5-1 electrical systems k si cemfasttrack 03 26 12 [read-only] si cem fast track... · power factor...
TRANSCRIPT
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ELECTRICAL SYSTEMSAND
ELECTRIC ENERGY MANAGEMENTSECTION KSECTION K
MAIN TOPICS DISCUSSED
Electric Rates
Electrical system utilization Electrical system utilization
Power quality
Harmonics
Power factor (Cos phi) improvement
Section K - 2
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ELECTRIC RATES
Utility Rate Structure Incentives
– Demand Reductions– Time of day rate or real time pricing– Seasonal rate– Power Factor (Cos phi) Correction– Primary vs. secondary metering– Rebates and Rate riders (electric heat, etc)
Potential approaches
– High efficiency equipment– High efficiency equipment– Scheduling uses off-peak– Demand limiting (demand response)– Duty cycling
Section K - 3
POWER COMPUTATION FORMULAS
Single-phase systemP = V I Cos phi
Where Cos phi = power factor
Three-phase systemP = 3 V I Cos phi
Where Cos phi = power factor3 323 = 1.732
Section K - 4
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EXAMPLES
a) For a 10 ampere, 220 volt, electric space heaterheater
P = 220 10 1.0 = 2200 watts
b) For a three phase 380 volt, 20 ampere motor with power factor (Cos phi) of 90%motor with power factor (Cos phi) of 90% at full load
P = 3 0.380 20 0.9 = 11.85kW
Section K - 5
ELECTRIC MOTOR EQUATIONS
kW = 3 kV I Cos phi
kVA = 3 kV I
Cos phi (PF) = kW/kVA
kWin = kWnp Load FactorpEfficiency
Section K - 6
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POWER QUALITY
Power Quality is related to how well a bus voltage—usually our facility load bus voltage—maintains a pure sinusoidal waveform at rated voltage and frequency.
PQ issues involve all momentary phenomena including spikes, notches and outages; as well as harmonics and power factor.
Modern electronic equipment both causes and is affected by the problemaffected by the problem.
Power Quality is becoming one of the most important issues in energy management today.
Section K - 7
HARMONICS
• Harmonics are a multiple of the fundamental frequency. If the fundamental frequency is 50 hertz, the 2nd harmonic is 100 Hz, the 3rd is150 Hz, the 4th is 200 Hz, etc.
Section K - 8
• Harmonics are usually generated by solid-state-based equipment such as switching power supplies in PCs, DC drives, variable frequency drives (VFDs), electronic ballasts, arc welders and ovens.
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IMPORTANCE OF GROUNDING Up to 80 percent of PQ problems in facilities today
may be caused by wiring and grounding systems that met the NEC at the time, but do not meet the
d f d ' i i l i ineeds of today's sensitive electronic equipment.
The first step taken to deal with PQ problems should be to inspect the wiring and grounding, and clean and tighten all connections. Loose connections come from vibration, oxidation, corrosion and agecorrosion, and age.
Section K - 9
TYPICAL FACILITY ELECTRICALDISTRIBUTION SYSTEM
A
B 3B
N
G
C
Neutral
Ground
3
Y System
Section K - 10
VL-L = 380 V
VL-N = 380/3 = 220 V
IN = 0in a balanced 3Φ system
Most facilities are upgrading internal distribution to 380 V
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WHAT PROBLEMS OCCUR BECAUSE OFHARMONICS?
Circuit breakers tripping
f Neutrals overheating (smoke, fire)
Panel or transformer overheating
RFI – Radio Frequency Interference
Errors/damage in Electronic Equipment
Digital clocks running fast
Failures in power factor correction capacitors
Section K - 11
MOTOR PROBLEMS ALSO OCCUR
Increased motor losses and overheating Power Factor decrease (from wave distortion as
compared to wave displacement )p p ) Reduced torque and torque pulsation
Negative sequence harmonics - like the 5th and 11th -try to force the motor to rotate in the reverse direction and cause torque pulsation. The 5th harmonic seriously reduces motor torque.
Vibration & overheatingReduces motor life, damages bearings and insulation - extreme cases can result in motor “cogging” which destroys couplings, shafts, and driven loads.
Section K - 12
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IEEE 519 PQ STANDARDS
• Old standard was IEEE 519-1992.
• Newest standard is IEEE 519-1998.
• THD (E) is Voltage Total Harmonic Distortion.
• For low voltage systems (less than 69 kV), the limits are:
General Systems 5%
Section K - 13
Special Applications 3%
(E.g. hospitals)
MITIGATION OF HARMONIC PROBLEMS
Derate equipment (symptom treatment)50% Transformers70% Load centers
Circuit breakersCircuit breakersNeutrals
Install preventive equipmentInductorsHarmonic filtersIsolation transformers
Locate near drive if possibleLocate near drive if possibleConnect back to "strongest" point of
power system – the load center
Section K - 14
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POWER FACTOR (COS PHI) CONSIDERATIONS
What is the power factor?How is the power factor computed?How is the power factor computed?What does a low power factor mean
to electric costs (i.e.-tariff costs, I2R losses, affect on PF)?
How can power factor be improved?How will power factor correctionHow will power factor correction
affect the system (Harmonics, capacity restoration, resonance, etc)?
Section K - 15
WARNING ON POWER FACTOR CORRECTIONBefore installing power factor (Cos phi)
correction correction equipment-especially capacitors-in your facility, make sure you p y y, yperform a power quality test to determine if there is little/no harmonics present which could adversely affect the electrical system.
Harmonic resonance effects can greatly increase the current through the power factor correction capacitors.p
Make sure to measure “true power factor” which accounts for harmonics.
Section K - 16
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POWER TRIANGLE
kVAkVAR
Section K - 17
kW
SCHEMATIC ARRANGEMENT SHOWING HOW CAPACITORS REDUCE TOTAL KVA BY SUPPLYINGMAGNETIZING REQUIREMENTS LOCALLY.
Section K - 18
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POWER FACTOR (COS PHI) CORRECTION
EQUIPMENT PANELS
Section K - 19
Transformer
M
Where to Put Power Factor Correction Capacitors
Section K - 20
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SAMPLE POWER FACTOR EXAMPLEA facility is operating with a demand of 2000 kW. The 2500 kVA transformer is fully loaded. How many kVARS are required to bring the power factor (Cos phi) back toare required to bring the power factor (Cos phi) back to unity?
kW2 + kVAR2=kVA2
kVAR2 kVA2 kW2kVAR2= kVA2-kW2
Section K - 21
150020002500kVAR 22
SAMPLE POWER FACTOR PROBLEM
During my last energy audit I saw a 100 kW electric motor that had the following full load informationmotor that had the following full load information on the nameplate: 380 volts; 182 amps; three phase; 95% efficient What is the power factor of this motor?
Section K - 22
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SAMPLE CEM TEST QUESTION
A facility is operating at a power factor (Cos phi) of 70% with a real power load of 2000 kW. How much corrective capacitancereal power load of 2000 kW. How much corrective capacitance in kVAR is needed to improve the facility power factor to 90%?
kVAR = Table Factor x Real power load in kW
Section K - 23
SHORT POWER FACTOR (COS PHI) TABLE
Section K - 24
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CEM REVIEW QUESTIONS
1. If power factor (Cos phi) correction capacitors are located at the utility meter, but on the customer’s side of the meter, the power factor out in the customer’s facility will not be improved.
A. True B. False2. A facility has a 100 kW electric resistance oven
for drying parts What is the power factor (Cosfor drying parts. What is the power factor (Cos phi) of the oven?
A. 0 % B. 50% C. 90% D. 100%
Section K - 25
3. A facility has a motor that draws 200 kVA and has a power factor (Cos phi) of 70.7%. How many kW and how many kVAR does it draw?
4. A facility has a motor that draws 200 kVA and has a power factor (Cos phi) of 80%. How many kW and how many kVAR does it draw?
Section K - 26
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FULL POWER FACTOR (COS PHI) TABLE
Section K - 27
END OF SECTION K
Section K - 28