exam i results p120/2007 avg: 85.9 = 74.6%. infiltration q = 0.018 btu/ft 3.hr.f o v k t here k is...

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Exam I results P120/2007 Histogram 0 2 4 6 8 10 12 14 30 40 50 60 70 80 90 100 115 Bin Frequency Frequency Avg: 85.9 = 74.6%

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Some typical R values MaterialThicknessR (ft 2.h. o F/Btu) Hardwood1”0.81 Concrete block8” pane window0.125” pane window0.5” air1.72 Fiberglass7”21.8 Polyurethane1”6.3 Nylon carpet1”2.0 Wood siding0.5”0.81 Plywood0.5”0.627 Plasterboard0.5”0.45 Steel1”0.0032

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Page 1: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Exam I results P120/2007Histogram

0

2

4

6

8

10

12

14

30 40 50 60 70 80 90 100 115

Bin

Freq

uenc

y

Frequency

Avg: 85.9 = 74.6%

Page 2: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Infiltration

Q = 0.018 Btu/ft3.hr.Fo V K T

Here K is the number of “Air exchanges per hour”and V is the interior volume of the house/building.Note: some exchange of airis necessary (you need to breath!), and this is not readily apparent in this figure.

Page 3: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Some typical R valuesMaterial Thickness R (ft2.h.oF/Btu)

Hardwood 1” 0.81Concrete block 8” 1.251-pane window 0.125” 0.882-pane window 0.5” air 1.72Fiberglass 7” 21.8Polyurethane 1” 6.3Nylon carpet 1” 2.0Wood siding 0.5” 0.81Plywood 0.5” 0.627Plasterboard 0.5” 0.45Steel 1” 0.0032

Page 4: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Degree-Days Heating/Cooling

http://www.ersys.com/usa/18/1836003/wtr_norm.htm

Indianapolis

Page 5: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Price of Natural Gas(dollars/MBtu wholesale I believe)

http://futures.tradingcharts.com/chart/NG/W

Page 6: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

“Low-e” (emissivity) coatings on windows

Conducting oxide

Double metal layer Single metal layer

Phys. Today Nov. 2000

Page 7: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Heat Pumps

Page 8: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Coefficient of Performance

• As the outside temperature goes down, the performance of a heat pump also goes down. You can, however, design the system to exchange heat with the earth instead of the air (geothermal systems sold locally)!

Page 9: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

http://eosweb.larc.nasa.gov/EDDOCS/images/Erb/components2.gif

Page 10: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Spectrum of Solar radaition at the Earth’s surface

H&K fig 6.2

Page 11: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Components of solar Energy on Earth

H&K fig 6.7

Page 12: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Insolation (Btu/ft2.day)Horizontal surf.surf. at = latitudeMean monthly T (oF)

H&K Appendix D

Page 13: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Fundamental components(any solar energy system)

• Solar collector• Storage system of some sort (to account

for night and cloudy days).• Energy transfer fluid (which could be air,

as in some systems we have seen, antifreeze, or even electrons)

• Auxilliary/backup system (typically)

Page 14: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Fundamental components(any solar energy system)

• Solar collector• Storage system of some sort (to account for

night and cloudy days).• Energy transfer fluid (which could be air, as in

some systems we have seen, antifreeze, or even electrons)

• Auxilliary/backup system (typically)

• Q: Does solar energy go to zero on cloudy days?

Page 15: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

H&K fig 6.8, 6.9 & 6.32Clear Day Insolation as a function of collector angle

Why does the angle make a difference?

Page 16: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Typical Passive Domestic solar heating systems

H&K 6.26 “Trombe” WallH&K 6.24

Page 17: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Typical Active Domestic solar heating system

Page 18: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

E.G. Domestic hot-water system

Page 19: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

Typical collector design(fig 6.18)

Can we understand the design criteria for each of these components?

What happens if you run such a collector too hot?

Page 21: Exam I results P120/2007 Avg: 85.9 = 74.6%. Infiltration Q = 0.018 Btu/ft 3.hr.F o V K  T Here K is the number of “Air exchanges per hour” and V is the

National Solar (thermal) test Facility (Sandia New Mexico)

http://www.sandia.gov/Renewable_Energy/solarthermal/nsttf.html

5 MW of thermal power for (with 222 “heliostats”)$21M (1978 $’s)