \f(2\r(5),5)
-
25
[] CDABO
CDAB
RtAOC
COeq \r(1212)eq \r(2)
ACeq \r(1232)eq \r(10)
sinAeq \f(OC,AC)eq \f(\r(2),\r(10))eq \f(\r(5),5).B.
-
25
-
1. 3045602. 75 25
2 [2012] ABCABeq \b\lc\|\rc\|(\a\vs4\al\co1(cosA\f(1,2)))eq \b\lc\(\rc\)(\a\vs4\al\co1(sinB\f(\r(2),2)))
eq \s\up12(2)0C________.
-
25
[] eq \b\lc\|\rc\|(\a\vs4\al\co1(cosA\f(1,2)))eq \b\lc\(\rc\)(\a\vs4\al\co1(sinB\f(\r(2),2)))
eq \s\up12(2)0
cosAeq \f(1,2)0sinBeq \f(\r(2),2)0
cosAeq \f(1,2)sinBeq \f(\r(2),2)
A60B45
C180AB180604575
75.
-
1. 2. 25225
3 [2012] 252RtABC
ACB90DABBECDE.AC15cosAeq \f(3,5).
(1)CD
(2)sinDBE
-
25
(1)AC15cosAeq \f(3,5)AB25CDeq \f(25,2)
(2)CD BDECBABC
cosECBcosABCeq \f(4,5).
BC20EC16EDeq \f(7,2).
BDeq \f(25,2)sinDBEeq \f(7,25).
-
4 [2011] (1)253ABCC90ABC30ACmCBDBDAB. D tan75 (2)M(20)MNyNOMN75.MN25325
-
25
(1)D15tan752eq \r(3)
(2)M(20)N(042eq \r(3))MNy(2eq \r(3))x42eq \r(3).
-
26
-
26 1 c2 90
532 RtABCC90 (1)a2b2________ (2)AB________ (3)sinAcosB________ cosAsinB________tanA________ (4)sin2Acos2A1 (1) (2) (3)(ca) (4)ab
eq \f(a,c)
eq \f(b,c)
eq \f(a,b)
-
2 hl 26
-
26 ()1. ()2.
-
26
1 [2012]
45.
30.
1.6 m.
20 m.
(eq \r(2)1.414eq \r(3)1.732)
-
26
BCDAE.
AExRtACEACE45AEB90
CAE45AECEx
RtABEB30AEx
tanBeq \f(AE,BE)tan30eq \f(x,BE)
BEeq \r(3)x.BECEBCBC20
eq \r(3)xx20x10eq \r(3)10.
ADAEDE1010eq \r(3)1.628.9()
28.9
-
[] BCDAE.AExRtACECEAERtABEBEBECEBCAEADAEDE.26
-
26126
-
26226326
-
1. 2. 26
-
2 [2012] 264AB12/. 601.5C()26426
-
26
CCDABD.
RtBDCBC121.518()
CBD904545
CD18sin459eq \r(2)()
RtADCCAD906030
AC2CD18eq \r(2)()
18eq \r(2)
-
1. 2. 3 [2012] 265ABCDAD.(iCEEDm)26526
-
26
BBFADBCEF.
EFBC4BFCE4.
RtABFAFB90AB5BF4.
AFeq \r(5242)3.
RtCEDieq \f(CE,ED)eq \f(1,2)
ED2CE248.
ADAFFEED34815()
-
[] BFADFABFAFCEDEDAD26