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SOL UTI ON S

WITH

ANSWER KEY

AITS-PT # 06 [SET-A]

DROPPER ENGINEERING

(PHYSICS, CHEMISTRY & MATHS)

TARGET : JEE (MAIN + ADVANCED) – 2019

Exam. Date : 24-02-2019

AITS-PT # 06 (Solutions) (Engineering Dropper) - 2018-19 (SET-A)

AITS-PT # 06 (Solutions) (Engineering Dropper) (SET-A) - 2018-19

Potential & Concept Educations Page. 2

ANSWER KEYS FOR AITS-PT # 06 [SET # A] (TARGET – JEE MAIN-2019)

DATE : 24-02-2019

ANSWERS [CHEMISTRY]

31. B 32. C 33. B 34. B 35. C 36. D 37. D 38. B 39. B 40. A41. B 42. B 43. B 44. D 45. A 46. C 47. C 48. B 49. A 50. C51. C 52. C 53. D 54. C 55. C 56. D 57. B 58. D 59. A 60. D

ANSWERS [PHYSICS]

1. D 2. D 3. B 4. B 5. B 6. B 7. A 8. A 9. A 10. D11. C 12. C 13. B 14. A 15. C 16. B 17. C 18. B 19. B 20. A21. A 22. D 23. D 24. B 25. A 26. C 27. B 28. A 29. C 30. D

ANSWERS [MATHS]

61. B 62. C 63. C 64. C 65. A 66. B 67. B 68. A 69. B 70. C71. C 72. A 73. C 74. B 75. D 76. A 77. D 78. C 79. D 80. C81. D 82. B 83. C 84. C 85. C 86. A 87. A 88. A 89. C 90. C



PHYSICS AITS-PT-06Engineering

Dropper Batch

1. Some liquid is filled in a cylindrical vessel of radius R. Let F1 be the force applied by the liquid on thebottom of the cylinder. Now the same liquid is poured into a vessel of uniform square cross-section ofside R. Let F2 be the force applied by the liquid on the bottom of this new vessel. Then :

(A) F1 = F2 (B) 21

FF

(C) 1 2F F (D) F1 = F2

Solution :Force is same pressure is different.Hence the answer is (D).

2. A U-tube having horizontal arm of length 20 cm, has uniform cross-sectional area = 1 cm2. It is filled withwater of volume 60 cc. What volume of a liquid of density 4 g/cc should be poured from one side into theU-tube so that no water is left in the horizontal arm of the tube?(A) 60 cc (B) 45 cc (C) 50 cc (D) 35 ccSolution :

Hence the answer is (D).3. An open cubical tank was initially fully filled with water. When the tank was accelerated on a horizontal

plane along one of its side it was found that one third of volume of water spilled out. The accelerationwas(A) g/3 (B) 2g/3 (C) 3g/2 (D) NoneSolution :



Hence the answer is (B).4. A piece of steel has a weight W in air, W1 when completely immersed in water and W2 when completely

immersed in an unknown liquid. The relative density (specific gravity) of liquid is :

(A) 1

2

W – WW – W (B)

2

1

W – WW – W (C)

1 2

1

W – WW – W (D)

1 2

2

W – WW – W

Solution :

Hence the answer is (B).5. A body having volume V and density is attached to the bottom of a container as shown. Density of the

liquid is d(>). Container has a constant upward acceleration a. Tension in the string is

(A) V[dg – (g + a)] (B) V (g + a) (d – ) (C) V (d – ) g (D) noneSolution :

Hence the answer is (B).6. Water flows into a cylindrical vessel of large cross sectional area at a rate of 10–4m3/s. It flows out from

a hole of area 10–4 m2, which has been punched through the base. How high does the water rise in thevessel ?(A) 0.075 m (B) 0.051 m (C) 0.031 m (D) 0.025 mSolution :

Hence the answer is (B).7. A barometer tube reads 76 cm of mercury. If the tube is gradually inclined at an angle of 60o with

vertical, keeping the open end immersed in the mercury reservoir, the length of the mercury column willbe

(A) 152 cm (B) 76 cm (C) 38 cm (D) 38 3cmSolution :

Hence the answer is (A).



8. A cubical block of side ‘a’ and density ‘’ slides over a fixed inclined plane with constant velocity ‘v’.There is a thin film of viscous fluid of thickness ‘t’ between the plane and the block. Then the coefficientof viscosity of the thin film will be :

(A) 3 agt

5v

(B) 4 agt

5v

(C) agtv

(D) None of these

Solution :

Hence the answer is (A).9. In Young’s double slit experiment, the slits are horizontal. The intensity at a point P as shown in figure is

034

I , where I0 is the maximum intensity. Then the value of is,

(Given the distance betrveen the two slits S1and S2 is 2)

(A) –1 1cos

12

(B) –1 1sin

12

(C) –1 1tan

12

(D) –1 3sin

5

Solution :




10. Young’s experiment is performed with light or wavelength 6000 Å wherein 16 fringes occupy a certainregion on the screen. If 24 fringes occupy the same region with another light of wavelength , then is(A) 6000 Å (B) 4500 Å (C) 5000 Å (D) 4000 ÅSolution :

Hence the answer is (D).11. Interference fringes were produced in Young’s double slit experiment using light of wavelength 5000 Å.

When a film of material 2.5 × 10–3 cm thick was placed over one of the slits, the fringe pattern shifted bya distance equal to 20 fringe widths. The refractive index of the material of the film is(A) 1.25 (B) 1.33 (C) 1.4 (D) 1.5Solution :

Hence the answer is (C).12. The angle between pass axis of polarizer and analyser is 45o. The percentage of polarized light passing

through analyser is(A) 75% (B) 25% (C) 50% (D) 100%Solution :>>>Hence the answer is (C).

13. The critical angle of a certain medium is –1 3sin5

. The polarizing angle of the medium is

(A) –1 4sin

5

(B) –1 5tan

3

(C) –1 3tan

4

(D) –1 4tan

3

Solution :

Here, critical angle, –1

c3i sin5

c3sini5

As c

1 5sin i 3



According to Brewster’s law tan ip = µwhere ip is the polarising angle

–1p p

5 5tan i i tan3 3

Hence the answer is (B).14. In YDSE shown in figure a parallel beam of light is incident on the slits from a medium of refractive index

n1. The wavelength of light in this medium is 1. A transparent slab of thickness t and refractive index n3is put in front of one slit. The medium between the screen and the plane of the slits is n2. The phasedifference between the light waves reaching point O (symmetrical, relative to the slits) is

(A) 3 21 1

2 n – n tn (B) 3 2

1

2 n – n t (C)

3

2 1 2

2 n n – tn n

(D) 13 2

1

2 n n – n t

Solution :

Hence the answer is (A).15. In the figure shown if a parallel beam of white light is incident on the plane of the slits then the distance

of the nearest white spot on the screen from O is d/A. Find the value of A. (assume d << D, << d]

(A) 3 (B) 5 (C) 6 (D) 4Solution :

Hence the answer is (C).



16. A small square loop of wire of side is placed inside a large square loop of wire of side L(L >> ). The loop are coplanar and their centres coincide. The mutual inductance of the system isproportional to –

(A) L

(B) 2

L

(C) L

(D) 2L

Solution :

Hence the answer is (B).17. An electron is moving near to a conducting loop then the induced current in the loop is

(A) clockwise (B) anticlockwise(C) first anticlockwise and then clockwise (D) no currentSolution :Hence the answer is (C).

18. When two co-axial coils having same current in same direction are bring to each other, then the value ofcurrent in both coils :(A) increases (B) decreases(C) first increases and then decreases (D) remain sameSolution :When two coils are brought near to each other then flux changes to both the coils, due to which inducecurrent produces, so the current in both decreases, because induce current oppose the main current.Hence the answer is (B).

19. The variation of induced emf (E) with time (t) in a coil if a short bar magnet is moved along its axis witha constant velocity is best represented as

S N

(A) (B) (C) (D)

Solution :As the magnet moves towards the coil, the magnetic flux increases (nonlinearly). Also there is a changein polarity of induced emf when the magnet passes on to the other side of the coil.Hence the answer is (B).

20. If = 0.02 cos 100t weber and number of turns is 50 in the coil, the maximum induced emf is -(A) 314 volt (B) 100 volt (C) 31.4 volt (D) 6.28 voltSolution :Hence the answer is (A).



21. A coil of 100 turns having an average area of 100 cm2 for each turn is held in a uniform field of 50 gauss.The direction of the field being at right angles to the plane of the coil. If the field is removed in 0.01 secthen average e.m.f induced in coil is(A) 0.5 v (B) 10 v (C) 20 v (D) 50 VSolution :Hence the answer is (A).

22. The armature of D.C. motor has 20 resistance. It draws current of 1.5 ampere when run by 220 voltsD.C. supply. The value of back e.m.f induced in it will be -(A) 150V (B) 170V (C) 180V (D) 190VSolution :Hence the answer is (D).

23. Two conducting loops of radii R1 and R2 are concentric and are placed in the same plane R1 >> R2,the mutual inductance M between them will be directly proportional to -

(A) 1

2

RR (B)

2

1

RR (C)

21

2

RR (D)

22

1

RR

Solution :Hence the answer is (D).

24. The frequency of oscillation of current in the inductor is :

(A) 1

3 LC (B) 1

6 LC(C)

1LC (D)

12 LC

Solution :

eff eff

1 1 1 1r2 L c 2 3L 3C 6 LC

.

Hence the answer is (B).25. In the circuit shown below, the ac source has voltage v = 20 cos(t) volts with = 2000 rad/sec. the

amplitude of the current will be nearest to

(A) 2A (B) 3.3A (C) 2/ 5A (D) 5ASolution :




26. When the rms voltages VL, VC and VR are measured respectively across the inductor L, the capacitor Cand the resistor R in a series LCR circuit connected to an AC source, it is found that the ratio VL : VC :VR = 1 : 2 : 3. If the rms voltage of the AC source is 100 V, then VR is close to(A) 50 V (B) 70 V (C) 95 V (D) 100 VSolution :

Hence the answer is (C).27. An AC voltage source of variable angular frequency and fixed amplitude V0 is connected in series with

a capacitance C and an electric bulb of resistance R (inductance zero). When is increased.(A) the bulb glows dimmer. (B) the bulb glows brighter.(C) total impedance of the circuit is unchanged. (D) total impedance of the circuit increases.Solution :The impedance of an RC network is given by

2

2

1Z R( C)

So whenever there is an increase in agnular frequency, the first term in the equation decreases.Power is inversely proportional to resistance. So, the bulb glows brighter.Hence the answer is (B).

28. When 100 volts dc is supplied across a solenoid, a current of 1.0 amperes flows in it. When 100 volts acis applied across the same coil, the current drops to.0.5 ampere. lf the frequency of ac source is 50 Hz,then the impedance and inductance of the solenoid are(A) 200 and 0.55 henry (B) 100 and 0.86 henry(C) 200 and 1.0 henry (D) 100 and 0.93 henrySolution :




29. Two identical bulbs are connected to an ac source by using an inductor and a capacitor in series, with thebulbs as shown then the brightness of B1 and B2 will be -

(A) Same for both cases. (B) More for B1 than B2

(C) Depends on the frequency of source (D) More for B2 than B1

Solution :>>>Hence the answer is ().The brigntness of B1 and B2 depend upon the currents in them which depends

upon the freqeuncy of the source. (Since XL =L and C1XC

)

AltemativeSince due to frequency, resistance will be difference, so the voltage drop would be different, so the brighnessdepends on frequency.Hence the answer is (C).

30. A transformer with 8 : 1 turns ratio has 60 Hz, 120 volt input. The frequency of output is :(A) 40 Hz (B) 480 Hz (C) 2 Hz (D) 60 HzSolution :In a transformer, frequency remains same for input & output.Hence the answer is (D).



CHEMISTRY AITS-PT-06Engineering

Dropper Batch

31. The most reactive compound towards formation of cyanohydrin on treatment with KCN followed byacidification is(A) Benzaldehyde (B) p-Nitrobenzaldehyde(C) Phenylacetaldehyde (D) p-Hydroxybenzaldehyde

Solution :

Hence the answer is (B).32. Which of the following compounds would not form a silver mirror with Tollen's reagent ?

(A) R.CHO (B) Ar.CHO (C) CH3–CO–R (D) RCHOHCOR

Solution :

Hence the answer is (C).33. Which does not react with Fehling solution

(A) CH3CHO (B) C6H5CHO (C) HCOOH (D) C6H12O6

Solution :Hence the answer is (B).

34. The appropriate reagent for the following transformation

(A) Zn(Hg)/HCl (B) NH2NH2, OH– (C) H2/Ni (D) NaBH4

Solution :

Hence the answer is (B).35. An organic compound of molecular formula C3H6O did not give a silver a silver mirror with Tollen's

reagent, but gave an oxime with hydroxylamine. It may be(A) CH2 = CHCH2OH (B) CH3CH2CHO(C) CH3COCH3 (D) CH2 = CH–O–CH3

Solution :Hence the answer is (C).

36. Which of the following compounds will undergo self aldol condensation in the presence of cold dilute alkali ?(A) CH2 = CH–CHO (B) CH C–CHO(C) C6H5CHO (D) CH3CH2CHOSolution :Hence the answer is (D).



37. Predict the product B in the sequence of reactions

(A) CH3COONa (B) CH3COOH (C) CH3CHO (D)


38. Two moles of an aldehyde react with concentrated solution of sodium hydroxide and produce one mole ofacid and one mole of alcohol. The aldehyde is(A) Acetaldehyde, CH3CHO (B) Formaldehyde, HCHO(C) Propionaldehyde, CH3CH2CHO (D) Isobutyraldehyde, (CH3)2CHCHOSolution :Hence the answer is (B).

39. In which of the following reacrions, both oxidised and reduced forms of the same compound are obtained ?(A) Aldol condensation (B) Cannizzaro's reaction(C) Reimer-Tiemann reaction (D) Kolbe's synthesis


40. Which one of the foliowing orders of acid strength is correct ?(A) RCOOH > HOH > ROH > HC CH (B) RCOOH > HOH > HC CH > ROH(C) RCO0H > HC CH > HOH > ROH (D) RCOOH > ROH > HOH > HC CH

Solution :

Hence the answer is (A).41. Give the expected product of the following reaction.

(A) (B)

(C) (D)


42. Product of the reaction is :

(A) (B) (C) (D)




43. Structure of (B) is:

(A) (B) (C) (D)


44. What is the product obtained from the following reaction ?

(A) i (B) ii (C) iii (D) iv


45. Compound (B) is :

(A) (B) (C) (D) (A) and (C) both

Solution :Hence the answer is (A).

46. A carbonyl compound gives a positive iodoform test but does not reduce Tollen's reagent of Fehling'ssolution. It forms a cyanohydrin with HCN, which on hydrolysis gtives a hydroxy acid with a methyl sidechain. The compound is(A) Acetaldehyde (B) Propionaldehyde (C) Acetone (D) CrotonaldehydeSolution :Hence the answer is (C).

47. Which of the following will not undergo Hoffmann bromamide reaction ?

(A) (B) (C) (D)




48. Which of the following give positive isocyanide test ?

(A) (B) CH3 – NH2 (C) CH3 – NH – CH3 (D)


49. Product (C) is :

(A) (B) (C) (D)

Solution :Hence the answer is (A).

50. Product (B) is :

(A) Ph – CH2 – NH2 (B) Ph – OH (C) Ph – NH2 (D) Ph – CH3


51. Product (B) is :

(A) (B) (C) (D)


52. Ferric hydroxide sol is positively charged colloid. The coagulating power of 243 , SONO and 3

4PO ionswould be in the order

(A) 34

243 POSONO (B) 3

4324 PONOSO

(C) 324

34 NOSOPO (D) 3

4243 POSONO

Solution :According to Hardy schulze rule the ions having opposite charge to sol particle cause coagulation andgreater the valency of oppositely charged ion more is the coagulating power 3

24

34( NOSOPO ).

Hence the answer is (C).53. Which one is Freundlich’s equation

(A) Pn

Kmx log1log (B) )(exp KP

mx

(C) 2KPmx (D) C

nK

mx log1loglog




54. Formation of Ni(CO)4 and subsequent its decomposition into Ni and CO (recycled) makes the basis ofMond’s process

CO4Ni)CO(NiCO4Ni 21 T4

T T1 and T2 are :(A) 1000C, 500C (B) 500C, 1000C (C) 500C, 2300C (D) 2300C, 500CSolution :Hence the answer is (C).

55. Match List I with List II and select the correct answer using the codes gives below the lists :List I List IIA.van Arkel method 1. Manufacture of caustic sodaB.Solvay process 2. Purification of titaniumC.Cupellation 3. Manufacture of Na2CO3D.Poling 4. Purification of copper

5. Refining of silverCodes :

A B C D(A) 2 1 3 4(B) 4 3 2 5(C) 2 3 5 4(D) 5 1 3 4Solution :Hence the answer is (C).

56. The process of heating and suddenly cooling of steel is known as :(A) tampering (B) annealing (C) hardening (D) quenchingSolution :Hence the answer is (D).

57. H2O2 has reducing action upon(A) PbS (B) O3 (C) H2S (D) Na2SO3

Solution :

Hence the answer is (B).58. Highest boiling point is of

(A) NH3 (B) AsH3 (C) PH3 (D) SbH3


59. Among CaH2, NH3, NaH and B2H6, which are covalent hydrides ?(A) NH3 and B2H6 (B) NaH and CaH2 (C) NaH and NH3 (D) CaH2 and B2H6

Solution :




60. Match list I with list II. Choose the correct matching codes from the choices given :List I List II

A. BaH2 1. ComplexB. AlH3 2. Lewis acidC. B2H6 3. InterstitialD. LaH3 4. CovalentE. LiAlH4 5. Ionic(A) A-3, B-2, C-4, D-5, E-1 (B) A-5, B-2, C-4, D-3, E-1(C) A-5, B-4, C-2, D-3, E-1 (D) A-5, B-4, C-2, D-3, E-1

Solution :>>>Hence the answer is (D).



61. If 4z – 2z , then the maximum value of |z| is equal to

(A) 3 1 (B) 5 1 (C) 2 (D) 2 2

Solution :

Hence the answer is (B).62. If |z + 4| 3, then the maximum value of |z + 1| is

(A) 4 (B) 10 (C) 6 (D) 0Solution :


63. If z2 + z + 1 = 0, where z is complex number, then the value of 2 2

22

1 1z zz z

2 23 6

3 61 1z ... zz z

is

(A) 54 (B) 6 (C) 12 (D) 18Solution :

MATHS AITS-PT-06Engineering

Dropper Batch



Hence the answer is (C).64. Let z and w be two complex numbers such that z iw 0 and arg (zw) = . Then, arg (z) equals

(A) 4

(B) 2

(C) 34

(D) 54

Solution :


65. If ( 1) is cube root of unity satisfying 21 1 1 2a b c

and

2 2 21 1 1 2

a b c

, then the value of

1 1 1a 1 b 1 c 1

is equal to

(A) 2 (B) –2 (C) –1 + 2 (D) None of theseSolution :


66. If 8 8cos isin11 11

, then Re ( + 2 + 3 + 4 + 5) is equal to

(A) 12

(B) 1–2

(C) 0 (D) None of these

Solution :



Hence the answer is (B).67. The remainder when 337 is divided by 80 is

(A) 78 (B) 3 (C) 2 (D) 35Solution :

Hence the answer is (B).68. If (1 + x – 2x2)8 = a0 + a1x + a2x2 + ... + a16x16, then the sum a1 + a3 + a5 + ... + a15 is equal to

(A) –27 (B) 27 (C) 28 (D) None of theseSolution :

Hence the answer is (A).69. If (1 + x)10 = a0 + a1x + a2x2 + ... + a10x10, then (a0 – a2 + a4 – a6 + a8 – a10)2 + (a1 – a3 + a5 – a7 + a9)2 is equal to

(A) 310 (B) 210 (C) 29 (D) None of theseSolution :

Hence the answer is (B).70. The coefficient of a8b4c9d9 in (abc + abd + acd + bcd)10 is

(A) 10! (B) 10!

8! 4! 9! 9! (C) 2520 (D) None of these

Solution :

Hence the answer is (C).71. The value of C0 + 3C1 + 5C2 + 7C3 + ... + (2n + 1)Cn is equal to

(A) 2n (B) 2n + n 2n – 1 (C) 2n (n + 1) (D) None of these



Solution :


72. The value of 50

100 200r 150 r

r 0( C C )

is equal to

(A) 300C50 (B) 100C50 · 200C150 (C) 100C50 (D) None of theseSolution :

Hence the answer is (A).73. If A = 2nC0

2nC1 + 2nC1 2n – 1C1 + 2nC2 2n – 2C1 + ..., then A is

(A) 0 (B) 2n (C) n · 22n (D) 1Solution :


74. If 2 35 5 7 5 7 9 ...

2!3 3!3 4!3

, then 2 + 4 is equal to

(A) 21 (B) 23 (C) 25 (D) 27Solution :



Hence the answer is (B).75. If n + 1Cr + 1 : nCr : n – 1Cr – 1 = 11 : 6 : 3, then nr is equal to

(A) 20 (B) 30 (C) 40 (D) 50Solution :

Hence the answer is (D).

76. If the 6th term in the expansion of the binomial xlog(10 – 3 ) (x – 2)log3 m5[ 2 2 ] is equal to 21 and it is knownthat the binomial coefficient of 2nd, 3rd and 4th terms in the expansion represent, respectively the first,third and fifth terms of an AP, then x is equal to(A) 0 (B) 1 (C) –2 (D) 3Solution :



Hence the answer is (A).77. The median and SD of a distribution are 20 and 4, respectively. If each item is increased by 2, then new

median and SD will be(A) 20, 6 (B) 22, 6 (C) 18, 6 (D) 22, 4Solution :Median = 20 + 2 = 22, SD = 4Hence the answer is (D).

78. The standard deviation for the set of numbers 1, 4, 5, 7, 8 is 2.45 nearly. If 10 is added to each number,then new standard deviation is(A) 24.45 (B) 12.45 (C) 2.45 (D) 0.245Solution :The standard deviation remains same = 2.45Hence the answer is (C).

79. The variation of 15 observations was found to be 8. If each observation is multiplied by 4, the newvariance of the series is(A) 32 (B) 24 (C) 8 (D) 128Solution :New variance = 8 · (4)2 = 128 [ Var (kx) = k2 Var (x)]Hence the answer is (D).

80. The average marks of boys in a class is 52 and that of girls is 42. The average marks of boys and girlscombined is 50. The percentage of boys is the class is(A) 40% (B) 20% (C) 80% (D) 60%Solution :




81. Suppose a population A has 100 observations 101, 102, ..., 200 and another population B has 100 observations

151, 152, ..., 250. If VA and VB represent the variances of the two populations respectively, then A

B

VV

is

(A) 94

(B) 49

(C) 23

(D) 1

Solution :

Hence the answer is (D).82. In a class of 100 students, there are 70 boys whose average marks in a subject are 75. If the average

marks of the complete class is 72, then what is the average of the girls?(A) 73 (B) 65 (C) 68 (D) 74Solution :

Hence the answer is (B).83. Let P(x) denotes the probability of the occurrence of event x. Then, all those points (x, y) = (P (A), P (B)),

in a plane which satisfy the conditions, 3P(A B)4

and 1 3P(A B)8 8 implies

(A) 11P(A) P(B)8

(B) 11P(A) P(B)8

(C) 7 11P(A) P(B)8 8 (D) None of the above

Solution :



Hence the answer is (C).84. Two dice are thrown simultaneously to get the coordinates of a point in XY -plane. Then, the probability

that this point lies inside or on the region bounded by |x| + |y| = 3 is

(A) 3

14(B)

23

(C) 1

12(D)

414

Solution :

Hence the answer is (C).85. In a game of tickets, 8 tickets numbered 1, 2, 3, ...., 8 are grouped in pairs at random and observed

pairwise, the lower numbered tickets of pairs are kept and other are thrown and this process is repeatedonce more. Then, the probability that out of remaining two tickets, one is numbered 4, is

(A) 2

35(B)

335

(C) 4

35(D)

17

Solution :

Hence the answer is (C).86. There are four players A1, A2, A3 and A4 in pool A and four players B1, B2, B3 and B4 in pool B. They are

arbitrarily paired in their respective pools to play against each other and one winner is decided in each pairto play in semi-final. It is known that whenever A1 plays with A2, A1 wins the game and whenever B1plays with B2, B1 wins. Then, the probability that(i) A1 and A2 reach in the semi-final.(ii) A1, A2, B2 and B3 reach semi-final.



(A) 1 1,6 12

(B) 1 1,6 6

(C) 1 1,6 16

(D) None of these

Solution :


87. Four persons independently solve a certain problem correctly with probabilities 12

, 34

, 14

, 18

. Then theprobability that the problem is solved correctly by at least one of them is

(A) 235256

(B) 21

256(C)

3256

(D) 253256

Solution :

Hence the answer is (A).88. Three boys and two girls stand in a queue. The probability, that the number of boys ahead of every girl is

at least one more than the number of girls ahead of her, is

(A) 12

(B) 13

(C) 23

(D) 34

Solution :




89. A box contains 24 identical balls of which 12 are white and 12 are black. The balls are drawn at randomfrom the box one at a time with replacement. The probability that a white ball is drawn for the 4th time onthe 7th draw is(A) 5/64 (B) 27/32 (C) 5/32 (D) 1/2Solution :

Hence the answer is (C).90. One Indian and four American men and their wives are to be seated randomly around a circular table.

Then, the conditional probability that the Indian man is seated adjacent to his wife given that each Americanman is seated adjacent to his wife is(A) 1/2 (B) 1/3 (C) 2/5 (D) 1/5Solution :


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