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HST Mr. Watson Chapter 1 Chapter 1 Chemistry and Measurement

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Chapter 1. Chemistry and Measurement. Chemistry. What is it? Why do we study it?. Physical States. solid fixed volume and shape liquid fixed volume shape of container, horizontal top surface gas takes shape and volume of container liquid crystal - PowerPoint PPT Presentation

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Page 1: Chapter 1

HSTMr. Watson

Chapter 1Chapter 1

Chemistry and

Measurement

Page 2: Chapter 1

HSTMr. Watson

ChemistryChemistry

What is it?Why do we study it?

Page 3: Chapter 1

HSTMr. Watson

Physical States Physical States

solid– fixed volume and shape

liquid– fixed volume– shape of container, horizontal top surface

gas– takes shape and volume of container

liquid crystal– some characteristics of solid and some of liquid states

Page 4: Chapter 1

HSTMr. Watson

Modern Chemistry: Modern Chemistry: A Brief GlimpseA Brief Glimpse

Page 5: Chapter 1

HSTMr. Watson

Air Bags: How Do They Work?Air Bags: How Do They Work?

http://whyfiles.news.wisc.edu/032air_bag/how_work.html

Page 6: Chapter 1

HSTMr. Watson

Science and the Ozone LayerScience and the Ozone Layer

For more information about the Ozone Layer: Ozone Depletion

– http://www.epa.gov/ozone/

Thickness of ozone layer– http://jwocky.gsfc.nasa.gov/teacher/ozone_overhead.html

Memphis: +35 latitude -90 longitude

Page 7: Chapter 1

HSTMr. Watson

MatterMatter

has massmass vs. weightoccupies space

Page 8: Chapter 1

HSTMr. Watson

Scientific MethodScientific MethodExperimentResultsHypothesis

– further experiments– refine the hypothesis

Theory– experiments to test the theory– refine the theory

Page 9: Chapter 1

HSTMr. Watson

Law of Conservation of MassLaw of Conservation of Mass

In an ordinary chemical reaction matter is neither created nor destroyed.

The sum of the masses of the reactants equals the sum of the masses of the products.

Page 10: Chapter 1

HSTMr. Watson

Properties of MatterProperties of Matter

Extensive Property depends on specific

sample under investigation

examples:– mass and volume

Intensive Property identical in all samples

of the substance examples:

– color, density, melting point, etc.

Page 11: Chapter 1

HSTMr. Watson

Physical PropertyPhysical Property

one that can be observed without changing the substances present in the sample

changes in physical properties of substances

Page 12: Chapter 1

HSTMr. Watson

Chemical PropertyChemical Property

the tendency to react and form new substances

Page 13: Chapter 1

HSTMr. Watson

Chemical ReactionChemical Reaction

reactants undergo chemical change to produce products

sucrose ---> carbon + water

reactant products

Page 14: Chapter 1

HSTMr. Watson

Chemical ReactionChemical Reaction

Reactions are indicated by:evolution of a gaschange of colorformation of a precipitate

Page 15: Chapter 1

HSTMr. Watson

Law of Definite ProportionsLaw of Definite Proportions

All samples of the same pure substance always contain the same elements in the same proportions by weight

Page 16: Chapter 1

HSTMr. Watson

Pure SubstancesPure Substances

Elements

Compounds

Page 17: Chapter 1

HSTMr. Watson

MixturesMixtures

Heterogeneousuneven texture

Homogeneous (Solution)sample uniform throughout

Page 18: Chapter 1

HSTMr. Watson

Page 19: Chapter 1

HSTMr. Watson

Separation of MixturesSeparation of Mixtures

filtrationdistillationchromatography

Page 20: Chapter 1

HSTMr. Watson

FiltrationFiltration

separate solids by differences in melting points

separate solids by differences in solubility (fractional crystallization)

mechanical separation such as in Fig. 1.11 page 13.

Page 21: Chapter 1

HSTMr. Watson

DistillationDistillation

separation by differences in boiling point (fractional distillation)– distillate– distillation

fractionating column - part of apparatus where separation occurs

Page 22: Chapter 1

HSTMr. Watson

Page 23: Chapter 1

HSTMr. Watson

ChromatographyChromatography

liquid-columnpaperthin-layer (TLC)gasHPLCelectrophoresis (DNA mapping)

Page 24: Chapter 1

HSTMr. Watson

Column ChromatographyColumn Chromatography

Page 25: Chapter 1

HSTMr. Watson

Paper Chromatography of Paper Chromatography of InksInks

Page 26: Chapter 1

HSTMr. Watson

Page 27: Chapter 1

HSTMr. Watson

Uncertainty in MeasurementsUncertainty in Measurements

Accuracy

closeness to true value

vs

Precision

reproducibility

Page 28: Chapter 1

HSTMr. Watson

Accurate and/or Precise?

Page 29: Chapter 1

HSTMr. Watson

Accurate and/or Precise?

Page 30: Chapter 1

HSTMr. Watson

Significant FiguresSignificant FiguresRules for determining which digits are significant: All non-zero numbers are significant Zeros between non-zero numbers are significant Zeros to the right of the non-zero number and to

the right of the decimal point are significant Zeros before non-zero numbers are not significant

Page 31: Chapter 1

HSTMr. Watson

Significant FiguresSignificant FiguresExamples:Examples:

Railroad Track Scale70,000,000 g + 500,000 g

7.00 x 107 g (scientific notation)

7.00 E7 g (engineering notation)

3 significant figures

Page 32: Chapter 1

HSTMr. Watson

Significant FiguresSignificant FiguresExamples:Examples:

Regular Lab Balance 1,000 g + 0.1 g

1.0000 x 103 g5 sig. fig.

400 g + 0.01 g4.0000 x 102 g

5 sig. fig.100 + 0.001 g

1.00000 x 102 g6 sig.fig.

Page 33: Chapter 1

HSTMr. Watson

Rules for MathematicsRules for MathematicsMultiplication and DivisionMultiplication and Division

For multiplication and division, the number of significant figures used in the answer is the number in the value with the fewest significant figures.

2 sig.fig.; 3 sig. fig. => 2 sig. fig.4 sig. fig.;

= 2.0 x 102(2075)*(14)

----------------

(144)

Page 34: Chapter 1

HSTMr. Watson

Rules for MathematicsRules for MathematicsAddition and SubtractionAddition and Subtraction

For addition and subtraction, the number of significant figures used in the answer is determined by the piece of data with the fewest number decimal places.

4.371 302.5 -------- 306.8

Page 35: Chapter 1

HSTMr. Watson

Rules for MathematicsRules for MathematicsAddition and SubtractionAddition and Subtraction

For addition and subtraction, the number of significant figures used in the answer is determined by the piece of data with the fewest number decimal places.

4.371 302.5 -------- 306.8

Page 36: Chapter 1

HSTMr. Watson

Rules for MathematicsRules for MathematicsAddition and SubtractionAddition and Subtraction

For addition and subtraction, the number of significant figures used in the answer is determined by the piece of data with the fewest number decimal places.

4.371 302.5 -------- 306.8

Page 37: Chapter 1

HSTMr. Watson

Exact NumbersExact Numbers

conversion factorsshould never limit the number of significant

figures reported in answer

12 inches = 1 foot

Page 38: Chapter 1

HSTMr. Watson

Round OffRound Off

Chemistry is an inexact scienceall physical measurements have some errorthus, there is some inexactness in the last

digit of any numberuse what ever round-off procedure you

choosereasonably close answers accepted

Page 39: Chapter 1

HSTMr. Watson

Measurement and UnitsMeasurement and Units

length - meter

volume - liter

mass - gram

Page 40: Chapter 1

HSTMr. Watson

Important Metric Unit PrefixesImportant Metric Unit Prefixes

deci -- 1/10*

centi -- 1/100*

milli -- 1/1000*

nano -- 1/1,000,000,000

kilo -- 1000*

Page 41: Chapter 1

HSTMr. Watson

LiterLiter1 liter = 1 decimeter3

by definition

where

1 decimeter = 10 centimeters

therefore

1 liter = (10 centimeters)3

or

1 liter =1000 cm3 =1000 mL

Page 42: Chapter 1

HSTMr. Watson

MilliMillimetermeter

1 millimeter = 1/1000 meter

1000 millimeter = 1 meter

1000 mm = 1 m

Page 43: Chapter 1

HSTMr. Watson

NanometerNanometer

1 nanometer = 1/1,000,000,000 meter

1,000,000,000 nanometer = 1 meter

1,000,000,000 nm = 1 m

Page 44: Chapter 1

HSTMr. Watson

LiterLiter

1 liter = 1 decimeter3

1 liter = 1000 milliliters

1 L = 1000 mL

1 mL = 0.001 L

Page 45: Chapter 1

HSTMr. Watson

MilligramMilligram

1 milligram = 1/1000 gram

1 mg = 0.001 g

Page 46: Chapter 1

HSTMr. Watson

KilogramKilogram

1 kilogram = 1000 gram

1 g = 0.001 kg

1 mg = 0.000001 kg

1 kg = 1,000,000 mg

Page 47: Chapter 1

HSTMr. Watson

Conversion of UnitsConversion of Units

1 in = 2.54 cm

Page 48: Chapter 1

HSTMr. Watson

TemperatureTemperature

Scales:FahrenheitRankin

– absolute scale using Fahrenheit size degree

CelsiusKelvin

– absolute scale using Celsius size degree

Page 49: Chapter 1

HSTMr. Watson

Page 50: Chapter 1

HSTMr. Watson

Comparison of Temperature Comparison of Temperature ScalesScales

Fahrenheit Celcius

body temp. 98.6 37.0

comfort temp. 68.0 20.0

bp water 212 100

mp 32 0

bp-mp 180 100

Page 51: Chapter 1

HSTMr. Watson

Temperature RelationshipsTemperature Relationships

C = 100/180 * (F - 32)

F = (180/100)*C + 32

K = C + 273.15

- 40o F = - 40o C

Page 52: Chapter 1

HSTMr. Watson

If the temperature of the room goes from 20 degrees C to 40 degrees C, the ambient thermal energy– doubles

– is halved

– increases by less than 10%

Page 53: Chapter 1

HSTMr. Watson

DensityDensity

Mass per unit of volumeMass equals volume times densityVolume equals mass divided by density

Page 54: Chapter 1

HSTMr. Watson

Problem Solving by Problem Solving by Factor Label MethodFactor Label Method

state question in mathematical formset equal to piece of data specific to the

problemuse conversion factors to convert units of

data specific to problem to units sought in answer

Page 55: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

Page 56: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

state question in mathematical form

#km

Page 57: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

set equal to piece of data specific to the problem

#km = 0.200 miles

Page 58: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

use conversion factors to convert units of data specific to problem to units sought in answer

#km = (0.200 miles)

* (5280 ft/mile)

Page 59: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

cancel units

#km = (0.200 miles)

* (5280 ft/mile)

Page 60: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

add another conversion factor

#km = (0.200)*(5280 ft)

*(12 in/ft)

Page 61: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

cancel units

#km = (0.200)*(5280 ft)

*(12 in/ft)

Page 62: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

#km = (0.200)*(5280)*(12 in)

Page 63: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

add still another conversion factor

#km = (0.200)*(5280)*(12 in)

*(2.54 cm/in)

Page 64: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

cancel units

#km = (0.200)*(5280)*(12 in)

*(2.54 cm/in)

Page 65: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

#km = (0.200)*(5280)*(12)*(2.54 cm)

Page 66: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

add still another conversion factor

#km = (0.200)*(5280)*(12)*(2.54 cm)

*(1 m/100 cm)

Page 67: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

cancel units

#km = (0.200)*(5280)*(12)*(2.54 cm)

*(1 m/100 cm)

Page 68: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

#km = (0.200)*(5280)*(12)*(2.54)

*(1 m/100)

Page 69: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

add still another conversion factor

#km = (0.200)*(5280)*(12)*(2.54)

*(1 m/100)*(1 km/1000 m)

Page 70: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

cancel units

#km = (0.200)*(5280)*(12)*(2.54)

*(1 m/100)*(1 km/1000 m)

Page 71: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

#km = (0.200)*(5280)*(12)*(2.54)

*(1/100)*(1 km/1000)

Page 72: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

solve mathematics

#km = (0.200)*(5280)*(12)*(2.54)

*(1/100)*(1 km/1000)

= 0.322 km

3 sig. fig.

Page 73: Chapter 1

HSTMr. Watson

ExampleExample

How many kilometers are there in 0.200 miles?

solve mathematics

#km = (0.200)*(5280)*(12)*(2.54) *(1/100)*(1 km/1000) = 0.322 km

3 sig. fig. exact numbers