chapter 2 introduction to signals students
TRANSCRIPT
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EE 23353 Analog Communications
Chapter 2: Introduction To Signals
Dr. Rami A. Wahsheh
Communications Engineering Department
Ch. 2: Introduction To SignalsReview of signals and linear systems: Chapters 2&3
2.1Size of a signal.g
2.2Classification of signals.
2.3Some useful signal operations
2.4Unit impulse function.
2.5Signals and vectors.
2
g
2.6Signal comparison: correlation.
2.7Signal representation by orthogonal signal set.
2.8Trigonometric Fourier series.
2.9Exponential Fourier series.
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Definitions
Signal: is a single-valued function of time, whichmeans that to each assigned instant of time (themeans that to each assigned instant of time (theindependent variable) there is one unique value ofthe function (the dependent variable). This valuemay be a real number, in which case we have real-valued signal, or it may be complex, and then wecan speak of a complex-valued signal. In eithercase the independent variable (time) is real-valued
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case the independent variable (time) is real valued.
Definitions
System: is an entity that processes a set of signals(inputs) to yield another set of signals (outputs)(inputs) to yield another set of signals (outputs).
SystemSignal Response
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2.1 Size of a Signal
How can a signal that exists over a certain timeand interval with varying amplitude be measured byand interval with varying amplitude be measured byone number that will indicate the signal size orstrength?
Signal Energy: the area under the signal |g(t)|2,g(t) is a complex valued signal.
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A necessary condition for the energy to be finite isthat the signal amplitude goes to zero as |t| goesto ∞. Otherwise the integral will not converge.
2.1 Size of a Signal
Signal Power: if the amplitude of g(t) does not goto zero as |t| goes to ∞ then the signal energy isto zero as |t| goes to , then the signal energy isinfinite.
The measure of the signal size in such a case wouldbe: the time average of the energy (if it exists:periodic or has a statistical regularity), which isthe average power Pg (i.e., the mean of the signal).
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The root mean square (rms) value of g(t) is thesquare root of Pg.
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2.1 Size of a Signal
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Units of Energy and Power
Depend on the nature of the signal g(t).
f ( ) l lIf g(t) is a voltage signal
The energy has units of volts squared seconds
The power has units of volts squared.
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Example 2.1 Page 17
Determine the suitable measures of the followingsignal:signal:
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Example 2.1 Page 17
Determine the suitable measures of the followingsignal:signal:
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Solution: g(t) = 2e-t/2 as |t| goes to ∞ g(t) goes to 0
844)(44)1
1(4422)( 0
0
0
1 0
22/22
eeedtedtdttgE tt
g
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Example 2.1 Page 17
Determine the suitable measures of the followingsignal:signal:
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Example 2.1 Page 17
Determine the suitable measures of the followingsignal:signal:
Solution: g(t) is periodic as |t| goes to ∞ g(t) doest t 0 th f th i t f thi
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not go to 0 therefore the power exists for thisperiodic signal. Averaging it over one period
3
1
3
1)
3
1
3
1(
2
1
32
1
2
1)(
11
1
31
1
22/
2/
2
g
T
T
g
Prms
tdttdttg
TP
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Example 2.2 Page 18
Determine the power and the rms value of:
tj
o
oDetgc
wheretCtCtgb
tCtga
)()
)cos()cos()()
)cos()()
21222111
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Example 2.2 Page 18Determine the power and the rms value of:
)cos()( o
S l ti
tCtg
2/
2/
2/
222/
2/
2 )(cos1
lim)(1
lim
2
T
T
T
oT
T
TT
g
oo
dttCT
dttgT
P
SignalPeriodicTPeriod
Solution
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2/
2/
22/
2/
2
2/
2/
2
)22cos(2
lim2
lim
)22cos(12
1lim
T
T
oT
T
TT
g
T
T
oT
g
dttT
Cdt
T
CP
dttC
TP
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Example 2.2 Page 18
Determine the power and the rms value of:
02
)22cos(2
lim2
lim
2
2
2/
2/
22/
2/
2
CP
TasC
P
dttT
Cdt
T
CP
g
T
T
oT
T
TT
g
Cancellation of +ve and –veareas of Sinusoid
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2
2C
rms
Pg
Example 2.2 Page 18
Determine the power and the rms value of:htCtCt )()()(
dttCdttCP
dttCtCT
P
Solution
wheretCtCtg
TT
T
TT
g
2/22
2/22
2/
2/
2222111
21222111
)(cos1
lim)(cos1
lim
)cos()cos(1
lim
)cos()cos()(
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dtttCCT
dttCT
dttCT
P
T
TT
TT
TT
g
2/
2/
221121
2/
222
2/
111
cos()cos(21
lim
)(coslim)(coslim
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Example 2.2 Page 18
)(cos1
lim)(cos1
lim2/
2222
2
2/
1122
1 dttCT
dttCT
PT
T
T
Tg
022
cos()cos(21
lim
22
22
21
2/
2/
221121
2/2/
TasCC
P
dtttCCT
TT
g
T
TT
TT
TT
Cancellation of +ve and –veareas of Sinusoid
17
2
222
21
22
21
CCrms
CCPg
Example 2.2 Page 18
Determine the power and the rms value of:tj oDetg )(
The signal is complex.
DP
DdtDT
dtDeT
PT
o
Ttj
og
oo
o 2
0
2
0
2 11
18
DPrms g
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2.2 Classification of Signals
1. Continuous-time and discrete-time signals2. Analog and digital signals3. Periodic and aperiodic signals4. Energy and power signals5 Deterministic and probabilistic (random) signals
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5. Deterministic and probabilistic (random) signals6. Causal vs. Non-causal Signals
1. Continuous-Time and Discrete-Time Signals
•Qualify the nature of a signal along the time axis.
•A Continuous time signal: is specified for everyvalue of time t. Example: a telephone or videocamera
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•A discrete time signal: is specified only atdiscrete values of t. Example: monthly sales of acompany.
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2. Analog and Digital SignalsAn analog signal:
1. Is a continuous function of time with continuousamplitude.
2. Its amplitude can take an infinite number ofvalues.
A digital signal:
1 Is a discrete function of time and amplitude
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1. Is a discrete function of time and amplitude(i.e., the amplitude can only have a finite set ofvalues).
2. Its amplitude can take a finite number ofvalues.
Analog and Digital Signals
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3. Periodic and Aperiodic Signals
Periodic Signal: if it satisfies the following equation
tallforTtgtg o )()(
Where To is the period of g(t). The signal muststart at -∞ and continue forever.
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Aperiodic Signal: if it is not periodic.
4. Energy and Power Signals
Energy Signal: if it has a finite energy. (zeropower) power)
dttgtg 2)()(
Power Signal: if it has a finite and nonzero power.(infinite energy)
2/
2)(lim0T
Tdttg
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2/T
T
•A signal can not both be an energy and a powersignal. If it is one it can not be the other.
•There are signals that are neither energy norpower signals. The ramp signal is such an example.
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5. Deterministic and Random Signals
A deterministic signal: can be modeled as acompletely specified function of time In othercompletely specified function of time. In otherwords, there is no uncertainty about its value atany time. For example, the sinusoid signalAcos(2πfct+θ) is deterministic if A, fc and θ areknown constants.
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A random (or stochastic) signal: cannot becompletely specified as a function of time.
5. Deterministic and Random Signals
• Deterministic signal: is a signal whose physicaldescription (i.e., mathematical or graphicalform) is known completelyform) is known completely.
• Random signal: is when the signal is known onlyin terms of probabilistic description, such as– Distribution– Mean value (i.e., the average or expected
l )
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value)– Squared mean value (i.e., the expected
value of the squared error)– Standard deviation (i.e., the square root
of the variance)
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6. Causal vs. Non-causal Signals• A causal signal is zero for t < 0 and a non-
causal signal is zero for t > 0 or
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Causal Signal Non-causal Signal
2.3 Some Useful Signal Operations
Time Shifting
T lTime Scaling
Time Inversion
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2.3 Some Useful Signal Operations
Time Shifting:
( T)•g(t-T) representsg(t) time-shifted byT seconds.
•If T is +ve, theshift is to the right(delay)
)(tg
)( Ttg
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(delay).
•If T is –ve, theshift is to the left(advance).
)( Ttg
2.3 Some Useful Signal Operations
Time Scaling:
Th•The compression orexpansion of a signalin time.
•g(2t) represents asignal that iscompressed in time
Compression
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compressed in timeby a factor of 2.
•Therefore, whateverhappens in g(t) at talso happens at timet/2 for Φ(t)
Expansion
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2.3 Some Useful Signal Operations
Time Inversion:
l f•Is a special case of timescaling with a=-1.
•Φ(t)=g(-t): Mirror imageof g(t) about the verticalaxis.
N M f
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•Note: Mirror image ofg(t) about the horizontalaxis is –g(t).
2.3 Example Page 26
Sketch g(3t) for the signal that is shown in a.
g(t): the value oft at 6,12,15,24
32
g(3t): is g(t) compressedby 3. Therefore,
t at 2,4,5,8
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Homework #1 •Solve the following problems: Due to one weekfrom today
•2.1-1
•2.1-5
•2.1-8
•2.2-1
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•2.3-1
•2.3-2
•2.3-3
2.4 Example Page 27
For the signal g(t) shown below, sketch g(-t):TimeInversionInversion
-1&-5 in g(t) aremapped into 1&5 ing(-t).
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2.4Unit Impulse Function
•One can visualize a unit impulse as a tall, narrowrectangular pulse of unit area
)(t
rectangular pulse of unit area.
•A unit impulse is regarded as a rectangular pulsewith a width that is very small, and a height thatis very large
1)(
00)(
dtt
tt
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1)( dtt
Multiplication of a Function by an Impulse
Impulse only exists at t=0)()0()()( ttt Impulse only exists at t 0
That is why the functiononly exists at t=0
)()0()()( ttt
)()()()( TtTTtt
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Sampling Property of the Unit Impulse Function
)0()()0()()(
dttdttt
This means the area under the product of afunction with an impulse δ(t) is equal to the value ofthat function at the instant where the unit impulseis located.
)()()()()(
37
This property is known as the sampling or siftingproperty of the unit impulse function.
)()()( TdtTtt
Unit Step Function u(t)
00
01)(
t
ttu
)()(
00
tdt
tdu
t
•If one wants a signal to start at t=0, thenmultiply the signal by u(t).
38
•e-at starts at t=-∞.
•To make it start at t=0,just multiply it by u(t).
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2.5 Signals and Vectors•Analogy between Signals and Vectors
• A vector can be represented as a sum of itspcomponents in a variety of ways.
• A Signal can also be represented as a sum of itscomponents in a variety of ways.
•Component of a vector:
• Specified by its magnitude and its direction
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• Specified by its magnitude and its direction.
• All vectors are denoted by boldface type.
Component of a VectorExample:
• Vector x of magnitude |x| and Vector g ofg gmagnitude |g|
• Let the component of g along x be cx
• Geometrically this component is the projection of gon x
• The component can be obtained by drawing a
40
• The component can be obtained by drawing aperpendicular from the tip of g on x and expressedin terms of x as: g = cx + e
• e is the error vector.
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Component of a Vector•Other ways to express g in terms of x:
g=c1x+e1=c2x+e2
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Component of a Vector•The dot (inner or scalar) product of two vectors gand x is defined as:and x is defined as:
g.x=|g| |x| cosθ
Where θ is the angle between vectors g and x.
•The length of the vector x is |x| where:
|x|2=x x
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|x| x.x
•The length of the component g along x is:
c|x| = |g| cosθ
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Component of a Vector• Multiplying both sides by |x| yields
| |2 | | | | θc|x|2 =|g| |x| cosθ= g.x
c= (g.x)/(x.x) = (1/|x|2) g.x
• If g.x = 0 then
1.g and x are perpendicular (orthogonal)
2 h l d 0
43
2.g has a zero component along x and c=0
Component of a Signal•Approximating a real signal g(t) in terms ofanother real signal x(t) over an interval [t1 t2]another real signal x(t) over an interval [t1,t2]
•The error e(t) in the approximation is given by:
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Component of a Signal• Energy is one possible measure of a signal size.
• To minimize the error signal we need to minimizegits size (its energy Ee over the interval [t1,t2]
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• Ee is minimum for some choice of c (not t)
Component of a Signal
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Component of a Signal1.Remarkable similarity
between the behavior ofvectors and signals Thevectors and signals. Thearea under the product oftwo signals corresponds tothe inner product of twovectors.
2.The energy of the signal is
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gy gthe inner product of a signalwith itself, and correspondsto the vector length squared(which is the inner productof the vector with itself).
Component of a Signal
dt
2
)()(1
• cx(t) is the projection of g(t) on x(t)
• If c = 0, then g(t) and x(t) are orthogonal over the interval [t1 t2]
dttxtgE
ctx1
)()(
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the interval [t1,t2]
0)()(2
1
dttxtgt
t
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Example 2.5 Page 33Find the component of g(t) of the form of sin (t) sothat the energy of the error signal is minimum.Where:Where: 20sin)( ttctg
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Example 2.5 Page 33ttx
t
sin)(2
222
tdttgdttxtgE
c
dttdttxE
o
t
tx
t
x
sin)(1
)()(1
)(sin)(
2
2
0
22
2
1
1
50ttg
tdttdtc
sin4
)(
4sinsin
1
0
2
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Orthogonality in Complex SignalsFor complex functions of t over an interval [t1,t2]
tetcxtg )()()(
dttxE
tcxtg
tetcxtg
t
t
x
22
1
)(
)()(
)()()(
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dttcxtgE
tcxtgtet
t
e
22
1
)()(
)()()(
Orthogonality in Complex Signals
uvvuvuvuvuvu222
Recall that:
dtttE
dttxtgE
dttgE
t
t
tx
t
t
e
)()(1
)()(1
)(
2
2
1
2
1
2
22
Independentof c
To minimizeEe, the 3rd
52
dttxtgE
cTherefore
dttxtgE
Ec
t
tx
tx
x
)()(1
)()(
2
1
1
e,term shouldbe zero
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Orthogonality in Complex SignalsTwo complex functions x1(t) and x2(t) are orthogonalover an interval [t1,t2], if
0)()(0)()( 2121
2
1
2
1
dttxtxordttxtxt
t
t
t
When the two functions are real, then
0)()(2
dt
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0)()(
0)()(
2
1
1
21
dttxtg
dttxtx
t
t
t
Energy of the Sum of Orthogonal Signals
Sum of two orthogonal vectors (x and y) is equal tothe sum of the lengths squared of the two vectors.If z=x+y thenIf z=x+y then
222yxz
The energy of the sum of two orthogonal signals isequal to the sum of the energies of the two signals.
54
If x(t) and y(t) are orthogonal over an interval [t1,t2]and z(t)=x(t)+y(t), then
yxz EEE
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2.6 Signal Comparison: Correlation
Two vectors g and x are similar if g has a largelcomponent along x.
This means that c= (g.x)/(x.x) = (1/|x|2) g.x is large, thenthe two vectors g and x are similar.
Is c a quantitative measure of the similarity?
Such a measure would be defective The amount of
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Such a measure would be defective. The amount ofsimilarity should be independent of the lengths of g andx.
Signal Comparison: CorrelationDoubling the length of g should not change the
similarity between g and x:• Doubling g doubles the value of c• Doubling x halves the value of cThen c is a faulty measure of the similarity
Similarity between two vectors is indicated by the
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angle θ between the vectors.A suitable measure would be:
xg
xgcn
.cos
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Signal Comparison: Correlation
xg
xgcn
.cos
• The larger the cosθ, larger is the similarity.• cn is independent of the lengths of g and x.• cn is called Correlation Coefficient.• The magnitude of cn is never greater than unity
If 1 th th t t li d
xg
11 nc
57
• If cn=1 then, the two vectors are aligned • If cn=-1 then, the two vectors are aligned in opposite
direction• If cn=0 then, the two vectors are orthogonal
Signal Comparison: CorrelationConsider signals over the entire time interval -∞ to ∞
To make c independent of the energies of g(t) and x(t),p g gall what we need to do is to normalize the two signals tohave unit energies.
dttxtgEE
cxg
n
)()(1
11 nc
58
Correlation between two signals is a measure of thedegree of similarity between the two signals
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Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
59
Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
55 1
dttxtgEE
cxg
n
)()(1
60
5)(
5)(
5
0
5
0
21
5
0
5
0
2
dtdttgE
dtdttxE
g
x
1.15.5
1
)()(1
5
0
1
dtc
dttxtgEE
cxg
n
MaximumSimilarity
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Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
61
Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
55 1
dttxtgEE
cxg
n
)()(1
62
25.1)5.0()(
5)(
5
0
25
0
22
5
0
5
0
2
dtdttgE
dtdttxE
g
x
1)5.0(5).25.1(
1
)()(1
5
0
2
dtc
dttxtgEE
cxg
n
MaximumSimilarity
c is independent of theamplitude of signals
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Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
63
Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
55 1
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MaximumDissimilarity
g(t) = -x(t)
5)(
5)(
5
0
5
0
23
5
0
5
0
2
dtdttgE
dtdttxE
g
x
1)1(5.5
1
)()(1
5
0
3
dtc
dttxtgEE
cxg
n
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Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
65
Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
5)(55
2 dtdttxE 1
661617.2)1(2
5
2
5)(
5)(
2
5
0
5
25
0
5
25
0
254
00
e
edtedteE
dtdttxE
ttt
g
x
961.0)1617.2(5
1
)()(1
5
0
54
dtec
dttxtgEE
c
t
xg
n
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Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
67
Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
5)(55
2 dtdttE 1
685.0)1(
2
1
2
1)(
5)(
10
5
0
25
0
25
0
25
00
2
e
edtedteE
dtdttxE
tttg
x
628.0)5.0(5
1
)()(1
5
0
5
dtec
dttxtgEE
c
t
xg
n
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Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
69
Example 2.6 Page 37Find the correlation coefficient cn between the pulse x(t)and the pulses gi(t), i=1,2,3,4,5 and 6
dttxtgEE
cxg
n
)()(1
1
70
5.22sin
5)(
5
0
26
5
0
5
0
2
dttE
dtdttxE
g
x
02sin)5.2(5
1
)()(1
5
0
6
dttc
dttxtgEE
cxg
n
g6(t) is orthogonal to x(t)
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Orthogonal Signal Space
Orthogonality of a signal set x1(t), x2(t), …, xN(t) over theinterval [t1, t2] as,
If the energies En=1 for all n, then the set is normalizedand is called an orthonormal set
71
and is called an orthonormal set.
Orthogonal Signal Space
72
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Orthogonal Signal Space
73
Trigonometric Fourier SeriesConsider a signal set: ,....sin....2sin,sin,....cos........2cos,cos,1 tnwtwtwtnwtwtw oooooo
• A sinusoid function with frequency nωo is called thenth harmonic of the sinusoid of frequency ωo when n isan integer.
• A sinusoid of frequency ωo is called the fundamental
• This set is orthogonal over any interval of duration
74
• This set is orthogonal over any interval of durationTo=2П/ωo because:
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Trigonometric Fourier Series
And
The trigonometric set is a complete set. Each signal g(t)can be described by a trigonometric Fourier series overany interval To :
75
any interval To :
Trigonometric Fourier SeriesWe determine the Fourier coefficients a0, an, and bn:
76
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Compact Trigonometric Fourier Series
The trigonometric Fourier series contains sine and cosineterms of the same frequency. We can represents theabove equation in a single term of the same frequencyusing the trigonometry identity
77
Compact Trigonometric Fourier Series
The trigonometric Fourier series contains sine and cosineterms of the same frequency. We can represents theabove equation in a single term of the same frequencyusing the trigonometry identity
78
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Compact Trigonometric Fourier Series
79
Webpagehttp://en.wikipedia.org/wiki/File:Fourier_Series.svg
80
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Webpagehttp://upload.wikimedia.org/wikipedia/commons/e/e8/Periodic_identity_function.gif
81
Example 2.7
82
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Example 2.7
83
??,?,0 nn baa
Example 2.7
84
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Example 2.7Compact Fourier series is given by
85
Example 2.7
86
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Example 2.7
87
Periodicity of the Trigonometric Fourier Series
We now show that the trigonometric Fourier series is aperiodic function of period To (The period of thef d t l)fundamental).
88
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Periodicity of the Trigonometric Fourier Series
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Fourier SpectrumThe compact trigonometric Fourier series
g(t) is expressed as a sum of sinusoids of
Frequencies: 0, wo , 2wo, …, nwo, …
Amplitudes: Co, C1, …, Cn, …
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p o 1 n
Phases: 0, θ1, θ2, …, θn, …
Cn vs. w (Amplitude Spectrum)
θn vs. w (Phase Spectrum)
The two plots together are the frequency spectra of g(t)
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Fourier Spectrum
• A signal has a dual identity: the time domain identityd th f d i id tit (F i t )and the frequency domain identity (Fourier spectra).
• The two identities complement each other. Takentogether, they provide a better understanding of asignal.
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Example 2.8• Find the compact Fourier series for the periodic
square wave w(t) shown in figure and sketch amplituded h tand phase spectrum.
Fourier series:
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Fourier series:
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Example 2.8
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Example 2.8
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Example 2.8
The series is already in compact form as there are nosine terms. Except the alternating harmonics havenegative amplitudes.
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g p
The negative sign can be accommodated by a phase ofradians as
Example 2.8
The series is already in compact form as there are nosine terms. Except the alternating harmonics havenegative amplitudes.
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g p
The negative sign can be accommodated by a phase ofradians as
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Example 2.8
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Example 2.8
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Example 2.8We could plot amplitude and phase spectra using thesevalues.
In this special case if we allow Cn to take negative valueswe do not need a phase of –П to account for sign.
Means all phases are zero, so only amplitude spectrum isenough.
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Example 2.8Bipolar square wave wo(t): is basically w(t) minus its dccomponent
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Example 2.8Bipolar square wave wo(t): is basically w(t) minus its dccomponent
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Example 2.9Find the trigonometric Fourier series and sketch thecorresponding spectra for the periodic impulse trainδ (t)δTo(t)
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Example 2.9The trigonometric Fourier series for δTo(t)
??,?,0 nn baa
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Example 2.9The trigonometric Fourier series for δTo(t)
??,?,0 nn baa
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Example 2.9
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Exponential Fourier SeriesThe set of exponentials
Orthogonal over any interval of duration To=2П/ωoOrthogonal over any interval of duration To 2П/ωo
A signal g(t) can be expressed over an interval ofduration To seconds as an exponential Fourier series
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Exponential Fourier SeriesEach sinusoid of frequency ω can be expressed as thesum of two exponentials ejωt and e-jωt (using Euler’sf l )formula)
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Exponential Fourier Series
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Example 2.10Find the exponential Fourier series for the followingsignal
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Example 2.10
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Example 2.10
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Exponential Fourier Spectra
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Exponential Fourier Spectra
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From Example 2.10
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From Example 2.10
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From Example 2.10
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Exponential Fourier Spectra1. The spectra exist for
positive as well as negativel f (th f )values of ω (the frequency).
2. The amplitude spectrum isan even function of ω andthe angle spectrum is an oddfunction of ω.
3 Th i l ti
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3. There is a close connectionbetween these spectra andthe spectra of thecorresponding trigonometricFourier Series for Ψ(t).
Exponential Fourier SpectraTrigonometric Fourier SeriesExponential Fourier Series
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Example 2.11Find the exponential Fourier series for the periodicsquare wave ω(t) shown below:
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Example 2.11
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Example 2.11
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Example 2.12Find the exponential Fourier series and sketch thecorresponding spectra for the impulse train δTo(t) shownb lbelow:
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Example 2.12
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Example 2.12
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Parseval’s Theorem• A periodic signal g(t) is a power signal.
• The power Pg of g(t) is equal to the power of itsThe power Pg of g(t) is equal to the power of itsFourier series.
• The power of the Fourier Series is equal to the sum ofthe powers of its Fourier components.
• For the trigonometric Fourier series
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Parseval’s TheoremFor the exponential Fourier series
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Homework #2 •Solve the following problems: Due to one weekfrom today
•2.3-4
•2.4-1
•2.4-2
•2.6-1
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•2.8-4
Problem 2.5-2
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Problem 2.5-2
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Problem 2.8-3
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Problem 2.8-3
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Problem 2.8-3
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Problem 2.8-3
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