section 5 2 single stub tuning package

Upload: tuan-thien

Post on 04-Apr-2018

221 views

Category:

Documents


0 download

TRANSCRIPT

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    1/10

    3/26/2009 5_2 Single_Stub Tuning.doc 1/1

    Jim Stiles The Univ. of Kansas Dept. of EECS

    5.2 Single-Stub Tuning

    Reading Assignment:pp. 228-235

    Q: If we cannot use lumped elements like inductors or

    capacitors to build lossless matching networks, whatcanwe

    use?

    A: Recall that a section of lossless transmission line is purely

    reactive, thus we can build lossless matching networks using

    specific lengths of transmission lines.

    We call these lengths of transmission line distributed

    elements.

    The distributed element analogue of the lumped element L-

    network is the single-stub tuner.

    Just like the L-network, there are two versions of this

    design:

    HO: THE SHUNT-STUB TUNER

    HO: THE SERIES-STUB TUNER

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    2/10

    3/26/2009 Shunt Stub Tuning.doc 1/5

    Jim Stiles The Univ. of Kansas Dept. of EECS

    Shunt Stub Tuning

    Consider the follow transmission line structure, with a shunt

    stub:

    The two design parameters of this matching network are

    lengths A and d.

    An equivalent circuit is:

    where of course:

    inY

    stubj B inY

    z=0

    0Z ,

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    3/10

    3/26/2009 Shunt Stub Tuning.doc 2/5

    Jim Stiles The Univ. of Kansas Dept. of EECS

    00

    0

    tan

    tanL

    in

    L

    Y j Y d Y Y

    Y j Y d

    + =

    +

    and the reactance stubjB of transmission line stub of lengthA

    iseither:

    0

    0

    tan for an -circuit stub

    cot for an -circuit stubstub

    jY

    jB

    jY

    =

    open

    short

    A

    A

    Therefore, for a matched circuit, we require:

    0instubjB Y Y+ =

    Note this complex equation is actually two real equations!

    i.e.,

    0Re{Y }in Y =

    andIm{ } 0in in stub stub jB Y B B + = =

    where

    Im{Y }in in B

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    4/10

    3/26/2009 Shunt Stub Tuning.doc 3/5

    Jim Stiles The Univ. of Kansas Dept. of EECS

    SinceinY is dependent on d only, our design procedure is:

    1) Set dsuch that 0Re{Y }in Y = .

    2) Then set A such that instubB B= .

    We have two choices for determining the lengths andd A . We

    can use the design equations (5.9, 5.10, 5.11) on p. 232,

    OR

    we can use the Smith Chart to determine the lengths!

    1) Rotate clockwise around the Smith Chart from Ly until you

    intersect theg=1 circle. The length of this rotation

    determines the value d. Recall there are two possible solutions!

    2) Rotate clockwise from the short/open circuit point around

    theg= 0 circle, until stubb equals inb . The length of this

    rotation determines the stub length A .

    For example, your book describes the case where we want to

    match a load of 60 80LZ j= (at 2 GHz) to a transmission line

    of 0 50Z = .

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    5/10

    3/26/2009 Shunt Stub Tuning.doc 4/5

    Jim Stiles The Univ. of Kansas Dept. of EECS

    Using shorted stubs, we find two solutions to this problem:

    Whose length values dand A where determined from a Smith

    Chart:

    short

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    6/10

    3/26/2009 Shunt Stub Tuning.doc 5/5

    Jim Stiles The Univ. of Kansas Dept. of EECS

    Q:Twosolutions! Which one do we use?

    A: The one with the shortest lengths of transmission line!

    Q: Oh, I see! Shorter transmission lines providesmallerand(slightly) cheaper matching networks.

    A: True! But there is a more fundamental reason why we select

    the solution with the shortest linesthe matching bandwidth is

    larger!

    For example, consider the frequency response of the two

    examples:

    Clearly, solution 1 provides a wider bandwidth!

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    7/10

    3/26/2009 Series Stub Tuning.doc 1/4

    Jim Stiles The Univ. of Kansas Dept. of EECS

    Series Stub Tuning

    Consider the following transmission line structure, with a series

    stub:

    Therefore an equivalent circuit is:

    where of course:

    00

    0

    tan

    tanL

    in

    L

    Z j Z d Z Z

    Z j Z d

    + =

    +

    inZ

    stubj X

    inZ

    z=0

    0Z ,

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    8/10

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    9/10

    3/26/2009 Series Stub Tuning.doc 3/4

    Jim Stiles The Univ. of Kansas Dept. of EECS

    OR

    we can use the Smith Chart to determine the lengths!

    1) Rotate clockwise around the Smith Chart from Lz until you

    intersect the r= 1 circle. The length of this rotation

    determines the value d. Recall there are two possible solutions!

    2) Rotate clockwise from the short/open circuit point around

    the r= 0 circle until stubx equals inx . The length of this

    rotation determines the stub lengthA

    .

    For example, your book describes the case where we want to

    match a load of 100 80LZ j= + (at 2 GHz) to a transmission line

    of 0 50Z = .

    Using open stubs, we find two solutions to this problem:

  • 7/31/2019 Section 5 2 Single Stub Tuning Package

    10/10

    3/26/2009 Series Stub Tuning.doc 4/4

    Jim Stiles The Univ of Kansas Dept of EECS

    Whose values where determined from a Smith Chart:

    Again, we should use the solution with

    the shortest transmission lines,although in this case that distinction is

    a bit ambiguous. As a result, the

    bandwidth of each design is about the

    same (depending on how you define

    bandwidth!).

    open