JAWABAN SOAL UTS STRUKTUR BAJA II

W14X74

3,5 m

W14X74 B

W12X79 W12X79 W10X60 4,5 m

W12X79

A

5,5 m 5,5 m 6 m

W10X60

A = 113,548 cm2

bf = 25,65 cm

tf = 1,727 cm

d = 25,91 cm

tw = 1,067 cm

Ix = 14193,5 cm4

Iy = 4828,28 cm4

rx = 11,15 cm

ry = 6,528 cm

W14X74 : Ix = 33132 cm4

E = 200000 Mpa

Fy = 240 Mpa

1. Mencari nilai kekakuan kolom (k)

GA = Gsendi = 10

Dari nomogram didapat nilai k = 1,8

2. Memeriksa penampang

a. Sayap

; compact/non-compact

b. Badan

; compact/non-compact

3. Menghitung Fcr

4. Menghitung Pn

Pn = 1118,05 kN

10 m

WDL = 7,5 kN/m WLL = 10 kN/m

W18X50 : Sx = 1456,8 cm3 d = 45,7 cm

Sy = 175, 34 cm3 tf = 1,448 cm

Zx = 1655 cm3 tw = 0,9 cm

Zy = 272 cm3 rts = 5,03 cm

rx = 18,97 cm h0 = 44,2 cm

ry = 4,191 cm J = 51,6 cm4

bf = 19,05 cm

E = 200000 Mpa Fy = 240 Mpa

Menentukan Jenis Balok

a. Sayap

Compact Local Torsional Buckling

b. Badan

Compact Local Torsional Buckling

Menghitung Lb, Lp, dan Lr

A B

Menghitung Momen Nominal

Diagram Momen

MA MB MC Mmax MA = 136,72 kNm

MB = 234,38 kNm

Mc = 292, 97 kNm

Mmax = 312,5 kNm

AMAN