viscoelastic characterization dr. muanmai apintanapong

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Viscoelastic Characterizati on Dr. Muanmai Apintanapong

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Page 1: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscoelastic Characterization

Dr. Muanmai Apintanapong

Page 2: Viscoelastic Characterization Dr. Muanmai Apintanapong

Elastic deformation - Flow behavior

Page 3: Viscoelastic Characterization Dr. Muanmai Apintanapong

Elastic behavior

Page 4: Viscoelastic Characterization Dr. Muanmai Apintanapong

Newtonian behavior

Page 5: Viscoelastic Characterization Dr. Muanmai Apintanapong

Newtonian liquid

Page 6: Viscoelastic Characterization Dr. Muanmai Apintanapong
Page 7: Viscoelastic Characterization Dr. Muanmai Apintanapong

E.

Page 8: Viscoelastic Characterization Dr. Muanmai Apintanapong

Introduction to ViscoelasticityAll viscous liquids deform continuously under the influence of an applied stress – They exhibit viscous behavior.

Solids deform under an applied stress, but soon reach a position of equilibrium, in which further deformation ceases. If the stress is removed they recover their original shape – They exhibit elastic behavior.

Viscoelastic fluids can exhibit both viscosity and elasticity, depending on the conditions.

Viscous fluid

Viscoelastic fluid

Elastic solid

Page 9: Viscoelastic Characterization Dr. Muanmai Apintanapong

Shear Stress

A

F

Page 10: Viscoelastic Characterization Dr. Muanmai Apintanapong

Shear Rate

Page 11: Viscoelastic Characterization Dr. Muanmai Apintanapong

Practical shear rate values

Page 12: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscosity =resistance to flow

Page 13: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscosity of fluids at 20C

Go to stress relaxation

Page 14: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscosity: temperature dependence

Page 15: Viscoelastic Characterization Dr. Muanmai Apintanapong

Flow curve and Viscosity curve

Page 16: Viscoelastic Characterization Dr. Muanmai Apintanapong
Page 17: Viscoelastic Characterization Dr. Muanmai Apintanapong

Flow behavior: flow curve

Page 18: Viscoelastic Characterization Dr. Muanmai Apintanapong

Flow behavior: viscosity curve

Page 19: Viscoelastic Characterization Dr. Muanmai Apintanapong
Page 20: Viscoelastic Characterization Dr. Muanmai Apintanapong
Page 21: Viscoelastic Characterization Dr. Muanmai Apintanapong
Page 22: Viscoelastic Characterization Dr. Muanmai Apintanapong
Page 23: Viscoelastic Characterization Dr. Muanmai Apintanapong
Page 24: Viscoelastic Characterization Dr. Muanmai Apintanapong
Page 25: Viscoelastic Characterization Dr. Muanmai Apintanapong

Stress Relaxation

Universal Testing Machine

Instron,

TA XT2

Force sensor

Page 26: Viscoelastic Characterization Dr. Muanmai Apintanapong

Stress Relaxation Test

Time, t

Strain

Stress

Elastic

Viscoelastic

Viscous fluid

0

StressStress

Viscous fluidViscous fluid

Page 27: Viscoelastic Characterization Dr. Muanmai Apintanapong

Strain is applied to sample instantaneously (in principle) and held constant with time.

Stress is monitored as a function of time (t).

Stress Relaxation Experiment

Str

ain

0 time

Page 28: Viscoelastic Characterization Dr. Muanmai Apintanapong

Stress Relaxation Experiment

Stress decreases with timestarting at some high value and decreasing to zero.

Response of Material

Str

ess

time0

Response of Classical Extremes

time0

stress for t>0is constant

time0

stress for t>0 is 0S

tres

s

Str

ess

Hookean Solid Newtonian Fluid

Page 29: Viscoelastic Characterization Dr. Muanmai Apintanapong

Stress is applied to sample instantaneously, t1, and held constant for a specific period of time. The strain is monitored as a function of time ((t) or (t)).The stress is reduced to zero, t2, and the strain is monitored as a function of timetort

Creep Recovery Experiment

Str

ess

timet1 t2

Page 30: Viscoelastic Characterization Dr. Muanmai Apintanapong

Creep Recovery Experiment

Response of Classical Extremes

– Stain for t>t1 is constant– Strain for t >t2 is 0

time

Str

ain

time

Str

ain

time

– Stain rate for t>t1 is constant– Strain for t>t1 increase with time– Strain rate for t >t2 is 0

t2S

tre

sst1

t1 t2 t2t1

Page 31: Viscoelastic Characterization Dr. Muanmai Apintanapong

Reference: Mark, J., et.al., Physical Properties of Polymers ,American Chemical Society, 1984, p. 102.

Creep Recovery Experiment:Response of Viscoelastic Material

Creep > 0

timet 1 t2

RecoverableStrain

Recovery = 0 (after steady state)

Str

ain

Strain rate decreases with time in the creep zone,

until finally reaching a steady state.

In the recovery zone, the viscoelastic fluid recoils, eventually reaching a equilibrium at some small total strain relative to the strain at unloading.

Page 32: Viscoelastic Characterization Dr. Muanmai Apintanapong

time

Recovery ZoneCreep Zone

Less Elastic

More Elastic

Creep 0 Recovery = 0 (after steady state)

/

Str

ain

t1 t2

Creep Recovery Experiment

Page 33: Viscoelastic Characterization Dr. Muanmai Apintanapong

Rheological Models

• Mechanical components or elements

Page 34: Viscoelastic Characterization Dr. Muanmai Apintanapong

Elastic (Solid-like) Response

A material is perfectly elastic, if the equilibrium

shape is attained instantaneously when a stress

is applied. Upon imposing a step input in strain,

the stresses do not relax.

The simplest elastic solid model is the Hookean

model, which we can represent by the “spring”

mechanical analog. E

Page 35: Viscoelastic Characterization Dr. Muanmai Apintanapong

Elasticity deals with mechanical properties of elastic solids (Hooke’s Law)

Stress,

L

Strain, = L/L

L

E=/

Page 36: Viscoelastic Characterization Dr. Muanmai Apintanapong

Strain,

Str

ess,

E

Eslope

/

Page 37: Viscoelastic Characterization Dr. Muanmai Apintanapong

Elastic (Solid-like) Response• Stress Relaxation experiment

strain)

time

stress)

timeto=0

• Creep Experiment

stress)

timeto=0

strain)

timeto=0

to=0

tsts

oo/E

o

Page 38: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscous (Liquid-like) ResponseA material is purely viscous (or inelastic) if following any flow or

deformation history, the stresses in the material become

instantaneously zero, as soon as the flow is stopped; or the

deformation rate becomes instantaneously zero when the stresses

are set equal to zero. Upon imposing a step input in strain, the

stresses relax as soon as the strain is constant.

The liquid behavior can be simply represented by the Newtonian

model. We can represent the Newtonian behavior by using a

“dashpot” mechanical analog:

Page 39: Viscoelastic Characterization Dr. Muanmai Apintanapong

Theory of Hydrodynamics

In Newtonian Fluids, Stress is proportional to rate of strain but independent of strain itself

Newton’s Law

Page 40: Viscoelastic Characterization Dr. Muanmai Apintanapong

Strain, ,

Str

ess,

dt

d

dt

dslope

///

Page 41: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscous (Liquid-like) Response• Stress Relaxation experiment (suddenly applying a strain to the sample and following the stress as a function of time as the strain is

held constant).

strain)

time

stress)

timeto=0

• Creep Experiment (a constant stress is instantaneously applied to the material and the resulting strain is followed as a function of time)

stress)

timeto=0

strain)

timeto=0

to=0

tsts

o

dt

dslope

so t o

o

0

consto

Page 42: Viscoelastic Characterization Dr. Muanmai Apintanapong

Energy Storage/Dissipation• Elastic materials store energy (capacitance)

• Viscous materials dissipate energy (resistance) t

Energy

Energy

t

E Viscoelastic materials store Viscoelastic materials store

andand dissipate a part of the dissipate a part of the energyenergy

t

Page 43: Viscoelastic Characterization Dr. Muanmai Apintanapong

What causes viscoelastic behavior?

Long polymer chains at the molecular scale, make polymeric matrix viscoelastic at the microscale

Reference: Dynamics of Polymeric Liquids (1977). Bird, Armstrong and Hassager. John Wiley and Sons. pp: 63.

Energy Storage +Dissipation

Page 44: Viscoelastic Characterization Dr. Muanmai Apintanapong

• Specifically, viscoelasticity is a molecular rearrangement. When a stress is applied to a

viscoelastic material such as a polymer, parts of the long polymer chain change position. This movement or rearrangement is called Creep.

Polymers remain a solid material even when these parts of their chains are rearranging in order to

accompany the stress, and as this occurs, it creates a back stress in the material. When the

back stress is the same magnitude as the applied stress, the material no longer creeps. When the original stress is taken away, the accumulated

back stresses will cause the polymer to return to its original form. The material creeps, which gives the prefix visco-, and the material fully recovers,

which gives the suffix –elasticity.

http://en.wikipedia.org/wiki/Viscoelasticity

Page 45: Viscoelastic Characterization Dr. Muanmai Apintanapong

Examples of viscoelastic foods:

• Food starch, gums, gels• Grains• Most solid foods (fruits, vegetables, tubers)• Cheese• Pasta, cookies, breakfast cereals

Almost all solid foods and fluid foods containing long chain biopolymers

Page 46: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscoelasticity Experiments

• Static Tests– Stress Relaxation test– Creep test

• Dynamic Tests– Controlled strain– Controlled stress(When we apply a small oscillatory str

ain and measure the resulting stress)

Page 47: Viscoelastic Characterization Dr. Muanmai Apintanapong

Why we want to fit models to viscoelastic test data?

• To quantify the data – mathematical representationFor use with other food processing applications- Some food drying models require viscoelastic

properties- Design of pipelines, mixing vessels etc., using

viscoelastic fluid foods

• To obtain information at different test conditions– Example: Extrusion

• To obtain an estimate of elastic properties and relaxation times– Helps to quantify glass transition

Page 48: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscoelastic Models• Maxwell Model

• Kelvin-Voigt Model

Used for stress relaxation tests

Used for creep tests

Page 49: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscoelastic Response – Maxwell Element

A viscoelastic material (liquid or solid) will not respond instantaneously

when stresses are applied, or the stresses will not respond

instantaneously to any imposed deformation. Upon imposing a step

input in strain the viscoelastic liquid or solid will show stress relaxation

over a significant time.

At least two components are needed, one to characterize elastic and the

other viscous behavior. One such model is the Maxwell model:

E

Page 50: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscoelastic Response

Let’s try to deform the Maxwell element

E

Strain,

Stress,

Page 51: Viscoelastic Characterization Dr. Muanmai Apintanapong

Maxwell Model Response• The Maxwell model can describe successfully the phenomena

of elastic strain, creep recovery, permanent set and stress

relaxation observed with real materials

• Moreover the model exhibits relaxation of stresses after a step

strain deformation and continuous deformation as long as the

stress is maintained. These are characteristics of liquid-like

behaviour

• Therefore the Maxwell element represents a VISCOELASTIC

FLUID.

Page 52: Viscoelastic Characterization Dr. Muanmai Apintanapong

Maxwell Model-when is applied

( )d

Dot representsdt

Stress

dd

ss

ds

dt

dE

1. will be same in each element

dt

d

Edt

d

E

andEE

t

t

or

ss

d

ss

s

ds

ds

1

/

2. Total = sum of individual

Page 53: Viscoelastic Characterization Dr. Muanmai Apintanapong

Maxwell Model Response1) Creep Experiment: If a sudden stress is imposed (step loading), an

instantaneous stretching of the spring will occur, followed by an extension of

the dashpot. Deformation after removal of the stress is known as creep

recovery:

.

tE

t oo

)(

stress)

timeto=0

timeto=0ts ts

oo/E

oslope

so t

Or by defining the “creep compliance”:o

ttJ

)(

)(

t

EtJ

1)(

Elastic Recovery

Permanent Set

o/Edashpot

spring

Page 54: Viscoelastic Characterization Dr. Muanmai Apintanapong

Maxwell Model Response2) Stress Relaxation Experiment: If the mechanical model is suddenly

extended to a position and held there (=const., =0):

/)( toet Exponential decay

strain)

timeto=0

.

o

/te oGG(t)

Also recall the definition of the “relaxation” modulus:o

ttG

)(

)(

/)( too eGt and

stress)

timeto=0

o=Goo /)( to et

= /E = Relaxation time = the time required by biopolymers to relax the stresses

Page 55: Viscoelastic Characterization Dr. Muanmai Apintanapong

Generalized Maxwell Model

The Maxwell model is qualitatively reasonable, but does

not fit real data very well.

Instead, we can use the generalized Maxwell model

1 2 3

nE1 E2 E3 En

Page 56: Viscoelastic Characterization Dr. Muanmai Apintanapong

n

Generalized Maxwell Model

Applied for stress relaxation test

)

n

n

tn

tt

tn

tt

eEeEeEt

eeet

//

2/

10

//2

/1

.....()(

.....)(21

21

Page 57: Viscoelastic Characterization Dr. Muanmai Apintanapong

Determination of parameters for Generalized Maxwell Model

• There are 4 methods.– Method of Instantaneous Slope– Method of Central Limit Theorem– Point of Inflection Method– Method of Successive Residuals

direct method and more popular

Optional

Page 58: Viscoelastic Characterization Dr. Muanmai Apintanapong

Method of Successive Residuals

• First plot-semilog plot: if it is linear, use single Maxwell Model

• If it is not linear, use Generalized Maxwell Model

Page 59: Viscoelastic Characterization Dr. Muanmai Apintanapong

Divided into many parts and plot of each part until the curvature disappears.

1

1

11

/1

/ln)(ln

)( 1

1/ - slope

ln intercept-y

tt

et t

timeto=0

ln Second plot

Slope of straight line = 1/2

Plot until it is straight

2

2

22

/2

/ln)(ln

)( 2

1/ - slope

ln intercept-y

tt

et t

timeto=0

ln First plot

Slope of straight line = -1/1

ln 1

ln 2

Page 60: Viscoelastic Characterization Dr. Muanmai Apintanapong

Example: Genealized maxwell model for stress relaxation test

• Test sample has 2 cm diameter and 4 cm long

Area = 3.142 X 10-4 m2

t (min) F (kg)

0 100

0.5 74

1 66.5

1.5 61

2 57

2.5 54.5

3 53

3.5 51.5

4 51

4.5 50

5 49

6 48.5

7 47.5

8 47

9 46

10 45

11 44

12 43

Page 61: Viscoelastic Characterization Dr. Muanmai Apintanapong

10000

100000

1000000

10000000

0 100 200 300 400 500 600 700 800

time (sec)

stre

ss (

Pa)

first plot

ln 1= 14.344238 =y-intercept

1= 1696771.4

slope= -0.000318

1= 3143.6655

second plot

ln 2= 14.183214 =y-intercept

2= 1444413.62

slope= -0.0198653

2= 50.3390334

ModelMaxwellTwo

eet tt 34.50/667.3143/6 10444.1 10697.1)(

Page 62: Viscoelastic Characterization Dr. Muanmai Apintanapong

  first plot second plot

t(s) stress Pa stress Pa

0 3121364 1424592.282

30 2309809 629153.0092

60 2075707 411012.9526

90 1904032 255148.5658

120 1779177 145954.4705

150 1701143 83432.09296

180 1654323 51976.02755

210 1607502  

240 1591895  

270 1560682  

300 1529468  

360 1513861  

420 1482648  

480 1467041  

540 1435827  

600 1404614  

660 1373400  

720 1342186  

Page 63: Viscoelastic Characterization Dr. Muanmai Apintanapong

Voigt-Kelvin Model Response

• The Voigt-Kelvin element does not continue to deform as long as

stress is applied, rather it reaches an equilibrium deformation. It does

not exhibit any permanent set. These resemble the response of cross-

linked rubbers and are characteristics of solid-like behaviour

• Therefore the Voigt-Kelvin element represents a VISCOELASTIC

SOLID.

The Voigt-Kelvin element cannot describe stress relaxation.

Both Maxwell and Voigt-Kelvin elements can provide only a qualitative

description of the response

Various other spring/dashpot combinations have been proposed.

Page 64: Viscoelastic Characterization Dr. Muanmai Apintanapong

Viscoelastic ReponseVoigt-Kelvin Element

The Voigt-Kelvin element consists of a spring and a dashpot connected in parallel.

E

dashpotspring

dashpotspring

E

Page 65: Viscoelastic Characterization Dr. Muanmai Apintanapong

Creep Recovery Experiment: applied 0 (step loading)

strain)

timeto=0

o

+strain)

timeto=0

= /E = characteristic time = time of retardation

/0)( teE

t

timet 0 t

Slope=

Str

ain (

t)

0/E

/0 1)( teE

t

Page 66: Viscoelastic Characterization Dr. Muanmai Apintanapong

Generalized Voigt-Kelvin Model

E1

E2

E3

En

i

ii E

itn

i i

eE

t /

10 1

1)(

Page 67: Viscoelastic Characterization Dr. Muanmai Apintanapong

Three element Model

• Standard linear solid

Page 68: Viscoelastic Characterization Dr. Muanmai Apintanapong

Four element Model

E1

E2 2

1

strain)

timeto=0

o

strain)

timeto=0

strain)

timeto=0

spring

Kevin

dashpot

1

0/

2

0

1

0 1)( t

eEE

t t

Page 69: Viscoelastic Characterization Dr. Muanmai Apintanapong

C B

A

.

Creep test: use 4-element model

2

2

1

0/

2

0

1

0 1)(

E

te

EEt

ret

t

dt

td

slopeACa

aE

BC

AB

)(

tan 1

0

2

0

timet0

Strain (t)

0/E2 =r

0/E1= 0

a = 2/E2=ret

.. Dashpot, 1

Kelvin, 2/E2

Spring, E1

Slope = 0/1

Page 70: Viscoelastic Characterization Dr. Muanmai Apintanapong

1

0

2

0

1

0

2

0

1

0/

2

0

1

0

1

0/

2

0

1

0

)(

10

1)(

:

1)(:

E

dt

td

E

t

dt

de

Edt

d

Edt

d

dt

tddiff

te

EEtfrom

ret

t

t

ret

ret

Page 71: Viscoelastic Characterization Dr. Muanmai Apintanapong

Generalized four-element model

• Combination of four-element model in series

Page 72: Viscoelastic Characterization Dr. Muanmai Apintanapong

Example• Analyze the given experimental creep curve

in terms of the parameters of a 4-element model.

0

0.1

0.2

0.3

0.4

0.5

0.6

0 1 2 3 4 5 6 7 8 9 10

time (s)

deformation (cm)

•Cylindrical specimen (2 cm in diameter and 5 cm long)

•Applied step load is 10 kg.

Page 73: Viscoelastic Characterization Dr. Muanmai Apintanapong

y = 0.0266x + 0.325

R2 = 0.9993

0

0.1

0.2

0.3

0.4

0.5

0.6

0 1 2 3 4 5 6 7 8 9 10

time (s)

deformation (cm)

r

aret

0

=0.2

slope = =0.0266

dashpot

kelvin

spring

Page 74: Viscoelastic Characterization Dr. Muanmai Apintanapong

Length = 0.05 m

Diameter = 0.02 m

Area = 0.00031429 m2

Load = 10 kg

312136.364 Pa

slope = Deformation/time = 0.0266 cm/s

slope = 0.00532 per sec

0.00532 per sec

58672248.8 Pa s

0.125 cm = 0.025 m/m

12485454.5 Pa

a = 0.9 = 11236909.1 Pa s

0/E1 = 0.2 cm = 0.04 m/m

7803409.09 Pa