electrical engineering objective questions part 9

8/12/2019 Electrical Engineering Objective Questions Part 9

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I .S.E Pr"r-20(\(, I ol 11ELECTRIC L ENGINEERING 11

3.

Malcb Ltst-1 wilb List-11 and selec1 theton-eel answer using the o d ~ goven belowthe listsList I (Chonocter)A Colon (')B. Blank ( JC Comma(,)D Semicolon (:)Wst I I (ln terpo-et'ation)L Separmes operation and Qperand fields: Separates openmds3. Beginnlng ofc


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b. 2.5' sd. 10Wh1cl1 fJf l h ~ f ~ l l 0 1 1 n r ~ csscnt1nlw l)-systlm1 (sl of a c t ~ t a ~ q u i s i t 1 1 1 1 1

t l l lI. ADC'~ OAC3 RAM-1 l'ruccsSll5. Nerwolit CardSe il>ct lhe 1.-oo:n:d 3 1 1 5 W ~ I "l'l"-l 1 1 ~ c ) l l ~given o ' ~01 1, 1,. 1 Md 4b Jand 5

4 onlyd. I. 3 and4,A 3-phnse fully n.c.. to d cco nvener feeds a oipple Tee averng.:Co li felll 1'100 A < n d.c hlM Wllnt 1 I l l ~rms 1'81ue of current camed by eachlhyl'llill l''/a 2 A10Q.Ji Ib J3 n

100c. joJ. 100 ,.j3A single p b n ~ e doOIOrd Avoltll> high vo> illtHC wheu tbc OliiiJIthyristor s rumed off

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. 111 IIW l c l t oue of the following statements 1s< 0 1 ' 1 ' ~The peak mverse v o h a ~ , ; e ratio ? of nlhyriStvr ' n McMn Y " 'ct1cn'a. Can be as Slliall llS the forwa rd voila "drt 1 imited to f H loing PCM and lime dilisjonmu lhplc,\ iug .,, cr n duuonel , whnl is liteminimum bandwidth requinotl fur

n r n o i : S S trnns no iss10n'1a. fHzb N m ~c. liNHzd 2N fH.tThe local QSc illaiQJ' 111 a BPSK signal

d e l ~ o r a . ~ n li11ed ph:1ge error of 1(1>Tbis plmse error deteriorates tbe SN R 111L h ~ ourpul hy wlull t'acHI(Ia. 0.87b 0 7Sc. o.sd oIn a I CM 5yslem mth omiform

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from 8 to 9 wiJJ reduce the CIUantizationnoise power by which filctor'/n. qb.c.d. :

20 Ir tbe an tenna diameter In a r a d ~ r system IsIncreased by a fnccor ot: 2. the JJIO'\imumrange will be increased by what factoru. lb .j,c. 8d. 16

l L Given J224), - D),What is the vulue of the mdjx rB. tOb. 8c.. 6d. 522. Which one of the tilllowing slatemems iscorrect1If u computer haS u "un i-bus'' tlrgnni1Alliooi means tltat the computer has only onea. Data busb. i\ddre ;S busc. Control busd. lntemal bus

13 is the i n s t r u ~ c l o n counL CPI 1: the11VIlmge nhmber of system c l o c ~ periods tuex.:cute por instntction and r is thedural on o clock period. Then which oneof the lbllowlng ~ x p r e s s e s the exectniontime?a. IC CPl*rb. JCCPJ/rc. IC r /CPId. CPl .. r fiC

24. Four - i n p u l multiplexers drive u single 4inpu1 MUX. What is the result?B. 4-input MUXb. 8-input MUX12-input MUXd. 32-lnput MUX:

15 Tbe.rc are N prc>cess


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In the olrcult shown in the tigurc above.th< $11 ilch S is c l l l ~ l - d nt t ~ 0. Whidl oneof the lo llowing gives cxp[Css ion lor thevo ltage ac'f(ISS the i u d u ~ t a u c c as a func tion1f tine?q. e /2b. (1-c ') 12" ( ~ - < )

10 6010

1 0 . : .

. 1 0 ~For thl' circuit above. lhe currcmllowlng.thmtgh I n e s i ~ I O r is udjiL\k'll t


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..:. 3R utttl2Rtl. ~ R o o d 4 RIf' lilt) nud lilt) hnvc t h ~ 1\ld ths (


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Both A 1111d R are iJtdividuully trut undR is the correct explnruuion ofA.b. Bmb A lllld Rare iudivlduall) lr\le butR is no I the corr.,ct : . ~ p u n n t i o ofA-c. A is true but R is falsed. A is titlse but R is truc

5.5 Assertion (A): lnducton; carrytng steadydi.rcct currents ool as effective 5h to theonserofstrong inversiond. T h ~ sen1 iC1111ductor surfaco lit'S in the.

r u n g ~ b ~ l \ v c e n flat-band unci subthn."l'hold Cilndit ions

7 u (58. Which one-ur tho following is U1c o o r r e ~statement?

5'.1-

1be llaU coollicieut of au 11-typescmicondut.1nra. Negative snd varies witb tc.mperutu"'b. N c g a and cons llnt

~ : . o ~ ' i h v . : o n d conslltnld. l'osithe nod varies wilb temperature

Er . ~ , . m l i O i r u ~ s t r l ~ u t l n n r t l n ~ t i o n is n u ~ dli>r ruur 1liilotenl t ~ r n J l < r o t U r n ('I') liScur;es labelled I to 4.Mtuch l.ist-1 with L ~ > i - 1 1 und >t IIl. Curvc-12. Curve-23. Curvc-34, Curve-1

" 13 c I~ I 2 3 4b. l J 4 2c. 4 J 2 ld. 1 l :;

bO. Ma1ch 41st I ltb Lis1 ll and select theco rrc.:t answer 11>i11g the codu gtvCIJ belowthe Ji>ts;List IA. O w . r n l l l l l i l l t n g ~B. Curren nm, due lO co ncentru t on

g r u d i ~ n t ut' charge .mrrler>C. Rate ,,r hange orcnrriur COIIL'\ ntratiunD f; lectric lield intl nsll\ in r c r m ~ ol'charge deo)Sily 'Ust llI. Continuity cquntlfln2_ fltliSS(tll '$ t i B I J ( I n3 Finstcin eqltStiun4. Oiflitsiun C


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e. __ _ ~Itt l h ~ ubow bnnd dtagram of uShUICC: Whllt IS it1ohegc r c g t ~ u t i ul full hud. ntld HIpnwt:r fllctor laggnlbna S ub_ b%c 6 od.Whfth ()nc of l ~ t o l l l l l l \ rs tht 1 ~ 1

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field comrot ofd c. shunt motor give11. .Coou;tnut kW driveb. Cons tant torque drivec Constan t speed drived Variable load speed driveMatch Li tl witb List-11 and select theeorrecLanswer using tbe code giv en beJowthe lis ts

i r ~ : : r~ t :. '- ,,.,.,....tu,. 1Clur,._.c -. teet

urr ntList J1 (Type ofgMerntors)l Shunt

Under compoundJ Ovet compoundDifl', remains ; 1 m ~

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u I Ic. Decrease by tO%. Decreaseby 10%d Nu i ncrease, No iucreaseAo under-excited synchronous motor isopermiug at n.o load on an illfiuile bus orV >llage 1-0 p.u. and dra.wing a eun-ent of0$ 11.u Its sy11chronous retJctance is QSp.u What Is Ue p.u. value of hs excitatio tlem ?8 . f.4b. I 0c. 0,6d. 0,4Match I isH IVith l, isr-11 and select thecorrecr answer using thecode given belowthe lists:List I Motor)A l-lystcresos rno rorB Shaded -po le rno rorC r a n c c mororD, Univer.sal mQiorList H (Application II l'hotocopym.g maohi ne2. Phonograph tum tableElectric Shaver4 Record playerA ll C 0a.hC,d.

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2424JJIFlow is the magnetic fi eld dH from a shansec tion dl of a cu rrool carrying wire, givenby Biot-Savnn s taw expressed'/

a. t i f f= mLJ trrb. dlf= JD/,sin0 / 4rrrc. t/H = n ,sin0 / 4rrr1d. dH = tr11f.sino 4;rrII potential field is given byV x1j - y:-Which one of the following expresses anelectriC' field at P(Z;-1 ,4)7a. 12i-s.ih J i i

' . -c, IJI-SJ+kd n i- )-kWhich one of rhe fo ll owing h not ~ (

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"- Equat ion ~ 0 - s\- 1' ) : p, mAy b(:1Cgarded : A" oissuu s el' binary digits). P,=power of the ~ i n l l l l o i d s ingle Aeos 01 tthen.what is lbe BJ'>SK oulput1

b ( l ) f , c o ~ mb.. IJ{t),[i>;cvsl'''e, C )J2P. I I ~ /< . o t)..fi01>9ml

81. In l'CM s ~ ' l e m with unilormIU31lization. t 3 S i J the tlUtbCI tJf b i L ~from 8 to Hl will inc1."lllle the s1gonl toJtlllllt ~ t i o n o i ~ e nuio by which li1cLOr?

d. 1.2Sb. 8... 10d. 16

1 Jtl483. \VJtich one of lhe o w i n ~ i c o r r c ~SU11ement?ln a Dtvl m the m n ofowrload inet\i4se wboolL Modulllting n l l l dtllDg"" rapidlyb. Modulating g I rt:mai1 'c. Pule amplitudl "' increasedd l>ul4ie rate ncreased84. Whiclt 0 e of t ~ c : fll llowing nol lliO ilt:rl)' Qf a u t i J c Q r r e l o t i Ulllelion(R(r)l 'la. R ( O ) ~ R ( r )b. l


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c : To Cl1CI) serihl data s1gnalsd. To syndtm1uzc events in various pam;

o f r h e ~ - y s u : m\\ tidt ooe ar be followilll is cxecm>d bya s i m p ~ ~ d d i i i O n .,ran ltWc:rtllr ro 1111 S ~lhp flop11. D-f11p flopb J.f' ntp flopc '.huu:rsiQw f11p flopd ffllp flOpflow 1111111) 4-fnpllt MUX u r ~ need,'< tomtplc:mcnr a S6-mp111 MliX"' Hnw mN hy

e l ~ wallthCI'C be"a. 8 1b 85 , 5c. 80 . ..d. .21 , 3

:: - - - - - - - ' D r - - - - ~~,- ____ ..JCom;Jdet the lostc cmull sbowll. w J1eliguregi\l:tl above. The functions r f1 andf (in canorucal 311Jll of prodncts fonn indirimal notatiou) 11te} j( II.XJ ', - ) = ) , 9,10( , ( II'.X. ) .:- ) =I 7_8.1 1.13,.14.15.f,( .."l-,1.:)=- ~ ) . 9\Vnidt ooe of he following is the limctionf.?n ~ ) . t ob ~ c I r.s.9d ~

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c Q : ~ ~ J ~For the logtc circmt shown m the tigtJroabove. whn1 IS the outpul ) equmto'la. ABI- -c. B PC.. ABd. All of he above

I I nt I93. ln the fabricauon of 11 pn junction. on ntypesubstrate. r.he processes involved nre

I D i t ' l l ~ i 1 1 1 1l ~ d n 1 1 1 1 n3 L h o l ) 1 1 l p h ~4 1-letalltzntionWhu t fs U t ~ ClliTI:tl sequ'llce m wtuchihcse l ' ( ) l . ' e ~ ~ s e s 81'1: carried out?n. 2 3-4 Ib 4-2-1- 3c. 2-4-3- 1d 2- 3- 1-1

1)4, Thn:c mput NAND jtRte is to be used ns nuIn e t 1 ~ Which nut M r h ~ rollowi ngmeasures i l l achieve tbis eud bell'a. All m p h t ~ nre d b a c(13) used?3. 3%b. s ~ c. 10 tl 16'%96, The outpu t response of a de amplifier to astep lnpw silO"S 35 ns me Utili Wbar ishs ~ n d w i nearly eqmltoa. I Mi ll.b 35 MHze. 10 Mll7d 35 Mllz

'17. C o ~ i d c r the follllWtnl( l l l l ' t n ~ n t t i1 Comtnou-dJuut omtJltfler os called

50 lt follower.~ Jl()( Vet)' lnr ;e R5 (tne resasruncecwnn.:ctcd b.:t" ecto source alld l fO\tud1ill.- OUiput impedance of 4 sotorcc

fO IIOWT oquul to t1SS'l3 The input impcdan"' of a commong81: flmplilk-r lowWinch ofrlle SlllletDflllS giveq above tslnrdcorrcct1a. I onlyb I 1111d 2. onlyc. 2 and 3,. only

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IJ 12tU\d3Co tJSidi r he iollowir1g stu l lncrus inconm.'Ction wi tll rmns istur umplifrers inclass aand c:lass AB rnodeI In tile e l l i S . ~ l i for luw signu l m g e t ~ ~the base. tbt coll.XIIIt current" Ll. tu., In Lhc cluss B. ther" 1S cross-over

distortion:1 In the class AB wilh no s1gnul 1hc depower drawn as zero .Wl11ch or the stat< rnents above nreCtlrretl'.'U 1. 1Md3b I tutd 2.. lltll)c. 2 and J. onlyd. I and 3. onlyCo tl )lder he fo llowmg Slfltementsregard1ng t r J n s t ~ o ~ Compared 10 11,lunctton lrllllSt&tor. n FE'fI 1 1 ~ tl large g111n b;tndwodth product2 I> less ntsy3, Has less mpu t raststance''W1uc.hof the Sl< temcnts gtven above IS/un:currecl' 'a. 1onlyb I nnd 3, onl

2 onlyd 1, 2nnd3A Zen.:r regulator has un tnpU vollag.:frlltn 15 V tl 20 Vand a load currem lrom10 rnA to 20 mA. I f he Zener voltage is 5V wlmt os the V1tlue of U1e n raststance' Assume I ,,1, = t))2sonb soon1 . 750il.d 15()(\0tvl:.ttb Lllltl (Diugt11J11 uf Ctn:M) WtlllLost- t Name of the Circuli) and selc>ctthecorn:ct ULSWt< L ~ t n g the code govun b


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R ~ _ 2 L _ I C(s)----::\. s(s+ 5) 1

\Vhm are che values of un droped llalura lfrequency and damping m1io res peclivelyfor loe syslem shown in the figul'e abo ve?a 5and05b, 25 and 0 5I Sand ld Ill and 0.5

I0(, Match the relollonshrp of Items given mLosll (Medtum) wi1h the Lost ll1Bxpressioo for lulnusoc Impedance) andselect the correct answer 1g t he codegiVen below:All sy mlx1ls bavc their usual m e a n i n ~List IA rreespaeca Perfect die lectricC. Partially conducuog mrdium[) C'onduc hngM ediUmListlll fF - 452l .

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I07, Matoh Lis -1 wlh L1st-ll and select thecorrect answer usiJlS .U1e code gi vcn be lowthe hstsLi SL l (Parameter)A Re flecllon coefficoent nl inpmB. VSWRC Input ompedaoceD l'hase shifi magnitude

II (Rnn geofvnlues)I Oto '1 . l to oc

IJ u[ JlJ . - 1 to I I4 0 to 2/TA B c Da. I 2 4b I 3 2c. 3 1 4 2d 3 2 1 4108 Wh1ch one of 1he fo llowmg is the correctexpression for the speci.lio speed n m rpn,

of a hydro power station furbwe al n rpm,Working for a head of h me ters andproducing r kwa. , = nJP) 1b = 0 sss(nJJ.i)1 1c. 11, - U65(nJP)1d. None of the above

I09 Whtch rme of the fo llowtng 1$ the correcLstatement?

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The elef u trailsJTiiSS10ri line forelectricpowera. Is non-zero eonslam f r < ~ m centre toconductor radius Ru. Is Le1o at the centre but nses very ho .IJut h conililctor out r surfacec. Undergoes a hnear nse from zero atcenlle to u umtc valueat the conductorradio

d Undergoes a linear decline' from atUlilc value at the centre to w ro HtJ1econductor ruruusIJ be power transmJssion I ne is mode ledS() as to telltcUm sending end vollsge v.and current t, \('the receJving end t ~ eV and current 1 by the relaoonsl11p1', ~ I, ~ l , -t-Df ,;Then which one of the l'ollowrnge.xpressesthe outpu1 unpedaorce of 1he lransmissiona D I 0 1 C 1 Af,)b cl: - AI ,)r(IJV,TAl)c. (DV,- CI, )I(DI ' - 111 ,)d. (D v; -/11,)1(.-'IJ',+ /)1 )Tn the [oad-ilo\v study ofa power system.one o d ~ rs selec1oo as ..slack" orfloa tin ,. bus-bar whtch lmpp lies he lossesin lbe network.

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Wltich one of lhe following is lhe COn'Cillo l.atement'l11te e r i s Oflhc '' siol l 1 t i o 1 1:ind lnvcrlenuttion are und< r;1. Consl:lnt"un-enL onltol individllllU)'b. C o l 5 ~ 1 extinction angle controlIndividually.:. Constant i n c t i ~ n angle '()nlrOI nnd

U t n t cum:ut oo uO 'OI c : , ~ p ~ c td. Constant cun'

electrical engineering objective questions part 9

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