carlota andrés - cern indico
TRANSCRIPT
Carlota Andrés
Fully resummed medium-induced emissions in
dynamic media
CPhT, École Polytechnique QM2022, Krakow, Poland
In collaboration with: L. Apolinario, F. Dominguez, M.G. Martinez, C.A. Salgado
2
Energy loss
• Jet quenching: high energy partons interact with the QGP losing energy
• How does a parton lose energy in a QCD medium?
• Collisions - Important for heavy particles
• Radiation - Extra gluon radiation induced by multiple scatterings with the medium Dominant for light quarks and gluons (this talk)
Carlota Andrés
ω, k
E, p0ω, k
QM2022
E, p0ω, k
• The in-medium spectrum is given by :(ω ≪ E)
The building block
• It has been traditionally evaluated in many approximations (GLV, AMY, HO…)
Caron-Huot and Gale, 1006.2379
Carlota Andrés 3 QM2022
BDMPS-Z
• Several new approaches go beyond the usual approximations
• It’s numerical evaluation is difficult
Finite length rates:
IOE (expansion around the HO):
Fully resummed spectrum: CA, Apolinario, Martinez, Dominguez, 2002.01517, 2011.06522
Mehtar-Tani, Barata, Soto-Ontoso, Tywoniuk, 1903.00506, 2106.07402
Finite length rates + non-perturbative potential: Schlichting, Soudi, 2111.13731
4Carlota Andrés
CA, Martinez, Dominguez, 2011.06522
QM2022
• Numerics done in the brick!
The building block: in the brick
Emission spectrum
Emission rates
10°3 10°2 0.1 1 10 50!/!̄c
0
2
4
6
8
10
12
!dI
med/d
!
n0L = 12.2
Full
HO + NLO
GLV N = 1
Low-! limit
Brick(IOE)
ωdIdω
= ∫L
0dt ω
dΓdωdt
dΓ/d
ωdt
Caron-Huot and Gale, 1006.2379
Brick T = 200 MeV
t
ω̄c =μ2L
2
Carlota Andrés 6
• The goal is to compute the energy lost by a hard parton along its trajectory within an evolving media
Beyond the brick
• Then, obtain the medium parameters entering the spectrum: n(T(t)) , μ(T(t)) . . .
• One should read the medium properties (for instance, the temperature T) from the hydro at each point of the path
• And feed them to the code and compute the spectrum along the trajectory
*with multiple scatterings
t (fm)
Glauber
fKLN
PbPb 2.76 TeV b=2.0 fm
T(M
eV)
The spectrum depends on the full trajectory, there is no “per-point spectrum”
QM2022
Carlota Andrés 7
Beyond the brick II• We can compute the spectrum with time-dependent variables along a path
*with multiple scatterings
• But this is computationally demanding. Currently, it seems too costly to do it for every trajectory on the fly
ω̄c =μ2L
2
nhydro(t) = kT3(t)
• Pre-tabulate it? How do we know a priori how the medium parameters will behave along all possible paths?
QM2022
10°3 10°2 10°1 100 101
!/!̄c
0
2
4
6
!dI
med/d
!
n0L = 5
fKLN x < 1 y < 1
Glauber x < 1 y < 1
Full
PbPb 2.76 TeV b=2.0 fm
t (fm)
Glauber
fKLN
PbPb 2.76 TeV b=2.0 fm
T(M
eV)
nhydro = kT3(t)
8Carlota Andrés
• Using average values
Use a static spectrum whose parameters are given by their average along the path
• Let’s say that along the path:
n(t) =n′ 0
(t + t0)α
• Obtain the full dynamic solution for n(t)
• Compare to the static case where n0L is given by the average of n(t) along the path:
n0L = ∫L
0dt n(t)
Using average values does not work well!** And this is something we know since 2003
ω̄c =μ2L
2
10°2 10°1 100 101
0
1
2
3
4
!dI
med/d
!
n0L = 5
Æ = 1
static
10°2 10°1 100 101
!/!̄c
1.0
1.2
1.4
1.6
rati
o
t0 = 0.1
Full
QM2022
Average values?
constantμ
Carlota Andrés 9 QM2022
• The idea is to find an equivalent static scenario
Find the values of the parameters that best approximate the dynamic spectrum along the path
• Example:
- Compute the spectrum for a dynamic media where
- Compare to the static scenario given by
n(t) =n′ 0
(t + t0)α
n0L = ∫L′
0dt n(t)
n0L2
2= ∫
L′
0dt t n(t)
10°2 10°1 100 101
0
1
2
3
4
!dI
med/d
!
n0L = 5
Æ = 1
static
10°2 10°1 100 101
!/!̄c
0.96
1.00
1.04
rati
o
Full
t0 = 0.1
ω̄c =μ2L
2
Scaling laws
Scaling laws similar to these ones have been used in the HO. Salgado, Wiedemann, 0302184
constantμ
Scaling laws?
Carlota Andrés
n(t) =n′ 0
(t + t0)α
n0L = ∫L′
0dt n(t)
n0μ2L2
2= ∫
L′
0dt t n(t) μ2(t)
• Compute the full dynamic solution using
• Find the values of the parameters of the static scenario we want to compare to:
μ2(t) =μ′
2
(t + t0)2α
10°2 10°1 100 1010
1
2
3
4
5
!dI
med/d
!
Æ = 1
static
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0ra
tio
n0L = 5t0 = 0.1
Scaling laws?
• It works better than using average values, but the errors go up to ~20%
Full
10
ω̄c =μ2L
2
QM2022
μ2(t)
Carlota Andrés
nhydro(t) = k1T(t)
n0L = ∫L′
0dt nhydro(t)
n0μ2L2
2= ∫
L′
0dt t nhydro(t) μ2
hydro(t)
• Compute the full solution along a path thorough a hydro
• Find the values of the parameters of the static scenario we want to compare to:
μ2hydro(t) = k2T2(t)
Scaling laws? Hydro
• It works better than using average values, but the errors go up to ~20%
11
ω̄c =μ2L
2
QM2022
Hydro: Luzum and Romatschke, 0901.4588
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
(n0L)st = 5
PbPb 2.76 TeV b = 2 fm
static
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
Full
μ2(t)
t0 = 0.1
Carlota Andrés
Scaling laws w.r.t. a power-law case?
12 QM2022
Goal: find matching relations between the spectrum in the real world (along a path throughout a hydro) and a pre-tabulated power-law spectrum
• Why the pre-tabulated spectrum needs to be the static one?
n(t) =n′ 0
(t + t0)α μ2(t) =μ′
2
(t + t0)2α
• For instance: Compute the spectrum along a path throughout a hydro:
Compare to a power-law spectrum for a profile given by:
• The idea is to find an equivalent scenario given by a power-law
with a scaling law given by
∫L1
0dt n(t) = ∫
L2
0dt nhydro(t)
nhydro(t) = k1T(t) μ2hydro(t) = k2T2(t)
∫L1
0dt t n(t) μ2(t) = ∫
L2
0dt t nhydro(t) μ2
hydro(t)
Carlota Andrés
Scaling laws w.r.t. a power-law case
13
ω̄c =μ2L
2
QM2022
Errors below the 10%
• Select a trajectory in central PbPb 2.76 TeV collisions
• Compute the full spectrum along this path
• Compare to a power-law spectrum given by
n(t) =n′ 0
(t + t0)α μ2(t) =μ′
2
(t + t0)2α
Hydro: Luzum and Romatschke, 0901.4588
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
n0L = 5
PbPb 2.76 TeV b = 2 fm
static
Æ = 0.5 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
μ2(t)
Carlota Andrés
Scaling laws w.r.t. a power-law case
13
ω̄c =μ2L
2
QM2022
Errors below the 10%
• Select a trajectory in central PbPb 2.76 TeV collisions
• Compute the full spectrum along this path
Hydro: Luzum and Romatschke, 0901.4588
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
n0L = 5
PbPb 2.76 TeV b = 2 fm
static
Æ = 0.5 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
μ2(t)
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
n0L = 5
PbPb 2.76 TeV b = 2 fm
static
Æ = 0.5 t0 = 0.1
Æ = 1 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
μ2(t)
• Compare to a power-law with α = 0.5
• Compare to a power-law with α = 1
Carlota Andrés
Scaling laws w.r.t. a power-law case
14
ω̄c =μ2L
2QM2022
• PbPb 2.76 TeV 30-40%
Hydro: Luzum and Romatschke, 0901.4588
• PbPb 2.76 TeV 0-5%
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
n0L = 5
PbPb 2.76 TeV b = 2.0 fm µ = 225
static
Æ = 0.5 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
μ2(t)
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
n0L = 5
PbPb 2.76 TeV b = 8.5 fm µ = 45
static
Æ = 0.5 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
μ2(t)μ2(t) μ2(t)
Carlota Andrés
Scaling laws w.r.t. a power-law case
14
ω̄c =μ2L
2QM2022
• PbPb 2.76 TeV 30-40%
Hydro: Luzum and Romatschke, 0901.4588
• PbPb 2.76 TeV 0-5%
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
n0L = 5
PbPb 2.76 TeV b = 2.0 fm µ = 225
static
Æ = 0.5 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
μ2(t)
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
n0L = 5
PbPb 2.76 TeV b = 8.5 fm µ = 45
static
Æ = 0.5 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
μ2(t)
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
n0L = 5
PbPb 2.76 TeV b = 2.0 fm µ = 225
static
Æ = 0.5 t0 = 0.1
Æ = 1 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
μ2(t)
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
n0L = 5
PbPb 2.76 TeV b = 8.5 fm µ = 45
static
Æ = 0.5 t0 = 0.1
Æ = 1 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
μ2(t)
Carlota Andrés 15
Conclusions• Many new developments in the computation of the medium-induced radiation
spectrum (in the brick)
• These numerical approaches allow to compute the spectrum along a path in realistic media (given by a hydro)
• So we want to use pre-compute the spectra for a set of given profiles approximating realistic conditions (scaling laws)
• Using power-law profiles reduces the errors substantially
• But it is computationally demanding
Whatever the approach/approximation used, we can quantify the errors!
• We can think of other approachesFor instance, MC approach to mimic the Caron-Huot rates Park et al. HP2016 proceedings 1612.06754
10°3 10°2 10°1 100 101
!/!̄c
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!dI
med/d
!
µ variable
(n0L)st = 10 µ2(t) = T 2(t) n(t) = T (t)
static
fKLNb2.0 x < 1 y < 1
Æ = 0.5 t0 = 0.1
10°3 10°2 10°1 100 101
!/!̄c
2
4
6
!dI
med/d
!
µ variable
(n0L)st = 5 µ2(t) = T 2(t) n(t) = T (t)
static
fKLNb2.0 x < 1 y < 1
Æ = 0.5 t0 = 0.1
T(t) =T0
(t + t0)α
10°2 100 102
0
1
2
3
4
5
6
7
!dI d!
n0L = 5 t0 = 0.1
staticmu constmu var
10°2 100 102
0
1
2
3
4
5
6
7
n0L = 5 t0 = 0.2
staticmu constmu var
10°3 10°2 10°1 100 101 102
!/!̄c
0.0
0.5
1.0
1.5
2.0
2.5
3.0
3.5
!dI d!
n0L = 2.4 t0 = 0.1
staticmu constmu var
10°2 100 102
!/!̄c
0
2
4
6
8
10
12
n0L = 10 t0 = 0.1
staticmu constmu var
n(t) =n′ 0
(t + t0)α
μ′ 2(t) =μ′ 0
2
(t + t0)2α
α = 1
Carlota Andrés
Scaling laws w.r.t. a power-law case
19
ω̄c =μ2L
2QM2022
• PbPb 2.76 TeV 30-40%
Hydro: Luzum and Romatschke, 0901.4588
• PbPb 2.76 TeV 20-30%
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
µ variable
(n0L)st = 5
hydro Glauber b = 5.5 fm
static
Æ = 0.5 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.7
0.8
0.9
1.0
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
µ variable
(n0L)st = 5
hydro Glauber b = 8.5 fm
static
Æ = 0.5 t0 = 0.1
10°2 10°1 100 101
!/!̄c
0.7
0.8
0.9
1.0
Why don’t we use the rates?
Carlota Andrés 20
Finite length (full) rates
dΓ/d
ωdt
They depend on the time
Brick T = 200 MeV
E = 16 GeV
ω = 3 GeV
limt→∞
dΓdωdt
Asymptotic rates
Caron-Huot and Gale, 1006.2379
t
Carlota Andrés 21
• If the formation time is small, computing the rates for a brick is a good approximation (i.e. we can assume a constant temperature during the emission)
• So, one can pre-compute the static rates for all medium temperatures and at each point of the path just read the rate corresponding to the temperature at that point
• The spectrum is the integral of the rates over the trajectory
• The rates are only sensitive to a region of the medium of the size of the formation time
ωdIdω
= ∫L
0dt ω
dΓdωdt
This is how MARTINI implements the AMY (infinite length) rates
Using rates
Carlota Andrés 22
Use of asymptotic rates
Dynamic spectrum: spectrum along the path for n(t) =
n′ 0
(t + t0)α
Asymptotic rates: spectrum obtained from integrating the asymptotic (static) rates
Static spectrum: static spectrum where the values of the parameters are set by the scaling laws
tf ∝ωk2
• Asymptotic rates do not work well, especially at large energies
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
Æ = 1
static spectrum
dynamic spectrum
asymptotic rates
10°2 10°1 100 101
!/!̄c
1.0
1.5
2.0
rati
o
t0 = 0.1n0L = 5
Carlota Andrés 23
Use of full rates• For each point of the trajectory read the value of n(t) and find the equivalent
full static rate
The static rate must be evaluated at an effective time
n0τ(t) = ∫t
0dt′ n(t′ )
• How fast the rates reach the asymptote depends on how dense the medium is
ωdΓ
/dω
dt
• But the full rates depend on the time
At each point of the trajectory we need to know which time to look at
Scaling laws at the level of the rates (at each point of the path)ω
dΓ/d
ωdt
′
Carlota Andrés 24
Full Rates n(t) =n′ 0
(t + t0)α μ2(t) =μ′
2
(t + t0)2α
Debye mass constant
10°2 10°1 100 1010
1
2
3
4
5
!dI
med/d
!
dynamic spectrum
static spectrum
full rates
10°2 10°1 100 101
!/!̄c
0.8
0.9
1.0
1.1ra
tio
n0L = 5t0 = 0.1
• It works similar to the scaling laws for the spectrum: errors go up to ~15%
10°2 10°1 100 1010
1
2
3
4
!dI
med/d
!
Æ = 1
static spectrum
dynamic spectrum
full rates
10°2 10°1 100 101
!/!̄c
0.9
1.0
1.1
1.2
rati
o
n0L = 5t0 = 0.1
25
• Emission Kernel
• Broadening
• Full one (soft) gluon emission in-medium calculation
BDMPS-Z
Carlota Andrés
V(q) =8π μ2(t)
(q2 + μ2(t))2
Lmed
(Vacuum subtracted)
CA, L. Apolinário, F. Dominguez, 2002.01517
L
The full solution as an example
σ(q) ≡ − V(q) + (2π)2δ2(q)∫lV(l)
Screening mass
tf
ω, k
QM2022
25
• Emission Kernel
• Broadening
Medium information
• Full one (soft) gluon emission in-medium calculation
BDMPS-Z
Carlota Andrés
V(q) =8π μ2(t)
(q2 + μ2(t))2
Lmed
(Vacuum subtracted)
CA, L. Apolinário, F. Dominguez, 2002.01517
L
The full solution as an example
σ(q) ≡ − V(q) + (2π)2δ2(q)∫lV(l)
Screening mass
tf
ω, k
QM2022