x2 t07 04 uniform circular motion (2010)
TRANSCRIPT
Acceleration with Uniform Circular Motion
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity. constantbealsoocity willlinear veltheofmagnitude the
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
constantbealsoocity willlinear veltheofmagnitude the
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
constantbealsoocity willlinear veltheofmagnitude the
A particle moves from A
to P with constant angular velocity.
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
constantbealsoocity willlinear veltheofmagnitude the
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
v
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
vv’
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
vv’
v
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
vv’
v
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
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Acceleration Involved inUniform Circular Motion
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Acceleration Involved inUniform Circular Motion
Forces Involved inUniform Circular Motion
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Acceleration Involved inUniform Circular Motion
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Forces Involved inUniform Circular Motion
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Acceleration Involved inUniform Circular Motion
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Forces Involved inUniform Circular Motion
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Acceleration Involved inUniform Circular Motion
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Forces Involved inUniform Circular Motion
e.g. (i) (2003)A particle P
of mass m
moves with constant angular velocity
on a circle of radius r. Its position at time t
is given by;
tryrx
where,sincos
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Acceleration Involved inUniform Circular Motion
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Forces Involved inUniform Circular Motion
e.g. (i) (2003)A particle P
of mass m
moves with constant angular velocity
on a circle of radius r. Its position at time t
is given by;
tryrx
where,sincos
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b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
2mrxm
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
2mrxm 2r
Am
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
22
rAmmr
2mrxm 2r
Am
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
22
rAmmr
2
23
A
mAmr
2mrxm 2r
Am
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
22
rAmmr
2
23
A
mAmr
32
Ar
2mrxm 2r
Am
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
T
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
T
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
T Tmg 0
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
T Tmg 0
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
T Tmg 0
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
T Tmg 0
xm
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
T Tmg 0
xm
T
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
2mrT T Tmg 0
xm
T
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
2mrT
25.02392 T Tmg 0
xm
T
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
2mrT
25.02392
rad/s982392
3922
T Tmg 0
xm
T
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
2mrT
25.02392
rad/s982392
3922
Exercise 9B; all
T Tmg 0
xm
T