Unit 9: Alternating-current circuits

Introduction. Alternating current features.

Behaviour of basic dipoles (resistor, inductor,

capacitor) to an alternating current.

RLC series circuit. Impedance and phase lag.

Power on A.C.

Resonance.

Niagara

Falls

Nikola Tesla 1856-1943

Coil turning inside a magnetic field B.

NBSwsenwtdt

d==

N S

S

B

t

wtNBS cos== SBNrr

%Um

Symbol:

Alternating-current generation

N1 N2

V1 ~ V2 ~

The transformer The current on primary produces a current and then a flux varying on time.

This flux is completely driven by the ferromagnetic material, producing an inducedelectromotive force on terminals of secondary. The flux on each loop u is the same forprimary and secondary.

It works due to electromagnetic induction and then it doesnt work on D.C.

Primary

winding

Secondary

windingdt

dNV u111

==

dt

dNV u222

==

1

2

1

2

2

2

1

1 V

N

N

VN

V

N

V==

Voltage ratio or ratio

of transformation

equals the turns ratio

On an ideal transformer the power on primary equals the power on secondary

On an real transformer there are three type of losses:

On windings: Joule heating

On core: Magnetic Histeresys

and Eddy currents

In order to minimize Eddy currents the core is built with

sheets isolated between them

B

r

i

Period T = 2/ (s)

Frequency f = 1/T (Hz)

Angular frequency

w = 2f (rad/s)

Phase wt+

Initial phase (degrees or radians) (phase at t=0)

Amplitude=Maximum voltage Um (V)

t

T

Um

u(t) = Um cos(t + )u(t)

f Europe: 50 Hz

f North America: 60 Hz

Sinusoidal alternating-current features

t

u =0

u(t) = Um cos(t + u)

u(t)

Initial phase. Examples.

t

u(t)

u=90 (/2 rad)

t

u(t)

u=-90 (-/2 rad)

t

u(t)

u=-45 (-/4 rad)

To simplify the analysis of A.C. circuits, a graphical representation of sinusoidalfunctions called phasor diagram can be used.

A phasor is a vector whose modulus (length) is proportional to the amplitude ofsinusoidal function it represents.

The vector rotates counterclockwise at an angular speed equal to . The anglemade up with the horizontal axis is the phase (t+).

Therefore, depending if we are working with the function sinus or the functioncosinus, this function will be repreented by the vertical projection or thehorizontal projection of the rotating vector.

t

T

Um

u(t) = Um cos(t + )

u(t)

Phasor diagram

U

t+

Um

+

+

)sin(:

)cos(:Pr

tUVertical

tUHorizontalojections

m

m

As the position of phasor is different for any time considered, the graphicalrepresentations are done on time t=0 and then, the initial phase is the anglebetween vector and horizontal axis. In this way, the phasor is a unique vector(not changing on time) for a given function:

t

T

Um

u(t) = Um cos(t + )

u(t)

Phasor diagram

U

Um

Phasor diagram

u(t) = Um cos(t + u )i(t) = Im cos(t+i)

t

iu =

Phase lag between two waves (voltage and intensity)

Phase lag is defined as

i=0 u

t

iu =Phase lag between two waves (voltage and intensity)

i=0u>0

0>

t

i

U =u

I

U =-i

I

Behaviour of basic dipoles. Resistor

Resistor

t

i

u

u(t) = R i(t) = RIm cost = Um cost

i(t) = Im cost

Ri(t)

u(t)

Um = R Im

= 0

Tipler, chapter 29.1

uR = iR

U

I

Behaviour of basic dipoles. Inductor

i(t) = Im cost

Li(t)

u(t)

Um = LIm

= /2

Tipler, chapter 29.1

Inductor

t

iu

)2

tcos(U)2

tcos(ILtsenILdt

)t(diL)t(u mmm

+=+===

XL = L Inductance ()

dt

)t(diLuL =

U

I

Behaviour of basic dipoles. Capacitor

Ci(t)

u(t)

= - /2

Tipler, chapter 29.1

Capacitor

t

i

u

u(t) = Um cost

)2

tcos(I)2

tcos(CU)t(senCUdt

)t(Cdu

dt

)t(dq)t(i mmm

+=+====

=

C

IU mmXC = 1/C Capacitance ()

Cuq =

U

I

R

L

C

)cos( umL wtLwIu +=

)cos( umR wtRIu +=

)cos( um

C wtCw

Iu +=

+=

=

2

mLLm IXU

=

=

0

mRm IRU

=

=

2

mCCm IXU

Behaviour of basic dipoles. Review

Voltage and intensity go on phase

Voltage goes ahead intensity 90

Voltage goes behind intensity 90

Sinusoidal functions are interesting because additionof (S.F.) is another S.F.

On the other hand, Fouriers law says that anyperiodic function can be split in S.F. of differentfrequencies. This is the main reason why behaviourof S.F. is studied.

Knowing response of basic dipoles to a sinusoidalcurrent, we know response to any (no sinusoidal)current.

Sinusoidal functions (S.F.) and Fouriers law.

L R C

uLuR uC

i(t)= Im cos (wt)

u(t) = uL (t)+ uR (t)+ uC (t)= Um cos (wt+)

Lets take a circuit with resistor, inductor and capacitor inseries. If a sinusoidal intensity i(t)=Imcos(wt) is flowingthrough such devices, voltage on terminals of circuit will bethe addition of voltages on each device:

RLC series circuit. Impedance of dipole

u(t)

Addition of sinusoidal

functions is another

sinusoidal function

RLC series circuit. Impedance of dipole

Um cos (wt+) = LwIm cos (wt +/2)+RIm cos (wt)+(1/Cw)Im cos (wt -/2)

UL

I URUC

UL-UC

I UR

U

Um

(L-1/C) Im

RIm

Um

ZXRXXRI

U

CwLwRIU CL

m

mmm =+=+=+=

222222 1)()((

tgR

X

R

XX

R

CwLw

tg CL ==

=

=

1Z Is called Impedance of dipole ()

is phase lag of dipole

Z and are depending not only on parameters of R, L and C, but also on frequency of applied current.

R

XL=Lw

ZX

X0)

Power on A.C.

Power consumed on a device on A.C. can be computed multiplying voltage and

intensity on each time. This is the Instantaneous power:

)tsin(I)t(i m =

)tsin(u)t(u m +==+== )tsin(I)tsin(U)t(i)t(u mm

t2sinsin2

IUtsincosIUtsin]sintcoscost[sinIU mm

2

mmmm

+=+=

Reactive powerActive or

Real power

p(t)

)(tp

Instantaneous power = Active power + Reactive power

Frequency of reactive power doubles that of active power

tIU mm 2sincos t

IU mm 22

sinsin

= +

Power on A.C.

> 0 and < 0 zero on a cycleAlways > 0

Active power + Reactive power = Instantaneous power

=+

t2sinsin2

IU mm

)t(p+ =

Example taking: Im = 1 A Um = 1 V = 1 rad/s = 0,6 rad

Average value on a cycle:

cos2

IUtdtsincosIU

T

1dt)t(p

T

1PP mm

T

0

2

mm

T

0

a

av

====

Power on A.C.

-0,4

-0,2

0

0,2

0,4

0,6

0,8

1

0 2 4 6 8 10 12

wt (rad)

Po

wer

(w)

Active pow er

Power on A.C.

-0,4

-0,2

0

0,2

0,4

0,6

0,8

1

0 2 4 6 8 10 12

wt (rad)P

ow

er

(w)

Reactive pow er

Power on A.C.

-0,4

-0,2

0

0,2

0,4

0,6

0,8

1

0 2 4 6 8 10 12

wt (rad)

Po

wer

(w)

Inst. pow er

cos Power factor

tsincosIU mm 2

=T

Tdtwt

0

2

2)(sin

DipoleActive

power Pa(t)Average

Paav

Reactive power Pr(t)

Average Prav

P(t) Pav

R=0

Cos =1

Sin =00 0

L=90

Cos =0

Sin =10 0 0 0

C=-90

Cos =0

Sin =-10 0 0 0

Rms magnitudes. Power for basic dipoles

Consumed power on basic dipoles (R, L and C):

)(2sinsin2

sincos 2 tptIU

tIU mmmm =

+

An A.C. current consumes the same power than a D.C. current having the rms magnitudes

cosIUcos2

IUpowerAverage rmsrms

mm =

=2

mrms

UU =

2

mrms

II =

tsinIU2

mm R

Um

2

2

tsinIU2

mm R

Um

2

2

t2sinL2

U2

m

t2sinL2

U2

m

t2sinC2

U2

m t2sinC2

U2

m

Tipler, chapter 29.1

22 1 )((Cw

LwRI

UZ

m

m +==

RLC series circuit. Resonance

Drawing Z v.s frequency

Z v.s. freq

0

100

200

300

400

500

600

0 500 1000 1500 2000 2500 3000 3500 4000

frequency (Hz)Z

(O

hm

)

Example taking: R = 80 L = 100 mH C = 20 F

Resonance: f0=707 Hz Z=80

On resonance, impedance of circuit is minimum, and

amplitude of intensity reaches a maximum (for a given

voltage). Intensity and voltage on terminals of RLC

circuit go then on phase. cos =1 and consumed

power on RLC dipole is maximum.

There is a frequency where XL=XC and then the impedance gets its minimum value (Z=R).

This frequency is called Frequency of resonance (f0) and can be easily computed:

LCf

LCCL

1

2

11100

0

0

===