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    Topic Training – New Concrete

    2

    All information in this document is subject to modification without prior notice. No part of this manualmay be reproduced, stored in a database or retrieval system or published, in any form or in any way,electronically, mechanically, by print, photo print, microfilm or any other means without prior writtenpermission from the publisher. SCIA is not responsible for any direct or indirect damage because ofimperfections in the documentation and/or the software.

     © Copyright 2015 SCIA nv. All rights reserved.

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    Table of contents

    3

    Table of contents

    Introduction ................................................................................................................................... 5 

    Concrete in SCIA Engineer 15 ..................................................................................................... 6 

    Settings ......................................................................................................................................... 8 

    Concrete settings (structure) ........................................................................................................... 8 

    Concrete settings dialogue............................................................................................................. 8 

    Setting per member ......................................................................................................................... 12 

    1D member data .......................................................................................................................... 12 Reinforcement design ................................................................................................................ 14 

    Internal forces .................................................................................................................................. 15 

    Parameters which influence the calculation ................................................................................. 16 

    Shifting of bending moments........................................................................................................ 19 

    Determination whether member is in compression ...................................................................... 19 

    First order bending moments with imperfection ........................................................................... 20 

    Calculation of second order effects .............................................................................................. 22 Slenderness ..................................................................................................................................... 27 

    Buckling data ................................................................................................................................ 27 Creep coefficient .......................................................................................................................... 27 

    Estimation of ratio of longitudinal reinforcement .......................................................................... 27 

    Calculation of slenderness ........................................................................................................... 28 

    Calculation of limit slenderness.................................................................................................... 28 Reinforcement design – theory ..................................................................................................... 31 

    Parameters ................................................................................................................................... 31 

    Design of longitudinal reinforcement ............................................................................................ 34 

    Design of shear reinforcement ..................................................................................................... 40 

    Torsional longitudinal reinforcement ............................................................................................ 46 Practical reinforcement ............................................................................................................. 47 

    Check ........................................................................................................................................... 48 

    Stiffness ........................................................................................................................................... 48 

    Theory .......................................................................................................................................... 50 Capacity - response (ULS) ............................................................................................................. 52 

    Theoretical background................................................................................................................ 52 

    Effective depth of cross-section ................................................................................................... 54 

    Inner lever arm ............................................................................................................................. 55 Capacity - diagram (ULS)................................................................................................................ 56 

    Theoretical background................................................................................................................ 56 

    Setup ............................................................................................................................................ 61 Shear + torsion (ULS) ..................................................................................................................... 62 

    Equivalent thin-walled closed cross-section ................................................................................ 62 

    Shear reinforcement ..................................................................................................................... 65 

    Shear check ................................................................................................................................. 66 

    Torsion check ............................................................................................................................... 71 

    Check interaction shear and torsion ............................................................................................ 73 Stress limitations (SLS) .................................................................................................................. 75 

    Theoretical background................................................................................................................ 78 

    Setup ............................................................................................................................................ 79 Check width (SLS) ........................................................................................................................... 81 

    Value of strength for calculation of cracking forces ..................................................................... 81 

    Check of normal stresses (occurring of crack width) ................................................................... 81 

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    Topic Training – New Concrete

    4

    Type of strength for calculation of cracking forces....................................................................... 81 

    Use of effective modulus of concrete ........................................................................................... 82 

    Type of maximal crack width ........................................................................................................ 82 

    Calculation of mean strain in the reinforcement and concrete ..................................................... 82 

    Calculation of maximum crack spacing ........................................................................................ 83 

    Calculation of crack width ............................................................................................................ 83 Deflections (SLS) ............................................................................................................................. 84 

    Theory .......................................................................................................................................... 85 

    Setup ............................................................................................................................................ 87 Detailing provisions ........................................................................................................................ 89 

    Minimal clear spacing of bars 8.2(2) ............................................................................................ 90 

    Maximal percentage of shear reinforcement (6.2.3(3)) ................................................................ 90 

    Minimal mandrel diameter (8.3(2)) ............................................................................................... 91 

    Minimal reinforcement area 9.2.1.1(1) ......................................................................................... 91 

    Maximal area of reinforcement 9.2.1.1(3) .................................................................................... 91 

    Minimal percentage of shear reinforcement (9.2.2(5)) ................................................................. 92 

    Maximal longitudinal spacing of stirrups based on shear (9.2.2(6)) ............................................ 92 

    Maximal longitudinal spacing of stirrups based on shear (9.2.3(3)) ............................................ 92 

    Maximal centre-to-centre bar distance based on torsion (9.2.3(4)) ............................................. 93 

    Maximal clear spacing of bars (Code independent) .................................................................... 93 

    Unity check calculation ................................................................................................................. 93 

    Minimal bar diameter of longitudinal reinforcement 9.5.2(1) ........................................................ 94 

    Minimal area of longitudinal reinforcement 9.5.2(2) ..................................................................... 94 

    Maximal area of longitudinal reinforcement 9.5.2(3) .................................................................... 94 

    Minimal number of bars in circular column 9.5.2(4) ..................................................................... 94 

    Minimal bar diameter of transverse reinforcement 9.5.3(1) ......................................................... 95 

    Maximal longitudinal spacing of stirrups (9.5.3(3)) ...................................................................... 95 

    Maximal centre-to-centre bar distance (9.3.1.1(3)) ...................................................................... 95 Annex 1: List of parameters ...................................................................................................... 96 

    Annex 2: National Annexes ..................................................................................................... 104 

    Annex 3: Concrete settings – Values ..................................................................................... 109 

    Solver settings ............................................................................................................................... 109 

    General ....................................................................................................................................... 109 

    Internal forces............................................................................................................................. 112 

    Design As ................................................................................................................................... 114 

    Interaction diagram .................................................................................................................... 116 

    Shear .......................................................................................................................................... 117 

    Torsion ....................................................................................................................................... 120 

    Stress limitation .......................................................................................................................... 120 

    Cracking forces .......................................................................................................................... 120 

    Deflection ................................................................................................................................... 121 

    Detailing provisions .................................................................................................................... 122 

    Design defaults.............................................................................................................................. 133 

    Minimal concrete cover .............................................................................................................. 133 

    Beam .......................................................................................................................................... 136 

    Beam slab .................................................................................................................................. 139 

    Column ....................................................................................................................................... 142 

    Default sway type ....................................................................................................................... 144 

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    Introduction

    5

    Introduction

    SCIA Engineer 15 brings a completely new solution for 1D concrete members. New technologies of theOpen design, powered by our SCIA Design Forms platform, have allowed for a complete revision of thedesign and checking of reinforced concrete 1D members. This allows us the use of all well knownfeatures of this platform such as very nice and detailed layouts of calculation, using equations in outputetc. Beside this, we offer more - rearrangement of the service tree, new concrete setup and memberdata and a couple of new checks. The described solution works for all kind of shapes of non-prestressed cross-section (e.g. with holes) subjected to all types of loading (e.g. biaxial shearcombined with torsion). Generally this new module provides the following advantages:

    •  high performance - design and checks run very fast using a parallel process providing resultsin a very small calculation time

    •  transparency - detailed output enables to verify each intermediate steps of check usingformulas with values and proper units; assisting in dealing with EN 1992-1-1

    •  dynamic figures - drawing of stress-strain state of cross-section, reinforcement pattern orinteraction diagram

    •  smart settings - new revised global and member settings, including 'quick search' function

    •  general solution 

    •  supporting interaction of all internal forces (N, My, Mz, Vy, Vz, T)•  supporting arbitrary cross-section shapes including openings & arbitrary reinforcement

    positions

    •  revised and updated generic functions for design & checking of reinforced concrete columns &beams

    •  code compliance - supporting compliance with EN 1992-1-1:2004/AC:2010-11, corrigendumincluding National Annexes (currently 18 NA´s)

    The revised design and checks functions are developed within the SCIA Design Forms  environment.This platform is linked as post-processor to SCIA Engineer. The new reporting style makes use of itsadvantages regarding the presentation of results. Next to text and tabular output, also formulas, codereferences, dynamic images and diagrams are included to increase the insight in the calculation!

    The Concrete Toolbox  is the new 'calculation heart', used by SCIA Design Forms. It contains a set ofcode-independent functions for the design and checking of reinforced concrete members. It makes useof advanced generic algorithms, however in full compliance with e.g. the Eurocode assumptions. Thismeans they are valid for arbitrary cross-section shapes and reinforcement positions. They also supportthe interaction of any mixture of internal forces (N, My, Mz, Vy, Vz, T).

    There are also some limitations. New concrete checks do not support the following items:

    •  numerical cross-section

    •  cross-section with more components

    •  phased cross-section

    •  member or cross-section with different material than concrete material – composite cross-

    section•  different reinforcement materials in one section

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    Topic Training – New Concrete

    Concrete in SCIA Engineer 15

    The new version of the Concrete module is placed in a completely different part of the main program

    tree. This module is situated in the new command ‘Concrete 15’ in the tree.

    Nevertheless, the existing old solution for concrete design and check is still available. The functionalityof existing concrete checks is activated in Project data - Functionality - Old concrete checks.

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    Concrete in SCIA Engineer 15

    When we go into the concrete tree we can also see a completely different arrangement of the tree. Theconcrete tree is split into four parts:

     •  Settings - global and local settings

    o  Concrete settings (structure)

    o  Reinforcement drawing settings

    o  Settings per member

      1D member data

      1D buckling data

    •  Reinforcement design - 1D members

    o  Internal forces

    o  Slenderness

    o  Reinforcement design - design oflongitudinal and shear reinforcement

    •  Input of real reinforcement

    •  Checks

    o  Internal forces

    o  Slenderness

    o  Stiffnesses

    o  Capacity - response (ULS)

    o  Capacity - diagram (ULS)

    o  Shear + Torsion (ULS)

    o  Stress limitation (SLS)

    o  Crack width (SLS)

    o  Deflection (SLS)

    o  Detailing provisions

    Each part will be explained more in detail in the following chapters.

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    Topic Training – New Concrete

    Settings

    Concrete settings (structure)

    There is a brand new Concrete settings (structure) setup for concrete members, which contains allneeded settings coming from the code or calculation routines. The global settings located in Concretesettings (structure) are by default valid for all members in the project, unless they are overwritten bySettings per member - 1D member data. A lot of input parameters and calculation settings are

    collected here, reflecting the complexity of the Eurocode.

    In Annex 3, the available settings are described more in detail.

    Concrete settings dialogue

    This dialogue is split into two main parts. The left part contains the values themselves and the rightside includes an explanatory figure with a description of the value. Additionally there are severalbuttons for searching, filtering, mode selection and default settings.

    The Concrete settings dialogue is presented as a kind of table with 9 columns (description, symbol,value, default, unit, chapter, code, structure and check type). Each column has enabled the possibilityfor searching. The user can easily start typing in the first row of a column and see the intermediate

    output of the search.

    Find

    There is also a 'Find' function, where the user can insert a search term. It brings some kind of filteringof items in the setup. This function enables the search of the defined value anywhere in the Concretesetting dialogue.

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    Settings

    View

    Furthermore, a very useful new option is the possibility of switching the type of view of items of thesetup - concrete commands view, code chapter view or list view.

    The first view is according to the commands (Concrete commands view) used for design and check.

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    Topic Training – New Concrete

    Another view is based on numbering of form design code as mentioned on the following figure.

    The last predefined view is the List view where all items are listed and could be alphabetically sorted.

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    Settings

    Additionally, the user has also the possibility to create his own view based on fi ltered items and usethem for some quick changes afterwards. The user defined view can be created using Save actualview where the new view name can be written.

    Afterwards, this view is possible to select in User item. It is possible to save or import this user viewfrom the file using Save views into file, and Import views from file.

    Finally, there is a possibility to see only changed items using Show only changed items in thesettings, and not the defaults.

    Filters

    The user can choose between a Standard or Advanced level, which filters the amount of data.

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    Topic Training – New Concrete

    Default

    Finally, when the user wants go back to the predefined values it is possible to press the button Default and all settings are restored.

    Setting per member

    1D member data

    These settings overwrite the global settings for a specific member. Member data can easily be copy-pasted to similar members. There is a differentiation based on type of member (beam, column, beamslab). As in the case of the concrete settings, member data has also been restyled. Local settingscontains about the same input parameters and calculation settings as the global settings in the setup.Moreover, the user can set his/her own value of limit deflection and limit width of crack, define moreenvironmental classes than just one as in the previous version.

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    Settings

    13

    Properties of 1D Member data

    1D Member data are arranged similarly as Concrete settings (structure). Generally, there are thefollowing items.

    •  Name – name of the member data

    •  Member - name of the associated member

    •  Member type - generally member data can be set for Beam, Columns and Beam Slab

    differently.

    •  Advanced mode - some items are visible only in advanced mode

    •  Solver settings

    •  Design defaults

    The available settings for the Solver settings and Design Defaults are described in Annex 1.

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    Topic Training – New Concrete

    Reinforcement design

    First you get an overview of the input data for the design:

    •  Internal forces, displaying the characteristic and design values.

    o  For member type 'column', the design values of the bending moments include the2nd order bending moments (if required) and the moments due to geometric

    imperfections.o  For member type 'beam', the design values of the bending moments include the

    shifting of the moment line - to take the additional tensile force due to shear intoaccount.

    •  Slenderness calculation (for member type 'column'), determining if 2nd order effects need betaken into account.

    The design of longitudinal reinforcement to resist N, My and Mz is done according to the Ultimate LimitState requirements. Design method is selected based on type of member (beam x column) andaccording to the acting load. There is not any limit for type of cross-section (formerly for columnsrectangle and column) nor for load type (formerly for beams - My OR Mz).

    In case the required area of reinforcement exceeds the available space on one layer, more layers (withadapted lever arm) are automatically generated. Designed reinforcement is automatically recalculatedto real bars afterwards.

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    Design

    The design of shear reinforcement to resist Vy and Vz is done according to the ULS requirements.Formerly, there was possibility to design shear reinforcement just for Vy or Vz.

    Internal forces

    The internal forces, which are used for design and checks of concrete members, can be different asthe internal forces calculated from FEM analysis. The differences may be caused by:

    •  for compression member (column)

    o  taken into account eccentricities caused by imperfections

    o  taken into account second order eccentricity

    •  for beams and beams as slab

    o  taken into account additional tensile forces caused by shear and torsion (shifting ofbending moments)

    The following preconditions are used for the calculation:

    •  The shifting of bending moments is taken into account only for beams and beams as slab andin both directions

    •  The second order effect and geometrical imperfection are calculated only for column incompression

    •  Cross-section with one polygon and one material is taken into account for calculation secondorder effect and imperfection in version SEN 15

    •  The material of all reinforcement bars have to be same in SEN 15

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    Topic Training – New Concrete

    Parameters which influence th

    Coefficient for calculation o

    Coefficient for calculation of effecsettings (Advanced level). The dedeformation, this value will be cal

    Coefficient for calculation o

    Coefficient for calculation of inner(Advanced level). The default valdeformation, this value will be cal

    Angle between concrete co

    Angle between concrete comprescalculated automatically or inputtangle of compression strut. Thismember data is not defined) or in

    •  Auto - angle of compressbetween qmin and qmax

    •  User(angle) - angle of co

    inputted value is outsidetaken into account for cal

    •  User(cotangent) - angleangle. If the inputted valuvalue is taken into accou

    Minimal and maximal angle of cothe Manager of national annex.

    Angle of shear reinforceme

    There are differences in using threinforcement and check.

    •  Design - angle of shear fconcrete member data isthe angle of shear reinfor

    •  Check - angle of stirrupsinput shear reinforcemen

    Type of member can be defined imember data

    e calculation

    effective depth of cross-section

    tive depth of cross-section can be set and loaded frfault value is 0.9. If the value cannot be calculated fculated by a simplified formula:

    lever arm

    lever arm can be set and loaded from the concretee is 0.9. If the value cannot be calculated from the

    culated by a simplified formula:

    pression strut and beam axis

    sion strut and beam axis perpendicular to the sheard by the user in SEN depending on parameter Typarameter can be changed in Concrete setting (if 1D1D concrete member data. There are the following

    ion strut is calculated automatically as minimal valuto condition according to equation 6.29 in EN 1992-

     

    mpression strut be input directly by the user as an a

    f the interval qmin and qmax , the minimal or maxiculation

    f compression strut be input directly by the user ase is outside of the interval qmin and qmax , the minit for calculation.

    mpression strut is a parameter of national annex an

    t

    angle of shear reinforcement in calculation betwee

    rce for member = Beam, can be set directly in Connot defined) or in 1D concrete member data. For mcement is always 90 degrees and cannot be chang

      is loaded from inputted shear reinforcement. It is onlt with an angle of 90 degrees in SEN 15.

    n properties of member via parameter Type or direc

    m the concreterom the plane of

    settingsplane of

    force can becalculation/inputconcreteptions:

    1-1

    ngle. If the

    um value is

    otangent of themal or maximum

    can be edited in

    n design of

    rete setting (if 1Dmber = Column,d.

    ly possible to

    tly in 1D concrete

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    Use equivalent first order v

    This setting allows to the user to1-1 will be taken into account forConcrete setting for Advanced morder moments, therefore this val

    Coefficient for calculation o

    Coefficient for calculation of forceconcrete settings (Advanced levemember is in compression, whichminimal eccentricity. Member is i

    Isolated member

    Check box for determination if thautomatic determination by the p

    others members. This setting canColumn (Advanced mode). Thisgeometrical imperfection, clause

    Buckling data

    The detailed description of inputtidescribed in Topic Training – Buconcrete members there are addi

    These additional data are import5.2(5) in EN 1992-1-1) and theyrelative lengths (member proper

    There are following additional dat•  Combo box Tot. height 

    or length of the isolated c

    o  Calculate – the tmembers in the

    o  User – the valueaccount if Calcul

    •  edit box Tot. height – thiisolated columns directlyset in combo box Tot. He

      lue

    et, if equivalent bending moment according to 5.8.he calculation of first order eccentricity. This settingde. The code EN 1992-1-1 recommends the use of

    ue is set to Yes by default.

    force at which member is in compressi

    s, when member is in compression, can be set andl). Default value is 0.1. This coefficient is used for dis necessary for calculation second order effect, imcompression, if condition below satisfies:

    member is an isolated member or not. Default settiogram and the member is isolated, if the member is

    be changed in 1D concrete member data for Meetting is used for calculation length of the member

    5.2(6) in EN 1992-1-1.

    ng buckling data and the way of calculating bucklingkling lengths. There is described the general functiotional parameters for definition of buckling data.

    nt for calculation of eccentricities caused by imperfan be defined in tab-sheet Buckling data in dialog

      ties > parameter Buckling and relative length > butt

    a:this combo allows to set type of calculation of total

    olumns. There are two items in the combo box:

    ot height. will be calculated automatically as sum ofuckling system

    can be inputted directly by the user. The input valuate = User

    s edit box allows to input total height of building or lby the user. The input value will be taken into accoight 

    Design

    .2(2) in EN 1992-  can be done in

    equivalent first

    n

    loaded fromtermination, if

    perfection and

    ng is thenot linked the

    ber type =or calculation of

    data arenality, but for

    ction (see clausee Buckling andn Edit ).

    height of building

    lengths of all the

    will be taken into

    ngth of thent if item User is

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    Topic Training – New Concrete

    18

    •  edit box my - is the number of vertical members contributing to the total effect of theimperfection perpendicular to y axis of LCS. It means that the value is used for recalculation ofbending moment around y axis. Only one value can be set for all columns in a buckling system

    •  edit box mz - is the number of vertical members contributing to the total effect of theimperfection perpendicular to z axis of LCS. It means that the value is used for recalculation ofbending moment around z axis. Only one value can be set for all columns in a buckling system

    The important parameter for calculation of buckling data is the type of structure (braced or unbraced).

    The global type of structure can be set in Concrete Setting (Design defaults > Default sway type). Forexample, the structures is braced perpendicular to y axis of GCS, if parameter Sway around y axis =NO (it means that the structure is not prone to sway perpendicular to y axis).

    Use geometric imperfection

    This setting allows the user to set, if geometrical imperfection will be taken into account of ULS or SLS.This setting can be done in Concrete settings (if 1D concrete member data is not defined) or directly in1D concrete member data for Member type = Column.

    The imperfection shall be taken into account in ultimate limit states and need not to be considered forserviceability limit states, see clause 5.2(2P) and 5.2(3) in EN 1992-1-1, therefore default setting inSEN is:

    •  ULS - use geometric imperfection = Yes , it means geometric imperfection will be taken intoaccount

    •  SLS - use geometric imperfection = No , it means geometric imperfection will not be taken intoaccount

    Use minimum eccentricity

    User can set if minimum first order eccentricity, calculated according to clause 6.1(4) in EN 1992-1, wil lbe taken into account in the calculation of first order eccentricity including geometrical imperfection forULS. This setting can be done in Concrete settings (if 1D concrete member data is not defined) ordirectly in 1D concrete member data for Member type = Column by using Advanced mode/level. 

    Use second order effect

    This setting allows the user to set if second order effect will be taken into account. This setting can bedone in Concrete settings (if 1D concrete member data is not defined) or directly in 1D concretemember data for Member type = Column.

    If check box Use second order effect = Yes, then the second order effect will be taken into account, ifconditions below are satisfied:

    •  the combination for ULS is used

    •  Member type = Column and it in case, that column is in compression

    •  calculated slenderness is greater than limit slenderness

    Design defaults

    Design defaults is a special group of properties where the user can define the basic parameters(diameter of longitudinal and shear reinforcement, type of value of concrete cover...) for design oflongitudinal and shear reinforcement. This setting can be done in Concrete settings (if 1D concretemember data is not defined) or directly in 1D concrete member data.

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    Determination of unfavoura

    This setting allows the user to seimperfection wil l be taken into acmember data is not defined) or diof Advanced mode/level.

    Shifting of bending momentsAdditional tensile forces causedsimplified calculation based on sbending moment is calculated onl

    Distance for shifting is calculated

    •  for beams

    •  for beams as slab

    Automatic calculation of angle besimplified method for shifting with

    •  shear of member for calcat whole cross-section p

    •  value Ak  and u k  for calculwhich has the same cros 

     

    Determination whether memb

    The second order effect, minimalfor member = Column, which is isatisfied:

    le direction

    in which direction the second order moment and th  ount. This setting can be done in Concrete settings

    rectly in 1D concrete member data for Member type

    y shear and torsion is taken into account in SEN15ifting of bending moments according to clause 9.2.1

    ly for beams and beams as slab.

    around for both axes dependent on type of member

     

    tween the concrete compression strut and beam axithe following simplifications:

    ulation value V Rd.max  is calculated as minimum widthrpendicular to direction of shear forces

    ation of T Rd.max  is calculated for effective rectangulas-sectional area and same perimeter as inputted cr 

      r is in compression

    eccentricity and geometrical imperfection are takencompression. Column is in compression if conditio

    Design

    e geometrical(if 1D concrete= Column in case

    by using a.3(2). Shifting of

    s is calculated by

    of cross-section

    cross-section,ss-section

    into account onlys below are

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    Topic Training – New Concrete

    First order bending moments

    The calculation of first order mocolumn is in compression it runs

    •  first order eccentricity wit

    •  eccentricity caused by im

    •  first order eccentricity inc

    Calculation of first order ec

    There are two options for calculacheck box Use equivalent first

    •  the equivalent first ordermoments will be the sambox Use equivalent firstis not defined) or in 1D c

    •  the first order eccentricitythat bending moments inequivalent first order vdefined) or in 1D concret

    The 1st order equivalent moment

    M0,ey = max (0,6*M02,y +0,

    M0,ez = max (0,6*M02,z +0, where

    •  M01y(z) is the first end benthe second end bendingcalculation of limit slende

    •  M02y(z) is the second endas the first end bendingcalculation of limit slende

     The user (real) reinforcement defcalculation effective depth of cro ULS in service Internal forces)

    Calculation of eccentricity d

    The imperfection in SEN is repreThe imperfection shall be taken iserviceability limit states, see claindependently if the imperfection

    The inclination is calculated arou

    where

    ith imperfection

    ent is calculated only for Member type = Column anccording to the following procedure:

    hout effect of imperfection is calculated,

    perfection is calculated,

    luding effect of imperfection is calculated.

    entricity without effect of imperfection

    ing first order moments and eccentricity in SEN deprder value.

    bending moments are taken into account. It means,e at the whole length of the member. This option isorder value = Yes in Concrete settings (if 1D concncrete member data

    is calculated from bending moments in the currenteach section can be different. This option is used iflue = No in Concrete settings (if 1D concrete memmember data

    is calculated according to clause 5.8.8.2 (2) in EN 1

    4*M01,y; 0,4* M02,y)

    4*M01,z; 0,4*M02,z)

    ding moments around y(z) axis of LCS with lesser aoment. |M01y(z)| < |M02y(z)| The same values ar

    rness

    bending moments around y(z) axis of LCS with greaoment. |M02y(z)| ≥ |M01y(z)| The same values are

    rness

    ined via REDES and free bars are not taken into acs-section for design reinforcement to column (Type

    ue to imperfection

    ented by an inclination according to clause 5.2(5) ito account in ultimate limit states and need not to bse 5.2(2P) and 5.2(3) in EN 1992-1-1. The user ca

    will be taken into account for ULS or SLS.

    d both axis (axis y and z) of LCS according to form

     

    d in the case that

    ending on the

    that bendingsed if check

    rete member data

    ection. It follows,check box Useer data is not

    992-1-1

    bsolute value asused for the

    ter absolute valueused for the

    ount forof check = Design

    EN 1992-1-1.e considered for

    set

    ula:

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    •  θ0 is the basic value of incan be different for eachEN 1992-1-1 > General

    •  αh is the reduction factorcalculated according to f

     •  αm,y(z) is the reduction fac

    •  l is the length of a columor not

    o  isolated member

    o  not isolated memThis height can b

    •  my(mz) is the number of

    perpendicular to y(z) of Lmoment around y(z) axis

    The effect of imperfection for an ieccentricity according to clause 5

    The direction (sign) of the valuedirection (sign) of first order ecce 

     

    Minimum first order eccentr

    The minimum first order eccentri

    The minimum eccentricity is takeYes 

    The direction (sign) of minimum feccentricity

    Calculation of first order ec

    First order eccentricity including

    eoEd,y(z) = e0,y(z) + ei,y(z) >

    After calculation of the first orderincluding the effect of imperfectio

    M0Ed,y(z) = NEd* eoEd,z(y) 

    lination. The value is a National parameter; it meancountry. The value can be set in the Manager for n

    ULS > General > Theta_0 

    for the length of a column or the height of a structurrmula

    or for the number of members calculated according

    or the height of a structure depending on, if the me

    l = L, where L is the length of the member

    ber l = H, where H is the total height of the buildinge defined in Buckling data

    ertical members contributing to the total effect of th

    CS. It means, that this value is used for recalculatioof LCS. These value can be defined in Buckling dat

    olated column and for a structure is always taken i.2(7a) in EN 1992-1-1.

    f eccentricity caused by imperfection has to be thetricity.

    icity

    ity is calculated according to clause 6.1(4) in EN 19

     

    into account, if check box Use minimum value of

    rst order eccentricity has to be same as direction (s

    entricity including effect of imperfectio

      ffect of imperfection is calculated according to the f

    e0,min,y(z) 

    eccentricity including the effect of imperfection, thens around y (z) axis of LCS is calculated:

    Design

    s that this valuetional annex >

    . The value is

    to formula

    mber is isolated

    (buckling system).

    imperfection

    of the bendinga

    to account as an

    ame as the

    92-1-1.

    eccentricity =

    gn) of first order

    rmula below

    st order moment,

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    Topic Training – New Concrete

    Calculation of second order ef

    The EN 1992-1-1 defines several(general method, simplified methcurvature...). SEN allows makingmethods:

    •  General method - equilibcalculated taking into acc

    and creep, see clause 5.•  Simplified method based

    The second order effect by the si

    •  for the ultimate limit state

    •  only for Member type = C

    •  check box Use second or

    •  calculated slenderness is

    Calculation of second order

    Nominal second order moment is

    M2,y(z) = NEd* e2,z(y) 

    The second order eccentricities a

    lz(y) >lz(y),lim  Use sec

    YES YES

    YES NO

    NO YES

    NO NO

    The direction (sign) of final valueorder eccentricity

    Calculation of curvature

    The curvature for the calculationin EN 1992-1-1.

    (1/r)y(z) = Kr*Kf,y(z)*(1/r0 It follows that the calculation of cimportant are the following:

    •  relative normal force

    •  mechanical ratio of reinfo

    •  effective creep ratio

    •  slenderness of the colum

    •  effective depth of cross-s

    •  basic value of curvature

    fects

    methods for the analysis of second order effects wid based on nominal stiffness, simplified method bathe analysis of the second order effect by using the

    ium and resistance is verified in the deformed stateount the relevant effects of cracking, non-linear mat

    .2(2) in EN 1992-1-1,on nominal curvature according to EN 1992-1-1, cla

    mplified method is taken into account:

    olumn and it in case that the column is in compress

    der effect in switched ON

    greater than limit slenderness

    moment

    calculated according to clause 5.8.8.2(3) in EN 199

    re calculated according to formulas below

    nd order effect Second order eccentricity

    e2y(z) = 0

    of second order eccentricity has to be same as dire

    f second order eccentricity is calculated according

    y(z) 

    rvature depends on many parameters and factors,

    rcement

    n

    ection

    h axial loaded on nominal

    following

    deformations areerial properties

    use 5.8.8

    ion

    2-1-1

    tion (sign) of first

    o clause 5.8.8.3

    ut the most

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    Coefficient Beta

    Slenderness of the column for calwhich is calculated according to f

     

    Effective depth of cross-sec Effective depth of cross-section icalculated according to clause 5.the reinforcement is not symmetriDesign of concrete structures”  th

    •  for symmetrical reinforcesides, but part of it is dist

    •  for other cases (design o

    •  for other cases (check) -simplified calculation, if t

    The calculation of the radius of greinforcement from tensile edgeare calculated for design of reinfodesign of reinforcement and for c The user (real) reinforcement defcalculation of effective depth of c  

    Design of reinforcement f

    Total area of reinforcement

    As =μs.Ac

    Calculation of ratio of reinforcem

    if σy= 0 MPa and σz=0, then ratioy Calculation area of reinforcement

    As,y(z) = ratioy(z)*As 

    Distance of centre of tensile reinf

    Posit ion of reinforcement from ce

    lculation of factor Kf,y(z) is taken into account by pararmula:

    tionused for the calculation of basic value of curvature.8.3(2) in EN 1992-1-1. The EN 1992-1-1 is not givi

    cal, but according to “Designers’ guide to EN 1992-following rules are used for the calculation of effec

    ent and in case if all reinforcement is not concentrributed parallel

    reinforcement)

    the effective depth is calculated from plane of equlibis value cannot be calculated from this plane

    ration of the total reinforcement and distance of ceepends on the shape of the cross-section and, if thrcement or for checks. It means that this value canhecks.

    ined via REDES and free bars are not taken into acoss-section for design reinforcement of a column

    or rectangular section

    nt in y and z direction

    = ratioz=0.5

    in direction of y(z) axis of LCS

    rcement from tensile

    ntroid of concrete cross-section in direction of y (z)

    Design

    meter (βy(z)) ,

    and it isng rules where

    Eurocode 2:ive depth:

    ted on opposite

    rium or by

    tre of tensileinternal forcese different for

    ount for

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    Topic Training – New Concrete

    Second moment of reinforcemen

    Radius of gyration of the total rei

    Design of reinforcement f

    Total area of reinforcement

    As =μs.Ac 

    Distance of centre of tensile reinf

    Posit ion of reinforcement from ce

    Second moment of reinforcemen

    Radius of gyration of the total rei

    Design of reinforcement f

    Total area of reinforcement

    As =μs.Ac 

    Area of reinforcement in each ed 

    Asi = As /nedge 

    Distance of centre of tensile reinf

    area

    forcement area

    or circular section

    rcement from tensile

    ntroid of concrete cross-section in direction of y (z)

    area

    forcement area

    or other cross-sections

    e

    rcement from tensile

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     Posit ion of reinforcement from ce

    Second moment of reinforcemen

    Radius of gyration of the total rei

    Checks for all type of cro 

     Total area of reinforcement

    Second moment of reinforcemen

    Radius of gyration of the total rei

    Basic value of curvature

    There is a rule for the calculationsymmetrical reinforcement. in EN

    For unsymmetrical cross-section“Designers’ guide to EN 1992-2should be used

    ntroid of concrete cross-section in direction of y (z)

    area

    forcement area

    s-sections

    area

    forcement area

    of basic curvature only for symmetrical cross-sectio1992-1-1, where the formula below should be used

     

    with unsymmetrical reinforcement according to recourocode 2: Design of concrete structures”  the follo

    Design

    n with:

    mmendation ofing formula

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    Topic Training – New Concrete

    Calculation of unfavourable

    The minimum eccentricity, geomcalculated in both directions. Thelimit slenderness and can be calcof the first-order moments and thoccur in the direction where the dlength of the column, is greatest.

    moment and second-order momeTherefore it is possible in SEN, tsecond order moment and geom

    There are 3 possibilities:

    •  Auto - the direction for thdetermined automatically

    The uniaxial calculation fare satisfied, otherwise b

    •  Uniaxial - second order

    direction (more unfavourassigned (accidental benboth direction), the seconin both directions.

    •  Biaxial - second order efdirections.

    There are no rules for the determused the procedure described inDesign of concrete structures, Gunfavourable direction is determi 

    ηy > ηz - unfavourableηy < ηz - unfavourableηy = ηz - both direction

     

    direction

    trical imperfection and first order moments includinsecond order effect depends on the comparison ofulated too in both directions. The column will deflect

    accidental moment. It proposes that the second or  eflection, due to first-order moment as a proportion

    It is assumed, though this is not stated in the code,

    nts will only occur in one direction and not in both di  define the unfavourable direction; it means the diretrical imperfection will be taken into account.

    e calculation of second order effect and geometricalaccording to conditions 5.38a and 5.38b in EN 199

      r automatic determination is taken into account; if ciaxial calculation will be used.

    ffect and geometrical imperfection is taken into acc

    ble direction). In case that the more unfavourable dding moments, effective length and css properties ad order effect and geometrical imperfection will be t

    fect and geometrical imperfection is always taken in

    ination of unfavourable direction in EN 1992-1-1, th“Designers’ guide to EN 1992-1-1 and EN 1992-1-2:neral rules for buildings and structural fire design” ,ed according to the equation below:

    direction is around y axisdirection is around z axiss are taken into account

    imperfection arelenderness andunder the actioner moments willf the effectivehat the accidental

    rections at once.ction in which the

    imperfection is-1-1

    onditions below

    unt only in one

    irection cannot bere the same inken into account

    o account in both

    refore in SEN isEurocode 2:here the

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    Design

    Slenderness

    Slenderness and limit slenderness of a column should be checked before the design or check of themembers. Using the second order effect in the calculation depends on the check of slenderness,because if the check of slenderness is greater than the limit slenderness, the second order effect hasto be taken into account for the column calculation.

    Conditions Calculation of second order effect

    YESNO

    The slenderness and limit slenderness is calculated according to clause 5.8.3.1 and 5.8.3.2 in EN1992-1-1. The following preconditions are used for calculation:

    •  The slenderness is calculated for beams and columns and for general load (N+My+Mz)

    •  The limit slenderness is calculated only if the axial forces is smaller than zero (N < 0 kN)

    •  Cross-section with one polygon and one material is taken into account in version SEN 15

    •  The material of all reinforcement bars has to be same in SEN 15

    Buckling data

    The detailed description of inputting buckling data and the way of calculating buckling data aredescribed in Topic Training – Buckling lengths. There is described the general functionality, but for thecalculation of slenderness and limit slenderness the following properties are important:

    •  properties for the calculation of effective length of the member around y and z axis

    •  if the member is braced (Sway = NO) or unbraced (Sway = YES ) around y and z axis

    The important parameter for calculation of buckling data is type of structure (braced or unbraced). Theglobal type of the structure can be set in Concrete Settings (Design defaults > Default sway type) .For example, the structure is braced perpendicular to y axis of GCS, if parameter Sway around y axis= NO  (it means the structure is not prone to sway perpendicular to y axis).

    Creep coefficientThis value can be set in the Concrete settings by using Advanced level or in 1D memberdata (advanced mode is ON), if it is defined. The creep coefficient can be calculated automatically byusing the input of ages of concrete and relative humidity (see annex B.1 in EN 1992-1-1), if the Typeinput of creep coefficient = Auto. If the Type input of creep coefficient = User value, the creepcoefficient can be inputted directly by the user.

    Estimation of ratio of longitudinal reinforcement

    There are some values in the design of reinforcement, which are dependent on the area ofreinforcement, for example:

    •  mechanical reinforcement ratio (μ) in the calculation of limit slenderness (clause 5.8.3.1(1) in

    EN 1992-1-1)

    •  mechanical reinforcement ratio (μ) in the calculation of second order eccentricity (clause5.8.8.3(3) in EN 1992-1-1)

    •  radius of gyration of the total reinforcement area (is) in the calculation of second ordereccentricity (clause 5.8.8.3(2) in EN 1992-1-1)

    •  calculation of the exponent of interaction formula x in the biaxial bending calculation (clause5.8.9.(4) in EN 1992-1-1)

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    Topic Training – New Concrete

    These values should be calculated before the design of reinforcement, but before the design we do notknow the area of reinforcement. It follows that for calculation of this value:

    •  area of reinforcement will be neglected,

    •  iterative calculation will be used,

    •  area of reinforcement will be estimated.

    The third solution is implemented in SEN via the parameter Estimation ratio of longitudinalreinforcement for recalculation internal forces, where the user can set the ratio of reinforcement, whichwill be used for calculation of the values above. This value can be set in the Concrete settings byusing Advanced level or in 1D member data (advanced mode is ON), if it is defined. Total area ofreinforcement is calculated according to formula:

    As = μs.Ac 

    Calculation of slenderness

    The slenderness (slenderness ratio) is calculated according to clause 5.8.3.2(1) in EN 1992-1-1.

    The simplified values and formulas for calculation of effective length for isolated columns, braced andunbraced frames are described in clauses 5.8.3.2(2-4) in EN 1992-1-1

    The slenderness is calculated in each section, it follows that for an arbitrary member and member witha haunch, the slenderness can be different along the length of the member

    Calculation of limit slenderness

    The limit slenderness is calculated according to clause 5.8.3.1(1) in EN 1992-1-1. The limitslenderness and the slenderness are always checked separately for each direction according to5.8.3.1(2) in EN 1992-1-1. The formula for the calculation of limit slenderness in EN 1992-1-1 is anational parameter, it means, that a different formula, method or value can be used in some countries,see concrete setup (Manager for national annex > EN 1992-1-1 > General > ULS > General >lambda_lim)

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    Design

    There are changes in the calculation of limit slenderness for some national annex, see the table below:

    National annex Calculation of limit slenderness

    Standard EN 1992-1-1 λ _lim = (20*A*B*C) ⁄ √n 

    DIN EN 1992-1-1 NAλ _lim = 25 ... for |n| ≥ 0,41λ _lim = 16 ⁄√n ... for |n| < 0,41

    CSN 1992-1-1 NA

    STN 1992-1-1 NAλ _lim = (20*A*B*C)

     ⁄ √n ≤ 75 

    The limit slenderness calculated according to standard EN 1992-1-1 depends on:

    •  effective creep ratio φeff (coefficient A),

    •  mechanical reinforcement ratio w (coefficient B),

    •  shape (ratio) of bending moment rm (coefficient C),

    •  relative normal force n.

    The limit slenderness is not calculated if normal force (relative normal force) is compressive.

    The limit slenderness is calculated in each section, it follows that for an arbitrary member or a memberwith a haunch, the normal force is not uniform at the length of the member or the reinforcement is notconstant at the length, the limit slenderness can be different along the length of the member.

    Effective creep ratio

    In SCIA Engineer, for the calculation of limit slenderness the creep ratio is used loaded from theconcrete settings (if member data is not defined ) or concrete member data. It means that if the userwants to take into account the effective creep ratio according to clause 5.8.4 in EN 1992-1-1, the valueof this creep ratio has to be directly inputted in the concrete settings or the concrete member data.Otherwise, the final creep ratio will be taken into account.

    The coefficient A is calculated according to formula:

    A = 1/1+0,2•φ.

    Mechanical reinforcement ratio

    Check

    The mechanical reinforcement ratio depends on total area of longitudinal reinforcement. For checks,the total area of reinforcement is calculated from inputted reinforcement via REDES or Free bars. Themechanical reinforcement can be different at the whole length of the column and in each section of themember and it is calculated according to formula below:

    The coefficient B is calculated according to formula:

    B = √(1+2∙ω)

    Design

    The mechanical reinforcement ratio depends on total area of longitudinal reinforcement. For design ofreinforcement, total area of reinforcement is calculated from estimation ratio loaded from Concretesettings (if concrete member data is not defined ) or concrete member data. The mechanical

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    Topic Training – New Concrete

    reinforcement ratio is the same aformula:

    The coefficient B is calculated ac

    B = √(1+2∙ω)

    Shape of bending moment

    Shape of bending moment is expinfluence of imperfection aroundon the type of member and on th

    •  if type of member is unbr

    •  if type of member is bracfrom or predominantly dualong the member is not

    •  otherwise, value rm is cal

    where

    •  M01y(z) is first end bendinsecond end bending moof limit slenderness.

    •  M02y(z) is second end benfirst end bending momenlimit slenderness.

    •  rm.y(z) is ratio of bending

    limit slenderness around

    The coefficient C is calculated ac

    Relative normal force

    Relative normal force is calculate

    n = NEd / Ac•fcd 

    If normal force is not uniform at lmember with haunch), the maxibe taken into account.

    the whole length of the column and it is calculated

    ording to formula:

    ressed by the ratio of first order end bending momehe selected local axis. The ratio of these moments (shape of shear force.

    aced around local axis (sway = YES), then rm = 1,0

    d around local axis (sway = NO) and first order moe to imperfections or transverse loading (maximumat the beginning or at the end of the member), then

    ulated according to formula

    moment around y(z) axis of LCS with lesser absolent. | M01y(z) |< | M02y(z) | The same values are used

    ing moment around y(z) axis of LCS with greater a. | M02y(z) |≥ | M01y(z) | The same values are used for

    oment around y(z) axis of LCS which is used for th

    y(z) axis of LCS.

    ording to formula:

    d according to formula

    ngth of column or part of the column (for arbitraryum value of normal force at length of column or par

    according to

    ts without thevalue rm) depends

    ents arise onlybending momentrm= 1,0

    te value asfor the calculation

    bsolute value ashe calculation of

    calculation of

    ember andof the column will

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    Design

    31

    Reinforcement design – theory

    SEN 15 allows to design reinforcement for a general cross-section which is loaded by general forces(N, My,Mz,Vy,Vz, Mx) . It is possible to design:

    •  statically required longitudinal reinforcement

    •  longitudinal reinforcement including detailing provisions

    •  statically required shear reinforcement

    •  shear reinforcement including detailing provisions

    •  torsional longitudinal reinforcement

    The following preconditions are used for calculation:

    •  additional tensile forces caused by shear is taken into account by shifting of bending moments,see clause 9.2.1.3(2)in EN 1992-1-1,

    •  cross-section with one polygon and one material is taken into account,

    •  practical (user defined) reinforcement is not taken into account.

    Parameters

    Design defaults

    Design defaults is a special group of properties where the user can define the basic parameters(diameter of longitudinal and shear reinforcement, type of value of concrete cover...) for design oflongitudinal and shear reinforcement. This setting can be done in Concrete settings (if 1D concretemember data is not defined) or directly in 1D concrete member data.

    Three types of 1D members with different design defaults parameter are supported in SEN 15:

    •  Beam - member predominantly loaded by bending moments, for which longitudinal and shearreinforcement can be designed. There are the following parameters:

    o  Longitudinal reinforcement

      diameter of upper/lower reinforcement  type of cover of upper and lower reinforcement (auto or user defined value)

      type of cover of side reinforcement (upper, lower or user defined value)

      material of longitudinal reinforcement (only in 1D concrete data)

    o  Stirrups

      diameter of stirrups

      number of cuts (number of shear links)

      angle of shear reinforcement

      material of shear reinforcement (only in 1D concrete data)

      basic (user defined stirrup) – the user can define user value of area of shear

    reinforcement per meter with some angle and material of this reinforcement

    •  Beam as slab - member predominantly loaded by bending moments for which shearreinforcement is not designed (for example cut of 2D member). There are the followingparameters:

    o  Longitudinal reinforcement

      diameter of upper/lower reinforcement

      type of cover of upper and lower reinforcement (auto or user defined value)

      type of cover of side reinforcement (upper, lower or user define value)

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    Topic Training – New Concrete

      material of longitudinal reinforcement (only in 1D concrete data)

    •  Column - member predominantly in compression for which longitudinal and shearreinforcement can be designed. There are the following parameters:

    o  Longitudinal reinforcement

      diameter of upper/lower reinforcement

      type of cover of upper and lower reinforcement (auto or user defined value)

      type of cover of side reinforcement (upper, lower or user define value)

      material of longitudinal reinforcement (only in 1D concrete data)

    o  Stirrups

      diameter of stirrups

      number of cuts (number of shear links)

      material of shear reinforcement (only in 1D concrete data)

    Design defaults in concrete settings:

    •  there is a possibility to define design defaults for all types of 1D member (beam, column, beamslab)

    •  it is not possible to input/edit the material of longitudinal and shear reinforcement in this setting,but material is loaded from project data and it is the same for all type of members

    Design defaults in 1D concrete member data

    •  only design defaults of selected type of member can be edited in this setting

    •  material of shear and longitudinal reinforcement can be edited directly in the concrete memberdata

    Design method

    The user can set the type of method for design of reinforcement for columns and beams This settingcan be done in Concrete settings (if 1D concrete member data is not defined) or directly in 1D concrete

    member data for Member type = Column or beams by using Advanced mode/level.

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    Design

    Four types of methods for design statically required reinforcement are supported for beams andcolumns:

    •  auto

    •  uniaxial around y

    •  uniaxial around z

    •  biaxial

    Uniaxial method around y axis is always used for type of member = beam as slab.

    Biaxial method independently on selected method is always used for circular and oval columns.

    Limit ratio of bending moments for uniaxial method

    The automatic method for design of reinforcement is based on the ratio of bending moments around yand z axis and on the value of limit ratio of bending moments for using uniaxial method. This limit valuecan be set and loaded from concrete setting (Advanced level). Default value is 0.1. It follows, if ratio ofmaximal bending moments around y and z axis for all combinations in current section is lesser thanlimit ratio of bending moments, uniaxial method is used for design, otherwise biaxial method is used.

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    Topic Training – New Concrete

    Design of longitudinal reinfor

    The design of statically required ruses an iteration routine to calculmaterial properties and position ointeraction of the normal force (N

    There are the following assumpti

    •  Plane sections remain pl•  Strain in bonded reinforc

    the concrete at the same

    •  Tensile strength of the co

    •  The stresses in the concr(bilinear or parabola-rect

    •  The stresses in the reinfo(bilinear with or without i

    Four methods are supported in S

    •  uni-axial around y axis

    •  uni-axial around z axis

    •  biaxial

    •  auto

    Uniaxial method around y axis is

    Biaxial method independently on

    Designed required area is for a bdirections of axis’s of LCS of the

    Except of statically required longilongitudinal reinforcement (As.prov  

    recalculated to real bars, where:

    •  diameter of longitudinal rinput diameter)

    •  minimal number of bars

    •  number of bars is rounde

    •  corner bars are taking intedge, and half of a bar fo

    ement

    einforcement is based on the calculation equilibriumate equilibrium based on the internal forces, the cro

      f reinforcement. Generally, this iterative method worwith uni-axial or bi-axial bending moments (My + M

      ns:

    ne.ment, whether in tension or compression, is the salevel

    ncrete is ignored.

    ete in compression are given by the design stress–ngular stress-strain diagram)

    rcing steel are given by the design stress–strain relclined horizontal branch stress-strain diagram)

    EN 15 for design of reinforcement for beams and co

      always used for type of member = beam as slab.

    selected method is always used for circular and ova

    tter overview and graphical presentation recalculatross-section (member).

    udinal reinforcement (As.req), the program calculates. It is the statically required longitudinal reinforceme

    inforcement is taken into account (cross-sectional

    er edge is 2

    d to whole number

    o account for all edges (half of a bar is taken into acr second edge)

    . This methods-section,ks for thez).

    e as the strain in

    train relationships

    tionships

    lumns:

    l columns.

    d to the

    also the providednt area

    rea of bars with

    count for one

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    Uniaxial method for design

    This method allows designing the(MEd). In case, that the cross-secmoment is ignored:

    •  for method uniaxial aroureinforcement is designe

    •  for method uniaxial aroureinforcement is designe

    The results of uniaxal method de

    •  for beams and beam as

    o  reinforcement isrequired or cross

    o  the reinforcemen

    o  the reinforcemen

    •  for columns

    o  reinforcement is

    o  reinforcement is

    The position of reinforcement is

    reinforcement only for normal force (NEd) and oneion is loaded by bending moments around both axe

    nd y, the bending moment MEdz is ignored, it followonly for normal forces NEd and bending moment M

      nd z, the bending moment MEdy is ignored, it followonly for normal forces NEd and bending moment M

      end on type of member:

    lab

    esigned only at one or two edges (if compressive r-section is loaded only by normal force)

    t can be unsymmetrical

    t can be designed in more layers

    esigned always at two edges and the reinforcemen

    esigned always at one layer

    alculated from parameters defined in Design defaul 

    Design

    ending moment, one bending

    that the

    Edy 

    that theEdz 

    inforcement is

    t is symmetrical

    s.

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    Topic Training – New Concrete

    Calculation position of reinf

    The position of reinforcement is cDesign defaults. The position of roffset of current cross-section indifferent for each edge and it is c

    •  beam

    •  beam as slab

    •  column

    The edge, for which the parametcrossed by the line in direction ofthe biggest linear stress in the cr  The edge, for which the parametcrossed by the line in direction ofthe biggest linear stress in the cr  

    Design for several layers

    The program is able to design reifollowing procedure is used:

    •  the reinforcement is desi

    •  designed area at each ereinforcement calculatedplaced along the edge

    •  if designed area at somelayer is done where:

    orcement

    alculated from parameters, which are defined in Coeinforcement is always in the middle of the edge, wistance as. This distance and diameter of reinforcelculated in dependence on type of member accordi

    r of upper reinforcement is used, is the edge abovebending moment resultant for dangerous combinatiss-section.

    r of lower reinforcement is used, is the edge underbending moment resultant for dangerous combinatiss-section.

    nforcement for more layers. It is an iterative calculati

    ned at the first layer for the selected method

    ge is checked with maximum area of reinforcementfrom minimum surface to surface distance of bars),

    edge is bigger than maximum area, then new desig

    crete settings >ich is created byent can be

    ng to formulas:

    axis which isn, which causes

    axis which isn, which causes

    ion, where the

    (area ofwhich can be

    n for the next

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    o  the area of reinfo

    o  the position of rei

    o  design with newreinforcement fro

    Maximal number of layers which ierror, when maximum number of

    Design for more layers is support

    rcement As,max is inputted to the previous layer

    inforcement for the next layer is calculated

    positions of reinforcement is run with taking into accm the previous layer

    s taken into account is 5 in SEN 15. The program filayer (nmax = 5) is inefficient.

    ed only for beams and beams as slab.

    Design

    unt

    ishes with some

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    Topic Training – New Concrete

    Recalculation reinforcemen

    Longitudinal reinforcement can bsection. Designed required area idirections of axes of LCS of the cdepends on the angle of the edgfollows, that 4 areas of reinforce

    Asz.req+ 

    requiplacefromassiglesse

    Asz.req- 

    requiplacefromassiglesse

    Asy.req+ 

    requiplacefromassiggreat

    Asy.req- 

    requiplacefromassiggreat

    to directions

    designed to more edges of a cross-section and fors for a better overview and a graphical presentationross-section (member). The recalculated area of reifrom y-axis and the angle of bending moment resulent can be presented in graphical and numerical o

    red area of reinforcement (mostly designed for bendd on edges above axis y with angle of edges lessery- axis. The edges with angle 45 degree and abovened to this direction if direction of bending moment rr or equal than 45 degree.

    red area of reinforcement (mostly designed for bendd on edges under axis y with angle of edges lessery- axis.The edges with angle 45 degree and underned to this direction if direction of bending moment rr or equal than 45 degree.

    red area of reinforcement (mostly designed for bendd on edges above axis z with angle of edges greatey- axis.The edges with angle 45 degree and abovened to this direction if direction of bending moment rer than 45 degree.

    red area of reinforcement (mostly designed for bendd on edges under axis z with angle of edges greatey- axis. The edges with angle 45 degree and underned to this direction if direction of bending moment rer than 45 degree.

    a general cross-  recalculated to

    forcementltant from y-axis. Ittput:

    ing moment My)than 45 degreeaxis y areesultant (αM) is

    ing moment My)han 45 degreexis y areesultant (αM) is

    ing moment Mz)r than 45 degreexis z areesultant (αM) is

    ing moment Mz)than 45 degree

    axis z areesultant (αM) is

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    Biaxial method for design

    This method allows designing theThis method is based on interacti

    Procedure of calculation:

    •  program designs initial arcross-section

    •  program increases areaand checks interaction fo

    •  if interaction formula is fuof reinforcement , if the p

    The results of biaxial method dep

    •  for beam and beam as sl

    o  the reinforcemen

    o  exponent of inter

    o  the reinforcemen

    •  for column

    o  reinforcement is

    o  exponent of inter

    o  reinforcement is

    Automatic method for desig

    There is a possibility to use the auniaxial or biaxial method accordi

    •  uniaxial method is used i

     reinforcement for normal force (NEd) and biaxial beon formula, equation 5.39 in EN 1992-1-1.

    ea of reinforcement according to linear stress on th

    f reinforcement, generates interaction diagram arormula in iterative calculation, till interaction formula i

    lfilled, then program checks plane of deformation anlane of deformation is not found

    end on type of member:

    ab

    t can be unsymmetrical

    action formula is 1

    t can be designed in more layers

    ymmetrical, if the cross-section is symmetrical

    action formula depends on shape of cross-section

    esigned always at one layer

    n

    tomatic method for design. The program automaticng to the values of bending moments around y and

    Design

    ding moments.

    edges of the

    nd y and z axesnot satisfied

    d increases area

    ally selects thez axis. It follows:

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    •  biaxial method is used in

    Different method for design of reidependence on values of bendin

    Design of shear reinforcement

    Design of shear reinforcement in

    •  design for biaxial shear f

    •  design for torsion

    •  design for interaction she

    Design is provided according to ctorsion is commonly based on thmodel is imagined in a concretehorizontal and diagonal membersbars are the main reinforcement

    There are the following assumpti

    •  The shear forces in bothdone for resultant of she

    •  The parameters of planeshear force resultant

    •  The design shear resistaaccording to clause 6.2.212.6.3 in EN 1992-1-1 is

    •  Design value of maximuand 6.2.3 (3,4) (VRd,max) i

    •  Design value of shear re

    •  The number of shear link

    concrete data

    •  The angle of compressio

    •  The torsional cracking m

    •  Design value of maximuclause 6.3.2(4) in EN 19

    •  The angle of stirrups for

    •  There are 5 possibilities f

    With the following limitations

    other cases

    forcement can be used in each section along themoments around y and z axis from all combination 

     

    ludes:

    rce

    ar force and torsion

    lause 6.1 -6.3 in EN 1992-1-1. Design reinforcementheory of the concrete truss-model too. In this theoeam. This truss-model has a set of vertical (or sligh. The vertical bars are considered to be the stirrups;nd the diagonal bars are the concrete struts.

    ns:

    directions are taken into account and design of sher forces

    of equilibrium (value d, z and h) are recalculated to

    ce of the member without shear reinforcement (VRd  (1) in EN 1992-1-1, if section is cracked in f lexure, o

    used

    shear force will be calculated according to clauseEN 1992-1-1

    istance is calculated according to 6.2.3 (3,4) (VRd,s)

    s is loaded directly from Design defaults from concr

    strut can be calculated automatically or defined by

    ment (TRd,c) is calculated according to clause 6.3.2(

    of torsional resistance moment (TRd,max) is calculat2-1-1

    esign of shear reinforcement for torsion has to be p

    or calculation of thin-walled closed section

    ember ins

    t for shear andry a virtual truss-

      ly diagonal),the horizontal

    r reinforcement is

    he direction of

    ,c) is calculatedtherwise clause

    .2.2(6) (VEd,max)

    in EN 1992-1-1

    te settings or

    the user

    5) in EN 1992-1-1

    ed according to

    erpendicular

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    •  Cross-section with one p

    •  The user (practical) reinf

    •  Design should be done othe resultant of shear for

    •  Inclined compression ch

    •  The widths of cross-secti

    There is no possibility for

    Except of statically required sheashear reinforcement (Aswm.prov  ). Itstirrups in longitudinal direction is

    Design shear reinforcement

    As was mentioned above, thereshear effects in concrete. In thisthe compressive concrete and terepresented by the diagram belo 

    lygon and one material is taken into account in ver

    rcement is not taken into account

    nly in case, that the angle between gradient of the ses is not greater than 15 degrees

    rd or inclined tensile chord are not taken into accou

    n for shear checks (value bw and bw1) are calculate

    definition of user value in SEN 15

    r reinforcement per meter (Aswm.req  ), the program calis statically required shear reinforcement, where therounded to 25 mm.

    for shear forces

    xists the general concept of “strut-and-tie” model foodel, the top compression and bottom tensile memsile reinforcement, respectively. The procedure for:

    Design

    ion SEN 15

    rain plane and

    nt

    d automatically.

    culates providedspacing of the

    the prediction ofbers representdesign can be

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    The formulas which are used for

    Generally, there are two possibiliexistence of cracked in bending:

    Shear concrete capacity in regio

    Shear concrete capacity in regio

    Additionally, there is calculated twhere load is applied in the uppe

    Maximal capacity of concrete co1992-1-1, because as has beenthe member axis.

    Statically required cross-sectionaformula 6.13 in EN 1992-1-1

    Design value of shear force sust

    6.13 in EN 1992-1-1

    Design value of shear force sust6.13 in EN 1992-1-1

    Final design value of shear forceformulas depending on type of m

    •  for beam as slab and for

    •  for other cases

    For a member with inclined chorcheck according to clause 6.2.1(chords. Nevertheless the calcula explained in the following figure.

    he calculation of each component of this model are

    ies for the calculation of shear capacity of concrete

    cracked in bending – formula 6.2.a, b in EN 1992-1

     

    uncracked in bending – clause 12.6.3(3) in EN 199

    e maximal shear force (VEd,max) without reduction by  r side of the member (see formula 6.5 in EN 1992-1

     

    pressive strut (VRd,max) is determined according to fentioned before, the angle of stirrups (θ) is always

    l area of the shear reinforcement per meter is calcul

    ined by shear reinforcement (VRd,s ) is calculated ac

    ined by shear reinforcement (VRd,s ) is calculated ac

    (VRd) carried by the member is calculated based onmber and area of shear reinforcement.

    other member with only detailing stirrups (Aswm.req =

    s the additional forces have to be taken into accoun ). The calculation is prepared for taking into accounion itself is not implemented yet. The partial compo

    the following.

    ependently on

    -1

    2-1-1

    b for member1).

    rmula 6.9 in ENperpendicular to

    ated from the

    cording to formula

    cording to formula

    the following

    0)

    t for the sheart also inclinedents are

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    Design shear reinforcement

    As was mentioned above, thereof torsion effects in concrete. In trepresent the compressive concr

    design can be represented by th

    The formulas which are used for

    for torsion

    xists a general concept of the “strut-and-tie” modelis model, the top compression and bottom tensilete and tensile reinforcement, respectively. The pro

    diagram below:

    he calculation of each component of this model are

    Design

    or the predictionembersedure for the

    the following.

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    Topic Training – New Concrete

    Torsional cracking moment is calstress caused by the torsional mfctd). It follows:

    Maximum of torsional resistance1-1.

    Statically required cross-sectionathe formula below:

    Design torsional resistance momformula below

    Final design value of torsional mfollowing formulas:

    •  for member without or wi

    •  for other cases

    ulated according to equation 6.26 in EN 1992-1-1,ment is equal to the design axial tensile strength of

    moment (TRd,max) is determined according to formula

    l area of the shear reinforcement per meter is calcul

    nt of torsional reinforcement (TRd,st) is calculated ac

    ment (TRd) carried by the member is calculated bas

    h only detailing stirrups for torsion (Aswm.req = 0)

    rovided that theconcrete (value

    6.30 in EN 1992-

      ated according to

    cording to the

    d on the

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    Design shear reinforcement

    As was mentioned above, thereof shear and torsional effects in cinteraction shear and torsion can

    Only minimum reinforcement is r1992-1-1) is satisfied:

    The maximum resistance of a meconcrete struts. In order not to ex

    1992-1-1) should be satisfied:

    Statically required cross-sectionaformulas

    for interaction shear and torsion

    xists a general concept of the “strut-and-tie” modeloncrete. The procedure for design of shear reinforcbe represented by the diagram below:

    quired, provided that the following condition (equati

    mber subjected to torsion and shear is limited by thceed this resistance the following condition (equatio

    l area of the shear reinforcement per meter is calcul

    Design

    or the predictionment for

    on 6.31 in EN

    capacity of then 6.29 in EN

    ated according to

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    Topic Training – New Concrete

    The force in shear reinforcementformula

    The maximum force which, can b

    Torsional longitudinal reinforc

    Additional tensile forces caused

    The required cross-sectional arewhen sum of design axial forces(bigger than 0). This area is calcpreconditions:

    •  reinforcement is designe

    •  longitudinal reinforcemen

    In a simplified way said, the longibelow:

    Additional tensile forces causedrequired reinforcement by shiftin

    caused by shear and torsion effect can be calculate

    e carried by shear reinforcement is given by formula

     

    ement

    y torsion are calculated from the equation 6.28 in E

    of the longitudinal reinforcement for torsion is calcNEd) and Additional tensile forces caused by torsionlated by using the biaxial method for design, with fol

    only for pure tension

    t is equally distributed on each edge of the cross-se

      udinal reinforcement for torsion is designed accordi

    y shear forces is taken into account in the design oof the bending moments.

    according to

    :

    N 1992-1-1:

    lated in the case,(Fsdt) is tensile

    llowing

    ction

    ng to the formula

    statically

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    Design

    47

    Practical reinforcement

    As in the past, a practical reinforcement layout can be defined for each 1D concrete member.Longitudinal bars, stirrups and free-form bars are available for manual input by the user. Additionally,also anchorage types may be chosen and their properties may be manipulated by the user.

    This practical reinforcement layout forms the basis for several ULS and SLS checks of reinforcedconcrete members.

    The input of practical reinforcement is explained more in detail in the Advanced Concept Training – 1Dconcrete members.

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    Check

    Stiffness

    The behaviour of reinforced concand it is therefore necessary to aaddition concrete is subject to sigthe curvature and stiffness of a r

    and stiffness of a reinforced conc

    Stiffness presentation command ifor calculation of stiffness is baseGenerally, two states of cross-se

    I. uncra