204107 data communication - suranaree university of...
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School of Information TechnologySchool of Information TechnologySuranareeSuranaree University of TechnologyUniversity of Technology
204107 – Data Communication
Dr. Thara Angskun (ดร. ธรา องัสกลุ่ )E-mail: [email protected]: (044)22 4535
Schedule
Quiz [8], Chapter 9** Sun Mar 9
Final ExamFri Mar 28Quiz [10], ReviewThu Mar 20Quiz [9], Chapter 10Thu Mar 13
Quiz [6-7], Chapter 8Thu Mar 6** Sun Mar 2
Chapter 6-7Thu Feb 28
** Substitution for Makha Bucha Day (Feb 21, 2008)
CH 6: Multiplexing
Multiplexing
FDM• Frequency Division Multiplexing
• Analog multiplexing that combines signals
Guard Bands
FDM Multiplexing Process
FDM Demultiplexing Process
Example 1• Assume that a voice channel occupies a
bandwidth of 4 KHz. We need to combine three voice channels into a link with a bandwidth of 12 KHz, from 20 to 32 KHz (no guard bands). Show the configuration using FDM.
Example 1 (Cont.)
Example 2• Five channels, each with a 100-KHz bandwidth,
are to be multiplexed together. What is the minimum bandwidth of the link if there is a need for a guard band of 10 KHz between the channels to prevent interference?
Example 3• Four data channels (digital), each transmitting
at 1 Mbps, use a satellite channel of 1 MHz. Design an appropriate configuration using FDM
Example 3• Four data channels (digital), each transmitting
at 1 Mbps, use a satellite channel of 1 MHz. Design an appropriate configuration using FDM
FDM Hierarchy
Why not 2.4 MHz?
Example 4• AMPS phone company uses two bands. The
first band, 824 to 849 MHz [BW=25MHz], is used for sending; and 869 to 894 MHz is used for receiving. Each user has a bandwidth of 30 KHz in each direction. How many people can use their cellular phones simultaneously?
• Solution = 25 MHz / 30 KHz = 833.33 • (In practice: 832 channels = 42 control + 790 users)
WDM• Wavelength Division Multiplexing
• Analog multiplexing that combines optical signals
WDM Mux-Demux
TDM• Time Division Multiplexing
• Digital multiplexing that combines low-rate channels into one high-rate
Output data rate = N x Data rate of an input link
TDM Frames
Example 5• Four 1-Kbps connections are multiplexed
together. A unit is 1 bit. Find • (1) the duration of 1 bit before multiplexing [INPUT]
• 1/1,000 = 0.001 s (= 1ms)• (2) the transmission rate of the link [OUTPUT]
• 4 Kbps• (3) the duration of a time slot [OUTPUT]
• 1/4000 = 0.00025 s (= 0.25 ms = 250 µs)• (4) the duration of a frame [OUTPUT]
• 4 * 0.25 ms = 1ms
Example 6• Four channels are multiplexed using TDM. If
each channel sends 100 bytes/s and we multiplex 1 byte per channel. Find the bit rate for the link, frame size, the frame rate and the duration of a frame.
Example 7• A multiplexer combines four 100-Kbps channels
using a time slot of 2 bits. Show the output with four arbitrary inputs. What is the bit rate? What is the frame rate? What is the frame duration?
Interleaving• The process of taking a group of bits from each
input line for multiplexing
Framing Bits
Digital Signal (DS) Hierarchy
T-4DS-4
T-3DS-3
T-2DS-2
T-1DS-1T-LineService
T Lines for Analog Trans.
T-1 Frame
Empty Slots• Inefficient use of bandwidth
Synchronous vs. Statistical
Data Rate Management
Not all input links may have the same data rate.
*** ASSIGNMENT 1 ***• 1) What are Multilevel Multiplexing, Multiple-Slot Allocation and
Pulse Stuffing?
• 2) Two channels, one with a bit rate of 100 Kbps and another with a bit rate of 200 Kbps, are to be multiplexed. How this can be achieved? What is the frame rate? What is the frame duration? What is the bit rate of the link?
• 3) Question 5 [p. 119]• 4) Question 7 [p. 119]• 5) Question 8 [p. 119]
Due date: Wed Mar 5, 2008