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TW40 UNIVERSITY OF BOLTON SCHOOL OF ENGINEERING BENG (HONS) IN MECHANICAL ENGINEERING SEMESTER 1EXAMINATION 2015/2016 ADVANCED THERMOFLUIDS & CONTROL SYSTEMS MODULE NO: AME6005 Date: Wednesday 13 January 2016 Time: 10.00 1.00 INSTRUCTIONS TO CANDIDATES: There are SIX questions. Answer ANY FOUR questions. All questions carry equal marks. Marks for parts of questions are shown in brackets. This examination paper carries a total of 100 marks. All working must be shown. A numerical solution of a question obtained by programming an electronic calculator will not be accepted. CANDIDATES REQUIRE : Thermodynamic properties of fluids provided Formula Sheet provided Take density of water as 1000 kg/m 3

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  • TW40

    UNIVERSITY OF BOLTON

    SCHOOL OF ENGINEERING

    BENG (HONS) IN MECHANICAL ENGINEERING

    SEMESTER 1EXAMINATION 2015/2016

    ADVANCED THERMOFLUIDS & CONTROL

    SYSTEMS

    MODULE NO: AME6005

    Date: Wednesday 13 January 2016 Time: 10.00 – 1.00

    INSTRUCTIONS TO CANDIDATES: There are SIX questions.

    Answer ANY FOUR questions.

    All questions carry equal marks.

    Marks for parts of questions are

    shown in brackets.

    This examination paper carries a total

    of 100 marks.

    All working must be shown. A

    numerical solution of a question

    obtained by programming an

    electronic calculator will not be

    accepted.

    CANDIDATES REQUIRE : Thermodynamic properties of fluids

    provided

    Formula Sheet provided

    Take density of water as 1000 kg/m3

  • Page 2 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    Q1 (a) Fluid is moving through a pipe. The velocity profile at some section is

    shown in Figure Q1a and is given mathematically as:

    2

    2

    r4

    d

    4u

    Where u = velocity of fluid at any position r, = a constant, =

    viscosity of fluid, d = pipe diameter and r = radial distance from

    centreline. Calculate:

    i. The shear stress at the wall of the pipe due to fluid. (6 marks)

    ii. The shear stress at a position r = d/4 (4 marks)

    And

    iii. If the given profile persists a distance L along the pipe, what drag

    is induced on the pipe by the fluid in the direction of flow over this

    distance. (5 marks)

    Figure Q1a

    Question 1 continued overleaf

  • Page 3 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    Question 1 continued

    (b) A shaft 70mm in diameter is being pushed at a speed of 400 mm/s

    through a bearing sleeve 70.2mm in diameter and 250mm long. The

    clearance is filled with oil with kinematic viscosity of 0.005 m2/s and

    specific gravity 0.9. Calculate the force exerted by the oil on the shaft.

    (10 marks)

    Total 25 marks

    Q2 (a) Show from first principles that the change of entropy for a gas is

    𝑆2 - 𝑆1 = ∁𝑉 𝐿𝑛 𝑇2

    𝑇1 + R 𝐿𝑛

    𝑉2

    𝑉1

    Use dQ = du + dw

    du = ∁𝑉 d T and dw = pdv (12 marks)

    (b) Water at 20oC flows at a rate of 0.05 m3/s in a 20cm diameter cast iron

    pipe. Calculate the head loss per kilometre of the pipe. Take the

    kinematic viscosity of water at: 20oC = 1 x 10-6 m2/s. The Ks value for

    cast iron = 0.12mm.

    Use the attached Moody diagram (13 marks)

    Total 25 marks

    Please turn the page

  • Page 4 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    Q3 (a) The wall shear stress τ

    w in a boundary layer is assumed to be a

    function of stream velocity U, boundary layer thickness δ, local turbulence velocity u′, density ρ, and local pressure gradient dp/dx. Using (ρ, U, δ) as repeating variables, rewrite this relationship as a dimensionless function. (15 marks)

    b) A Rankine cycle works between 40 bar and 400℃ at the boiler exit and 0.035 bar at the condenser. Sketch the cycle and calculate the cycle efficiency.

    Assume isentropic expansion and ignore the energy term at the feed pump.

    (10 marks)

    Total 25 marks

    Q4 A solar tracking system shown in Figure Q4, in which a PID controller is used to control the system. The system responses for a unit step input are required as:

    The maximum overshoot is less than 10%

    The settling time is 50% less than the closed loop system without the PID controller

    The steady-state error is 0.

    If the solar system Gp(s) = 100

    (𝑠+3)(𝑠+6),

    (a) Evaluate the performances of closed loop system (ξ, ωn,

    Percentage Overshoot, ts and steady-state error) without the PID

    controller to determine how much improvement is required.

    (8 marks)

    Question 4 continued overleaf

  • Page 5 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    Question 4 continued

    (b) Determine the PID parameters KP, Ki, and Kd.

    (12 marks)

    (c) If a velocity feedback is introduced into Figure Q4, draw a block

    diagram with the velocity feedback and explain the effects on a

    control system of including the velocity feedback. (5 marks)

    Total 25 marks

    Q5 A simplified driverless vehicle model is shown in Figure Q5, in which

    the computer performs the function of controller by using Global Positioning System (GPS) information to generate input commands for the vehicle.

    (a) Determine the range of sampling interval, T, which will make the

    feedback control system stable, and the range that will make it unstable. (8 marks)

    (b) For a unit step input and a unit ramp input, find the steady-state

    error for the feedback control system. (8 marks)

    Question 5 continued overleaf

    Figure Q4 A Solar Tracking System

  • Page 6 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    Question 5 continued

    (c) If the controller has a 16 bit Analogue to Digital Converter with

    the signal range between -10 Volt to +10 Volt:

    (i) What is the resolution of the AD converter? (2 marks)

    (ii) What integer number represented a value of 5 Volts?

    (2 marks)

    (iii) What voltage does the integer 1000 represent?

    (2 marks)

    (iv) What voltage does 1011010110110011 represent?

    (3 marks)

    Total 25 marks

    Please turn the page

    Figure Q5 A Simplified Driverless Vehicle Model

  • Page 7 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    Q6 A simple mechanical system shown in Figure Q6. K1 and K2 are the

    spring stiffness, C is the viscous damping coefficient, and M1 and M2

    are the masses for Mass 1 and Mass 2. The input to the system is the

    Force F and the outputs are the velocities dy1/dt and dy2/dt, and

    displacements y1 and y2.

    (a) Develop the system’s differential equations (5 marks)

    (b) Determine the state variables dy1/dt, dy2/dt, y1 and y2 (2 marks)

    Figure Q6 A Mechanical System

  • Page 8 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    (c) Determine the state differential equations and matrices A, B, C and D, where A, B, C, and D have their usual meaning.

    (10 marks)

    Question 6 continued overleaf

    Question 6 continued

    (d) Explain the following two approaches for the analysis and design of closed loop control systems and give two advantages and two disadvantages for each of the technique :

    The frequency responses technique

    The state space technique (8 marks)

    Total 25 marks

    END OF QUESTIONS

  • Page 9 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    FORMULA SHEETS

    W = P (v2 – v1)

    V

    V PV = W

    1

    2ln

    Q = Cd A √2gh

    12 21

    g

    ghgCV m

    .ΔMΔt

    ΔMF

    F = ρ QV

    Re = V L ρ/

    dQ = du + dw

    du = cu dT

    dw = pdv

    pv = mRT

    h = hf + xhfg

    1 -n

    V P - V P =W 2211

  • Page 10 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    s = sf + xsfg

    v = x Vg

    hm w - Q...

    3

    2

    2

    R

    RL

    LF

    n

    T

    dQds

    1

    2n12 L

    T

    TCSS pL

    f

    fg

    pLgT

    hTCS

    273L n

    f

    pu

    f

    gf

    pLT

    TC

    T

    hfTCS nn L

    273L

    1

    2n

    1

    2np12

    P

    PMRL

    T

    TL MCSS

    sCDFD2u

    2

    1

    suFL2

    LC 2

    1

    )( gZPds

    dS p

    L

    pDQ

    128

    4

  • Page 11 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    gD

    L

    Rh f

    2

    v64 2

    Re

    16f

    g2d

    fLv4h

    2

    f

    g

    Khm

    2

    v2

    g

    VVkhm

    2

    2

    21

    H

    L

    T

    T1

    T

    QSSSgen )12

    geno STSSTUUW 02121 )(

    )( 12 VVPWW ou

    )()()( 21021021 VVPSSTUUWrev

    )()()( 00 oVVPoSSTUU

    genToSI

  • Page 12 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    1000

    gQHp

    RRt60

    NT

    R

    RL

    uL2F

    t

    V

    rV

    4

    2

    4

    1

    2

    1

    2n

  • Page 13 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    G(s) = )()(1

    )(

    sHsGo

    sGo

    (for a negative feedback)

    G(s) = )()(1

    )(

    sHsGo

    sGo

    (for a positive feedback)

    Steady-State Errors

    )]())(1([lim0

    ssGse iOs

    ss

    (for an open-loop system)

    )]()(1

    1[lim

    0s

    sGse i

    os

    ss

    (for the closed-loop system with a unity feedback)

    )](

    ]1)()[(1

    )(1

    1[lim

    1

    10

    s

    sHsG

    sGse i

    sss

    (if the feedback H(s) ≠ 1)

    ])1)((1

    )([lim

    12

    2

    0d

    sss

    sGG

    sGse

    (if the system subjects to a disturbance input)

    Laplace Transforms A unit impulse function 1

    A unit step function s

    1

    A unit ramp function 2

    1

    s

    First order Systems

    )1( / tssO eG (for a unit step input)

    )1( / tssO eAG (for a step input with size A)

  • Page 14 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

    Performance measures for second-order systems

    dtr = 1/2

    dtp =

    P.O. = exp %100))1(

    (2

    ts = n

    4

    d = n(1-2)

  • Page 15 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005

  • Page 16 of 16

    School of Engineering BEng (Hons) Mechanical Engineering Semester 1 Examination 2015/2016 Advanced Thermofluids & Control Systems Module No: AME6005