viscoelastic characterization dr. muanmai apintanapong
TRANSCRIPT
Viscoelastic Characterization
Dr. Muanmai Apintanapong
Elastic deformation - Flow behavior
Elastic behavior
Newtonian behavior
Newtonian liquid
E.
Introduction to ViscoelasticityAll viscous liquids deform continuously under the influence of an applied stress – They exhibit viscous behavior.
Solids deform under an applied stress, but soon reach a position of equilibrium, in which further deformation ceases. If the stress is removed they recover their original shape – They exhibit elastic behavior.
Viscoelastic fluids can exhibit both viscosity and elasticity, depending on the conditions.
Viscous fluid
Viscoelastic fluid
Elastic solid
Shear Stress
A
F
Shear Rate
Practical shear rate values
Viscosity =resistance to flow
Viscosity of fluids at 20C
Go to stress relaxation
Viscosity: temperature dependence
Flow curve and Viscosity curve
Flow behavior: flow curve
Flow behavior: viscosity curve
Stress Relaxation
Universal Testing Machine
Instron,
TA XT2
Force sensor
Stress Relaxation Test
Time, t
Strain
Stress
Elastic
Viscoelastic
Viscous fluid
0
StressStress
Viscous fluidViscous fluid
Strain is applied to sample instantaneously (in principle) and held constant with time.
Stress is monitored as a function of time (t).
Stress Relaxation Experiment
Str
ain
0 time
Stress Relaxation Experiment
Stress decreases with timestarting at some high value and decreasing to zero.
Response of Material
Str
ess
time0
Response of Classical Extremes
time0
stress for t>0is constant
time0
stress for t>0 is 0S
tres
s
Str
ess
Hookean Solid Newtonian Fluid
Stress is applied to sample instantaneously, t1, and held constant for a specific period of time. The strain is monitored as a function of time ((t) or (t)).The stress is reduced to zero, t2, and the strain is monitored as a function of timetort
Creep Recovery Experiment
Str
ess
timet1 t2
Creep Recovery Experiment
Response of Classical Extremes
– Stain for t>t1 is constant– Strain for t >t2 is 0
time
Str
ain
time
Str
ain
time
– Stain rate for t>t1 is constant– Strain for t>t1 increase with time– Strain rate for t >t2 is 0
t2S
tre
sst1
t1 t2 t2t1
Reference: Mark, J., et.al., Physical Properties of Polymers ,American Chemical Society, 1984, p. 102.
Creep Recovery Experiment:Response of Viscoelastic Material
Creep > 0
timet 1 t2
RecoverableStrain
Recovery = 0 (after steady state)
Str
ain
Strain rate decreases with time in the creep zone,
until finally reaching a steady state.
In the recovery zone, the viscoelastic fluid recoils, eventually reaching a equilibrium at some small total strain relative to the strain at unloading.
time
Recovery ZoneCreep Zone
Less Elastic
More Elastic
Creep 0 Recovery = 0 (after steady state)
/
Str
ain
t1 t2
Creep Recovery Experiment
Rheological Models
• Mechanical components or elements
Elastic (Solid-like) Response
A material is perfectly elastic, if the equilibrium
shape is attained instantaneously when a stress
is applied. Upon imposing a step input in strain,
the stresses do not relax.
The simplest elastic solid model is the Hookean
model, which we can represent by the “spring”
mechanical analog. E
Elasticity deals with mechanical properties of elastic solids (Hooke’s Law)
Stress,
L
Strain, = L/L
L
E=/
Strain,
Str
ess,
E
Eslope
/
Elastic (Solid-like) Response• Stress Relaxation experiment
strain)
time
stress)
timeto=0
• Creep Experiment
stress)
timeto=0
strain)
timeto=0
to=0
tsts
oo/E
o
Viscous (Liquid-like) ResponseA material is purely viscous (or inelastic) if following any flow or
deformation history, the stresses in the material become
instantaneously zero, as soon as the flow is stopped; or the
deformation rate becomes instantaneously zero when the stresses
are set equal to zero. Upon imposing a step input in strain, the
stresses relax as soon as the strain is constant.
The liquid behavior can be simply represented by the Newtonian
model. We can represent the Newtonian behavior by using a
“dashpot” mechanical analog:
Theory of Hydrodynamics
In Newtonian Fluids, Stress is proportional to rate of strain but independent of strain itself
Newton’s Law
Strain, ,
Str
ess,
dt
d
dt
dslope
///
Viscous (Liquid-like) Response• Stress Relaxation experiment (suddenly applying a strain to the sample and following the stress as a function of time as the strain is
held constant).
strain)
time
stress)
timeto=0
• Creep Experiment (a constant stress is instantaneously applied to the material and the resulting strain is followed as a function of time)
stress)
timeto=0
strain)
timeto=0
to=0
tsts
o
dt
dslope
so t o
o
0
consto
Energy Storage/Dissipation• Elastic materials store energy (capacitance)
• Viscous materials dissipate energy (resistance) t
Energy
Energy
t
E Viscoelastic materials store Viscoelastic materials store
andand dissipate a part of the dissipate a part of the energyenergy
t
What causes viscoelastic behavior?
Long polymer chains at the molecular scale, make polymeric matrix viscoelastic at the microscale
Reference: Dynamics of Polymeric Liquids (1977). Bird, Armstrong and Hassager. John Wiley and Sons. pp: 63.
Energy Storage +Dissipation
• Specifically, viscoelasticity is a molecular rearrangement. When a stress is applied to a
viscoelastic material such as a polymer, parts of the long polymer chain change position. This movement or rearrangement is called Creep.
Polymers remain a solid material even when these parts of their chains are rearranging in order to
accompany the stress, and as this occurs, it creates a back stress in the material. When the
back stress is the same magnitude as the applied stress, the material no longer creeps. When the original stress is taken away, the accumulated
back stresses will cause the polymer to return to its original form. The material creeps, which gives the prefix visco-, and the material fully recovers,
which gives the suffix –elasticity.
http://en.wikipedia.org/wiki/Viscoelasticity
Examples of viscoelastic foods:
• Food starch, gums, gels• Grains• Most solid foods (fruits, vegetables, tubers)• Cheese• Pasta, cookies, breakfast cereals
Almost all solid foods and fluid foods containing long chain biopolymers
Viscoelasticity Experiments
• Static Tests– Stress Relaxation test– Creep test
• Dynamic Tests– Controlled strain– Controlled stress(When we apply a small oscillatory str
ain and measure the resulting stress)
Why we want to fit models to viscoelastic test data?
• To quantify the data – mathematical representationFor use with other food processing applications- Some food drying models require viscoelastic
properties- Design of pipelines, mixing vessels etc., using
viscoelastic fluid foods
• To obtain information at different test conditions– Example: Extrusion
• To obtain an estimate of elastic properties and relaxation times– Helps to quantify glass transition
Viscoelastic Models• Maxwell Model
• Kelvin-Voigt Model
Used for stress relaxation tests
Used for creep tests
Viscoelastic Response – Maxwell Element
A viscoelastic material (liquid or solid) will not respond instantaneously
when stresses are applied, or the stresses will not respond
instantaneously to any imposed deformation. Upon imposing a step
input in strain the viscoelastic liquid or solid will show stress relaxation
over a significant time.
At least two components are needed, one to characterize elastic and the
other viscous behavior. One such model is the Maxwell model:
E
Viscoelastic Response
Let’s try to deform the Maxwell element
E
Strain,
Stress,
Maxwell Model Response• The Maxwell model can describe successfully the phenomena
of elastic strain, creep recovery, permanent set and stress
relaxation observed with real materials
• Moreover the model exhibits relaxation of stresses after a step
strain deformation and continuous deformation as long as the
stress is maintained. These are characteristics of liquid-like
behaviour
• Therefore the Maxwell element represents a VISCOELASTIC
FLUID.
Maxwell Model-when is applied
( )d
Dot representsdt
Stress
dd
ss
ds
dt
dE
1. will be same in each element
dt
d
Edt
d
E
andEE
t
t
or
ss
d
ss
s
ds
ds
1
/
2. Total = sum of individual
Maxwell Model Response1) Creep Experiment: If a sudden stress is imposed (step loading), an
instantaneous stretching of the spring will occur, followed by an extension of
the dashpot. Deformation after removal of the stress is known as creep
recovery:
.
tE
t oo
)(
stress)
timeto=0
timeto=0ts ts
oo/E
oslope
so t
Or by defining the “creep compliance”:o
ttJ
)(
)(
t
EtJ
1)(
Elastic Recovery
Permanent Set
o/Edashpot
spring
Maxwell Model Response2) Stress Relaxation Experiment: If the mechanical model is suddenly
extended to a position and held there (=const., =0):
/)( toet Exponential decay
strain)
timeto=0
.
o
/te oGG(t)
Also recall the definition of the “relaxation” modulus:o
ttG
)(
)(
/)( too eGt and
stress)
timeto=0
o=Goo /)( to et
= /E = Relaxation time = the time required by biopolymers to relax the stresses
Generalized Maxwell Model
The Maxwell model is qualitatively reasonable, but does
not fit real data very well.
Instead, we can use the generalized Maxwell model
1 2 3
nE1 E2 E3 En
n
Generalized Maxwell Model
Applied for stress relaxation test
)
n
n
tn
tt
tn
tt
eEeEeEt
eeet
//
2/
10
//2
/1
.....()(
.....)(21
21
Determination of parameters for Generalized Maxwell Model
• There are 4 methods.– Method of Instantaneous Slope– Method of Central Limit Theorem– Point of Inflection Method– Method of Successive Residuals
direct method and more popular
Optional
Method of Successive Residuals
• First plot-semilog plot: if it is linear, use single Maxwell Model
• If it is not linear, use Generalized Maxwell Model
Divided into many parts and plot of each part until the curvature disappears.
1
1
11
/1
/ln)(ln
)( 1
1/ - slope
ln intercept-y
tt
et t
timeto=0
ln Second plot
Slope of straight line = 1/2
Plot until it is straight
2
2
22
/2
/ln)(ln
)( 2
1/ - slope
ln intercept-y
tt
et t
timeto=0
ln First plot
Slope of straight line = -1/1
ln 1
ln 2
Example: Genealized maxwell model for stress relaxation test
• Test sample has 2 cm diameter and 4 cm long
Area = 3.142 X 10-4 m2
t (min) F (kg)
0 100
0.5 74
1 66.5
1.5 61
2 57
2.5 54.5
3 53
3.5 51.5
4 51
4.5 50
5 49
6 48.5
7 47.5
8 47
9 46
10 45
11 44
12 43
10000
100000
1000000
10000000
0 100 200 300 400 500 600 700 800
time (sec)
stre
ss (
Pa)
first plot
ln 1= 14.344238 =y-intercept
1= 1696771.4
slope= -0.000318
1= 3143.6655
second plot
ln 2= 14.183214 =y-intercept
2= 1444413.62
slope= -0.0198653
2= 50.3390334
ModelMaxwellTwo
eet tt 34.50/667.3143/6 10444.1 10697.1)(
first plot second plot
t(s) stress Pa stress Pa
0 3121364 1424592.282
30 2309809 629153.0092
60 2075707 411012.9526
90 1904032 255148.5658
120 1779177 145954.4705
150 1701143 83432.09296
180 1654323 51976.02755
210 1607502
240 1591895
270 1560682
300 1529468
360 1513861
420 1482648
480 1467041
540 1435827
600 1404614
660 1373400
720 1342186
Voigt-Kelvin Model Response
• The Voigt-Kelvin element does not continue to deform as long as
stress is applied, rather it reaches an equilibrium deformation. It does
not exhibit any permanent set. These resemble the response of cross-
linked rubbers and are characteristics of solid-like behaviour
• Therefore the Voigt-Kelvin element represents a VISCOELASTIC
SOLID.
The Voigt-Kelvin element cannot describe stress relaxation.
Both Maxwell and Voigt-Kelvin elements can provide only a qualitative
description of the response
Various other spring/dashpot combinations have been proposed.
Viscoelastic ReponseVoigt-Kelvin Element
The Voigt-Kelvin element consists of a spring and a dashpot connected in parallel.
E
dashpotspring
dashpotspring
E
Creep Recovery Experiment: applied 0 (step loading)
strain)
timeto=0
o
+strain)
timeto=0
= /E = characteristic time = time of retardation
/0)( teE
t
timet 0 t
Slope=
Str
ain (
t)
0/E
/0 1)( teE
t
Generalized Voigt-Kelvin Model
E1
E2
E3
En
i
ii E
itn
i i
eE
t /
10 1
1)(
Three element Model
• Standard linear solid
Four element Model
E1
E2 2
1
strain)
timeto=0
o
strain)
timeto=0
strain)
timeto=0
spring
Kevin
dashpot
1
0/
2
0
1
0 1)( t
eEE
t t
C B
A
.
Creep test: use 4-element model
2
2
1
0/
2
0
1
0 1)(
E
te
EEt
ret
t
dt
td
slopeACa
aE
BC
AB
)(
tan 1
0
2
0
timet0
Strain (t)
0/E2 =r
0/E1= 0
a = 2/E2=ret
.. Dashpot, 1
Kelvin, 2/E2
Spring, E1
Slope = 0/1
1
0
2
0
1
0
2
0
1
0/
2
0
1
0
1
0/
2
0
1
0
)(
10
1)(
:
1)(:
E
dt
td
E
t
dt
de
Edt
d
Edt
d
dt
tddiff
te
EEtfrom
ret
t
t
ret
ret
Generalized four-element model
• Combination of four-element model in series
Example• Analyze the given experimental creep curve
in terms of the parameters of a 4-element model.
0
0.1
0.2
0.3
0.4
0.5
0.6
0 1 2 3 4 5 6 7 8 9 10
time (s)
deformation (cm)
•Cylindrical specimen (2 cm in diameter and 5 cm long)
•Applied step load is 10 kg.
y = 0.0266x + 0.325
R2 = 0.9993
0
0.1
0.2
0.3
0.4
0.5
0.6
0 1 2 3 4 5 6 7 8 9 10
time (s)
deformation (cm)
r
aret
0
=0.2
slope = =0.0266
dashpot
kelvin
spring
Length = 0.05 m
Diameter = 0.02 m
Area = 0.00031429 m2
Load = 10 kg
312136.364 Pa
slope = Deformation/time = 0.0266 cm/s
slope = 0.00532 per sec
0.00532 per sec
58672248.8 Pa s
0.125 cm = 0.025 m/m
12485454.5 Pa
a = 0.9 = 11236909.1 Pa s
0/E1 = 0.2 cm = 0.04 m/m
7803409.09 Pa