electrical engineering objective questions part 8

8/20/2019 Electrical Engineering Objective Questions Part 8

http://slidepdf.com/reader/full/electrical-engineering-objective-questions-part-8 1/39

C

.S.

E

.

E

l

e

c

tr

ic

a

l

E

n

g

g

. (

P

R

H

I

M

.

) -

2

0

0

5

C

.

S

.E

.

E

L

E

C

T

R

IC

A

L

E

N

G

I

N

E

E

R

I

N

G

-

2

0

0

5

(

P

R

P

.

IM

I

N

A

R

Y

)

T

im

e

/

lo

w

ed

:

2

/w

;

M

a

x

im

t

ll

lt

M

tr

k

3

0

U

~

.

··

··

·

I.

2.

3

~

~

D

r

[

x

.1

_

.

C

J

I

f

h

e

in

p

n

l

lO

d

w

<

li ;

:

·i

ta

i

d

r

c

u

t

c

o

n

s

is

t

in

g

~

~

o

f

2

0

_X

O

R

1

.

· ·

:·

th

en the

o

u

/

~

u·

to

X

(

e

,

.

\

(

C

)

0

v

I

C

~

J

O

0

I

1

1

I

0

~

o

1

I

·

+

--

-

+

-

-

0

c

)

A

C

d

)

i>

C

www.examrace.co



4

.

.

(

d)

(P

+

Q

)

(l

hS

)

I

f

al

l

th

e

m

e

ss

ag

e

s

o

f

a

s

o

ur

ce

h

av

e

th

e

sa

m

e

p

r<

>b

a

b i

lir

y

P

th

e

n t

h

e

so

u

rc

e

e

nt

ro

p

y

(m

.)

i

s

g i

v ~

u

b

y

a

)

lo

g

P

p

c)

l -

p

(b

) +

lo

g

P

1

- p

d)

p

.

;

_

.:.

....

_:

_

'

J

3

m

;

6.

To

t

ra

n

s

m

t

N

S

ig

na

ls

,

TD

M

,

w

il

l

re

qu

i

re

a

t

o

f,.

by

:

o

f

·

7.

a

)

fm

H

z

c)

N

fm

H

z

I

n

3

D

M

s

y

s

t

f

l f

a

n

u

la

r

no

is

e·

o

cc

u

w

he

n

t

he

m

o

d

u

la

t

i;

e

g

(

a)

incre · rly

(b)

incr

ease-S

e

xpon

entially ,

(c

n

st.

an

t

(d

) d

ec

re

as

e

s:

ra

pi

dl

y

8

.

C

on

s

i

t

f

ol

lw

o

in

g

s

tl

. 't

em

c

nt

s

in

c

on

n

ec

ti

on

w

ith

:

P

s.

s

er

n

:

:

C

t\'4

i

s m

u

c

h b

et

te

r

fo

r

n

o i

se

im

m

u

n

it

y a

s

it

de

p

en

d

s

g

1v

en

l

lm

e

.

2

.

PC

M

re

q

ui

re

s

a

sm

a

ll b

a

nd

w

id

th

C

{

m

par

ed

an

al

og

;

sy

s

te

m

s.

3. P.cM. requ ires very

~ o

p

encoding

and qu

a ntiz ing

C

ti 'C

U

J t

y.

4

P

C

M

ha

s al

l

ad

v

an

ta

g

es

o

f

fr

e

qu

e

nc

y

m

o

d

u

la

tio

n

www.examrace.co



when

it

co

mes to n

ois

e perfo

rman

ce .

Wh

ich

of the s ta

teme

t

g iv

en a

bove

are

co

rrect

:

a )

l

, 2

a

nd 4

b)

I , 3

and

4

{c) 2

, 3

and

4

{d)

l

a

nd

3

I

. T

he frequ

ency

spect

rum

o a

n

am

plitud

e-mo

dulat

ed

si

gnal

conta

ins

10.

11.

(a)

canier

frequency onl

y

(b ) sideb

and

freque

nc

ies on

ly

·

c)

mQdu

lating

freq

uency

only

d) c

arrie

r a

nd si

d

eba

nd . f

reque

nc ies

max

im um

amp

litud

e A

,n and

a

m in

im u

m e ·t

A,;a

a posit

ive

v a lue

) , the

n t

he m o

-dula

o n

· ex

is

giv

en

by

a)

A ..

A.,...

c)

A..

,.,. - Anun

A.. . ,

.+ A

,,n

In

•

b)

of the

fouri

er

}f

tnon o

f

Time

with

List

an

d

selec

t th

e c

o

rrect

b

elow

the

Lis t s

:

U

st -11

I

.

IF

oo) I

2.

www.examrace.co



c

j (t) c o

s

U o

t

a.

l F

w )

w

:

V

0

( ):'

\

•;

--

}

\

\1

D.

4

r

f(t)•

s in w t

r: F(W

I

-

/1

\h

/1

L

J

A . -

·-

_ _ l

_

V\:{(

)U

-

r ~

t

C

I

A B

c D

A

t eJ·

a)

l

3

2

4

(b

)

2

(c)

:1

4

2

(d )

2

12.

rg

I ou rier lra n · c

g te

fu ncti

on

a s

shown ah

<>vc is

f(t)

: :

l

:2 l i

t i

: ;

()

.r

•tse

f · J,u

f

l

· 11>} 1S

" ( \..r<)

-r sir 2

c. r

(

. .

. .

{ ~ : :

2(;)

\

.

., '

r

; :

1) r

\ )

t

· ·

.,

l< t 12)

l,.

wJ '}

: ,•

. : . ( .

www.examrace.co



1

4

.

m

A

-

K

-

· A

NII

v

sv

w

orki

ng

w

ith t

5 v

and

-5 v p {

W f f sup

plies

.To

vo

ltage

V

0

is e

q u aJ to

{a)

5 v

b

)

1 V

c)

-

1 V

>

V

15V

•

5V

n

0kn

-

T

he cin

:

u

it

gi

v

is

a.) p

eak det

c o

b)

Sc

hm i t

t tr igger

c)

buffe

r

d)

u n

ity

gain

ampl

ifie r

15.

a t c

h ~

Sch

eme o

{ F

eedba

ck

with

List-

11

P

erfor

· e

. ea

s

u

re

an

d

sel

ect

the

correc t

an

s

w

er

·

th o

d e

g iv e

n belo

w th

e L

ists :

t t ~

l

Li

st·II

rrr<:

nt series

l .

I

nput ·imp

ecbn

c:c in

c reas

es,

outp

ut i

mped

an

ce

decre

a ses

. Curr

ent S

hu

nt

2.

Input

im

peda

nce d

ecreas

es,

.

. ..._

ou

tput

im

pedan c

e

d

ecreas

es

~

-

C.

V<

>ltage

se

ries

:3. I

nput im

peda

n

ce

inc

reases.

www.examrace.co



ou

put im

pedan

ce inc

rease s

D. V

oltage

S

t lunl

4 Inp ut

imp

edan

ce decre

ases

ou

tp

u t

impe

dance

i

nc rea

ses

A

B

c

D

A

B

c

a}

4

2 I

b)

2

l

3

4

{:)

4

2

d)

2

4

3

1

HL

v,.,

a)

50rt

c)

v

'

· · · · · · · · · · · · · · · · ~ ·

: : : r

17

. Th

H ~ r llr.J i

p

{C)

0·

30

d) 0·60

d

d

www.examrace.co



19

:w

.

2

1.

A

bu

nlc

d con

du c

10r

has

3 c

o n d

u cto

r

s,

sp

ace

d

sho

w n a

bov

e. D is

t

he G

MR

in

d iv id

u al

·

c

ondu

cto

r. W

hat

is

the

GM

R c>

f

th(l bun

dled

cn

ndu

ctor

?

(

D , "

<J) '

(c

) (D,

"

d

1

) : .

(b)

(D,

<l)

''

(u

) D,x

d

2

In

a shor t

transm is sion

i in

c,

i f

the intpcdant

l

of th <

lin

e is

0 ·01

+j

O

IS

p e r

un i

t

w

h n t h e

lo

ad nm

en

l

s 1

·0 p

.u .

at 0·

8 la

g po

wer

fact

o r

a nd

the

en

d

vo

l

t

a g e

Vn

= 1

·

0

p.u .,

w

ha t is

th

e re

gul

at ion

of

the

lin

e?

0

a) 0

·8 %.

(hl

0·

9 '':.

(c

) l·8'\

\

·,

(d )

J ,

r

~

Wh i

ch

o n<:

of

the

y

ields

the

v

ah

lc of

of

w

ndu

cto r

s betw

een

tw

o po

I es

?

(W i

s

w

u

n it

~ o

f co

nd u

cto r

in

:'llfm,

L

is

th

l

betw een

IWO

pol

es

in

m ete r,

f

iS l

ir\

con

du

c

w

r

in

N

)

a)

\Vl}

ti6T

<:) W

l

2

t

T

ts g

ive n

b

y

22.

is eorr l l'l :

In

a

for a

ti ir

\lq;

r<)t0.

d pow e

r

I

he

re

pres

en ts

th e

~ q ~ y co

ntrih

ua:rl

by

on

(b )

m aj

or c

h(:rm

al s

ta t io

n

bydr

o or

g

as

:il<

Hi > l

b

·onv

enti

ona l

po

wer

stal io

ns

e r

th e

f

o

llow

ing

sta t

e m

ents

for

a

Tor

que

is

con

stan

t fm

m slan

(b ti

ll

up t <

syn

ch ro

not:;

;

SJ C

· etl

N

'

www.examrace.co



21.

25

2.

Ho Or is providecl with narrow

slots

embedded with

bars.

:5.

Tor(jue at swning is :some

w h < ~ t

m o n ~ than

that

at

syncht·oncms

speed N ~ .

4. As

the name

st1ggests,

only hysleresis

torque

s

produced from

zero speed

:right

up to t- :r

5. Hotor nli.'lt( rial

p l : s s c s s t ~ s

very wide hysteresis

loop.

\ ~ h i c h · » ~ : . · t ~ H ~ : ~ l . a t t m H : n t s given_ ~ h ~ J v ~ are c o r r e c t ~ ?

{<t)

J,

•. t ~ m l ., (b)

J

.H.d

;

(C) J an<l 1 (d) 2. and 5

Th4

field eurrcnt of

a

synchronous motor is inc

while

it:; load is c()nstant.

How

will it.s

pow

and )Ower

factor

change·:

(<lJ P o w ~ r

<'lr.lgle

decreases

and.

p o w t . ~ r ·

f<tctor

(b) P(JWt:r a n ~ l e

remains

- ~ H n H : t h r o u r t

H

p }WCr

factor

imf)roves

(c)

Powe ·

angle

n c r ~ l S : : ;

white

ils

Sj

or

gradually

de(r(;'a:;es

(d) P o w e ~ r angle and power f ~ increase

Two

<oltcnlato:rs

(M

1

ansJ. J:ve

been pr(>perly

:>ynchronizcd

and conn · c ·n

parallel to

a c o m m ~ m

bu >ha r. f

h e r ~

is

n ) I o · busbar, at·ld

the the

fic .d

exdtati(m

~ > f

th( s

n

· l ternawr (Mz)

is

inct·casc<l

j ;radu.ally

by s ~

ul)t, frQm its

·nNmal

x c i t < ~ t i < > u

for

w:hkh the , e.m.f.'s

f

and

E:: of

the two

m;H:hines arc q the armature reaction

due

t-o the

circulatin a c current would be

ia)

www.examrace.co



List-1

A Capaciwr-run

otor

)

Capacitor-start

end run

otor

C

Shaded-pole motor

D

Resistor-sp ir

phase

moter

A

a)

2

<) 3

27.

List-11

T o ~ q u e

3

2

- · · · · · - · r · · ·

1

·-·----- "\

0

~ p e e d

\

B

c

D

(t))

2

4

d)

: 2

•

www.examrace.co



3 >

C

.S.

E.

Electri

cal En.gg. (

PRELI

M. -2

005

2X.

29.

I

·c;)

s

(d)

I

- S

s

To prC\ C

l1 t

s h

~

of

t

he

mag

netic

n ~

a xis,

(:<IUS

.( d

hy th

e . l lr l

t urc

react io

n ' i :

a

d.c;

,

m h

i n ~

the most cffc

ctwe m

etho

d to

ncutr

ah1..c

t

he n

rm a tur

nux i

s to

0

(<:)

shift r

hc

x i : ; ·

(h) p

ro vid

e high

-re luc

ta

nce main

pole t i p ~

r ~

c) c

u t

hor

izonw

slo

ts in

th

e

ma

in po

les

( .i)

l : : ~ c c com

pcnsa

ing w

ind in g

s on t

h '

·n · f¥> 1c face

s

Ht

• ·· --()

.

\

' \ .

.

'

.

r. .

I

l

§

I

4

v

C o(

r >

0

~

0\

l

t .

r

•

ri

1

3

40

0V

f.'

ig

.

2 Fig . 3

·

I

·g

.

e o n ~ c

t c d an au

to l

ransfo

rm er

shown

in

hg.

llw

t i o n s

of the

100

V w in

d ing arc

rev

er sed

()\

\ II in F

ig

.

a. w

hat is

the

\ <t

iUC

of the

vOlta

ge

V

1

i red

lu he a

ppli

e d acr

oss tre

mina

ls

X ~ and H

, to

ob

tain t

lw same

40

0 V

ou

tput?

\ ~ 1 ) 5t) f

) \,'

(b)

. () () v

{(

)

o o v

{d) 1

o

n v

3

0.

Two

t r a n s

f o n m

wi

th i

dcntie

al vo lt ag

e r

atings

o re

wo

rk in g

in

paralle

l to

s

upply

a com

mon

loa

d. The

p

erccma

ge im

ped a

nce <

>f on

e tran

sfo

rmer is hig

her

ro

mparc

d to th

at of

th

e

oth

er.

The

load

sha

ring

i W < ~

the

two

r a n s

f o r m e

v.'i l

www.examrace.co



:n.

(a) be proportionate to their percentage lmpc danees

(b) be independant c>f their pen.:entage impedanC( S

(c) he

nvcrs.ely proportional to

their

respc<:t

ive

impedances

(d) depl;)nd on the resistance to k a k a ~ e reactance ratto

of

each

transformer

ConsidN

a

< > Y S l ( ~ m

having

forward

path

and

feedback

path tran•,fer functi(ms as

}j()

(s(s+0·8))

n d ~ l

·

res.pceth•. ly. \Vhich is the

characteristic

poly

1ia

of the

system?

~ 1 } ~ Z . + J · 8 ~ ; i · · I G b) :sZ·I·2·8s+·loo

(C) s

2

; ;32

·8s r H) (d) : ·

:J2so ·

i

Whkh of the ioll.owing correct?

The feedbadz affects the eontrot system fott()wing

ways: e·

. h i c ~ C < ~ s c s

.:accuracy

but

t·edu

'

:::itivi:y of

g:<lin

1o

vanauon

tn

system

parap.c-r

: . l n u e < ~ s e s b m d w i t h ~ ~ c s the

cffcd

of r ~ o n ·

mean y.

Increases

ten<.le

t<

v·

· s

o.citlation or l e a d ~

even

tn inst.abirity.

(a) I and

2 (b) I

and

(c) 2 n d ~ (dl

I,

2 and :.3

The tr·

f t Vnc t ion

B s)

si mpllfi<:ation

< f which

oM

of

the f<lllowing

diagrams'

{sf >

, L ~

B s)

www.examrace.co



h)

R

A s) I

r

ln s

)

I

l

A

I 1

d )

1

I

C s}

)

C s)

+ 1

l

I

< t ~ J I

1

www.examrace.co



35

www.examrace.co



s

l l

·····;····

-··

······

-;:·

s· ·<

u

>

W

hat

will

be

the o

utput

v

ol

tage

if the

i11

p

u

t v

oltag

e

is b t ?

(

a)

,fi

i11

61

t ...

l't

/ 4

)

(b)

cos j

- si

n

u)t

c) c o ~

w

t

(

d) [

2 si

n(l:lt t·

r

/

4 )

Whkh

<_>f th

e

follo

wing

cha

racter

istics

of y

~

a

rc

m

e

b y

y

t) =

x ( t

> C<>s

(1 O ~ t

?

L h

is l

inear

.

:2 It

i

s time

invari

o - .

h

cau

sal.

4. 1t

is <\

stahl<

;

·J. it

ts sne

rnory l

ess.

Selec

t th

e co-rf

ect a nsw

er

using

the

r :ooe

giv

low

:

{a ) l, 2

3 an

d 4

(b

2

, 3

~

·

(c)

4

<1nd

5

d)

d

5

·10

. Ma

tch Lis

t-

(Po

le

Loca

tion) wa

.

i

s

t Jl

Tim

e

1 ?e

spom;e

u e

l.o

lnilia

l

~

an

d :;ele

ct th

e

torrcc

t ?ns

wer u

s ing

t h e

en _

b elow

th e L

ists :

l . ISt · l

a

st

-II

f ~ > k

im

e-

e s p o n

due t

Q

.

ni

tial Co

nditio

n)

( t )

:\

j t

.

g ( t )

I

=v

t

- - 1 - -

+-+

---1-

-\-...

~

·

T

.....

..........

..

~

2

g(

t)

I

--

-

www.examrace.co



4

1

c

D

j

l)

.

.

I

•

·

l

;

0

w

i

..

;)

-

A

a)

C

)

2

B

C

1 4

3

0

3

4

3

.

g

t

)

_

_

.

.

·

·

·

4

.

x

.

l

j

.o

r

t

h

e

n

e

t

w

o

rl

s

h

o

w

n

a

b

o

v

e

?

.

r

u

<

:to

·

t

h

)

••

d

)

f

.

4

www.examrace.co



' - ' )

i .

r + r

.

'

__

._.

r

r:: j

. . - - - ~

00 0

c

·-·

v 5 c o s c ~ t + L

-..,

5

)2

- - - · · · · ·

l·o r

t

ll<.: ;._ c

d

r(:ttit

; ~ i \'(' > l ilh<>vt:,

i f GO\\ < r

dissipat'Cd by

the

5 0 resistor is

e r ~

Pcn

w h . ~ l

is

the

power

factor of the drcit?

{<l)

0

l

ing;g;ing

(b)

0( '1J.,

·

(<:) (Hl k ~ ; 1 d i n g (d).

~ i n ~

A 2-terminal

nctwor·k

is 1 ~ H ~ R-1.-C

clements..

The ~ ~ l c m e n t

is

c o n n e ~ · ~ a.c

supply.

The

rurn:nt

through the

·• 1 l is

I

When a

capacitor

b

ins« rtcd in seri

c c n the source and

the

elemerlt, the ( 'U T t ·ough

the

e.lement

becomes

21 The c.lem

(a) t i ;:

(-(1

;s

a

(b)

is an inductm

(d) oeannot

be

a

s i n g k ~

cleme:ni

www.examrace.co



4

5.

46

.

Fb

r

lll

c

a

bo

ve

c i

rc

ui

t,

i t

he

.

cu

rre

nt

t an

d

1

·5

A

f

or

R

1

_=

0

an

d

2

D

r

es

p

c

<:t iv

:ly

,

t

he

n

w

h

at

is

(

he

va

lu

e

o

f

I

fo

r

R

I.

1

)?

a

) 0

·5

A

(

b

l

} A

c}

Z

·O

A

d

)

:3-

0

A

l

2 4

5

G

,,,.,

_

_

[

1

L

l

0

0

A

()

l

0

0

·-

l

0

0

1

)

n

30

V

W

ha

t

a

lu

e

o

f t

he

c

u

rr

e

nt

l

i

tiH

:

)

,

e

.

/

\

\

(

h

:

.ll

\

(

dl

:

\

4

-b

it,

2

s

m

p

l

e m

e n

~

r

ep

re

cn

l<H

io

n (

tf

a

dc

t:

irn

al

mb

c

r

is

1

00

0.

\V

h

at

i

s

the

r

m

mt

le

r

.,

a

)

o

<1}

www.examrace.co



4

8.

50

.

1

<

>f

X

y

T

ht\

o

ut

pu

t f

of

t

he

<Ho

-1

M

U

X sh

ow

n

in

t

he

ab

ov

e

f

igu

re

i

s

(a

}

()()

)

+

x

(c)

x

·

+

y

·

0

Cl

k

b)

x +

y

(d

)

y

+

x

Q

a

·

T

he

r

req

uen

ey

o

f t

he

cl

oc

ks

ed

ge

t

rig

ge

red

D

f

lip

-fl

o

ab

ov

e

is

I0

kH

z

.

\\

ha

t ·

:w

ail

ab

ll

at

Q

?

a

.

} 2

0 I<H

;

;

{c

5

k

Hz

G

0

{ou

t

pu

t

www.examrace.co



51.

52.

53.

T

he ci

rcuit

i n the

f

i g ure g

iven

above

ha

s two

l

\1

0S

NO

R g

~ e s Thi

s

<:ircui

t func

tions

a s a

an

a} fl i

p -

f

lop

(b) mono

stabl

e m

ul r iv i

b r a to

r

c)

Sch

mit

t

t rig

ger

(d}

a s t

able

mul ti

vibrat

or

W

hat

is th

e n

u.mbe

r th

e comp

arato

rs

r

equ

ir

e d

in

a

3-b

it co

mpar

a to r- t

y

pe

AD

C?

a} 2.

b

} 3

c)

7

(

d)

8

T

he

a

vaila

ble mu

ltiple

ac

cess and

br

oa

dcas

t

syste

ms

are

0

; ~ ~

~

~ i ~

~ ~

~

5

. S

DMA

-

J

W h

ich

of t he

a

bove

a re em

plo

y z

o

r • s

at e ll

i te

co

mmun

icati

ons?

(a}

l ,

2

and

:3

b)

2 ,

;

c)

l

a

nd

4

{d) l

.

::1 4

a

nd

5

f the

max

imum

Ra

dar r

n

~

e

do

ubl

e

d , the

pow

er o-f

the

d ~

t r

~

s to be

i

ncrea

s

e

d

l

<eep in

g : a

U o t ~ c r

p a ra

te

ntac

t)

a}

tw

o

im

es

f

our tim

es

C) eigh

t

time

s

)

six

teen

tim

es

5 4 . \ \ hic

h on

e of l

o· in

g state

ment

s

is

o ?

bi

ts half-

wave s

ymm

e try,

then

Qu

ri e

r s

er

ies

s

va

ni

sh

hann

oni<:

s n

v ~

p r

v a

nd

arr

ay p

ro-cess

or·s

Jd?

S

l: ;i

J

www.examrace.co



57.

58.

5 ~ ) .

60.

What is/are the

di:sadvantage(s) of Gauss-Seidel

m€thod

over

Newton's method in load·flow

prog:ra mmes "

(a) More iteration

b) Mor'c rncm<)i'y rcquitemonr and less

accuracy

(<:) Less

iterations but

more memory

(d) More accuracy and

more

memory

Match List-

with L i s ~ - I I

and select the correct

a n l w ~ r

using the code given below the Lists :

Ust-I

Ust-U

A.

Buchholz relay I. lim ines 0

B. Mho

relay

2.

Shm1

lines

C.

Jrnpedance relay

3. M e d i u m ~ ~

0.

H e a c t a n < ~ e

relay 4.

Transfor s

\BCD A B ~ D

(a)

4

i

3 2

(b)

3

•4

(C)

4

2 (d)

3 ~

I

If

the fault current is

2 0 0 t 8 ·h relay

scuing

is

50% and CT r.ado is 400: , • what is

the

plug

setting

multiplier?

(a) 25 'b) 5

(<:)50 ~

10

In a static

over·

re relay, hov.; are inverse time

c h a r a c t e r i s t i c ~ e ?

(a)

By

us in,. a ·

stor amplifier

(h)

r ~ y

u:'

n a .

egratlng circuit

(<:)

ltzi

, ransistor switch

(d) I ' i a

d i f f e r e r . ~ i a t i n g

circuit

. <nis · · · tum·off of ; > ~ thyristor

t a k t ~ s p l a c ~

if the

~ ~ r ~

bias

peri:nl

or

t h { ~

d e v k ~ ~ .

aft-c '

its eurl ent

·

" heeonw

:r.ern, b

~ n : < : t t c r th::tn its tu:·n-off

tjrnc

~ n )

]es:;

i h c ~ n ~ ~ s turn·

off

t i r n ~

(C) } £ r c a t : ~ ·

l

hitn

·he

(:in:uit

rirnc-Cil)f iSUHH

'

\C.

I

www.examrace.co



61.

10 A

I

1

1

0

T/2

~ ' : '

2 •

62.

A MOSFET rated

for

20 A, carries a periodic current as

shown

in the above figure. The or1-slate resistance

l f

the MOSFEf is 0·2 ohm. What is the average on-state

power loss of device per cyc e : . 0

(a)

20W

(b)

i5W

J

(c) lOW

(d)

5W

0 .

l v.,<•mt fl CJ

(bl 180•

(C) 200" (dl 240°

63. Match Li h List -II and select the correct answer

usin the e given below lhe Lists :

. st-1 List-11

. verter) (Application)

factor

B H•lf·<OOtn>lled ooo rt

2.

So ft ' ' ' . ' · '

www.examrace.co



l i5

.

motor

C.

: -

pha se a.<

.:.

vo ltag

e

nm t

roitc

r

3. S

peeo

revc r

.;a

l

D . C

ycloco n

vcrtcr

4. S

moo

th low

sp cc

tl

rever

s ib le

high

p o w e r

a

.c.

drive

s

5. S

ynch

r

o

nous

moto-

r

corlln

>

B

CD

B

CD

a) :l

l

2 ·

(h

) 2

4

5

(C ) :\

2

l

(

d) 2

5

4

a

Vhi

<'h

or

I

he

f

>l

low

ing

.are t

he adv

ant

ag

es fr

w

l H ~ l ' l

i n

g

of

Load

c u

rrent

in ph

asc -

r J .d

e o

~ l i i

?

.

II rTduc

es r c < ~

p

o

wer d

eman

d of the

co

r

2.

I

i mpr'

O'

CS

t

ht:

d is p

lacemen t

•

·L

r e q

u l n l r g <

r i

ndiclaJ

1Ce

pt

v c

< O

n

tinuou

s

L

It i

n

1prov

es

d is t.tlrt i

on fac

to

r .

c

onduc

tion.

ij

,

Sdc ·

( ' l th(;

( ~ M r

a n

w ( " '

~ l l

·

c o d ~ ~ ~ t i v

b

elow

:

l

''

.,

I 1

·t .

)

.,

; ) . <

• <

ln (

(

- <trl(l

t:i

I

and 4

1 2.

:l

an<l ,I

\\.'hi

<:h o

f th

e fr) llo

a

funct

ion s

of f

cNib

ac

k

;

-

.

: : .

l

.

>VI .

c r e1urn

pa:h

i

o

r t h e r·

cac li

ve cm r

cnr M

k d

' l

.

T( ·

d e : a r

<:rth

fo

r

the exce

ss of

com

rnun i <at

ion

UITl'n

l

ab

ov

e th

e

l o ~ 1 d

u r r c

·1

tw

t ~ r u

smg

he

eo<k

g

iv e n

be

l

ow

. .

:; < tnd

-1

<h)

2

and -

,

. 2 a

nd J

(d)

:J and

-t

)

,\

: -ph

ase indu c

tion

mot

or o

pNatc

-s at c

ons la n

t slip

www.examrace.co



0 to rated value. Which one of

the

followi.ng

statements is corrocc:t?

The torque developed by the motor

is

a)

proportional to speed

(b) proportional to square of speed

(c) inversely pn>portionai

to speed

{d) constant in the

complete

n m ~ up to

base

speed

l)irections : The following 6 (six)

i tems

consist of two

statements; one a

belled s

the

Assertion (A)·

m1

the other as Reason (R) . You are to examine t

two

statements carefully and select.

the

£msw

hese i tems

usin.g the code

given below:

(a)

Both

A and H are

indiv[dually

rwe a1 ... ......

correct explanation of A.

b)

Both A

and

R are individually tnw

but

H

correct

.explanation of

A • n.

+

(c} A

is tme

but

R is

a l s < ~ (J

(d) A

is false but

R

is true.

r

~

67.

Assertion

A) A

s i n ~ ~ b ~

s;unpkd

<H

:wi<:e \ ~ t J ; . i m u m frequency oi

Reason (R) ; ng is to be d()ne at Nyql)ist

) avoid aliasing.

68.

Assertion

A ) ~ good degree- of relative

y vstabi l i ty a control system should

have a phase margin

of

about

40° and a gain margin

nf 0·5.

Reaso : A large gain

margin

or a largt

phase

margin corresponds

to

a

+

highly

oscillatory system. and a

very small gain margin or a

ph.a:;e

ma.rgin

approaching 0° indicatt':s

a v t ~ r y ~ > t a h l t botH sluggish system .

...._

A.r;;serlion (A)

SiC

1

is added

to

Cl

2

in

order t<

~ .

dry

etch aiuminium

www.examrace.co



R

ea

son {

R

)

70

.

As

s

e r

tion

(A)

e a

~ o n

{)

71.

H

cas

)n

( I {)

n

\

sS(:.

rtion

(A

}

(

U)

110

is

orropic

a ly

.

Cl

2

e

tches

a

lum

iniu

m w h

ile

SiC

.

etc llcs

nat

ive

alu

min

ium

o

xid

f;

and

a

lso

pro

vide

s

~ n i

s o t r

o p y

by

form

in g

inhi

bit<ws

.

r1

d isc

re te

as

we

ll as

JC de

vice

r

b

rica

t

ion ·v

re t o

x:id :

ation

of Si

in t

o its

na

t

ur<l

l oxi

de is

p r

r

r e ~ d

Th

e

ra1

e of

gro

wrh

o

f w

e

oxi

c a

t ion i

s

low

er

th

an th a

t

f

d

r·y

oxid

adon,

h

e n

ce a

n

,

tt

n lity

oxi

de

<:a

n b

e

gro

.

Dif

fe r

enti

al

amp

lifi

er

·

w

·it

h <

curr

(mt

so

urce

o

.r 1ig

h

C

M J

m .

D

iffe

rent

ia l

a m ~

. \

fi ll

ha

ve

h i

giH r

gain

u · ~

O n

m o

de

sign

als

.

t

s

c

·

s

ync

hro

nou

s

r

a

CS

I

nee

d

n

ot

a.

w

ind

in

gs.

D

' v

ind

ings

are

r

e

s

p

onsi

ble

. t r

~ t n ~

i e n t

a

n e in

·

·y

n

ro

no

u

s m

oto

rs.

7

3.

sys

tem

G(s),.

H

s s

+ 4)

ra ti

o

of

0·5

is

C) 4

(d)

2

/.t.

1

Mlst-1

w i

th L

is t-

:

md

~ l e c

the

<

:orre

ct .an

sw e

r

the

co

d e g

ive

n

bel

ow t

he

Lis

ts

l. .

ist- 1

Li

st-

C h

arac

teri

sti

c

(N

at

ure

o

f U

n

it S

~ e p

E

qu

atio

n)

n

csp

on

se

)

~

-

A.

sz + 8

s ;

15

0

1.

Un

dam

ped

www.examrace.co



75.

76.

77.

B

. s

+ 24

.s + 225

'

0

c.

s

2

+ 20·2

5

, 0

D .

s

2

+

20s

+

t O

O = 0

A

B

c

D

(a) 1

3

:2

4

(:}

l

4 J

2

2.

3 .

4 .

(b

)

(d )

U

nderd

ampe

tl

Cri

t

ica

lly

d

a

mped

Ove

rdam

ped

A

B

C

D

4

3 I

2

4

2

:.

Given

the

m.

atr

ix

ro

'

1

0

A

~ lo

0

1

I

\-G

<.

- 1 I -·

)

\Vhat

are th

e

e

igenv

alues

o

f A?

J

(a)

-1 , - 2

,

-3

(h )

- 1. 2

,

-·3

(c

)

0

, 0.

- 6

d)

6.

•

Co ns

id e

f the

follow

ing

a t c m

a

s d on

ga i n

ma

rgin a

nd

ph

ase of .a

s

yste .

les

s ·t

h an

ph ase

c r

o

s

s -(>V

en c

y .

l.

Fo

r

stab

le

t i le g \.

· S

·

vcr f reque

ncy

is

:. .

Fo

r lJOsta

h te s y s t e

m s

~

· c r

os s-o

ver

freque

ncy

is

gr

eater

th a

n ph a

· -

sS··<

)VeJ·

fre

quen y

.

:3.

For mar

ginall

y

· ·

1k

s em

s, the

gain

ft

N}l.iC:: \

CY is c I

h

ase cw

ss-<

wer c q

u ~ n c y

W

hich

of the

strt

·S

give

n ab

ove arc

CMr'l:

l: t ?

(a

} I a

nd 2

b )

2 a

nd :

) l

d ) I.

2 a n

d 3

hic

h

n

liit

1c f

ilow

ing

re

prese

nts the

t r a nsf

er

u n c t i

p

hase -

lag co

n

trolle

r?

_ ~

a < 1

(h) l t < l

I : S

a > 1

1 ;. rs

·

l

·t·

T

s

T

llllilo

(

d)

l··· aT

s

.._.....

..

a > 1

l-t T

s

lhc ~ l

e a d y

s t a t ~

) f

a

con

trol

www.examrace.co



79.

so

sy

stem .

w

hich

one o

f th

e

fo

llow i

ng

co

ntrol

wm

be

empl{

)ye d ?

a

)

c

ascad

e

PO

(b)

Casc

ade P

I

s c

hemes

(c)

Ra

te reedb

a <:k

d) I

ntegr<

il

fee

dbac

k

The

res is t

an ce

m

ea

s

ured

betw

een th

~

r

T

w -t

Jo

op and

an

in in

itely long

co

nduct

or,

e

a h

s

eur

r

c

m I

IS s how

n in

f igur

e gi

ven

above.

is

th e

fo r e

on

w

loop

'

..

._ \.

C•

e•

'

Y

fmm

th e

ctmd

uc<m

~ .

•l

www.examrace.co



81.

2.

(b)

l l.I•

·- towards the conductor

41t

l [2

(c) ~ ; · l o g , 2 away

from

the conductor

d)

The m g n e t i c ~ tentia at the point

I-'

due to the

current

1 < ~ 0 n i11 the above

flgure is in

the

dire(·tion

< ~ )

0

{b) 5,.

> •

~ .

a , ' < ~ ,

• f(J ,I ,

s

'·

S' h (ll\<.: v t h ~

following

statements is correct'?

oC> ;' <HI

electromagnetic

wave strikes the air-

di le nk interface

a t

<HI .angle

www.examrace.co



85

.

(b)

the

ta

ngen

tial magn

etic

fi

e

ld

com

ponen

ts a

r

e

cont

inuou

s

c) the el

ectrom

agn

e

tic

w

ave

is ref l

ec ted

b ck acco

rding

to

n

ell s l a

w

(d

)

the

c l e c t

r o m a g n

< . · wave

is

diffra

ct

e

d

I

r =

l

~ B

t

1

0

I

v

Fo

r

the

c

urren

t 1

d

ecre

asing

in

the

d

ir

eC1io n

,

the e.

m.f.

in th e

tw

o 111

0ps

A an

d B

Lh

fi

gure

above. is

in

the d i

rc<

:

tion

h)

antic

ockw

is in A an

d. c

·

·e

i

n B

{c)

c

lockw

i

se

in both

~

.

d) an

t ' ic oc

k

wi

se

in

tl<

H

A / 4

~ - A

. / 4 - -

4 i l

•

R

st

u<

. lure

C<lllS

isting:

M two

loss·l

ess

lin es

,

e

ach X/4

figur

-e giv

en a

Th<.-

I in

es

have c

harac

terist

ic

;

m po

d ' '

of

' z

n•

>p.oH

•oly

., >h o

w .

W h

www.examrace.co



8 6

.

i

s lh

e

i

mp

ed

a

nee

m ea

su

red

a t

th

e

en

d

XX

?

~

R

O

»

R

c

) Z

r/

fR

(d

)

4Z

o•/R

M

at

ch

Li

s

t -

E

xp

re

ssi

on

w

ith

L

is

t

-

IJ

{

Coe

ffi

cie

nt

an

d s

>Ci

ect

t h·c

cor

re

ct

a n

sw

er

usi

ng

th

e

code

giv

·e n

be

low

th

e

Li s

ts

A.

B

.

D

Li

st

· I

Ex

pr

ess

ion

)

Z

.

.. 1

. '

'·(I

p

·;

:

: '

;:··

z

. .

www.examrace.co



Circuit/Rectifier with Ust-11 Type

of

Clipper/

l ~ e c t i { i e r and select the correct answer using the

eode given below the Lists :

List·

(fransfer Characteristics

ofClipper CircuittRectifier)

A

l.

Vout

~ : . . . . ~

Vin

List-11

Type

of

Clipper

Rectifier)

Doubled-ended clipper

2 Positive lipper J

n.•

- . , . ' - - - ~

Vin (J

Vout

c

_

out

D

~ ·

/\

l3

c

, t

I 2

·I

J)

fl CJ

·ve clipper

Full-wave positive rectifier

and no: a clipper

8

.

.

3

4

I

www.examrace.co



89.

Co

n sid

er

th e

foll

ow in

g c ir

cuits

v

l

d t:al

;

I

den

t

1

~

I

;

i

iJ

·

Vo

~

Vo

.

u

t

V

I

*

L

*

ld

caJ

f

r

v

i l

3

I

1

Whi

ch

of

the

follow in g

circuits

~ ~

t: e

f

ollo

wing

inp

ut-o

utpu

t ch

arac

te ri

stics

v

o = v

, fo

r

v;

<

V

f i

=

V

for

v.

>

V

S

elec

t th e

co

r ect

a

n ~ w

us·

· co

e

giv

en bel o

w :

(a)

1 on

ly

.l}

y

(c)

l a

nd

3

l

, 2 a

nd

:

9Q.

B

y add

itio

n

of

nt

or whi

ch

on

e of t

he

f

ollow

in g

p

o

r S

i0

2

in

IC

fab

rica

lion

b

e im

pro

ved

?

a)

Bo

ron

(b)

Ch

lori

r.e

ci Z i

rco

Q

_

(

d) I

nc iu

m

H.

Con

side

r

l

o w

n

sta

tem

e n ts

:

l

~ o n

e pro

cess

is u

~ d

for

r in

i ng

S

i fr

om

s ha

ving

seg

reg

ation

co

dfic

ien

K

< 1.

T he

he l

d

ver

tical

ly and

the

zone

is

m o

ved

from

o

ttom

to

top

of the

ing

o t. A

fte r

each

run

a

nd i s

to be

cu

t thro

wn

b d

t

he n

ext

run .

www.examrace.co



H.2

.

n : ~ .

2.

th

e

bot

tom

en

d of

the

ingot

conta

in

s

m ax

i mu m

inp

ur·itics

and

is

to be

cut

and 1

hrown

b

efore

t h ( ~ next

r

un.

3.

there

is no

need of

cunin

g

t he bo

ttom e n

d befo

re the

next ru

n a

s it cont

"ains m

i n i

mum

impur

i ties .

W

hi<:h

of

the

>aatem

cnts gi

ven

abo

ve

i

s/a

n ; <;;

(lrrecl

'

(a

)

l

only

(b )

2 only

(c)

2

anrJ

Cll)

I

and

;i

W

hich

of

the

follow

ing

la tem

ents ar

e co

rret•

t ?

I M

ol( \ u

lar

H ~ a

m

E

p itaxy

(M

BE)

i s .a p

hy

si c

(

VI 'E)

involv

(:S d w

mi

cal rea

ct ion

.

1

I

n-silL'

etchi

ng of s

il icon

is pos

sible

on ly i

t l

01

in

V

PE

sy

stem

l .

M l iE

of silic

on is

carrie

d out at

a

lower

te rn

aturc

com

p< re

d

to

~

•

4. The g

ro-wth

rate

of

lhe

1

accuratdy

n

mtt

·()JI

ed durin

g B ~

E

tha

n

d r n

( ) r r { a

n swe

r ~

· .

give n

belo

w:

(<l) 1 and

2

f

4

(('}

l. .a

nd ·i

d)

a

nd 4

Con

sider

th

e fo

llowi

·:

Ients

:

Hapid

Therm

al A

ng

(HT

A} i

s prd

crroed

o

ver

(' o nv

cn t i(

mal

c.

·mr

aling a

fter io

n -im

plant

ation

bec

aus t·

1.

RTA

do

c.

t a

. c any

ch n

ge in

th e

dopin

g prof

ile

.

2.

Then

' is lowe r if IU A

i:;

used

.

3,

R T

a

icd ou

t at lo

wer te

rm pe

raturc

.

W h

i ~ : h _

h

_statc

rn etm

i v e ~

a ~

) o v c

iS.

f

are cor

rect '?

(

2

, · 5

(bJ

1

a

nd

2

• • y

(

d) 2

on v

f

der

th

e folll'rW

i •IJ1:

t ; ~ l e

c n t s

~ ~ t h o

<

f crys ta l

pul inK

is

a

popu .l<lr

t< :

chni4lW

f<l'

r

v ~ ~ n h l

v

.:lk

a t e . to

t

rystal_

c c a

u

. . . . .

1 'l

.,

o

smg;

e crys

l< :l to

JnttJate

th e

~ .

I

U'\lW h

.

www.examrace.co



2.

t

he

s

e

e

d

cr

ys

tal

sh

ou

ld

b

e

p1

JfC

an

d

fr

ee

f

or

h

ig

h q

ua l

ity

g

ro

wth

.

:3

. in

ten

ti

on

al

ly

d

op

e

d s i

ng

le

c

ry

st

al

s ca

nn

ot

ob

ta

in

ed

by

t

hi

s

te c

h

ni

qu

e .

W

h

ich

o

f th

e s

t

at

em

en

ts

gi

ve

n

a t

)ov

c

a

oe

co

rr

e

c

t'?

<

l

l,

2

a

n

d 3

(b

)

I

a

nd

2

c)

2 a

nd

3

{d

)

l

an

d

3

9

5.

W

h

at

is

t

he

c

o m

~ c

t

s

eq

u

en

ce

o

r t

he

f

o l

low

i

n g

s

te

ps

ur

in

g

is

ol

at

io

n

b

y

L

OC

O

S

te

ch

n

iq

ue

?

I

.

Si

e t

ch

i

n

g

2.

G r

ow

t

h

of

th

in

p

ad

o

x

id e

.

D

ep

o

s

it

ion

a

nd

pa

tt

ern

in

g

o f

s

il ic

o

n

nit

ri

de

4

.

G

roW

1

h

of

i

~

S e

le

c

t t

he

co

rrec

t

a

n

sw

e r

us

in

g

th

e

c

od

e g

iw

:n

b

c

l

o

-

J

a

) I

-

3 -

4

-

2

b

)

2 -

3

-

I

-

·

(c

)

4

- 2

... 1

-

3

d

)

: -

I

-

4

- 2

f

>

•

96.

Consider

the

fo llow ing statem

e

nts

ar; -fs:

i

F

er

rit

e:;

ha

ve

h

ig

h

re

s

ist

iv

ity

.

2

.

F

er

ri

tc

s

ha

ve

lo w

e

dd

v

·.

3

.

F

e

rri

te

s a

re

u

se

d

as

co

re

m

I

n

g

h

fr

eq

ue

n

ct

M

Hz

)

tr a

n

sfo

rm

e

rs

.

\V

hi

ch

o

ne

of

th

e

st

atc

rn

(

O

5

•

h

ov

e

a

n

<:o

r

rec

t

)

a)

1,

2

an

d

3

.n

d

2

c) 1

a

n

d 3

d)

2

an

d

3

9

7.

A

n

ec

es

sa

ry

b

ut

r

f i

c ie

n

t

c

on

d it

io

n

fo

r

a

cr

ys

t

al

to

s

h

ow

e

r

·

ct

.ri

cit

y

i

s

a)

absenc

e

<

symmetry

(

b)

p

r e

s e

trc

of

s

ym

m

et

ry

c

)

pr

e

se

b

o

th

tra

n

sla

ti

o

na

l a

n

d

r

ot

ati

on

<l

l

m

e

ns.

o

f b

ot

h t

ra

ns

la

tio

na

l

n

d

ro

tz

t io

na

l sy

m

m

et

ry

98

.

m

at

er

i

a l

th

er

e

a

re

fo

u

r

co

n

tr i

bu

ti

on

s

o

la

l

p

ol

ar

isa

i

<>

n.

O

ut

o

f

th

es

e on

ly

o

ne

· is

p

e

nd

en

t

o

n

te

m

per

atu

re

an

d

th

is

co

n

tri

bu

ti

on

is

..

.. .

._

e

le

ctro

n i

c

po

la

ri

sa

tio

n

~

-

(

b)

s

p

ac

c

-c

ha

r·

ge

p

ol

a

r

is

at i

on

www.examrace.co



(

c)

io

n

i

c

p

o

la

r

is

<ll

i

o

n

d

}

o

ric

n

ta

tio

n

al

p

o

ln

r

isa

ti<

m

H

m

:

pe

rm

an

e

nt

di

po

le

m

o

m

en

t

,

k

B

ol

t l.m

a

nn

c

o

n ~

a

n

d

T

:

ab

s

ol

u

te

t

em

p

e

ra

t

ur

e ,

th

en

M

i

o

n

p

ola

ri

sah

il

it

y

i

s e

qu

a

l

·t

o

m

( (

t)

3kT

(

b}

m

(

<;)

:J

k

Tm

Hl

O

.

W

h i

~ :

h

<

M

of

C

o

pp

e

r

a n

d

s i

li c

cm

cq

u

ili

hr

i u

m

)

h)

(

C)

I 0

1

1

02

.

cy

e x

p

eri

m

e

n

t

m

in

ciu

c

ed

c u

rr

en

l

d

eca

y

ex

p

er

i

me n

t

:

0

M

as

s

S

p

o p

e

x

pe

ri

m

en

t

a

w

hi

ch

o

ne

o '

t

he

f

ol

l o

w

in

g s t

a t

em

e

nL

< ;

r

r

c

ct

?

1e

\ )

t:: l

n

um

b

•:;

r e

lf p

o

ss

ib

le

w

av

e

in

a

n

y

e

n

er

gy

b

an

d

-eq

ua

l w

th

e

n

um

b

u

o

f

u

ni

t c

e ll

s

T

h

<:

t

>ta

nu

m

b

r,:

r o

f

f:x

>S

Si

blc

w

ave

f

un

c

t i

on

s

in

a

ay

en

cr

h'Y

b

a

nd

i s

e

qu

a

l

t•

>

f

•ic

e

he

n

u

m

be

r

o

f u

ni t

c

ell

s

www.examrace.co



103.

according: to Pauli principle

c) The ;otal number of pos.sible wave f:Jnctions

in

any

energy band

is

equal

to

the total number oi free

electrons :n the band

d) The number of possible wave functions in any m ~ r g v

band is independent of the number of unit wiis

104 While ~ · n the value of distributed capacitance

by Q-mc

h

eson nces were obtained

l ith

values

of t

l·ng dtor

s c,

nd C

2

for

the frequencies

d

~ >

f

1

nd 2f

1

respectively. What is the

_

~ ~ distributed c a p a ; i t : ~ ~ ; ; ~ ?

~ ~ ~ ··· -,--··- (b)

www.examrace.co



I05

lOl

L

- (

<

e

::

• .

: , I.

.,

•.I

(d

)

~ -

~

3

. , . · · ·

-

• I

(:

-

· ~ >

-

-

--

;

v

=

I

o

.-

...

a

_

-

~

~

I

n t

he

f i

~ u n

s

lw

w

n a

b

tw

e,

A

I,

A2

a

A

id

ea l

am

m

ete

rs . I

f \2

an

d

A

re a

d

lA

an

0

e¥

>e

c

tiv

c l

y

wh

at

i

s l

h()

rca

djn

g

of

A

l ?

{i

l \

~

(

h )

3 A

-

J

te

l )

\

~

d

c

:an

not

be

ca l

cu

la

l

<

d ~

r i

V

e

va

lue

s o

f

:m

d

C

W

a g

n ~

r

E

a rt

h

D ~

v i

·

c

u

s ~ d

f

o r

a .

c . b

ridg

e

r

in.:

u it

:; f

or

t<t)

<

·l im

in a

t in

g

th

t

o

i ca

tt

h cap

ad

tan

cc

s

d

li

e l

i m i

n a

i n

g

·t

of

ear

th

c

apa

d t

anc

cs

(

c )

:l

im

im1 t

i

g

·

·cc:t

<

>f st r

ay

f

ie

lds

idl

:>hit:l<l

h

.

Hlg

e

elements

1

07

. \

\ 'h

i l

' '

£ l

.

a

c

oil

ha

v i n

t;

a

r

c_s

ista

nc

e

of

I

i

l ,

o t l ;

c cu

r

red

w

h(

n

th

{ : o

scJ

ll at

<>

r freq

u e

n cy

~

\

~

J.

and

t

h e

va

r i

a

ble

c

ap

a c

i t

or

w

as

set

at

~

~

pt

W

ha

t is

th

e

v

alu

e

o

f

<:»

f

t

h

e

to

i l '

. . . .

.

(

; } :2

00

b

) 25

4

~

.

,

\< :i

;

H 4

(d)

5

42

www.examrace.co



1

08.

c ..

{unk

n

o

v.Tl)

C

-E-

s ~

n d

ca

pa-cito

r

109.

A r

esista

n

c

e

is

m

easu

red

c

tmctc

r-amm

eter

meth

od.

The voltm

e te

r r

e·

:>

0

V

on

1

00 V

sca

le

a

nd am

met

er r

eadin

g i. i<O

m 100

rnA S

t a lc.

I f

both t

he

m e t

s e

·

,

· cNi

for

y

w ithin

2% of

full scal

e,

..

· the

lim

it wit l

1 in

w hich

res

istanc

e

ea

n

b

e

c

?

(a} lO

n

b}

2

0 n

110. A

re

sista

0

n

is

s ~

usin

g

s

ignifi

carH

c

)

4

0

~

(d

) 80 n

llgur

es

li

· r

•a ed

be lo

w :

L

l l

2.

1 0

·0 0

1.

OOOO

llO M

O

Fo he

.

ovG th

t·e< in

dicati

on

s.

whk

h o f

he

fo

w i ~

s .a

r<:n w ·

nts is

H T ~ c t

:

. . .

. .

c

j

~ .

d)

~ s e n t

g

r

e<

H

t

)

r p

n:cisi

on

than

a

nd :l

sam

e

p

r

n :; t

P

2

an

ti

n

m

s<mw p

n .•ch. i

o n

mo

re p n

:dst:

t

han

1

nne. 2

www.examrace.co



L

t ;;

5 V d

. c.

~ u p p l y is

co

n

n

et

ted acro

:;s

<

'O

m

hin ed

re

s

istarK

c

o f O O

a

nd

an unkn

ow n

re s is t

a n c

e

o

f

R

n

iu

s

er ie s. l f

a

V l

lm

cter

ha

ving

a r e s

ista n

ce of

1

·2 k n is

co

nnect

ed

lt<:ros

s HO

O

n

re

sis tor an

d

r e

ad

s

J th

e n w

h a t i

s tiH

value

o

f the re

sis t

ance

R?

(<'J

1

20

n

(h )

soo

n

c 1·7

kn

(d)

2·4 k

o

l 12 .

(.

:()nsid

er t

he

u w l n com

pon

ents;

l.

SRAM

2. E

.P ROl

\1

in

a m

icrop

roc e

ssor

.

n

l

\} :V

fcm Ul li

\ : \ i :(:

,.;

(<

:J Por

ts .

J

J

t.

As

sembl

er di

r( Ctivt

S

(

a)

PO

lU

t))

G

(<l)

1

2

www.examrace.co



1

17.

Con

s

id

er

the

f

oll

ow

i

ng:

1

.

Sm

a

ll·

a p

2

.

Fa.

sr m

e m

o

y

ac

ce

ss

:.3

.

N

c l s

r

4

.

V

er

y

o

~

T

he

e

ss

cm

;a

ch

a r

ac

te

r

i

s

tic

s

o

f a C

a

ch

e m

e

m

o

r

y in

cl

u

d

e

1,

.

2

,

s

a

nd

1

(b

)

I

, 2

a

nd

3

(

c )

I

. 2 a

n

d

4

d)

:1

a

nd

4

11:8.

An

ins

tructio

n eye {

1s.

t h e

time

in

whic

h, a

har

d·

wi

red

c

on

t

rc

)li(

:

r c

o· r

np

l(

)tC

S f

o

u

r

fu

n

c

tio

ns

.

\ ~

h a

t

the

c

o

rre

cl

se

qu

en

ce

o f

t

he

'ic

f

u

nc

t io

ns

?

(•

\

)

F< :t

d l

· u

pd

at

e -

cl

eco

de

•

u t

(h .)

F

crd

1

·

de·

c<'l

d e

-

·

0

(c

)

D

e( (

JC

c

.. e

e

tc

h ·

u

pd

m

e

(d

)

E

xe

cu te

· d

<:c

:od

e -

fe

tc

h -l.l

pc.

laH

:

11

9.

C

o u

si

dc

r t

he

fo

llo

w

in

g

fo

ur

c

o

mp

o n

e n

ts

o

d

in

the

A

L

U

of

a

co

m

p

ut

e

r

:

f

>

.,

•

l.

XO

R

gat

t:

S

2.

l i ·

3

.

~ , ; l

su

bt

ra

ct

o r

4 .

.

if

t c

Vlhi

ch

of

t

ile

ab

ov

e

co

mp

o

ner

l

j

>

m

bl

na

tio

na

l

c

i r

cu

its

>

(a)

1 :.

: • :

J a

nd

4

1 ~

:l

a

nc

l :5

(

c)

I a

nd

2

a

nd

<

12

0.

W

hi

ch

o

f th

e

~

a

re

ss

in

g

m

o

de

s i

mp

l

y 1h

a 1

t

he

o p

era

n

d

I .

re

se

pa

ra

te

ly

in

t h

e

ma

in

m

em

o

ry

?

l

.

l n

i n

~

~

~ t

2.

Im

m

ed

ia

te

3 . Inde x

S e

le

c t

•ct

a

n

sw

er

us

i ng

the

c

o

d

e g

ive

n h

e

ow

:

(

a)

1,

n

a

(h

)

1

an

d

2

·

.

(

d)

I

a

n

d

3

electrical engineering objective questions part 8

Documents