lecture 14 biot-savart law p ids r u Ö db 4s r
TRANSCRIPT
Physics 212 Lecture 14, Slide 1
Physics 212 Lecture 14
Biot-Savart Law
0
2
ˆ
4
I ds rdB
r
:05
Physics 212 Lecture 14, Slide 2
Biot-Savart Law:
:05
0
2
ˆ
4
I ds rdB
r
We can use this law to calculate the magnetic field produced by ANY current distribution BUT Easy analytic calculations are possible only for a few distributions:
Infinite Straight Wire
Axis of Current Loop
Field at the center of a ring
d s
r̂d B
Pd B points out of page for each d s
0 0
2 24 4P P
I Id s r dd B d B
r r
2 2
0 0
0 04 2
P
I IB d B d
r r
P
d sr
I
ds r dd
0
2
ˆˆ
4
I d s x r rd B r
r r
Physics 212 Lecture 14, Slide 4
B from infinite line of current
Current I OUT
•
r = distance from wire
7
0 4 10 /Tm A
0
2
IB
r
r
Magnitude:
B
:07
Direction:
Thumb: on I Fingers: curl in direction of B
Current in WireCurrent in Wire
Resulting B fieldResulting B field
II
Physics 212 Lecture 14, Slide 5
A long straight wire is carrying current from left to right. Two identical charges are moving with equal speed. Compare the magnitude of the force on charge a moving directly to the right, to the magnitude of the force on charge b moving up and to the right at the instant shown (i.e. same distance from the wire).
a) |Fa |> |Fb|
b) |Fa |= |Fb|
c) |Fa |< |Fb|
v
I
v (a)
r r
(b)
28
Currents + Charges
F qv B
| | sinF qvB
Same q, |v|, B and (=90)
:10
• B
Forces are in different directions
• F
F
Physics 212 Lecture 14, Slide 6
Two long wires carry equal and opposite currents
What is the direction of the magnetic field above, and midway between the two wires carrying current – at the point marked “X”?
x
Magnetic Fields obey superposition
A) Left B) Right C) Up D) Down E) Zero
B
x
:13
Physics 212 Lecture 14, Slide 7
Force between current-carrying wires
• I1 F
Conclusion: Currents in same direction attract.
•
I1
I2
F
Conclusion: Currents in opposite direction repel.
:16
B d
B d
21 2 1F I L B 21 2 12
oF I L Id
• I2
Physics 212 Lecture 14, Slide 8
Checkpoint 1
What is the direction of the force on wire 2 due to wire 1?
A) Up B) Down C) Into Screen D) Out of screen E) Zero
:18
X B
F
Uniform force at every segment of wire
No torque about any axis
What is the direction of the torque on wire 2 due to wire 1?
A) Up B) Down C) Into Screen D) Out of screen E) Zero
Physics 212 Lecture 14, Slide 9
Checkpoint 3a
What is the direction of the force on wire 2 due to wire 1?
A) Up B) Down C) Into Screen D) Out of screen E) Zero
:21
Physics 212 Lecture 14, Slide 10
B
B
I F out of screen
Net Force is Zero!
:22
Consider Force on Symmetric Segments!
I F into screen
r r
Physics 212 Lecture 14, Slide 11
Checkpoint 3b
What is the direction of the torque on wire 2 due to wire 1?
A) Up B) Down C) Into Screen D) Out of screen E) Zero
B
B
i i
F out of screen F into screen
:24
Checkpoint 2
:24
A B C D E
A current carrying loop of width a and length b is placed near a current carrying wire.
How does the net force on the loop compare to the net force on a single wire segment of
length a carrying the same amount of current placed at the same distance from the wire?
A. The forces are in opposite directions
B. The net forces are the same
C. The net force on the loop is greater than the net force on the wire segment
D. The net force on the loop is smaller than the net force on the wire segment
E. There is no net force on the loop Physics 212 Lecture 14, Slide 12
Checkpoint 2
:24
A B C D E
X B1 X
B2 X B1
F2
B ~ 1/R B1 > B2
Ftop + Fbottom =0
F1 F1
Fnet
A current carrying loop of width a and length b is placed near a current carrying wire.
How does the net force on the loop compare to the net force on a single wire segment of
length a carrying the same amount of current placed at the same distance from the wire?
A. The forces are in opposite directions
B. The net forces are the same
C. The net force on the loop is greater than the net force on the wire segment
D. The net force on the loop is smaller than the net force on the wire segment
E. There is no net force on the loop Physics 212 Lecture 14, Slide 13
Physics 212 Lecture 14, Slide 14
B on axis from Current Loop
:24
Current in WireCurrent in Wire
II
Resulting B fieldResulting B field
Current in WireCurrent in Wire
II
Resulting B fieldResulting B field
3
1B z R
z
Physics 212 Lecture 14, Slide 15
What about Off-Axis ??
:24
Biot-Savart works, but need to do numerically
See Simulation !!
B
Magnetic field of a dipole moment
Direction of B reverses
from inside to outside.
B gets weaker
S N
Physics 212 Lecture 14, Slide 17
Two identical loops are hung next to each other. Current flows in the same direction in both. The loops will: A) Attract each other B) Repel each other
Two ways to see this:
1) Like currents attract
Two Current Loops
:30
N S N S
2) Look like bar magnets
Physics 212 Lecture 14, Slide 18
Right Hand Rule Review
06
1. ANY CROSS PRODUCT
BvqF
BLIF
Fr
B
0
2
ˆ
4
I ds rdB
r
2. Direction of Magnetic Moment
Thumb: Magnetic Moment
Fingers: Current in Loop
3. Direction of Magnetic Field from Wire
Thumb: Current
Fingers: Magnetic Field
Physics 212 Lecture 14, Slide 19
Calculation Two parallel horizontal wires are located in the vertical (x,y) plane as shown. Each wire carries a current of I =1A flowing in the directions shown. What is the B field at point P?
y
x
.
z
y
P 3cm
I1=1A
Front view
I2=1A
4cm
4cm
Side view
(A) (B) (C) (D) (E)
y
.
z
y
P
.
z
y
P
• What is the direction of B at P produced by the top current I1?
.
z P
.
z
y
P
.
z
y
P
:35
Physics 212 Lecture 14, Slide 20
Calculation Two parallel horizontal wires are located in the vertical (x,y) plane as shown. Each wire carries a current of I =1A flowing in the directions shown. What is the B field at point P?
• What is the direction of B at P produced by the bottom current I2?
y
x
.
z
Side view
y
P 3cm
I1=1A
Front view
I2=1A
4cm
4cm
(A) (B) (C) (D) (E)
.
z
y
P
.
z
y
P
.
z
y
P
.
z
y
P
.
z
y
P
:37
Physics 212 Lecture 14, Slide 21
Calculation Two parallel horizontal wires are located in the vertical (x,y) plane as shown. Each wire carries a current of I =1A flowing in the directions shown. What is the B field at point P?
• What is the direction of B at P?
y
x
.
z
Side view
y
P 3cm
I1=1A
Front view
I2=1A
4cm
4cm
(A) (B) (C) (D)
.
z
y
P
.
z
y
P
.
z
y
P
.
z
y
P z P
.
y
90o
:40
Physics 212 Lecture 14, Slide 22
Calculation Two parallel horizontal wires are located in the vertical (x,y) plane as shown. Each wire carries a current of I =1A flowing in the directions shown. What is the B field at point P?
y
x
.
z
Side view
y
P 3cm
I1=1A
Front view
I2=1A
4cm
4cm
• What is the magnitude of B at P produced by the top current I1? (0 4 x 107 T-m/A)
(A) 4.0 x 106 T (B) 5.0 x 106 T (C) 6.7 x 106 T
0
2
IB
r
• What is r? – r = distance from wire axis to P
3cm z
y
.
4cm r 2 23 4 5r cm
770 (4 10 ) 1
40 102 2 .05
IB
r
:45
Physics 212 Lecture 14, Slide 23
Calculation Two parallel horizontal wires are located in the vertical (x,y) plane as shown. Each wire carries a current of I =1A flowing in the directions shown. What is the B field at point P?
y
x
.
z
Side view
y
P 3cm
• What is the magnitude of B at P? (0 4 x 107 T-m/A)
(A) 3.2 x 106 T (B) 4.8 x 106 T (C) 6.4 x 106 T (D) 8.0 x 106 T
I1=1A
Front view
I2=1A
4cm
4cm
3cm z
y
.
4cm 5cm 1 1 cosxB B
B1
B2
2 2 cosxB B
6 6
1
42 cos 2 4 10 6.4 10
5xB B
:49
Btop = 4 X 10-6 T