you will need your text book (volume 2) today

You will need your text book

(volume 2) today.

5 Minute CheckComplete in your notes.

1. What is 25% of 60?

2. What is 140% of 60?

3. 27 is 30% of what number?

4. What percent is 6 of 40?


1. What is 25% of 60?


1. What is 25% of 60?

𝟐𝟓

𝟏𝟎𝟎=

?

𝟔𝟎

25 x 60 = 1500 ÷ 100 = 15


2. What is 140% of 60?


2. What is 140% of 60?

𝟏𝟒𝟎

𝟏𝟎𝟎=

?

𝟔𝟎

140 x 60 = 8400 ÷ 100 = 84



30

100= 27

?

100 x 27 = 2700 ÷ 30 = 90



?

100=

6

40

100 x 6 = 600 ÷ 40 = 15

The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.

a. (1,7) and (1,1)

b. (3,3) and (-5,3)

c. (-3,4) and (-3,-2)

d. (0,0) and (-2,-4)

e. (-1,5) and (5,5)

f. (-8,3) and (-2,3)

OST Test Prep


a. (1,7) and (1,1)

OST Test Prep


a. (1,7) and (1,1)

I7I - I1I 7 - 1

6

OST Test Prep

1 7

6 units

If the unique numbers have the same signs, subtract their absolute values, placing the largest number first.


b. (3,3) and (-5,3)

OST Test Prep


b. (3,3) and (-5,3)

I-5I + I3I 5 + 3

8

OST Test Prep

-5 3

8 units

If the unique numbers have opposite signs, add their absolute values together.


c. (-3,4) and (-3,-2)

OST Test Prep


c. (-3,4) and (-3,-2)

I4I + I-2I 4 + 2

6

OST Test Prep

-2 4

6 units



d. (0,0) and (-2,-4)

OST Test Prep


d. (0,0) and (-2,-4)

Since there a two sets of unique numbers, the distance can not be determined.

OST Test Prep


e. (-1,5) and (5,5)

OST Test Prep


e. (-1,5) and (5,5)

I5I + I-1I 5 + 1

6

OST Test Prep

-1 5

6 units



f. (-8,3) and (-2,3)

OST Test Prep


f. (-8,3) and (-2,3)

I-8I – I-2I 8 - 2

6

OST Test Prep

-8 -2

6 units

If the unique numbers have the same signs, subtract their absolute values, placing the largest number first.

Tuesday, Jan 22

Lesson EE7.1

Algebraic Equations

Tuesday, Jan 22

In your text book, turn to page 521.

Tuesday, Jan 22

Work with a partner to answer questions 1 and 2 on page 522


?


Algebraic Equation and Solution?


?


Algebraic Equation and Solution?

Tuesday, Jan 22

Lesson EE7.1

Algebraic Equations

Objective: To understand how to solve algebraic equations.

6.EE.7 I can solve real-world and mathematical problems by writing and solving equations of the form x + p = q and px = q (where p, q and x are all nonnegative rational numbers).

Algebraic Equations

Expression: a combination of numbers and operations.

2r² + 3 = 21

expression

Algebraic Equations

Term: a single number or variable or numbers and variables multiplied together and separated by addition or subtraction.

2r² + 3 = 21

Algebraic Equations

terms

Variable : a symbol, usually a letter, used to represents a number.

2r² + 3 = 21

Algebraic Equations

In this term r is a variable.

Coefficient: A number used to multiply a variable.

2r² + 3 = 21

Algebraic Equations

This term has a coefficient of 2.

In algebra, if no operation is written it is assumed to be multiplication.

2r² + 3 = 21

Algebraic Equations

In this term 2 is multiplied by r².

Constant: A number without a variable.

2r² + 3 = 21

Algebraic Equations

Constants

Exponent: tells how many times a number or variable is multiplied by itself.

2r² + 3 = 21

Algebraic Equations

r² = r ∙ r

Solution: is the numeric value that can be substituted in place of the variable to make the equation true.

There will be a value for r that makes this equation true.

2r² + 3 = 21

Algebraic Equations

Algebraic Expression: An expression that contains at least one variable and at least one operation.

e.g.

x + 6

Algebraic Expression

Algebraic Equations

In an algebraic expression something is being done to the variable.

e.g.

x + 6

6 is being added to the variable

Algebraic Equations

In an algebraic expression something is being done to the variable.

e.g.

x + 6

6 is being added to the variable

To undo adding 6, you would subtract 6.

Algebraic Equations

In this algebraic expression, what is being done to the variable and how is it undone?

x + 2

Algebraic Equations


x + 2

2 is being added to the variable.


Use the inverse operation to undo.

Algebraic Equations


r + 15

Algebraic Equations


r + 15

15 is being added to the variable.


Algebraic Equations


y - 5

Algebraic Equations


y - 5

5 is being subtracted from the variable.

To undo subtracting 5, you would add 5.

Algebraic Equations

Solve the equation.

a + 2 = 8

How to Solve Algebraic Equation - Use the inverse operation to undo whatever is being done to the variable.

Algebraic Equations

Solve the equation.

a + 2 = 8

How to Solve Algebraic Equation - Use the inverse operation to undo whatever is being done to the variable.

Algebraic Equations

Yes, I know you already know the solution.

Solve the equation.

a + 2 = 8

To solve algebraic equations undo whatever is done to the variable.

What is being done to the variable?

Algebraic Equations

Solve the equation.

a + 2 = 8


Algebraic Equations

Adding 2. How can adding 2 onto something be undone?

Solve the equation.

a + 2 = 8


Algebraic Equations

By subtracting 2 from both sides.

Solve the equation.

a + 2 = 8


Algebraic Equations


Why both sides?

Solve the equation. a + 2 = 8

-2 -2


Algebraic Equations

Write this down.


-2 -2

a = 6


Algebraic Equations

Write this down.

Since 2 - 2 is zero, you do not have to write the zero.


-2 -2

a = 6


Algebraic Equations

The solution to this algebraic equation is 6.


Algebraic Equations

The solution to this algebraic equation is 6.

a 2

8

Solve the equation.

54 = d + 5

What is being done to the variable?

Algebraic Equations

Solve the equation.

54 = d + 5

Algebraic Equations

Adding 5. How can this be undone?

Solve the equation.

54 = d + 5

Algebraic Equations


Solve the equation.

54 = d + 5-5 -5

Algebraic Equations

Make sure you line up the numbers.

Solve the equation.

54 = d + 5-5 -5

49 = d

The solution is 49.

Algebraic Equations

d 5

54

Solve the equation.

456 + k = 1004

Do this on your own.

Algebraic Equations

Solve the equation.

456 + k = 1004-456 = -456

k = 548

This is work that needs to be shown on today’s assignment.

Algebraic Equations

456 k

1004

Solve the equation.

3.5 + x = 12.75


Algebraic Equations

Solve the equation.

3.5 + x = 12.75-3.5 = -3.50 annex zero

x = 9.25


Algebraic Equations

Solve the equation.

4.6 = e + 3.2

Algebraic Equations

Solve the equation.

4.6 = e + 3.2-3.2 = -3.2 1.4 = e


Algebraic Equations

Solve the equation.

y + 45.76 = 53.53

Algebraic Equations

Solve the equation.

y + 45.76 = 53.53-45.76 =-45.76

y = 7.77


Algebraic Equations

Solve the equation.

21 = h + 21

Algebraic Equations

Solve the equation.

21 = h + 21-21 = -21

0 = h


Algebraic Equations

You have $40 in your checking account. You write a check for $7.99 and $11.45. Write an algebraic equation that represents this situation where c is how much money is left in your checking account.

____ = ____ + ____ + _____


Algebraic Equations

You have $40 in your checking account. You write checks for $7.99 and $11.45. Write an algebraic equation that represents this situation where c is how much money is left in your checking account.

40 = 7.99 + 11.45 + c

How much money is left in your checking account?

Algebraic Equations

You have $40 in your checking account. You write checks for $7.99 and $11.45. Write an algebraic equation that represents this situation where c is how much money is left in your checking account.

40.00 = 7.99 + 11.45 + c

40.00 = 19.44 + c

-19.44 -19.44

20.56 = c

Algebraic Equations

A hot air balloon is 200 feet in the air. A few minutes later it ascends to 450 feet. Write and solve an algebraic equation that represents this situation where h is the change in altitude of the balloon.

____ = ____ + ____


Algebraic Equations


450 = 200 + h

Algebraic Equations


450 = 200 + h-200 -200250 = h

Algebraic Equations

Write two different algebraic equations that have 12 as a solution.

Algebraic Equations

In the equation x + y = 5, the value for x is a whole number greater than 2 but less than 6. Determine the possible solutions for y.

Algebraic Equations

In the equation x + y = 5, the value for x is a whole number greater than 2 but less than 6. Determine the possible solutions for y.

x = 3 x = 4 x = 5

3 + y = 5 4 + y = 5 5 + y = 5

y = 2 y = 1 y = 0

Algebraic Equations

Place your math binder on the corner of your desk.

Practice Skills EE7.1

Due Wednesday, Jan 23

#3 Daily Assignment should be g + 6 = 21

When complete, work on the EE1 assignment on Delta Math

until 100% is reached.

EE7 Assessment

Thursday, Jan 31

Retakes on Jan 31 during class.

Algebraic Equations


Algebraic Equations

We can also solve this with a tape diagram.


Algebraic Equations

We can also solve this with a tape diagram.Step 1 – Make two tape diagrams the same length.


Algebraic Equations

We can also solve this with a tape diagram.Step 2 – Label the first diagram with the side of the equation that only has a number.


Algebraic Equations


8


Algebraic Equations

We can also solve this with a tape diagram.Step 3 – Label the second diagram with the other side of the equation.

8


Algebraic Equations


8

a 2

It doesn’t matter where this line is.


Algebraic Equations

We can also solve this with a tape diagram.Step 4 – Use both diagrams to determine the value of the variable.

8

a 2

It doesn’t matter where this line is.

Solve the equation. a + 2 = 8 , the solution is 6

Algebraic Equations

We can also solve this with a tape diagram.Step 4 – Use both diagrams to determine the value of the variable.

8

6 2

you will need your text book (volume 2) today

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