incineration exercise
TRANSCRIPT
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Incineration Exercise
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Objectives
Compute the composition of uegas
Compute the temperature of uegas (a function of waste heat valueand composition)
Compute the amount of airrequired
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tep !" #aste
Composition$etermine the chemical
composition (lb)% water content
(lb)% and energ& content
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Step 1: Calculate chemical composition, water content, and energy content.
Component Composition Moisture Energy Dry --------------- Chemical Composition (dry basis -------------- Energy
(lb Content Content !eight Carbon "ydrogen #$ygen %itrogen Sul&ur 'sh (tu
(lb) lb (tu) lb (lb
*ood !aste + . 1.+/ .10 1.1 . .11 .10 12,
3aper 04 / 0. 10.+0 1.+12 14./ .+/ ./4 1.+12 44,2
Cardboard / . .2 .00/ .4 .1 .11 .2 4,3lastics 14 /.+ 4.11/ .4+4 1./4 . . ./2/ +2,
5e$tiles 1 1.2 .++ .11+ ./ .20 .0 .4 1,
6ubber . 1 . .02 .4+ . .1 . .4+ ,
7eather . 1 . . .0/ . .4 . .4 0,
8ard !astes 12. / 2 .4 0.0 .444 .21 . . .000 1,2
!ood 2 1./ .+ .+/ ./20 .0 . .4 1/,
9lass 2 / .2 .0+ .2 .01 .2 . .4 42
5in Cans / 0 0 .2 ./ .0 . ./ . ./ 1,2
'lumiinum . . . .0 .1 . . .440
#ther Metal 0 0 0 .+ .101 .1 .1 .0 . ./04 +
Dirt, ash, etc 0 2 0 .2 ./ .20 . .14 ./ 1.2 +,
sum: 1 2.2 2.+ 0.21 0.2 ./1 .1 1.4+ /,0
!ater content: 1. lb
Energy content /.0 tu)lb
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tep ' and " $etermine
the moles of Ox&genrequiredtep '" convert chemical
composition and water content
from lb to lbmole using molecularweights
tep " $etermine the moles of
ox&gen required to combust thesample completel&
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C---;C#
4"---;"
---;%---;%
S---;S#Note: oxygen in the waste mass is released during thecombustion process and decreases the oxygen required
for stoichiometric combustion
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Step and 0:
Component !eight Molecular Moles Moles
(lb !eight (lbd
Carbon 2.+ 1 C---;C#"ydrogen 0.21 1 4"---;"
#$ygen 0.2 1/ # --;#
%itrogen ./1 14 %---;%
Sul&ur .1 0.1 S---;S#
!ater 1. 12?nerts ('sh 1.4+ n)a
1.
#$ygen &or combustion o& 1 lb o& MS! lb
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Step and 0:
Component !eight Molecular Moles Moles
(lb !eight (lbd
Carbon 2.+ 1 .414 .414 C---;C#"ydrogen 0.21 1 0.21 .+ 4"---;"
#$ygen 0.2 1/ 1.42/ -.40 # --;#
%itrogen ./1 14 .40 %---;%
Sul&ur .1 0.1 .4 .4 S---;S#
!ater 1. 12 1.1+
?nerts ('sh 1.4+ n)a 1.
#$ygen &or combustion o& 1 lb o& MS! ./0 lb
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tep *" Composition of
+lue ,asCalculate the composition of gas
produced b& combustion of waste
-e sure to add the water content inthe waste sample to the waterproduced b& combustion
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Step 4
Component Moles Combustion Combustion
(lb
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tep ." Calculate the /ir
0equirementsCalculate the air suppl& required to
provide the ox&gen needed for
stoichiometric combustion1oles of air required 2
0equired O'suppl&3O'mole
fraction
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4&pical /ir Composition
(mole fractions)
Component mole fractionCO2 0.0003
N2 0.!02
O2 0.20"#$2O 0.0%2"
&ir Composition
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Moles o& 'ir re=uired per 1-- lb o& waste lb
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'oles of air ( 2."3)0.20"#
( %2. lb*moles
tep .
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tep 5" Composition of /ir
uppliedCalculate the moles of each gas
component supplied in air using
the air composition provided intep .
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Step /: Composition o& supplied air
Component 'ir supply(lb
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Step /: Composition o& supplied air
Component 'ir supply(lb
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tep 6" $etermine the
Composition of +lue ,astoichiometric (78 excess air) gas
composition
/dd tep * results to tep 5 results
Calculate in both moles andpercent
um moles to calculate total molesgas production
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Step : *lue gas composition
Combusti --------- Moles o& *lue 9as ---------
3roduct Combustion 'ir Supply 5otal 3ercent3roduct 9as
C#
"
#
%
S#
. 1. 1./ 1.
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Step : *lue gas composition
Combustion --------- Moles o& *lue 9as ---------
3roduct Combustion 'ir Supply 5otal 3ercent
3roduct 9as
C# .41 . .4 1.
" 0.2 .1/ 0.4 .2
# . . . .
% . +.+1 +.+0 /0./S# . . . .
. 1. 1./ 1.
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tep 9" Calculate the +lue
,as Enthalp&-4:3lbmole is a function of temperature
and compound% this function is complex%
nonlinear#e will calculate the enthalp& of the ue
gas at various temperatures (!777% !.77%'777% '.77o+) using enthalp& data for
individual gases and ue gas composition4otal -4:3lbmole is a weighted average
of all gases present
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0equired Enthalp& $ata
5emp C# " # %
1 142 /+ /+4 /
1 1/14 0140 112 1/
1+ 0/+0 11+1 14
+0+ 44 1+1 12/+
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Step 2: Calculate &lue gas enthalpy
5emp, * tu)lb
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Step 2: Calculate &lue gas enthalpy
5emp, * tu)lb
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tep ;" Convert Enthalp&
in ,as to
moles of ue gas (from tep 6)3(!77 lb of waste)
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Step +: Con@ert enthalpy &rom tu)lb
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Step +: Con@ert enthalpy &rom tu)lb
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tep !7" +lue ,as
4emperature$etermination based on
conservation of energ& (Energ& In
2 Energ& Out ?osses)@nowing energ& is transferred from
waste to gas we can interpolate
from tep ; the temperaturecorresponding to the heat value ofthe waste
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tep !7" Continued
Calculate the temperature of the uegas assuming no losses b& using the
energ& content of the waste tointerpolate between temperaturesusing information calculated in tep ;
Calculate temperature of the ue gasassuming an eAcienc& of combustion
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Step 1:
Case ': %o losses
Energy in &lue gas /.0 tu)lb
5emperature *
Case : A losses
E&&iciency 2 A
Energy in &lue gas 4. tu)lb5emperature *
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Step 1-:
Case ': %o losses
Energy in &lue gas -/ tu)lb
5emperature 0 *
Case : -A losses
E&&iciency 2- A
Energy in &lue gas 4- tu)lb
5emperature / *
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Excess /ir Calculation
Combustion is generall& not donewithout excess airB Excess air is
supplied to control temperatureand increase mixing to ensurecomplete combustion
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Excess /ir Calculations
tep !!/$etermine how man& moles of air
will be added"
(8E/3!77)>(moles reqd for 78 E/(tep .))
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tep !!/ '.8 Excess /ir
%2. lb moles + 2,)%00 ( 3.%! lb moles
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Excess /ir Calculations
tep !!-$etermine composition (lb mole) of
extra air supplied using air
composition tep ./dd gas components from tep -
to gas components (lb moles) fromtep 6 for 78 excess air
um moles and convert topercentage composition
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tep !!- '.8 Excess /ir
Combustio ase &lue gas E$cess 5otal
3roduct &rom -A E' 'ir 3ercent
lb
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Combustion ase &lue gas E$cess 5otal
3roduct &rom A E' 'ir 3ercent
lb
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Excess /ir Calculation
tep !!C0epeat teps 9 through !7
In tep ;% use the moles of gas
calculated in tep !!-
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5emp, * tu)lb
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5emp, * tu)lb
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5emp, * tu)lb waste
1---
1--
---
--
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5emp, * tu)lb waste
1
1 21
0//0
44
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Case ': %o losses
Energy in &lue gas /.0 tu)lb
5emperature *Case : A loss
E&&iciency 2 A
Energy in &lue gas 4. tu)lb
5emperature *
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Case ': %o losses
Energy in &lue gas / tu)lb
5emperature + *
Case : A loss
E&&iciency 2 A
Energy in &lue gas 4 tu)lb
5emperature 0 *
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0epeat for .78% 6.8% and
!778 Excess /ir
50 % Excess Air
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E$tra air supplied: /.0 lb
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E$tra air supplied: +.0 lb
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100 % Excess Air
E$tra air supplied: 1.- lb