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FOR SCIENTISTS AND ENGINEERS A STRATEGIC APPROACH 4/E PHYSICS RANDALL D. KNIGHT Chapter 15 Lecture © 2017 Pearson Education, Inc.

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Page 1: Chapter 15 Lecture - Faculty/Staff Websites & Bios

FOR SCIENTISTS AND ENGINEERS A STRATEGIC APPROACH 4/E PHYSICS

RANDALL D. KNIGHT

Chapter 15 Lecture

© 2017 Pearson Education, Inc.

Page 2: Chapter 15 Lecture - Faculty/Staff Websites & Bios

© 2017 Pearson Education, Inc.

Chapter 15 Oscillations

IN THIS CHAPTER, you will learn about systems that oscillate in simple harmonic motion.

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Chapter 15 Preview

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Chapter 15 Preview

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Chapter 15 Preview

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Chapter 15 Preview

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Chapter 15 Preview

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Chapter 15 Preview

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Chapter 15 Reading Questions

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A “sinusoidal” function of x can be represented by

A. cos(x)

B. sin(x)

C. tan(x)

D. Either A or B.

E. Either A, B or C.

Reading Question 15.1

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A “sinusoidal” function of x can be represented by

Reading Question 15.1

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A. cos(x)

B. sin(x)

C. tan(x)

D. Either A or B. E. Either A, B or C.

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What is the name of the quantity represented by the symbol ω?

A. Angular momentum

B. Angular frequency

C. Phase constant

D. Uniform circular motion

E. Centripetal acceleration

Reading Question 15.2

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What is the name of the quantity represented by the symbol ω?

A. Angular momentum

B. Angular frequency

C. Phase constant

D. Uniform circular motion

E. Centripetal acceleration

Reading Question 15.2

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What is the name of the quantity represented by the symbol ϕ0?

A. Angular momentum

B. Angular frequency

C. Phase constant

D. Uniform circular motion

E. Centripetal acceleration

Reading Question 15.3

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What is the name of the quantity represented by the symbol ϕ0?

A. Angular momentum

B. Angular frequency

C. Phase constant D. Uniform circular motion

E. Centripetal acceleration

Reading Question 15.3

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Wavelength is

A. The time in which an oscillation repeats itself.

B. The distance in which an oscillation repeats itself.

C. The distance from one end of an oscillation to the other.

D. The maximum displacement of an oscillator.

E. Not discussed in Chapter 15.

Reading Question 15.4

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Wavelength is

A. The time in which an oscillation repeats itself.

B. The distance in which an oscillation repeats itself.

C. The distance from one end of an oscillation to the other.

D. The maximum displacement of an oscillator.

E. Not discussed in Chapter 15.

Reading Question 15.4

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What term is used to describe an oscillator that “runs down” and eventually stops?

A. Tired oscillator

B. Out of shape oscillator

C. Damped oscillator

D. Resonant oscillator

E. Driven oscillator

Reading Question 15.5

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What term is used to describe an oscillator that “runs down” and eventually stops?

A. Tired oscillator

B. Out of shape oscillator

C. Damped oscillator D. Resonant oscillator

E. Driven oscillator

Reading Question 15.5

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Chapter 15 Content, Examples, and QuickCheck Questions

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Oscillatory Motion

Objects that undergo a repetitive motion back and forth around an equilibrium position are called oscillators.

The time to complete one full cycle, or one oscillation, is called the period T.

1 Hz = 1 cycle per second = 1 s–1

The number of cycles per second is called the frequency f, measured in Hz:

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Simple Harmonic Motion

A particular kind of oscillatory motion is simple harmonic motion.

In the figure an air-track glider is attached to a spring.

The glider’s position measured 20 times every second.

The object’s maximum displacement from equilibrium is called the amplitude A of the motion.

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QuickCheck 15.1

D. A and B but not C. E. None are.

Which oscillation (or oscillations) is SHM?

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QuickCheck 15.1

D. A and B but not C. E. None are.

Which oscillation (or oscillations) is SHM?

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Simple Harmonic Motion

The top image shows position versus time for an object undergoing simple harmonic motion.

The bottom image shows the velocity versus time graph for the same object.

The velocity is zero at the times when x = ± A; these are the turning points of the motion.

The maximum speed vmax is reached at the times when x = 0.

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Simple Harmonic Motion

If the object is released from rest at time t = 0, we can model the motion with the cosine function:

Cosine is a sinusoidal function.

ω is called the angular frequency, defined as

ω = 2π/T

The units of ω are rad/s:

ω = 2πf

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Simple Harmonic Motion

The maximum speed is vmax = ωA

The position of the oscillator is

Using the derivative of the position function, we find the velocity:

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Example 15.1 A System in Simple Harmonic Motion

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Example 15.1 A System in Simple Harmonic Motion

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Example 15.1 A System in Simple Harmonic Motion

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Example 15.2 Finding the Time

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Simple Harmonic Motion and Circular Motion

Figure (a) shows a “shadow movie” of a ball made by projecting a light past the ball and onto a screen.

As the ball moves in uniform circular motion, the shadow moves with simple harmonic motion.

The block on a spring in figure (b) moves with the same motion.

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The Phase Constant

What if an object in SHM is not initially at rest at x = A when t = 0?

Then we may still use the cosine function, but with a phase constant measured in radians.

In this case, the two primary kinematic equations of SHM are:

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Oscillations described by different values of the phase constant.

The Phase Constant

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Example 15.3 Using the Initial Conditions

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Example 15.3 Using the Initial Conditions

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Example 15.3 Using the Initial Conditions

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Example 15.3 Using the Initial Conditions

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QuickCheck 15.2

A. –π/2 rad B. 0 rad C. π/2 rad D. π rad E. None of these

This is the position graph of a mass oscillating on a horizontal spring. What is the phase constant ϕ0?

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QuickCheck 15.2

Initial conditions: x = 0 vx > 0

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A. –π/2 rad B. 0 rad C. π/2 rad D. π rad E. None of these

This is the position graph of a mass oscillating on a horizontal spring. What is the phase constant ϕ0?

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QuickCheck 15.3

This is the position graph of a mass oscillating on a horizontal spring. What is the phase constant ϕ0?

A. –π /2 rad B. 0 rad C. π /2 rad D. π rad E. None of these

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QuickCheck 15.3

Initial conditions: x = –A vx = 0

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This is the position graph of a mass oscillating on a horizontal spring. What is the phase constant ϕ0?

A. –π /2 rad B. 0 rad C. π /2 rad D. π rad E. None of these

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QuickCheck 15.4

The figure shows four oscillators at t = 0. For which is the phase constant ϕ0 =–π /4?

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QuickCheck 15.4

The figure shows four oscillators at t = 0. For which is the phase constant ϕ0 =–π /4?

Initial conditions: x = 0.71A vx > 0

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Energy in Simple Harmonic Motion

An object of mass m on a frictionless horizontal surface is attached to one end of a spring of spring constant k.

The other end of the spring is attached to a fixed wall.

As the object oscillates, the energy is transformed between kinetic energy and potential energy, but the mechanical energy E = K + U doesn’t change.

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Energy in Simple Harmonic Motion

Energy is conserved in Simple Harmonic Motion:

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QuickCheck 15.5

A block oscillates on a very long horizontal spring. The graph shows the block’s kinetic energy as a function of position. What is the spring constant?

A. 1 N/m B. 2 N/m C. 4 N/m D. 8 N/m E. I have no idea.

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QuickCheck 15.5

A block oscillates on a very long horizontal spring. The graph shows the block’s kinetic energy as a function of position. What is the spring constant?

A. 1 N/m B. 2 N/m C. 4 N/m D. 8 N/m E. I have no idea.

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Frequency of Simple Harmonic Motion

In SHM, when K is maximum, U = 0, and when U is maximum, K = 0.

K + U is constant, so Kmax = Umax:

Earlier, using kinematics, we found that

So

So

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QuickCheck 15.6

A mass oscillates on a horizontal spring with period T = 2.0 s. If the amplitude of the oscillation is doubled, the new period will be

A. 1.0 s

B. 1.4 s

C. 2.0 s

D. 2.8 s

E. 4.0 s

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QuickCheck 15.6

A mass oscillates on a horizontal spring with period T = 2.0 s. If the amplitude of the oscillation is doubled, the new period will be

A. 1.0 s

B. 1.4 s

C. 2.0 s

D. 2.8 s

E. 4.0 s

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QuickCheck 15.7

A block of mass m oscillates on a horizontal spring with period T = 2.0 s. If a second identical block is glued to the top of the first block, the new period will be

A. 1.0 s

B. 1.4 s

C. 2.0 s

D. 2.8 s

E. 4.0 s

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QuickCheck 15.7

A block of mass m oscillates on a horizontal spring with period T = 2.0 s. If a second identical block is glued to the top of the first block, the new period will be

A. 1.0 s

B. 1.4 s

C. 2.0 s

D. 2.8 s

E. 4.0 s

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QuickCheck 15.8

Two identical blocks oscillate on different horizontal springs. Which spring has the larger spring constant?

A. The red spring

B. The blue spring

C. There’s not enough information to tell.

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QuickCheck 15.8

Two identical blocks oscillate on different horizontal springs. Which spring has the larger spring constant?

A. The red spring

B. The blue spring

C. There’s not enough information to tell.

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Example 15.4 Using Conservation of Energy

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Example 15.4 Using Conservation of Energy

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Example 15.4 Using Conservation of Energy

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Simple Harmonic Motion Motion Diagram

The top set of dots is a motion diagram for SHM going to the right.

The bottom set of dots is a motion diagram for SHM going to the left.

At x = 0, the object’s speed is as large as possible, but it is not changing; hence acceleration is zero at x = 0.

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Acceleration in Simple Harmonic Motion

Acceleration is the time-derivative of the velocity:

In SHM, the acceleration is proportional to the negative of the displacement.

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Dynamics of Simple Harmonic Motion

Consider a mass m oscillating on a horizontal spring with no friction.

The spring force is

Since the spring force is the net force, Newton’s second law gives

Since ax = –ω2x, the angular frequency must be .

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QuickCheck 15.9

A mass oscillates on a horizontal spring. It’s velocity is vx and the spring exerts force Fx. At the time indicated by the arrow,

A. vx is + and Fx is +.

B. vx is + and Fx is –.

C. vx is – and Fx is 0.

D. vx is 0 and Fx is +.

E. vx is 0 and Fx is –.

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QuickCheck 15.9

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A mass oscillates on a horizontal spring. It’s velocity is vx and the spring exerts force Fx. At the time indicated by the arrow,

A. vx is + and Fx is +.

B. vx is + and Fx is –.

C. vx is – and Fx is 0.

D. vx is 0 and Fx is +.

E. vx is 0 and Fx is –.

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A. vx is + and Fx is +.

B. vx is + and Fx is –.

C. vx is – and Fx is 0.

D. vx is 0 and Fx is +.

E. vx is 0 and Fx is –.

QuickCheck 15.10

A mass oscillates on a horizontal spring. It’s velocity is vx and the spring exerts force Fx. At the time indicated by the arrow,

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QuickCheck 15.10

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A. vx is + and Fx is +.

B. vx is + and Fx is –.

C. vx is – and Fx is 0.

D. vx is 0 and Fx is +.

E. vx is 0 and Fx is –.

A mass oscillates on a horizontal spring. It’s velocity is vx and the spring exerts force Fx. At the time indicated by the arrow,

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Vertical Oscillations

Motion for a mass hanging from a spring is the same as for horizontal SHM, but the equilibrium position is affected.

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Example 15.6 Bungee Oscillations

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Example 15.6 Bungee Oscillations

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Example 15.6 Bungee Oscillations

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QuickCheck 15.11

A. Negative.

B. Zero.

C. Positive.

A block oscillates on a vertical spring. When the block is at the lowest point of the oscillation, it’s acceleration ay is

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QuickCheck 15.11

A. Negative.

B. Zero.

C. Positive.

A block oscillates on a vertical spring. When the block is at the lowest point of the oscillation, it’s acceleration ay is

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The Simple Pendulum

Consider a mass m attached to a string of length L which is free to swing back and forth.

If it is displaced from its lowest position by an angle θ, Newton’s second law for the tangential component of gravity, parallel to the motion, is

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The Simple Pendulum

If we restrict the pendulum’s oscillations to small angles (< 10º), then we may use the small angle approximation sin θ ≈ θ, where θ is measured in radians.

and the angular frequency of the motion is found to be

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Example 15.7 The Maximum Angle of a Pendulum

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Example 15.7 The Maximum Angle of a Pendulum

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QuickCheck 15.12

A. 1.0 s

B. 1.4 s

C. 2.0 s

D. 2.8 s

E. 4.0 s

A ball on a massless, rigid rod oscillates as a simple pendulum with a period of 2.0 s. If the ball is replaced with another ball having twice the mass, the period will be

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QuickCheck 15.12

A. 1.0 s

B. 1.4 s

C. 2.0 s

D. 2.8 s

E. 4.0 s

A ball on a massless, rigid rod oscillates as a simple pendulum with a period of 2.0 s. If the ball is replaced with another ball having twice the mass, the period will be

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QuickCheck 15.13

A. 1.0 s B. 1.4 s C. 2.0 s D. 2.8 s E. 4.0 s

On Planet X, a ball on a massless, rigid rod oscillates as a simple pendulum with a period of 2.0 s. If the pendulum is taken to the moon of Planet X, where the free-fall acceleration g is half as big, the period will be

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QuickCheck 15.13

A. 1.0 s B. 1.4 s C. 2.0 s D. 2.8 s E. 4.0 s

On Planet X, a ball on a massless, rigid rod oscillates as a simple pendulum with a period of 2.0 s. If the pendulum is taken to the moon of Planet X, where the free-fall acceleration g is half as big, the period will be

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The Simple-Harmonic-Motion Model

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The Physical Pendulum

Any solid object that swings back and forth under the influence of gravity can be modeled as a physical pendulum.

The gravitational torque for small angles (θ < 10º) is

Plugging this into Newton’s second law for rotational motion, τ = Iα, we find the equation for SHM, with

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Example 15.9 A Swinging Leg as a Pendulum

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Example 15.9 A Swinging Leg as a Pendulum

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Example 15.9 A Swinging Leg as a Pendulum

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QuickCheck 15.14

A. The solid disk B. The circular hoop C. Both have the same period. D. There’s not enough information to tell.

A solid disk and a circular hoop have the same radius and the same mass. Each can swing back and forth as a pendulum from a pivot at one edge. Which has the larger period of oscillation?

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QuickCheck 15.14

A. The solid disk B. The circular hoop C. Both have the same period. D. There’s not enough information to tell.

A solid disk and a circular hoop have the same radius and the same mass. Each can swing back and forth as a pendulum from a pivot at one edge. Which has the larger period of oscillation?

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Damped Oscillations An oscillation that runs down

and stops is called a damped oscillation.

The shock absorbers in cars and trucks are heavily damped springs.

The vehicle’s vertical motion, after hitting a rock or a pothole, is a damped oscillation.

One possible reason for dissipation of energy is the drag force due to air resistance.

The forces involved in dissipation are complex, but a simple linear drag model is

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Damped Oscillations

When a mass on a spring experiences the force of the spring as given by Hooke’s Law, as well as a linear drag force of magnitude |Fdrag| = bv, the solution is

where the angular frequency is given by

Here is the angular frequency of the undamped oscillator (b = 0).

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Damped Oscillations

Position-versus-time graph for a damped oscillator.

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Damped Oscillations

A damped oscillator has position x = xmaxcos(ωt + ϕ0), where

This slowly changing function xmax provides a border to the rapid oscillations, and is called the envelope.

The figure shows several oscillation envelopes, corresponding to different values of the damping constant b.

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Mathematical Aside: Exponential Decay

Exponential decay occurs in a vast number of physical systems of importance in science and engineering.

Mechanical vibrations, electric circuits, and nuclear radioactivity all exhibit exponential decay.

The graph shows the function:

where • e = 2.71828… is

Euler’s number. • exp is the

exponential function. • v0 is called the decay constant.

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Energy in Damped Systems

Because of the drag force, the mechanical energy of a damped system is no longer conserved.

At any particular time we can compute the mechanical energy from

Where the decay constant of this function is called the time constant τ, defined as

The oscillator’s mechanical energy decays exponentially with time constant τ.

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Driven Oscillations and Resonance Consider an oscillating system that, when left to itself,

oscillates at a natural frequency f0. Suppose that this system is subjected to a periodic

external force of driving frequency fext. The amplitude of oscillations is generally not very high

if fext differs much from f0. As fext gets closer and closer to f0, the amplitude of the oscillation rises dramatically.

A singer or musical instrument can shatter a crystal goblet by matching the goblet’s natural oscillation frequency.

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Driven Oscillations and Resonance

The response curve shows the amplitude of a driven oscillator at frequencies near its natural frequency of 2.0 Hz.

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Driven Oscillations and Resonance

The figure shows the same oscillator with three different values of the damping constant.

The resonance amplitude becomes higher and narrower as the damping constant decreases.

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QuickCheck 15.15

A. The red oscillator

B. The blue oscillator

C. The green oscillator

D. They all oscillate for the same length of time.

The graph shows how three oscillators respond as the frequency of a driving force is varied. If each oscillator is started and then left alone, which will oscillate for the longest time?

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QuickCheck 15.15

A. The red oscillator B. The blue oscillator

C. The green oscillator

D. They all oscillate for the same length of time.

The graph shows how three oscillators respond as the frequency of a driving force is varied. If each oscillator is started and then left alone, which will oscillate for the longest time?

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Chapter 15 Summary Slides

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Page 99: Chapter 15 Lecture - Faculty/Staff Websites & Bios

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General Principles

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Page 100: Chapter 15 Lecture - Faculty/Staff Websites & Bios

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General Principles

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Important Concepts

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Important Concepts

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Applications

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Page 104: Chapter 15 Lecture - Faculty/Staff Websites & Bios

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Applications

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