practical geometry
TRANSCRIPT
Ch 4Practical Geometry
Lecture 4
Question of the day!
Veena who is the sister-in-law of Ashok, is the daughter-in-law of Kalyani. Dheeraj is the father of Sudeep who is the only brother of Ashok. How Kalyani is related to Ashok?
A. Mother-in-lawB. AuntC. WifeD. None of these
Solution:-
Answer: Option D
Explanation:
Ashok is the only brother of Sudeep and
Veena is the sister-in-law of Ashok. Hence
Veena is the wife of Sudeep. Kalyani is the
mother-in-law of Veena. Kalyani is the
mother of Ashok.
HomeworkSailors
xxx
Heeba , Sudhiksha, Joel,
Divgun, Sanya Harshita,
Jeshika, Harshita, Sudi,
Amber, Bhavana,
● When four sides and one diagonal are given.
● When two diagonals and three sides are given.
● When two adjacent sides and three angles are given.
● When three sides and two included angles are given.
● When other special properties are known.
Constructing a Quadrilateral
Construction of a Square
Construct a square with side 5ccm
Steps:
Step 1: Draw a line segment PQ of 5 cm.
Step 2: With the help of compass draw 90 degree angle at P.
Step 3: With the help of compass draw 90 degree angle at Q.
Step 4: Use compass and 5 cm wide open. With P as center, draw an arc; which cuts arms of 90 degree angle. And mark point of intersection as S.
Step 5: Use ruler and measure length of SP. Length of SP should be 5 cm and we get:
Step 6: Again Use compass and 5 cm wide open. With Q as center, draw an arc; which cuts arms of 90 degree angle. And mark point of intersection as R.
Step 7: Use ruler and measure length of RQ. Length of RQ should be 5 cm and we get:
Step 8: Join points S & R.
we get resultant square PQRS:
Construction of a Rhombus
Construct a rhombus ABCD in which diagonal AC = 8 cm and diagonal BD = 6.2 cm.
Steps:
➢ Draw line segment AC = 8 cm.
➢ Draw the perpendicular bisector of AC.
➢ With O as the centre and radius =3.1 cm, mark arcs on both the sides of AC to intersect its perpendicular bisector. Mark the points of intersection as B and D.
➢ Join points A, D, points C, D, points C, B, and points B, A.
➢ ABCD is the required rhombus.
Question:
A rhombus whose diagonals are 5.2 cm and 6.4 cm long.
Solution:
Step I: Draw AC = 6.4 cm.
Step II: Draw the right bisector of AC at E.
Step III: Draw two arcs with centre E and radius
= 5.2/2 = 2.6 cm to cut the previous diagonal at B and D.
Step IV: Join AD, AB, BC and DC.
Thus ABCD is the required rhombus.
A rectangle with adjacent sides of lengths 5 cm and 4 cm.
Construction of a Rectangle
Solution:
Step I: Draw PQ = 5 cm.
Step II: Draw an angle of 90° at Q and cut QR = 4 cm.
Step III: Draw an arc with centre R and radius 5 cm.
Step IV: Draw another arc with centre P and radius 4 cm to meet the previous arc at S.
Step V: Join RS and PS.
Thus, PQRS is the required rectangle.
A parallelogram OKAY where OK = 5.5 cm and KA = 4.2 cm. Is it unique?
Construction of a parallelogram
Solution:
Step I: Draw OK = 5.5 cm.
Step II: Draw an angle of any measure (say 60°) at K and cut KA = 4.2 cm.
Step III: Draw an arc with centre A and radius of 5.5 cm.
Step IV: Draw another arc with centre O and radius 4.2 cm to cut the previous arc at Y.
Step V: Join AY and OY.
Thus, OKAY is the required parallelogram.
No, it is not a unique parallelogram. The angle at K can be of measure other than 60°.
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Question of the day!
JUNE Month● Blood relation● Direction sense Test
Comment and tell your answers after
the session
Question of the day!One morning Udai and Vishal were talking to each other face to face at a crossing. If Vishal's shadow was exactly to the left of Udai, which direction was Udai facing?
A. EastB. WestC. NorthD. South
Tomorrow’s scheduleClass 7 - 2:00 pm
Data Handling - Doubt + MENTI
Class 8 - 3 :00 pmFind Mistakes in the constructions
done by Sana ma’am
