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    UNIVERSITI TEKNOLOGI MARAFAKULTI KEJURUTERAAN KIMIA

    Chemical Engineering Laboratory I (CHE465)

    NO. Title Allocated Marks (%) Marks1 Abstract 52 Introduction 53 Aims 5

    4 Theory 55 Apparatus 56 Methodology/Procedure 107 Results 108 Calculations 109 Discussion 20

    10 Conclusion 1011 Recommendations 512 Reference 5

    13 Appendix 5TOTAL MARKS 100

    Remarks:Checked by:

    -------------------------------Date:

    NAME : LUQMAN BIN MOHD IDRISSTUDENT NO : 2012625202GROUP : EH2202B

    EXPERIMENT : FILM AND DROPWISE CONDESATION UNITDATE PERFORMED : 20 th MAY 2013SEMESTER : 2PROGRAMME CODE: EH220SUBMIT TO : DR. ABDUL HADI

    http://i-learn.uitm.edu.my/Course/courseframe.php?cid=CHE465&module=informationhttp://i-learn.uitm.edu.my/Course/courseframe.php?cid=CHE465&module=information
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    Abstract

    The equipment that is used is Film and Dropwise Condensation Unit (Model: NE 163).

    There are about four experiments that should be run to achieve the objective of the experiment.

    The student must be observed the process of heat transfer during condensation, as well as gather

    experimental data for a better theoretical understanding. The main components in the unit are the

    specially designed condensers for the observation of both filmwise and dropwise condensation.

    Introduction

    Filmwise and Dropwise are two form of condensation. In filmwise condensation a laminar

    film vapour is created upon a surface. This film can then flow downward, increasing in thickness

    as additional vapour is picked up along the way. In dropwise condensation vapour droplets form

    at an acute angle to a surface. These droplets then flow downwards, accumulating static droplets

    below them along the way.

    The objective of this experiment is to investigate the difference in heat flux between the two

    forms of condensation for the same conditions. The next objective is to investigate what effect

    the presence of air in the condenser has on the heat flux and surface heat transfer coefficient.

    This experiment would be used in by any industry which is trying to increase the efficiency of

    heat transfer. An example of this is any vapour cycle such as the Rankine cycle. By increasing

    the efficiency of the condenser, its operational pressure can be reduced and the overall efficiency

    of the cycle can be increased.

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    Aims

    To demonstrate the filmwise and dropwise condensation To determine the filmwise heat flux and surface heat transfer coefficient at constant

    pressure

    To determine the dropwise heat flux and surface heat transfer coefficient at constant

    pressure

    To determine the effect of air on heat transfer coefficient of condensation

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    Theory

    Condensation of steam on the surface of a condenser causes heat to transfer from the

    steam into the cooling medium flowing through the condenser. This type of heat transfer may

    occur at very high fluxes depending on the conditions at the condenser surface. Steam may

    condense in two different manners filmwise or dropwise. For the same operating conditions,

    dropwise condensation exhibits a much higher and efficient heat transfer compared to filmwise

    condensation. Although dropwise condensation is always desirable, it seldom occurs in practice

    for a continuous period of time.

    In filmwise condensation, most heat transfer surfaces on a heat exchanger are made of

    wet table materials. During condensation, a film of condensate spreads over these surfaces. Asmore vapour condenses on the outside of the film, its thickness increases and the film will start

    flowing downwards due to its weight. Heat transfer occurs through this film of condensate to the

    surface material beneath, then to the cooling medium. The liquid film is generally a poor

    conductor of heat, contributing much to the thermal resistance and inefficiency of this mode of

    condensation.

    In dropwise condensation, If the heat transfer surfaces are treated to become

    nonwettable, the condensate that forms o n the surface will be shaped like spherical beads.

    These beads adheres together to become larger as condensation proceeds. The bigger beads will

    then start to flow downwards due to their weight, thus collecting all other static beads along the

    way. As the beads increase in size, the velocity increases, finally leaving a trail of bare surface

    free from liquid film. This bare surface offers very little resistance to the transfer of heat.

    Therefore, very high heat fluxes are possible.

    Formula used for log mean temperature difference:

    Tm = (equation 1)

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    Formula used for heat flux:

    Heat flux, = (equation 2)

    Formula for heat transfer coefficient :

    Heat transfer coefficient, U = (equation 3)

    Formula for heat remove from condensation:

    Qx = C T (equation 4)

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    Apparatus

    Film boiling condensation

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    Procedure

    1.1: General start-up procedure

    1. Main switch was ensured in the off position.

    2. The power regulator knob is turned fully anticlockwise to set the power to minimum.

    3. Ensured valve one and valve six was closed.

    4. The chamber was filled with distilled water until the water level stays between the heater

    and baffle plates. Always make sure that the heater is fully immersed in the water

    throughout the experiment, water could be filled into the chamber through the drain valve

    with the vent valve, V4 opened. Then closed the vent valve,V4.

    5. The water flow rate was adjusted to the condenser by controlling the control valveaccording to the experimental procedure.

    6. The main and heater switch was turned on. The heater power was set by rotating the

    power regulator clockwise to increase the heating power.

    7. The water temperature reading was observed, it should increase when the water starts to

    heat up.

    8. The water was heated up until to boiling point until the pressure reaches 1.02-1.10 bar.

    Valve V1 was immediately opened and follow by valve V5 for 1 minute to vacuum out

    the air inside the condenser. Then valve V1 and valve V5 was closed

    9. Let the system to stabilize. Then all relevant measurements for experimental purpose

    were takes. Make adjustment if required.

    1.2 : General shut down procedure

    1. The voltage control knob was turned to 0 volt position by turning the knob anticlockwise.

    Keep the cooling water flowing for at least 5 minutes through the condenser to cold them

    down.

    2. The main switch and power supply was switched off. Then, unplug the power supply

    cable

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    3. The water was closed and disconnected the cooling water connection tubes if necessary.

    Otherwise, leave the connection tubes for next experiment.

    4. The water inside the chamber was discharged using the discharge valve.

    Experiment 1: Demonstration of Filmwise and Dropwise condensation

    1. The basic procedure was followed as written in section 1.1. Make sure that the equipment

    is connected to the service unit.

    Experiment 2: The Filmwise Heat Flux and Surface Heat Transfer Coefficient

    Determination at Constant Pressure

    1. Cooling water was circulated through the filmwise condenser starting with a

    minimum value of 0.1LPM

    2. The heater power was adjusted to obtain the desired pressure at 1.01bar.

    3. The steam(T sat) and surface temperature(T surf ), T in(T1) and T out(T2), and flowrate was

    recorded.

    Experiment 3: The dropwise Heat Flux and Surface Heat Transfer Coefficient Determination at

    Constant Pressure

    1. Cooling water was circulated through the dropwise condenser starting with a

    minimum value of 0.4LPM

    2. The heater power was adjusted to obtain desired pressure at 1.01bar.

    3. The steam(T sat) and surface temperature(T surf ), T in(T3) and T out(T4), and flowrate was

    recorded.

    Experiment 4: The Effect of Air Inside Chamber

    1. Cooling water was circulated through the filmwise condenser at the highest flowrate

    until the pressure was reduced to below 1bar.

    2. The discharged was opened and let an amount of air to enter the chamber.

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    3. The water flowrate was regulated to the condenser starting with a minimum value of

    0.4LPM.

    4. The heater power was adjusted to obtain the desired pressure at 1.01bar.

    5. The steam(T sat) and surface temperature(T surf ), Tin(T 3) and T out(T4) and flowrate was

    recorded.

    6. Step 1-5 was repeated for dropwise condensation.

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    Result

    Experiment 1: Demonstration of filmwise and dropwise condensation

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    Experiment 2: The filmwise heat flux and surface heat transfer coefficient determination atconstant pressure.

    Flowrate

    (LPM)

    Power

    (W)

    T in

    C)

    Tout

    Tsat

    Tsurf

    Tsat-

    Tsurf

    Tm

    (w/m 2)

    U

    (w/m 2.k)

    %

    0.1 73 34.5 37.7 71.3 38.3 33.0 35.2 5531.02 157.13 3

    0.2 79 34.3 35.0 70.5 34.7 35.8 35.8 2419.98 67.60 7

    0.3 97 34.1 34.4 71.2 34.1 37.1 36.9 1555.52 42.10 10

    0.4 102 34.0 34.3 70.7 33.7 37.0 36.6 2075.80 56.79 15

    0.5 240 34.0 34.1 71.0 33.4 37.6 36.1 864.45 23.40 19

    0.6 280 34.0 34.1 70.9 33.5 37.4 36.9 1037.84 28.16 22

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    Experiment 3: The dropwise heat flux and surface heat transfer coefficient determination at

    constant pressure

    Flowrate

    (LPM)

    Power

    (W)

    T in

    Tout

    Tsat

    Tsurf

    Tsat-

    Tsurf

    Tm

    (w/m 2)

    U

    (w/m 2.k)

    %

    0.4 167 33.9 35.0 70.7 63.4 8.3 36.25 7606.71 209.84 19

    0.6 256 34.6 38.5 71.5 57.8 13.7 34.91 40436.18 1158.30 23

    0.8 260 34.5 37.4 71.1 52.0 19.1 35.13 40081.97 1140.96 30

    1.0 265 34.6 37.1 71.3 51.1 20.2 35.44 43210.36 1219.25 35

    1.2 273 34.7 36.9 71.2 51.5 19.7 35.39 45620.43 1289.08 40

    Experiment 4: The effect of air inside chamber

    For filmwise condenser

    Flowrate

    (LPM)

    Power

    (W)

    Tin

    Tout

    Tsat

    Tsurf

    Tsat-

    Tsurf

    Tm

    (w/m 2)

    U

    (w/m 2.k)

    %

    0.1 267 34.9 44.6 70.9 53.1 17.8 30.90 16766.46 542.60 3

    0.2 310 34.5 40.1 71.2 45.9 25.3 31.38 19352.39 616.71 70.3 314 34.3 37.6 71.1 43.2 27.9 35.12 17108.28 487.14 11

    0.4 333 34.2 36.6 71.0 42.0 29.0 35.59 16598.03 466.37 15

    0.5 355 34.1 36.0 71.3 40.6 30.7 36.32 16417.21 453.01 20

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    For dropwise condenser

    Flowrate

    (LPM)

    Power

    (W)

    Tin

    Tout

    Tsat

    Tsurf

    Tsat-

    Tsurf

    Tm

    (w/m 2)

    U

    (w/m 2.k)

    %

    0.4 267 34.1 36.5 72.8 42.5 30.3 37.49 9286.08 247.69 20

    0.6 269 34.1 36.0 71.1 40.2 30.9 36.04 19699.16 546.59 25

    0.8 272 34.1 35.7 71.0 39.3 31.7 36.09 21358.72 591.82 30

    1.0 274 34.1 35.5 71.1 38.8 32.3 36.30 24197.30 666.59 37

    1.2 275 34.3 35.7 71.1 38.7 32.4 36.10 29032.31 804.22 43

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    Calculation

    Experiment 2:

    Volumetric flowrate

    = 0.10LPM=0.1 L

    =

    =1.667 g/s

    Power, q x

    Qx=C T

    . g s . g. . - .

    =22.33 W

    Log mean temperature difference:

    Tm =

    =

    =

    =35.2 C

    Heat flux, =

    =

    = 5531.02 w/m 2

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    =

    = 2419.98 w/m 2

    Heat transfer coefficient, U =

    =

    =67.6 w/m 2.K

    Volumetric flowrate

    = 0.30LPM

    =0.3 L

    =

    =5 g/s

    Power, q x

    Qx=C T

    =5 g/s4.186kJ/kg.K(34.4-34.1

    = 6.28 W

    Log mean temperature difference:

    Tm =

    =

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    =

    =36.95 C

    Heat flux, =

    =

    =1555.52 w/m 2

    Heat transfer coefficient, U =

    =

    =42.1 w/m 2.K

    Volumetric flowrate

    = 0.40LPM

    =0.4 L

    =

    =6.67 g/s

    Power, q x

    Qx=C T

    =6.67 g/s4.186kJ/kg.K(34.3-34.0

    = 8.38 W

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    Log mean temperature difference:

    Tm =

    =

    =

    =36.55 C

    Heat flux, =

    =

    =2075.80 w/m 2

    Heat transfer coefficient, U =

    = =56.79 w/m 2.K

    Volumetric flowrate

    = 0.50LPM

    =0.5 L

    =

    =8.333 g/s

    Power, q x

    Qx=C T

    . g s . g. . - .

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    =3.49 W

    Log mean temperature difference:

    Tm =

    =

    =

    .

    Heat flux, =

    =

    = 864.45 w/m 2

    Heat transfer coefficient, U =

    =

    =23.4 w/m 2.K

    Volumetric flowrate

    = 0.60LPM=0.6 L

    =

    =10.0 g/s

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    Power, q x

    Qx=C T

    . g s . g. . - .

    = 4.186 W

    Log mean temperature difference:

    Tm =

    =

    =

    =36.85 C

    Heat flux, =

    =

    = 1037.84 w/m 2

    Heat transfer coefficient, U =

    =

    =28.16 w/m 2.K

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    Experiment 3:

    0

    20

    40

    60

    80

    100

    120

    140

    160

    180

    32 33 34 35 36 37 38

    Surface heat transfer coefficient vs. Temperature difference

    0

    1000

    2000

    3000

    4000

    5000

    6000

    32 33 34 35 36 37 38

    Heat flux vs. Temperature difference

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    Volumetric flowrate

    = 0.40LPM

    =0.4 L

    = =6.67 g/s

    Power, q x

    Qx=C T

    =6.67 g/s4.186kJ/kg.K(35.0-33.9

    = 30.71 W

    Log mean temperature difference:

    Tm =

    =

    =

    =36.25 C

    Heat flux, =

    =

    =7606.71 w/m 2

    Heat transfer coefficient, U =

    =

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    =209.84 w/m 2.K

    Volumetric flowrate

    = 0.60LPM

    =0.6 L

    =

    =10.0 g/s

    Power, q x

    Qx=C T

    =10.0 g/s4.186kJ/kg.K(38.5-34.6 = 163.25 W

    Log mean temperature difference:

    Tm =

    =

    =

    =34.91 C

    Heat flux, =

    =

    =40436.18 w/m 2

    Heat transfer coefficient, U =

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    =

    =1158.30 w/m 2.K

    Volumetric flowrate

    = 0.80LPM

    =0.8 L

    =

    =13.33 g/s

    Power, q x

    Qx=C T

    =13.33 g/s4.186kJ/kg.K(37.4-34.5

    = 161.82 W

    Log mean temperature difference:

    Tm =

    =

    =

    =35.13 C

    Heat flux, =

    =

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    =40081.97 w/m 2

    Heat transfer coefficient, U =

    =

    =1140.96 w/m 2.K

    Volumetric flowrate

    = 1.0LPM

    =1.0 L

    =

    =16.67 g/s

    Power, q x

    Qx=C T

    . g s . g. . - . = 174.45 W

    Log mean temperature difference:

    Tm =

    =

    =

    =35.44 C

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    =35.39 C

    Heat flux, =

    =

    =45620.43 w/m 2

    Heat transfer coefficient, U =

    = =1289.08 w/m 2.K

    0

    5000

    10000

    15000

    20000

    25000

    30000

    35000

    40000

    45000

    50000

    0 5 10 15 20 25

    Heat flux vs. Temperature difference

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    Experiment 4:Filmwise condenser

    Volumetric flowrate

    = 0.10LPM

    =0.1 L

    =

    =1.667 g/s

    Power, q x

    Qx=C T=1.667 g/s4.186kJ/kg.K(44.6-34.9

    =67.69 W

    Log mean temperature difference:

    0

    200

    400

    600

    800

    1000

    1200

    1400

    0 5 10 15 20 25

    Surface heat transfer coefficient vs. Temperature difference

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    Tm =

    =

    =

    =30.90 C

    Heat flux, =

    =

    = 16766.46 w/m 2

    Heat transfer coefficient, U =

    =

    =542.60 w/m 2.K

    Volumetric flowrate

    = 0.20LPM

    =0.2 L

    =

    =3.333 g/s

    Power, q x

    Qx=C T

    =3.333 g/s4.186kJ/kg.K(40.1-34.5

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    = 78.13 W

    Log mean temperature difference:

    Tm =

    =

    =

    =31.38 C

    Heat flux, =

    =

    = 19352.39 w/m 2

    Heat transfer coefficient, U =

    =

    =616.71 w/m 2.K

    Volumetric flowrate

    = 0.30LPM

    =0.3 L

    =

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    =5 g/s

    Power, q x

    Qx=C T

    =5 g/s4.186kJ/kg.K(37.6-34.3

    = 69.07 W

    Log mean temperature difference:

    Tm =

    =

    =

    =35.12 C

    Heat flux, =

    =

    =17108.28 w/m 2

    Heat transfer coefficient, U =

    = =487.14 w/m 2.K

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    Volumetric flowrate

    = 0.40LPM

    =0.4 L

    =

    =6.67 g/s

    Power, q x

    Qx=C T

    =6.67 g/s4.186kJ/kg.K(36.6-34.2

    = 67.01W

    Log mean temperature difference:

    Tm =

    =

    =

    =35.59 C

    Heat flux, =

    =

    =16598.03 w/m 2

    Heat transfer coefficient, U =

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    =

    =466.37 w/m 2.K

    Volumetric flowrate

    = 0.50LPM

    =0.5 L

    =

    =8.333 g/s

    Power, q x

    Qx=C T

    =8.333 g/s4.186kJ/kg.K(36.0-34.1

    =66.28 W

    Log mean temperature difference:

    Tm =

    =

    =

    =36.24 C

    Heat flux, =

    =

    = 16417.21 w/m 2

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    Heat transfer coefficient, U =

    =

    =453.01 w/m 2.K

    16000

    16500

    17000

    17500

    18000

    18500

    19000

    19500

    0 5 10 15 20 25 30 35

    Heat flux vs. Temperature difference

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    Experiment 4:Dropwise condenser

    Volumetric flowrate

    = 0.40LPM

    =0.4 L

    =

    =6.67 g/s

    Power, q x

    Qx=C T

    =6.67 g/s4.186kJ/kg.K(36.5-34.1 = 67.01 W

    Log mean temperature difference:

    0

    100

    200

    300

    400

    500

    600

    700

    0 5 10 15 20 25 30 35

    Surface heat transfer coefficient vs. Temperature difference

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    Tm =

    =

    =

    =37.49 C

    Heat flux, =

    =

    =9286.08w/m 2

    Heat transfer coefficient, U =

    =

    =247.69 m 2.K

    Volumetric flowrate

    = 0.60LPM

    =0.6 L

    =

    =10.0 g/s

    Power, q x

    Qx=C T

    . g s . g. . - .

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    = 79.53 W

    Log mean temperature difference:

    Tm =

    =

    =

    =36.04 C

    Heat flux, =

    =

    =19699.16 w/m 2

    Heat transfer coefficient, U =

    =

    =546.59 m 2.K

    Volumetric flowrate

    = 0.80LPM

    =0.8 L

    =

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    =13.33 g/s

    Power, q x

    Qx=C T

    =13.33 g/s4.186kJ/kg.K(35.7-34.1

    = 89.23 W

    Log mean temperature difference:

    Tm =

    =

    =

    =36.09 C

    Heat flux, =

    =

    =21358.72 w/m 2

    Heat transfer coefficient, U =

    = =591.82w/m 2.K

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    Volumetric flowrate

    = 1.0LPM

    =1.0 L

    = =16.67 g/s

    Power, q x

    Qx=C T

    =16.67 g/s4.186kJ/kg.K(35.5-34.1

    = 97.69 W

    Log mean temperature difference:

    Tm =

    =

    =

    =36.30 C

    Heat flux, =

    =

    =24197.30 w/m 2

    Heat transfer coefficient, U =

    =

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    =666.59 w/m 2.K

    Volumetric flowrate

    = 1.2LPM

    =1.2 L

    =

    =20 g/s

    Power, q x

    Qx=C T=20 g/s4.186kJ/kg.K(35.7-34.3

    = 117.21 W

    Log mean temperature difference:

    Tm =

    =

    =

    =36.10 C

    Heat flux, =

    =

    =29032.31 w/m 2

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    Heat transfer coefficient, U =

    =

    =804.22w/m2

    .K

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    0

    5000

    10000

    15000

    20000

    25000

    30000

    35000

    30 30.5 31 31.5 32 32.5 33

    Heat flux vs. temperature difference

    0

    100

    200

    300

    400

    500

    600

    700

    800

    900

    30 30.5 31 31.5 32 32.5 33

    Heat traansfer coefficient vs. Temperature difference

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    0

    10000

    20000

    30000

    40000

    50000

    60000

    36 36.5 37 37.5 38 38.5

    U ( W / m 2 )

    Temperature Difference (K)

    Heat Flux vs. Temperature Difference

    Filmwise

    Dropwise

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    Discussion

    Heat flux increases with steam pressure and the temperature difference between the

    steam and the condenser surface and that the values for Heat flux for each set value of pressure is

    higher using dropwise condensation that by using filmwise condensation in the same conditions.

    The final observation is confirmed in the which quotes that at atmospheric pressure, the Heat

    Flux in dropwise condensation can be more than twenty times larger than in filmwise. This can

    be explained in terms of how the condensation forms on the condenser.

    The vapour drops indropwise condensations are discrete and are continually formed and

    released which means that the surface of the condenser is also continually exposed. In

    comparison, the film created in filmwise condensation always covers the surface of the

    condenser. As a relatively poor conductor of heat, this film creates a thermal resistance which isthe reason why the value for Heat Flux is lower for filmwise in comparison to dropwise

    condensation.

    To check the accuracy of the experiment, the values for the Heat Transfer Coefficient in

    the filmwise condenser were compared to the values which are obtained theoretically using the

    Nusselt equation. One explanation for this is the presence of non-condensable gases in the steam

    vapour. The graph shows that for a certain temperature difference, the Heat Flux for a condenser

    using steam mixed with 5% of air is significantly smaller than pure steam, and the magnitude of

    this difference increases with temperature difference. In the case of Heat Transfer Coefficients,

    the value for both steam and steam with air approaches zero, but when the steam is mixed with

    air it consistently slows.

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    Conclusion

    In conclusion, dropwise condensation is a more effective method of heat transfer than

    filmwise condensation and the presence of air in steam vapour significantly reduces the heat

    transfer. This result is based on the data that is collected and the observation in the graph. The

    heat flux and the heat transfer coefficient of dropwise condensation is higher compared to

    filmwise condensation. Filmwise is poor conductor of heat which creates thermal resistance that

    causes heat flux and heat transfer coefficient is lower than dopwise condensation.

    Recommendation

    The most important thing in this experiment is student should make sure that heater always

    immersed in water during the experiment. If not the experiment should not be carry on. Next, the

    equipment that is used in the experiment must be in best condition before starting the

    experiment. Students should ask the technician that is responsible for that equipment if there

    issomething wrong with it. When student take the result, ensure that the reading pressure is at

    1.01 bar, where it is stabilized.

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    Reference

    1) Mayhew, Y, Rogers, G. (1992). Engineering thermodynamics: Work & Heat Transfer 4th ed.

    Prentice Hall.

    2) J.W. Rose, Condensation Heat Transfer Fundamentals, Transactions of the IChemE,

    vol.76(A), pp. 143 152, 199

    3) Incropera, F, DeWitt, D. (1996).Fundamentals of heat and mass transfer. 4thed. Wiley

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    Appendix