[aptitude] time n distance_ early and late to office (shortcut using product consistency method) for...

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Aptitude (http://mrunal.org/category/aptitude) / 2 years Ago / 43 Comments (http://mrunal.org/2013/01/aptitude-time-n-distance-early-and-late-to-office-shortc 1. Case : Early Late Approach #1: Product consistency Approach #2 (STD Table) 2. Case #2: Tappu’s school Approach #1: Product consistency Approach #2 (STD Table) 3. Case: Pinku’s college (total time given) 4. Mock Questions 5. Answer and explanation Before proceeding further, make sure your concept regarding “product-consistency method” Is clear. If not, then go through my previous article click me (http://mrunal.org/2013/01/aptitude- product-consistency-shortcuts-ssc-ibps-csat-cat.html) Case : Early Late Jethalal goes to shop at the speed 30 km/h, and he reaches six minutes early. Next day he goes at the speed of 24 km/h, and he reaches five minutes late. Find the distance between his home and shop. This can be solved with any of the two approaches 1. Approach #1: Product consistency 2. Approach #2: STD table. Approach #1: Product consistency [Aptitude] Time n Distance: Early and late to oce (shortcut using product consistency method) for SSC, IBPS, CSAT, CAT, CMAT English: SP Bakshi (http://www.flipkart.com/objective-general- english-2012/p/itmdyuqqgafhtehp? pid=9788183480000&affid=mrunalrugm) Mrunal (http://mrunal.org/)

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  • Aptitude (http://mrunal.org/category/aptitude) / 2 years Ago /43 Comments (http://mrunal.org/2013/01/aptitude-time-n-distance-early-and-late-to-office-shortcut-using-product-consistency-method-for-ssc-ibps-csat-cat-cmat.html#comments)

    1. Case : Early LateApproach #1: Product consistencyApproach #2 (STD Table)

    2. Case #2: Tappus schoolApproach #1: Product consistencyApproach #2 (STD Table)

    3. Case: Pinkus college (total time given)4. Mock Questions5. Answer and explanation

    Before proceeding further, make sure your concept regarding product-consistency method Isclear. If not, then go through my previous article click me (http://mrunal.org/2013/01/aptitude-product-consistency-shortcuts-ssc-ibps-csat-cat.html)

    Case : Early Late

    Jethalal goes to shop at the speed 30 km/h, and he reaches six minutes early. Next day he goesat the speed of 24 km/h, and he reaches five minutes late. Find the distance between his homeand shop.This can be solved with any of the two approaches

    1. Approach #1: Product consistency2. Approach #2: STD table.

    Approach #1: Product consistency

    [Aptitude] Time n Distance: Early and late to oce (shortcut usingproduct consistency method) for SSC, IBPS, CSAT, CAT, CMAT

    English: SP Bakshi(http://www.flipkart.com/objective-general-

    english-2012/p/itmdyuqqgafhtehp?pid=9788183480000&affid=mrunalrugm)

    Mrunal (http://mrunal.org/)

  • Let me rephrase the question:Price of sugar is increased from 24 per kg to 30 per kg and now Jethalal is buying 11/60kilograms sugar less (in the same budget). What was his original consumption?

    Does it ring any bell with previous sums of product Consistency? Yep, thats our approach.Prepare this table, plug in the speed values in ascending order

    Slow speed Fast speed

    Speed km/h 24 30

    Ratio-reversed (Time)

    What is the time difference between these two cases?suppose on regular speed, Jethalal used to reach office @10 AMon slow speed, he is 5 minutes late=10.05AMon fast speed he is 6 minutes early=09.54 minutesso the time difference between slow speed and fast speed = 11 minutes.in the exam, just add the two minutes given to you (6+5)=11 and since speed is given in km/h,weve to convert 11 minutes into hours =11/60 hours.

    Slow speed Fast speed

    Speed km/h 24 30

    Ratio-reversed (Time)

    Now apply the product consistency method:Take ratio of 24/30=(6 x 4)/ (6 x 5)=4/5Reverse it.=5/4. Update the table

    Slow speed Fast speed

    Speed km/h 24 30

  • Ratio-reversed (Time) 5 4

    So, when speed is increased, what is the decrease in time?5 to 4=(5-4)/5 x 100=20% (or just keep it in fraction form of 1/5)Meaning new time is 20% less than time.suppose during slow speed, he took M time.Then in fast speed hell take M minus 20% of M time.That means difference between two situations is 20% of mbut weve already inferred that time difference between two situations is 11/60 hourstherefore 20% of m=11/60or in other words1/5 x m=11/60M=115/60M=11/12 hours.This is the time he takes during slow speed, to reach his destinationNow just apply STD formula(slow) Speed x time = distance24 x 11/12 = distanceHence distance = 22 kms.This technique looks odd but It is very fast once you practice.

    Thought process in the exam

    You dont even need to draw table. Just think in your head, speed is decreased from 24 to 30 soreverse ratio is 30/24=5/4And hence decrease from 5 to 4 is (5-4)/5=1/5.It means 1/5 of (slow) time =(6+5)/60Hence time = 11x 5/60Hence distance = just multiple time with slow speed=11 x 5 x (24)/60=22 km.Now lets try solving It, using the

    th

  • Approach #2 (STD Table)

    Case 1 Case 2

    Speed 24 30

    Time ? ?

    Distance D D

    Weve ssumed that in both cases, he has to cover same distance D kms.Apply STD formula in column 1 (case 1)Speed x time = distanceTherefore time = distance / speed = D/24Similarly for case2, we get time=D/30Update table

    Case 1 Case 2

    Speed 24 30

    Time D/24 D/30

    Distance D D

    From the question, we can infer that time difference between two cases is (6+5=11 minutes=11/60 hours)ThereforeD/24-D/30=11/60Simplify this equation and you get D=22 kms.Please note: in the fractions, D/24 is >greater than> D/30Thats why I did D/24-D/30=11/60Lets try second question with both methods

    Case #2: Tappus school

  • Tappu walks from home to school @5kmph and reaches 15 minutes early. After the school isover, he walks back from school to home @3kmph and reaches 9 minutes late. Find distancebetween his home and school.

    Approach #1: Product consistency

    The question is talking about two times: 15 minutes early and 9 minutes late.Therefore total time difference between two situation =15+9=24 minutes=24/60 hrs.

    Slow speed Fast speed

    Speed km/h 3 5

    Ratio-reversed (Time) 5 3

    What is the percentage decrease in time?(5-3)/5=2/5 (=40% decrease)Thats it. If time taken during slow speed =mThen 2/5 of m=24/60 hours (the time difference between two cases)Hence M=1 hour (=time taken during slow speed)Now speed x time = distance3 (slow speed) x1= distanceTherefore distance between Tappus school and home is 3 kms.

    Approach #2 (STD Table)

    Slow speed Fast speed

    Speed km/h 3 5

    Time ?? ??

    Distance D D

    Apply STD formula in each column you getSpeed x time =distanceTime = distance / speed

    th

  • Time = D/3 in first case and D/5 in second case update table

    Slow speed Fast speed

    Speed km/h 3 5

    Time D/3 D/5

    Distance D D

    The time difference between two situations is (15+9)=24 minutes=24/60 hoursThereforeD/3 D/5=24/60Solve this equation and you get D=3 kmsMeaning distance between Tappus school and home is 3 kmsNow lets try a bit complicated case

    Case: Pinkus college (total time given)

    Pinku goes to college @ speed of 3 kmph and returns back @2kmph.He spends total 5 hours inwalking. What is the distance between his home and college?Slow speed , fast speed = 2 and 3 km respectively.

    Slow speed Fast speed

    Speed km/h 2 3

    Ratio-reversed (Time) 3 2

    What is the decrease % in time? (3-2)/3= 1/3 (=33.33%)It means if Pinku take M hours during slow speed.Hed take M minus 33.33% of M hours during fast speed.Therefore, total time (taken to goto college and come back)=m + m -33.33% of m=2m-m/3 (because 33.33%=1/3)=(6m-m)/3=5m/3

  • And we know that total time is 5 hourstherefore 5m/3=5 hourshence m=3 hours. (time taken during slow speed)Apply STDSpeed x time = distance2 (slow speed) x 3 (time)=distanceHence distance=6 km

    Thought process in the exam

    Speed increased from 2 to 3, therefore reverse ratio is 3/2 and %decrease in time is 1/3.Pinkus Total time is given 5 hours, thereforeM + m -(1/5)m=5 hours. Solve it and multiple with slow speed, youll get the distance.

    Mock Questions

    1. Gogi walks from home to school @2.5kmph and he is 6 minutes late. Next day he increasesspeed by 1 kmph and reaches 6 minutes early. Find distance between home and school?

    2. Sonu walks @6kmph and late to college by 5 minutes. If she walks @5kmph, she is late by 30minutes. Find total distance. (please note: since shes late in both cases the time differenceis 30-5=25 minutes. rest approach is same)

    Answer and explanation

    1. Gogi school

    Question is talking about two speeds : 2.5 and (2.5+1.0)=3.5 kmphs

    Slow speed Fast speed

    Speed km/h 2.5 3.5

    Ratio-reversed (Time) 7 5

    Whats the decrease in time %From 7 to 5,=(7-5)/7

  • =2/7Suppose during slow speed case, Gogi takes m hours to reach school.In fast case, hell do it in less time =m 2/7 of m.but from question, we already know that time difference between two cases =6+6=12minutes=12/60 hrsit means 2/7 of m=12/60 hourstherefore m=7/10 hours :This is the time taken during slow speed.Multiply it with slow speed and youll get the distance.Distance= 7/10 x 2.5= 7/4 kms.

    2. Sonu college

    Slow speed Fast speed

    Speed km/h 5 6

    Ratio-reversed (Time) 6 5

    So % decrease in time=(6-5)/6=1/6Therefore 1/6 of slow time (m)= 25/60 hrs.M=25 x 6/60 hrsMultiply it with slow speed (5) and you get distanceDistance=speed x time=5 x 25 x 6/60=25/2=12.5 km distance between home and college.

    Tags: STDW (http://mrunal.org/tag/stdw)

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    sanjaymrunal please suggest strategy for IFS(Forest) exam General studiespaper.please help me

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    manish

  • manishmurnal sir you have been doing an edifying service to the pupils andgood thereof.moreover, i want you to tell me the name of the bookcovering the portion of number system ,taking in view the SSC exam.

    regardsmanish

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T -U S I N G - P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 0 9 5 # R E S P O N D )

    Mrunal (http://mrunal.org)In SSC exams, the questions on number system / remainderproblem, are asked from very limited concepts and I aim to coverthose concepts in upcoming articles. so no need to get any specialbook.There are books like Nishth Sinhas Demystifying number systembut it goes way too deep from CAT point of view.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 0 3 1 # R E S P O N D )

    Anshuman RaiThanks sir. I found the second method of solving it better. quickly D/Timeand equating it to time gap. Thanks for both the methods.

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    Pratik Kumbhani

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  • Please Check them Out and let me know. This query is not only forMrunal. any advice or suggestion is welcome.Waiting for your reply!!!

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    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T -U S I N G - P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 3 2 2 # R E S P O N D )

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    Mrunal (http://mrunal.org)it is given in the http://www.Mrunal.org/aptitude(http://www.Mrunal.org/aptitude)

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    Lady Nightingaleother way to solve such question is to follow question language .like intopmost question regarding jetalal..let distance be x km and speed be u km/hr.

    from 1st part of question-s/u-s/30=6/60.eqn-1

  • from 2nd part of quesns/24-s/u=5/60..eqn-2

    now from eqn-1put s/u value in eqn-2 and we gets/24- s/30- 6/60= 5/60s(5-4)/120= 11/60s=11*120/60= 22kms. is the ans.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 3 7 8 # R E S P O N D )

    anonymous kashmirisir is pearsons book fr csat better than tmh?Ther hv been sm negatv reviwz abou TMH,,,so i m n a fix wch book tobuy?I hv ample tym leftso plz help me outif anybdy else wnts to giv hz/hr sugstn n ds matr i wl b thankful

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 6 6 4 # R E S P O N D )

    yogeshSTD Approach is fantastic.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 6 9 9 # R E S P O N D )

    Ankit SInghSir,,,plzzz also explain the questions in which speed is not given and only toldthat speed is increased or decreased ,,,, also late or early time is given

  • and we have to find the distance .

    solution Like above methods(atleast by first method).

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T -U S I N G - P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 7 0 5 # R E S P O N D )

    Mrunal (http://mrunal.org)give me a sample question.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E -S H O R T C U T - U S I N G - P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T -C M A T . H T M L ? R E P L Y T O C O M = 2 9 7 5 2 # R E S P O N D )

    ankit singhA man covered a certain distance at some speed.Had hemoved 3 kmph faster,he would have taken 40 minutes less. Ifhe had moved 2 kmph slower, he would have taken 40minutes more. The distance (in Km) is :

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O -O F F I C E - S H O R T C U T - U S I N G - P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C -I B P S - C S A T - C A T - C M A T . H T M L ? R E P L Y T O C O M = 3 7 5 3 9 # R E S P O N D )

    SudeepLet distance = D, speed= S, time taken = T (formula, weknow S*T=D)

    Lets assume the man covered the distance twice(2D),one D with S+3 kmph and another D with S-2 kmph

    So, D + D = (S+3) (T-40) + (S-2) (T+40)

  • 2D = ST + 3T 40S 120 + ST 2T + 40S 80==> 2D = 2ST + T -200But ST = D,So T-200 = 2D-2D = 0==> T = 200 min

    Now with S+3 speed, time taken = 200-40 = 160and with S-2 speed, time taken = 200+40 = 240 nowwe have problem in our earlier format.. solve it.. Youwill get D, distance = 40 km

    sankarA man covered a certain distance at somespeed.Had he moved 3 kmph faster,he wouldhave taken 30 minutes less. If he had moved 2kmph slower, he would have taken 20 minutesmore. The distance (in Km) is ///now would yousolve in above method??

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 7 0 3 # R E S P O N D )

    amitthe best simple rule

    [(24*30)*(5+6)]/[(24~30)*60]=22

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 8 5 6 # R E S P O N D )

    lily dutta

  • lily duttathanks 4 ur article sir,m little bit weak in English and arithmetic,plzsuggest me which book ill usefull 4 me to improve in these area,as mpreparing 4 competitive xam

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T -U S I N G - P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 1 3 4 5 6 # R E S P O N D )

    G.A.suryaYour Good Name ( ?)1111=right side fist number right firstnumber.this result left side11 1=12 1 =121 . if 1212 you can add the last number 2 to the leftside of the number.this is surya-9705701141

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 9 9 0 2 # R E S P O N D )

    deepasir plz upload some cubes problems also.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 3 0 2 0 6 # R E S P O N D )

    RaghavSir Pls guide me regarding SBI PO, here they are including marketing,computer, data interpretation etc beside other usual stuff

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 3 0 7 2 5 # R E S P O N D )

    Yagya

  • Assume distance = xTime = y

    Follow the question, if t min early then time = y-tIf late then = y tMake 2 equations in form of distance=speed*time then,

    We know distance will remain same,so equal both equations.You will get ans.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 3 1 3 1 7 # R E S P O N D )

    santu (http://gmail.com)sir,plz help me with the information (necessary link) about cds ssbinterview..sir plz reply.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 3 2 3 6 3 # R E S P O N D )

    smitif we take the problem as..appu walks from home to school @5kmph and reaches 9 minutes late.After the school is over, he walks back from school to home @3kmphand reaches 15 minutes late. Find distance between his home andschool.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 4 4 3 4 3 # R E S P O N D )

    Abubakkar Sithik

  • Abubakkar SithikHi Mrunal, Thank above has been given all information .This site is everuse in my life.this site not only improving exam but also increase ourknowledge

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 5 5 3 8 1 # R E S P O N D )

    ISSHUA man covered a certain distance at some speed. Had he moved 3 kmphfaster, he would have taken 40 minutes less. If he had moved 2 kmphslower, he would have taken 40 minutes more. The distance (in km) is:

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T -U S I N G - P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 1 0 6 7 5 1 # R E S P O N D )

    MudasirDear ISSUE,Let total distance covered be D,total time taken T and average speed be SNow, S=D/T orD =S*TIst case:Ddistance is same,speed increased from S to (S+3) and timedecreased from Tto (T-40/60)=T-2/3=(3T-2)/3D=(S+3)(3T-2/3)3D=3ST-2S+9T-63D-3ST=-2S+9T-60+2S=9T-6Bcoz, 3 speed*time=3 distance2S=(9T-6) -i

  • 2nd casedistance is same D,speed reduced to (S-2), time increased to(3T+2)/3D=(S-2)(3T+2)/33D=3ST+2S-6T-43D-3D-2S=-6T-4(-2S=-6T-4)*-S=(6T+4)/2 -iiput the value of S in =n i ,we getS=12 and T=10/3D=12*10/3D=40 ans

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 9 6 8 1 3 # R E S P O N D )

    john pkM + m -(1/5)m=5 hours. Solve it and multiple with slow speed, youll getthe distance.

    sir i think there is a error it should be M + m -(1/3)m=5 hours. Solve it andmultiple with slow speed, youll get the distance.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T -U S I N G - P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 1 0 7 4 6 3 # R E S P O N D )

    MudasirAnother way to do it is D/2+D/3=5D=6

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -

  • P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 1 4 2 6 8 8 # R E S P O N D )

    Rahulguys y complicate things use this

    (x/5) + ( 15 / 60 ) = (x/3) (9/ 60) . solve for x..thats your ans for tappu

    (x/30) + ( 6 / 60 ) = (x/24) (5/60) . solve for x..thats your ans for Jethalalgoes to shop

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 1 7 3 5 0 5 # R E S P O N D )

    ARJUN SINGHSir it can be solved by different formula which goes to..S1.S2/S1-S2.T1+T2/60.where s1,s2 r speeds,n t1,t2 time for late and early..n itconsume lots of timee during exam..

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 1 8 7 6 0 3 # R E S P O N D )

    DharamvirsinhSir, I tried a lot but couldnt found std table and pipe cistern article.canu please proved me a link for that?

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 0 4 6 5 2 # R E S P O N D )

    sib

  • Mrunal Ji u saved a lot of bucks of the pooru are doing a marvellousand kind job..If there are websites like yours then surely all coachingbusiness will be at dawnjust take care of u as u might have made a lotof enemies in the country

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 1 2 1 0 6 # R E S P O N D )

    AkashHello Sir,I applied STD table in Pinkus college question but not working out to bea correct answer. Please help

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 1 6 0 1 7 # R E S P O N D )

    hafishi mrunal sir,

    please direct me by giving the link for pipes and cistern article.Thanks

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 1 6 4 3 7 # R E S P O N D )

    amritthanku this is very helpful mrunal sir.

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 2 3 4 9 7 0 # R E S P O N D )

    Illaventhan

  • Write your message!

    IllaventhanWhen Kiran drives a car at a s peed of 55 km/hr towards his office, hereaches l ate by 20 minutes ;but if he driv es at a s peed of 70 km/hr, he reaches earl y by 15 minutes .Find the usual time thathe takes to reach his office exactly on time? please anyone slove this

    R E P L Y ( / 2 0 1 3 / 0 1 / A P T I T U D E - T I M E - N - D I S T A N C E - E A R L Y - A N D - L A T E - T O - O F F I C E - S H O R T C U T - U S I N G -P R O D U C T - C O N S I S T E N C Y - M E T H O D - F O R - S S C - I B P S - C S A T - C A T - C M A T . H T M L ?R E P L Y T O C O M = 3 3 3 1 6 0 # R E S P O N D )

    Ajay KumarSir help for this question

    a man covered a certain distance at some speed. had he moved 3kmphfaster, he would have taken 40 minutes less. if he had moved 2 kmphslower, he would have taken 40 minutes more. the distance is ?/

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    07-Jul: NBCC Building (http://www.nbccindia.com/nbccindia/nroot/njsp/Career.jsp)

    01-Jul: NIELIT Spec. (http://www.nielit.gov.in/recruitments.aspx)

    30-Jun: Rajendra Agro. (http://www.mangaldhwani.com/pusa/wp-

    content/uploads/2014/09/Advt_-01_2015.pdf )

    30-Jun: IIT Kanpur (http://www.iitk.ac.in/new/vacancies-in-administrative-and-technical-

    cadre )

    28-Jun: ONGC Rajbhasha (NET)

    (http://ongcindia.ongc.co.in/wps/wcm/connect/ongcindia/home/career/recruitment+notices/recruitment-

    of-olo-2015)

    25-Jun: Raj. Industrial Development (http://www.riicorecruitment.org/)

    25-Jun: HSCC Noida (http://www.hsccltd.com/)

    24-Jun: Haryana Gramin Agro (http://www.shgb.co.in/RecruitmentsandPromotions)

    24-Jun: Haryana Gramin Law Officer (http://www.shgb.co.in/RecruitmentsandPromotions)

    Medics

    14-Jul: MP medical officer (http://www.mppsc.nic.in/)

    30-Jun: HAL Medical officer (http://www.hal-

    india.com/Common/Uploads/Resumes/144_CareerPDF1_Med-advt-AC.pdf)

  • ParaMedics

    Not At the moment

    Deskjobs

    05-Aug: NBE Assistants (http://natboard.edu.in)

    31-Jul: IIIT Allahabad Gr.C (http://www.iiita.ac.in/announcements.php)

    20-Jul: NISER Clerks (http://www.niser.ac.in/drupal_new/)

    15-Jul: Jammu Univ. (http://www.cujammu.ac.in//Default.aspx?

    option=article&type=single&id=32&mnuid=734&prvtyp=site)

    07-Jul: NBCC Building (http://www.nbccindia.com/nbccindia/nroot/njsp/Career.jsp)

    01-Jul: NIELIT Deskjobs (http://www.nielit.gov.in/recruitments.aspx)

    13-Jun: Bank Note Press (http://www.jobapply.in/bnpdewas/)

    30-Jun: Lucknow Law univ. (http://rmlnlu.ac.in/recruitment-notification-process.html)

    30-Jun: Rashtriya Sanskrit Sansthan (http://sanskrit.nic.in/advt_22_05_2015.pdf)

    25-Jun: Pawan Hans Limited (http://pawanhans.co.in/site/Careern.aspx)

    24-Jun: SJVN (PH) (http://sjvn.nic.in/careerdetail.htm?10/jobdetail)

    Faculty

    31-Jul: IIIT Allahabad (http://www.iiita.ac.in/announcements.php)

    20-Jul: Raipur Univ. (http://www.prsu.ac.in:8010/Univ_Req.aspx)

    15-Jul: NIT Puducherry (http://www.nitpy.ac.in/assets/teaching.pdf)

    16-Jul: RPSC Home Science (http://rpsconline.rajasthan.gov.in/)

    15-Jul: Jammu Univ. (http://www.cujammu.ac.in//Default.aspx?

    option=article&type=single&id=32&mnuid=734&prvtyp=site)

    12-Jul: GBPUAT (http://www.gbpuat.ac.in/)

    10-Jul: NITTTR Chandigarh (http://www.nitttrchd.ac.in )

    07-Jul: Palampur, Himachal asst. (http://www.ihbt.res.in/recruit/recruitNotice.php)

    06-Jul: PEC Chandigarh (http://pec.ac.in/~pecac/new/jobs)

    03-Jul: SKHM Government Medical College (http://www.gmcmewat.ac.in)

    30-Jun: IIT Roorkee (http://www.iitr.ernet.in/administration/pages/Openings+Faculty.html)

    30-Jun: Ambedkar Uni. Delhi (http://aud.ac.in/careerataud)

  • 30-Jun: NEIGRIHMS (http://neigrihms.gov.in)

    30-Jun: Lucknow Law (http://rmlnlu.ac.in/recruitment-notification-process.html)

    30-Jun: AIIMS Raipur (http://www.aiimsraipur.edu.in/Career.aspx)

    28-Jun: Ranchi Agro (http://www.bauranchi.org/application-for-the-post-of-teachers-2/)

    22-Jun: DIATPune (http://14.139.111.180/admin.html)

    22-Jun: IGIT (http://www.igitsarang.ac.in/careers.php)

    22-Jun: Himachal Central Univ. (http://www.cuhimachal.ac.in/job_emp.aspx)

    Uniform

    19-Jul: Navy Officers (http://www.irfc-nausena.nic.in/hindi/join_indiannavy.htm)

    17-Jul: NDA Officers (http://upsconline.nic.in/mainmenu2.php)

    15-Jul: Army Dental (23) (http://indianarmy.nic.in)

    10-Jul: Army 10+2 (http://joinindianarmy.nic.in/)

    30-Jun: BSF Constable (http://bsf.nic.in/en/recruitment.html)

    15-Jun: Navy Sailers (SSR) (http://nausena-bharti.nic.in/forthcomingSailor.php)

    15-Jun: Daman Diu Constables (http://daman.nic.in/jobs/2015/616-12-05-2015.PDF)

    B.Com,CA,HR,MBA

    20-Jul: Pawan Hans Audit (http://pawanhans.co.in/site/Careern.aspx)

    06-Jul: GBPUAT Accountant (http://www.gbpuat.ac.in/)

    01-Jul: NIELIT Accounts (http://www.nielit.gov.in/recruitments.aspx)

    25-Jun: MP Electricity Accounts

    (https://www.mponline.gov.in/Portal/Services/Recruit_MPKVV/Indore/notification.aspx)

    21-Jun: Lucknow Metro Accounts

    (https://www.digialm.com/EForms/html/form2399/index.html)

    RESULT /MARKSHEET

    SSC 2014 T2

    NCLAT

    Hotel Management

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    uri=CivilServiceExam)HOME (HTTP://MRUNAL.ORG/) ECONOMY (HTTP://MRUNAL.ORG/ECONOMY)

    DOWNLOAD (HTTP://MRUNAL.ORG/DOWNLOAD) CONTACT ME (HTTP://MRUNAL.ORG/CONTACT)

    The work of Mrunal (http://mrunal.org/) is under the Creative Commons Attribution-Non Commercial-ShareAlike 4.0License (http://creativecommons.org/l icenses/by-nc-sa/4.0/deed.en_US).Permissions beyond the scope of this l icense

    may be available at Mrunal.org/contact (http://mrunal.org/contact).

    1. Online Form Part-I stops few days before deadline, so don't wait till last date. Dont forget

    reg.id & roll no.Note'em in Google Drive (https://www.google.com/drive/)

    2. I usually update vacancies every Monday.Purple link= newly added,Blue= existing.Last

    updated Mon. Jun 22, at 9:04PM

    TENTATIVE NOTIFICATIONS

    IAS-IPS-IFoS: 16 May

    IES: 7 Feb

    SSC CGL: 2 May

    SSC 10+2: 6 June

    SSC Sub insp: 28 Mar

    CAT: Aug 2015

    RBI Officer / Assistant: ??

    IBPS PO / Clerk / RRB: ??

    ACIO 2015: ??

    // /

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