ba(oh)2 precipitacion

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BaCl 2 0.5M NaOH 0.5M 1 ° M U E S T R A 4 ml × 0.5 mol 1000ml =0.002 0.002 mol 0.024 l =0.08 M⇒[ Ba +2 ]=0.08 20 ml× 0.5 mol 1000 ml =0.01 0.01mol 0.024 l =0.42 M⇒ ¿ 2 ° M U E S T R A 8 ml× 0.5 mol 1000ml = 0.004 0.004 mol 0.024 l =0.17 M⇒[ Ba +2 ]=0.17 16 ml× 0.5 mol 1000 ml =0.008 0.008 mol 0.024 l =0.33 M⇒[ Ba +2 ]=0.33 3 ° M U E S T R A 12 ml× 0.5 mol 1000 ml =0.006 0.006 mol 0.024 l =0.25 M⇒[ Ba +2 ]=0.25 12 ml× 0.5 mol 1000 ml =0.006 0.006 mol 0.024 l =0.25 M⇒[ Ba +2 ]=0.25 4 ° M U E S T R A 16 ml× 0.5 mol 1000 ml =0.008 0.002 mol 0.024 l =0.33 M⇒[ Ba +2 ]=0.33 8 ml× 0.5 mol 1000ml = 0.004 0.004 mol 0.024 l =0.17 M⇒[ Ba +2 ]=0.17

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Mecanismo de reaccion del Ba(OH) 2

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BaCl2 0.5MNaOH 0.5M

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