mc0067 database set1

Download Mc0067 Database Set1

Post on 05-Apr-2018

219 views

Category:

Documents

0 download

Embed Size (px)

TRANSCRIPT

  • 7/31/2019 Mc0067 Database Set1

    1/18

    MC0067Database Management System

    Set-1

    Question 1. Write about:1. Linear Search

    2. Collision Chain

    ANS.

    Linear SearchLinear search, also known as sequential search, means starting at the beginning of the data

    and checking each item in turn until either the desired item is found or the end of the data is

    reached. Linear search is a search algorithm, also known as sequential search that is

    suitable for searching a list of data for a particular value. It operates by checking every

    element of a list one at a time in sequence until a match is found. The Linear Search, orsequential search, is simply examining each element in a list one by one until the desired

    element is found. The Linear Search is not very efficient. If the item of data to be found is at

    the end of the list, then all previous items must be read and checked before the item that

    matches the search criteria is found. This is a very straightforward loop comparing every

    element in the array with the key. As soon as an equal value is found, it returns. If the loop

    finishes without finding a match, the search failed and -1 is returned. For small arrays,

    linear search is a good solution because it's so straightforward. In an array of a million

    elements linear search on average will take500, 000 comparisons to find the key. For a much

    faster search, take a look at binary search.

    Algorithm

    For each item in the databaseif the item matches the wanted info

    exit with this item

    Continue loop

    wanted item is not in database

    Collision Chain:In computer science, ahash table orhash map is a data structure that uses a hash function to map

    identifying values, known as keys (e.g., a person's name), to their associated values (e.g., their

    telephone number). Thus, a hash table implements an associate array. The hash function is used to

    transform the key into the index (the hash) of an array element (the slot or bucket) where thecorresponding value is to be sought.

    Ideally, the hash function should map each possible key to a unique slot index, but this ideal is rarely

    achievable in practice (unless the hash keys are fixed; i.e. new entries are never added to the table

    after it is created). Instead, most hash table designs assume that hast collisionsdifferent keys that

    map to the same hash valuewill occur and must be accommodated in some way.

    2. Write about:

  • 7/31/2019 Mc0067 Database Set1

    2/18

    ANS.

    2.1 Integrity Rules:These are the rules which a relational database follows in order to stay accurate and accessible.

    These rules govern which operations can be performed on the data and on the structure of the

    database. There are three integrity rules defined for a relational databse,which are:-

    Distinct Rows in a Table - this rule says that all the rows of a table should be distinct to

    avoid in ambiguity while accessing the rows of that table. Most of the modern database

    management systems can be configured to avoid duplicate rows.

    Entity Integrity (A Primary Key or part of it cannot be null) - this rule says that 'null' is

    special value in a relational database and it doesn't mean blank or zero. It means the

    unavailability of data and hence a 'null' primary key would not be a complete identifier. This

    integrity rule is also termed as entity integirty.

    Referential Integrity - this rule says that if a foreign key is defined on a table then a value

    matching that foreign key value must exist as th e primary key of a row in some other table.

    The following are the integrity rules to be satisfied by any relation.

    No Component of the Primary Key can be null. The Database must not contain any unmatched Foreign Key values. This is called the

    referential integrity rule.

    Unlike the case of Primary Keys, there is no integrity rule saying that no component of the

    foreign key can be null. This can be logically explained with the help of the following

    example:

    Consider the relations Employee and Account as given below.

    2.2 Relational Operators:In the relational model, the database objects seen so far have specific names:

    Name MeaningRelation Table

    Tuple Record(Row)

    Attribute Field(Column)

    Cardinality Number of Records(Rows)

    Degree(or Arity) Number of Fields(Columns)

    View Query/Answer table

    On these objects, a set of operators (relational operators) is provided to manipulate them:

    1. Restrict

    2. Project

    3. Union

    4. Difference

    5. Product

    6. Intersection

    7. Join

    8. Divide

    Restrict:

    Restrict simply extract records from a table.

    it is also known as Select, but not the same SELECT as defined in SQL.

    Project:Project selects zero or more fields from a table and generates a new table

  • 7/31/2019 Mc0067 Database Set1

    3/18

    that contains all of the records and only the selected fields (with no duplications).

    Union:

    Union creates a new table by adding the records of one table to another

    tables, must be compatible: have the same number of fields and each of the field pairs has to

    have values in the same domain.

    Difference:

    The difference of two tables is a third table which contains the records which appear in the

    first BUT NOT in the second.

    Product:

    The product of two tables is a third which contains all of the records in the first one added to

    each of the records in the second.

    Intersection:

    The intersection of two tables is a third tables which contains the records which are commonto both.

    Join:

    The join of two tables is a third which contains all of the records in the first and the second

    which are related.

    Divide:

    Dividing a table by another table gives all the records in the first which have values in their

    fields matchingALL the records in the second.

    The eight relational algebra operators are

    1. SELECTTo retrieve specific tuples/rows from a relation.

    2. PROJECTTo retrieve specific attributes/columns from a relation.

    http://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image00634.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image00427.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image00634.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image00427.gif
  • 7/31/2019 Mc0067 Database Set1

    4/18

    3. PRODUCTTo obtain all possible combination of tuples from two relations.

    4. UNIONTo retrieve tuples appearing in either or both the relations participating in the

    UNION.

    Eg: Consider the relation Ord_Jul as

    ollows

    (Table: Ord_Jul)

    Note: The union operation shown above logically implies retrieval of records of Orders

    placed in July or in August

    5. INTERSECTTo retrieve tuples appearing in both the relations participating in the

    INTERSECT.

    Eg:

    To retrieve Cust# of Customers whove placed orders in

    July and in AugustCust#003

    6. DIFFERENCETo retrieve tuples appearing in the first relation participating in the

    DIFFERENCE but not the second.

    http://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01220.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01027.jpghttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image00823.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01220.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01027.jpghttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image00823.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01220.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01027.jpghttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image00823.gif
  • 7/31/2019 Mc0067 Database Set1

    5/18

    Eg: To retrieve Cust# of Customers whove placed orders in July but

    not in August

    Cust#001

    7. JOINTo retrieve combinations of tuples in two relations based on a common field in

    both the relations.

    Eg:

    ORD_AUG join CUSTOMERS (here, the common column is

    Cust#)

    3. Write about:

    Three Level Database ArchitectureData and Related Structures

    Data are actually stored as bits, or numbers and strings, but it is difficult to work with data at

    this level.

    http://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01613.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01414.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01613.gifhttp://train-srv.manipalu.com/wpress/wp-content/uploads/2009/06/clip-image01414.gif
  • 7/31/2019 Mc0067 Database Set1

    6/18

    It is necessary to view data at different levels of abstraction.

    Schema:

  • 7/31/2019 Mc0067 Database Set1

    7/18

    Description of data at some level. Each level has its own schema.

    We will be concerned with three forms of schemas:

    physical,

    conceptual, and external

    Physical Data Level

    The physical schema describes details of how data is stored: files, indices, etc. on the

    random access disk system. It also typically describes the record layout of files and type offiles (hash, b-tree, flat).

    Early applications worked at this level - explicitly dealt with details. E.g., minimizing

    physical distances between related data and organizing the data structures within the file

    (blocked records, linked lists of blocks, etc.)

    Problem:

    Routines are hardcoded to deal with physical representation.

    Changes to data structures are difficult to make.

    Application code becomes complex since it must deal with details. Rapid implementation of new features very difficult.

    Conceptual Data Level

    Also referred to as the Logical level

    Hides details of the physical level.

    In the relational model, the conceptual schema presents data as a set of tables.

    The DBMS maps data access between the conceptual to physical schemas automatically.

    Physical schema can be changed without changing application:

    DBMS must change mapping from conceptual to physical.

    Referred to as physical data independence.

  • 7/31/2019 Mc0067 Database Set1

    8/18

    External Data Level

    In the relational model, the external schema also presents data as a set of relations. An

    external schema specifies a view of the data in terms of the conceptual level. It is tailored to

    the needs of a particular category of users. Portions of stored data should not be seen by some

    users and begins to implement a level of security and simplifies the view for these users

    Examples:

    Students should not see faculty salaries. Faculty should not see billing or payment data.

    Information that can be derived from stored data might be viewed as if it were stored.

    GPA not stored, calculated when needed.

    Applications are written in terms of an external schema. The external view is computed when

    accessed. It is not stored. Different external schemas can be provided to different categories

    of users. Translation from external level to conceptual level is done automatically by DBMS

    at run time. The conceptual schema can be changed without changing application:

    Mapping from external to conceptual must be changed.

    Referred to as conceptual data independence.

    DBMS SERVICEJump to:navigation,search

    DBMS_SERVICE is aPL/SQLpackage that can be used to define and manage

    database services for a single instance. To define aRACservice (multi-instance) see

    svrctl. Please note that services can also be defined from theDBCAGUI.

    Functions

    [edit] dbms_service.CREATE_SERVICE

    SQL> exec dbms_service.CREATE_SERVICE(SERVICE_NAME=>'orderentry',NETWORK_NAME=>'db11g')

    http://www.orafaq.com/wiki/DBMS_SERVICE#column-onehttp://www.orafaq.com/wiki/DBMS_SERVICE#column-onehttp://www.orafaq.com/wiki/DBMS_SERVICE#column-onehttp://www.orafaq.com/wiki/DBMS_SERVICE#searchInputhttp://www.orafaq.com/wiki/DBMS_SERVICE#searchInputhttp://www.orafaq.com/wiki/DBMS_SERVICE#searchInputhttp://www.orafaq.com/wiki/PL/SQLhttp://www.orafaq.com/wiki/PL/SQLhttp://www.orafaq.com/wiki/PL/SQLhttp://www.orafaq.com/wiki/RAChttp://www.orafaq.com/wiki/RAChttp://www.orafaq.com/wiki/RAChttp://www.orafaq.com/wiki/Svrctlhttp://www.orafaq.com/wiki/Svrctlhttp://www.orafaq.com/wiki/DBCAhttp://www.orafaq.com/wiki/DBCAhttp://www.orafaq.com/wiki/DBCAhttp://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=3http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=3http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=3http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=3http://www.orafaq.com/wiki/DBCAhttp://www.orafaq.com/wiki/Svrctlhttp://www.orafaq.com/wiki/RAChttp://www.orafaq.com/wiki/PL/SQLhttp://www.orafaq.com/wiki/DBMS_SERVICE#searchInputhttp://www.orafaq.com/wiki/DBMS_SERVICE#column-one
  • 7/31/2019 Mc0067 Database Set1

    9/18

    [edit] dbms_service.MODIFY_SERVICE

    Modify an existing service. Example:

    SQL> exec DBMS_SERVICE.MODIFY_SERVICE( -

    > service_name => 'o11gr1', -> goal => DBMS_SERVICE.GOAL_THROUGHPUT, -> failover_method => DBMS_SERVICE.FAILOVER_METHOD_BASIC, -> failover_type => DBMS_SERVICE.FAILOVER_TYPE_SELECT, -> failover_retries => 10, -> failover_delay => 1, -> clb_goal => DBMS_SERVICE.CLB_GOAL_LONG);PL/SQL procedure successfully completed.

    [edit] dbms_service.START_SERVICE

    SQL> exec dbms_service.START_SERVICE('orderentry')SQL> show parameter service

    [edit] dbms_service.STOP_SERVICESQL> exec dbms_service.STOP_SERVICE('orderentry')

    [edit] dbms_service.DELETE_SERVICE

    SQL> exec dbms_service.DELETE_SERVICE('orderentry')

    [edit] Monitor

    Use the following dictionary views to monitor services:

    dba_services - All defined services

    gv$active_services - All active (started) services

    To see what service a session is connected to:

    SELECT username, program, machine, service_name FROM gv$session;

    Q. 4 explain the SQL syntax for :

    1. Table Creation with constraint imposing using an example

    Ans.

    2. Functions Count, Sum, Average with appropriate examples

    Ans.

    Five Important aggregate functions are COUNT, SUM, AVG, MIN, and MAX. They are

    called aggregate functions because they summarize the results of a query, rather than listingall of the rows.

    http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=4http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=4http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=4http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=5http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=5http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=5http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=6http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=6http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=6http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=7http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=7http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=7http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=8http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=8http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=8http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=7http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=6http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=5http://www.orafaq.com/wiki/index.php?title=DBMS_SERVICE&action=edit&section=4
  • 7/31/2019 Mc0067 Database Set1

    10/18

    1. COUNT (*) gives the number of rows satisfying the conditions

    2. SUM () gives the total of all the rows, satisfying any conditions, of the given column,

    where the given column is numeric.

    3. AVG () gives the average of the given column.

    4. MIN () gives the smallest figure in the given column.

    5. MAX () gives the largest figure in the given column.

    1. COUNT (*)

    The keyword COUNT can be used together to count the number of distinct results.

    Syntax :-

    SELECT COUNT (column) FROM table

    EXAMPLE:-

    With this "Persons" Table:

    NAME AGE

    Varsha 34

    Ranjan 45

    Devi

    This example finds the number of persons with a value in the "Age" filled in the "Persons"

    table:

    SELECT COUNT (Age) FROM Persons

    RESULT:-

    2

    The COUNT (column) function is handy for finding columns without a value. Note that the

    result is one less than the number of rows in the original table because one of the persons

    does not have an age value stored.

  • 7/31/2019 Mc0067 Database Set1

    11/18

    2. SUM ()

    The SUM function returns the total sum of a column in a given selection. NULL values

    are not included in the calculation.

    Syntax :-

    SELECT SUM (column) FROM table

    EXAMPLE I :-

    With this "Persons" Table:

    NAME AGE

    Varsha 34

    Ranjan 45

    Devi 19

    This example returns the sum of all ages in the "person" table:

    SELECT SUM (Age) FROM Persons

    RESULTS:-

    98

    EXAMPLE II :-

    This example returns the sum of ages for persons that are more than 20 years old:

    SELECT SUM(Age) FROM Persons WHERE Age>20

    RESULT:-

    79

    3. AVG ()

    The AVG function returns the average value of a column in a selection. NULL values

    are not included in the calculation.

  • 7/31/2019 Mc0067 Database Set1

    12/18

    Syntax :-

    SELECT AVG (column) FROM table

    EXAMPLE I :-

    This example returns the average age of the persons in the "Persons" table:

    SELECT AVG(Age) FROM Persons

    Q. 5. Compare and Contrast the Centralized and Client / Server Architecture for DBMS.

    AnsIncentralized database systems, the database system, application programs, and user-

    interface all are executed on a single system and dummy terminals are connected to it. The

    processing power of single system is utilized and dummy terminals are used only to display

    the information. As the personal computers became faster, more powerful, and cheaper, the

    database system started to exploit the available processing power of the system at the users

    side, which led to the development of client/server architecture.

    Disadvantages of centralized database system::

    o When the central site computer or database system goes down, then everyone is

    blocked from using the system until the system comes back.

    o Communication costs from the terminals to the central site can be expensive.

    In client/server architecture, the processing power of the computer system at the users end

    is utilized by processing the user-interface on that system.

    A client is a computer system that sends request to the server connected to the network, and aserver is a computer system that receives the request, processes it, and returns the requested

    information back to the client. Client and server are usually present at different sites. The end

    users (remote database users) work on client computer system and database system runs on

    the server. Servers can be of several types, for example, file servers, printer servers, web

    servers, database servers, etc. The client machines have user interfaces that help users to

    utilize the servers. It also provides users the local processing power to run local applications

    on the client side.

    There are two approaches to implement client/server architecture. In the first approach, the

    user interface and application programs are placed on the client side and the database system

    on the server side. This architecture is called two-tier architecture. The application programsthat reside at the client side invoke the DBMS at the server side. The application program

    http://my.safaribooksonline.com/9788131731925/gloss01#gloss01_037http://my.safaribooksonline.com/9788131731925/gloss01#gloss01_037http://my.safaribooksonline.com/9788131731925/gloss01#gloss01_037http://my.safaribooksonline.com/9788131731925/gloss01#gloss01_037
  • 7/31/2019 Mc0067 Database Set1

    13/18

    interface standards like Open Database Connectivity (ODBC) and Java Database

    Connectivity (JDBC) are used for interaction between client and server.Figure 1.9shows

    two-tier architecture.

    Fig. 1.9. Two-tier architecture

    The second approach, that is, three-tier architecture is primarily used for web-based

    applications. It adds intermediate layer known as application server (or web server) between

    the client and the database server. The client communicates with the application server,

    which in turn communicates with the database server. The application server stores the

    business rules (procedures and constraints) used for accessing data from database server. It

    checks the clients credentials before forwarding a request to database server. Hence, it

    improves database security.

    When a client requests for information, the application server accepts the request, processes

    it, and sends corresponding database commands to database server. The database server sends

    the result back to application server which is converted into GUI format and presented to theclient.Figure 1.10shows the three-tier architecture.

  • 7/31/2019 Mc0067 Database Set1

    14/18

    Fig. 1.10. Three-tier architecture

    ADVANTAGES:

    1. CLIENT / SERVER system has less expensive platforms to supportapplications that had previously been running only on large and

    expensive mini or main frame computers.

    2. Client/ server environment facilities in more productive work by theusers and making better use of existing data.

    3. It is more flexible as compared to the centralized systems.4. Responsive time 7 throughput is high.5. A single dg(on server) can be shared across several distinct client

    (application) system.

    DISADVANTAGE:

    1. Programming cost is high in client / server environment, particularly ininitial phases.

    2. Theres a lack of management tools for diagnosis, performancemonitoring and tuning and security control, for the DBMS client and

    OS and networking environments.

    Q. 6 Taking an example Enterprise System, List out the Entity types, Entity Sets, Attributesand Keys

    Ans

    Q 7

  • 7/31/2019 Mc0067 Database Set1

    15/18

    Ans Relational Notation

    Relational notation is a process of transforming an E/R diagram into a more friendly and usable

    type of daigram that is easily readalbe. This can be done by taking the names of each table and

    its attributes and ordering them in a specific order. You always start with the primary key(s), whichare always underlined. Next all other attributes are added. The only rule for attributes is if it

    happens to be a foreign key it needs to be underlined with a dashed line:

    Diagram 1

    Looking at this E/R diagram to translate this into relational notation it would look like:

    AUTHOR (Author_id, Author_lname, Author_fname, Address, City, State, Zip)

    Note: the primary key in the table is underlined to show that it is the unique attribute.

  • 7/31/2019 Mc0067 Database Set1

    16/18

    2

    Diagram2Relational Notation:

    TITLE (Title_id, Title, Pub_id)

    Note: in this example the attribute Pub_id is what is known as a foreign key because it links

    to the following table (PUBLISHER) through that attribute. Normally this is represented by

    being placed at the end of the attribute list in the relational notation and is shown with a

    dashed underline.

    Diagram 3

    Relational Notation:PUBLISHER (Pub_id, Pub_name, City)

  • 7/31/2019 Mc0067 Database Set1

    17/18

    Diagram 4

    Relational Notation:

    AUTHOR_TITLE (Author_id, Title_id)

    By translating E/R diagrams into relational notation it also makes it easy for an individual to

    normalize and denormalize any given table in the schema; and if needed it is not very

    complicated to restore relational notation back to E/R diagram format.

  • 7/31/2019 Mc0067 Database Set1

    18/18

    Relational notation is a shorthand way to represent E/R diagrams. It is a half-way step

    between an abstract tool and an implementation specific tool (SQL create table commands).

    In terms of cardinalities, if you have a 1:1 (one-to-one) relationship between two tables youcan place the foreign key on either side when translating to relational notation, but is

    dependant upon the context of the scope of what the prolect is requiring.. If you are presented

    with a 1:N (one-to-many) relationship between tables foreign keys always will be on the

    many side.

    When dealing with suptype/supertype, they are considered a special form of a 1:1 therefore

    foreign key placement is immaterial, due to the fact that subtypes are know as inheriting

    everything from a supertype unless other wise noted.

    Advantages

    One of the best advantages of relational notation format is the ease to go from an E/R

    diagram to an English format of notation rather easily. What this means is, it very easy to turn

    an E/R diagram into something easily readable and useable, and still capture table names,

    composite keys, primary keys, foreign keys, and all attributes.. Relational notation is also a

    great refference point when creating tables in a SQL type program. Relational notion still

    allows a user or designer an easy way to transfer dependencies and re-create composite keysin a graphical interface if so desired. It is also has an accepted format, which once learned,

    can be applied to any table structure.

    Disadvantages

    One disadvantage of the relational notation is lack of visual descriptiveness. Essentially,

    tables created by relationships and tables themselves lose a visual format to model them. This

    can however be an advantage too though.

    Q 8. Consider a University Database System and develop the ER Conceptual Schemadiagram i.e. E-R Diagram for the same

    Ans....