bivariate analysis linear regression chi test

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Bivariate Analysis (a)Correlation using Linear Regression (Fitting a straight line between two S calar Variables ) Use dataset modified_class_example

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Page 1: Bivariate Analysis Linear Regression Chi Test

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Bivariate Analysis

(a)Correlation using Linear Regression

(Fitting a straight line between two Scalar Variables)

Use dataset modified_class_example

Page 2: Bivariate Analysis Linear Regression Chi Test

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Is there a relationship between salaries and

Student Age?

Page 3: Bivariate Analysis Linear Regression Chi Test

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Go to ChartBuilder->Scatter/Dot

Select Student Age onto horizontal axis and Salary on vertical one

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Is there a relationship between Student Age and Expected Marks?

Page 5: Bivariate Analysis Linear Regression Chi Test

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Can we forecast a relationship between Student age and Salaries?

YES. Use linear regression. That is fit a straight line between Student

Age and Salaries.

Example:

Y = ax + b

X is the Independent Variable

Y is the Dependent Variable 

Gradient a 

X

Y Y = aX + b 

Page 6: Bivariate Analysis Linear Regression Chi Test

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Analyse -> Regression -> Linear

Model Summaryb 

Model

R R Square

 Adjusted R

Square

Std. Error of the

Estimate

i

m

n

i

n

 

1 .964a  .930 .928 2120.38027

a. Predictors: (Constant), Student Age

b. Dependent Variable: Monthly Salary

Page 7: Bivariate Analysis Linear Regression Chi Test

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R = Pearson Coefficient (-1, 1)

-1 = Negative perfect

1= Positive Perfect

Coefficientsa 

Model

Unstandardized Coefficients

Standardized

Coefficients

t Sig.B Std. Error Beta

1 (Constant) -424.000 1625.122 -.261 .796

Student Age 996.417 50.752 .964 19.633 .000

a. Dependent Variable: Monthly Salary

b = -424.0

a = 996.417

Sig. less than 0.05 for a, shows good correlation and not by chance

Y = aX + b

Salary = 996.417 x Student Age – 424.0

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Page 9: Bivariate Analysis Linear Regression Chi Test

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Correlation between Categorical or Nominal variables

(Chi-Square Test)

Is there an Association/Relationship between Gender andMotivation?

Are males and females motivated to the same degree?

Use of Contingency tables

Page 10: Bivariate Analysis Linear Regression Chi Test

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Analyse -> Descriptive -> Crosstabs

(Switch Display Clustered Bar on)

Statistics button

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Cell button

Case Processing Summary 

Cases

Valid Missing Total

N Percent N Percent N Percent

Student Gender * How

motivated is student?

31 100.0% 0 .0% 31 100.0%

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Student Gender * How motivated is student? Crosstabulation 

How motivated is student?

Total

Somewhat

Motivated Well Motivated Very Motivated

Student Gender male Count 12 1 5

Expected Count 7.5 2.9 7.5 18

% within Student Gender 66.7% 5.6% 27.8% 100.0

% within How motivated is

student?

92.3% 20.0% 38.5% 58.1

% of Total 38.7% 3.2% 16.1% 58.1

Female Count 1 4 8

Expected Count 5.5 2.1 5.5 13

% within Student Gender 7.7% 30.8% 61.5% 100.0

% within How motivated is

student?

7.7% 80.0% 61.5% 41.9

% of Total 3.2% 12.9% 25.8% 41.9

Total Count 13 5 13

Expected Count 13.0 5.0 13.0 31

% within Student Gender 41.9% 16.1% 41.9% 100.0

% within How motivated is

student?

100.0% 100.0% 100.0% 100.0

% of Total 41.9% 16.1% 41.9% 100.0

Expected frequencies E(i,j) = R(i) C(j)/ N 

Chi-Square Tests 

Value df

 Asymp. Sig. (2-

sided)

Pearson Chi-Square 11.287a  2 .004

Likelihood Ratio 12.787 2 .002

Linear-by-Linear Association 7.490 1 .006

N of Valid Cases 31

a. 2 cells (33.3%) have expected count less than 5. The minimum

expected count is 2.10.will comment on this later………. 

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Sig. is less than 0.05 (5%) This means that the probability of the values (Count) in the above

table occurring by chance is less than 5%. Therefore there is a significant association/

relationship between gender and Motivation.They are not independent.Some times this test is

also called the chi test for independence.

See diagram (Females are more motivated)