two-dimension curvature of a wire: a simple model using shear modulus concept
TRANSCRIPT
Two-dimension curvature of a wire: A simple model using
shear modulus conceptS. Viridi, M. Abdullah, N. Amalia
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Outline
• Introduction• Model• Results #1• Data• Results #2• Summary
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Introduction
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Stan G, Ciobanu C V, Parthangal P M and Cook R F 2007 Nano Lett. 7 3691
Introduction (cont.)
• Eqns (8) & (9)
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Stan G, Ciobanu C V, Parthangal P M and Cook R F 2007 Nano Lett. 7 3691
c
c
s ER
Et
ER
NW
NW
c
c
s GR
Gt
ER
NW
NW
Introduction (cont.)
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Chen C Q, Shi Y, Zhang Y S, Zhu J and Yan Y J 2006 Phys. Rev. Lett. 96 075505
4
4
3
3
2
2
00 243181
Dr
Dr
Dr
Dr
EE
EE sssss
Model
• Shearmodulus
AFG /
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Model (cont.)
• Model
L
l
dlrgF 2sin
L
l
dlrGr
g 22
sin
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Model (cont.)
• Discretization
L
l
dllrlrlGlglll 2
2
sin
lLlxllx sin
lLlylly cos
NLl
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0
0.2
0.4
0.6
0.8
1
0 0.05 0.1 0.15 0.2
x
y
Results #1
• Arbitrary parameters:θ0 = 10°, L = 1 m,M = 2–22 g, D = 2 mm,G = 2.5×104–105 N/m2,N = 5–80
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Results #1 (cont.)
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0
0.2
0.4
0.6
0.8
1
0 0.2 0.4 0.6 0.8 1
x
y
G = 10î 104
G = 5î 104
G = 4î 104
G = 3î 104
G = 2.5î 104
0.5
0.6
0.7
0.8
0.9
1
1E+3 2E+4 4E+4 6E+4 8E+4 1E+5
T
G
20
20
1 yyxxL
T NN
Results #1 (cont.)
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-1
-0.6
-0.2
0.2
0.6
1
0 0.2 0.4 0.6
x
y
-1
-0.6
-0.2
0.2
0.6
1
0 0.2 0.4 0.6
x
y
-1
-0.6
-0.2
0.2
0.6
1
0 0.2 0.4 0.6
x
y
Results #1 (cont.)
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0
0.2
0.4
0.6
0.8
1
0 0.2 0.4 0.6 0.8 1
x
y
M = 2 g M = 8 g
M = 12 g
M = 16 g
M = 20 g
M = 22 g
Data
• Nanowire parameters
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Data (cont.)
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Data (cont.)
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Data (cont.)
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Data (cont.)
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Results #2 (cont.)
• A ‘straight’ nanowire
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0.000000
1.2E-07
1.4E-07
1.6E-07
1.8E-07
65 70 75 80 85 90 95
θN–θ0
G
Results #2 (cont.)
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0,12 GE
Summary
• A simple model of wire bending derived from definition of shear modulus has been presented
• It can be used for arbitrary parameters• It not so successful for the size of nanowire,
since it predicts too higher value than expected
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Thank you
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