thermofluids report

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REPORT PHYSICAL PROPERTIES OF FLUID DJM 2043 THERMOFLUIDS LECTERUR NAME : PN AINA GROUP NAME : NAME NO MATRICS MUHAMMAD HANIF BIN HUSHAIRI 15DEM14F1019 MUHAMMAD AMIRUL BIN ABDUL AZIZ 15DEM14F1008 MUHAMMAD RIDZUAN BIN AZIZZI 15DEM14F1005 MOHAMAD AMIRUL BIN MUSTAFA 15DEM14F1008 MUHAMMAD AFIQ DANIEAL 15DEM14F1011 MUHAMMAD FARHAN ‘ABID 15DEM14F1023

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DESCRIPTION

Fluid is a substance that is changes continuously depends to the forced exerted into it. Fluid can be classified into two categories, liquid and gas. Each fluid has their own physical properties. The application of the fluid can be recognized or treasured by knowing the physical properties of the fluid.The mass per unit volume is defined as density. The unit used is kg/m3. The measurement is simple in the case of solids and liquids.Density of substance, ρ= mass/volume= m/V (g/cm3 @ kg/m3) The ratio of the density of the fluid to the density of water. Usually 1000 kg/m3 at a standard condition…… is defined as Specific Gravity or Relative Gravity δ of fluids. This is a ratio and hence no dimension or unit is involved.Specific gravity, s.g= ρ_substance/ρ_water

TRANSCRIPT

REPORTPHYSICAL PROPERTIES OF FLUID

DJM 2043THERMOFLUIDS

LECTERUR NAME : PN AINA GROUP NAME :NAMENO MATRICS

MUHAMMAD HANIF BIN HUSHAIRI15DEM14F1019

MUHAMMAD AMIRUL BIN ABDUL AZIZ15DEM14F1008

MUHAMMAD RIDZUAN BIN AZIZZI15DEM14F1005

MOHAMAD AMIRUL BIN MUSTAFA 15DEM14F1008

MUHAMMAD AFIQ DANIEAL 15DEM14F1011

MUHAMMAD FARHAN ABID15DEM14F1023

INTRODUCTION

Fluid is a substance that is changes continuously depends to the forced exerted into it. Fluid can be classified into two categories, liquid and gas. Each fluid has their own physical properties. The application of the fluid can be recognized or treasured by knowing the physical properties of the fluid.The mass per unit volume is defined as density. The unit used is kg/m3. The measurement is simple in the case of solids and liquids.

Density of substance,

The ratio of the density of the fluid to the density of water. Usually 1000 kg/m3 at a standard condition is defined as Specific Gravity or Relative Gravity of fluids. This is a ratio and hence no dimension or unit is involved.

Specific gravity,

OBJECTIVE

At the end of the session the students will be able to;i. Determine the density of substance.ii.

EXPERIMENT 1 (a) : TO DETERMINE THE FLUID DENSITY BY USING THE MEASUREMENT CYLINDER

APPARATUSa) Measurement cylinderb) Electronic Balancec) Oil and water

Procedures :1. First measure the weight of empty measurement cylinder.2. Fill the measurement cylinder with 100 ml of water.3. Reweight the measurement cylinder that fill with water and remark the mass.4. Calculate the density of the water using the density equation.5. Repeat the experiment by using oil.

ResultItemWaterOil

Mass of cylinder (kg)0.256 kg0.256 kg

Mass of cylinder + fluid (kg)0.256 kg + 0.096 kg= 0.352 kg0.256 kg + 0.089 kg= 0.045 kg

Mass of Fluid (kg)0.096 kg0.089 kg

Fluid Volume (m3)100 ml 10002= 0.0001 m3100 ml 10002= 0.0001 m3

Fluid Density (kg/m3)0.096 kg 0.0001 m3= 960 kg/m30.089 kg 0.0001 m3=890 kg/m3

Analysis

Discussion1. Shows the calculation of mass density and the specific gravity for water and oil.

Water :

Oil :

EXPERIMENT 1 (b) : TO DETERMINE THE DENSITY OF OBJECT USING MEASUREMENT CYLINDER.

THEORY ;By using the Archimedes Principle, the weight of fluid displaced by the object equal to the weight of submerged object.

Apparatus :a) Measurement cylinderb) Electronic Balancec) Waterd) Object

Procedures :1. First fill up the empty measurement cylinder with water.2. Remark the fluid volume.3. Measure the weight of object.4. Fill in the measurement cylinder with object.5. Remark the volume of measurement cylinder with the object.

ItemWater

Object12Average

Volume of water (m3)

Mass of the object (kg)

Volume of water and object (m3)

Volume of displaced water (m3)

Density of the object (kg/m3)

ResultItemWater

Object12Average

Volume of water (m3)0.0001 m30.0001 m30.0001 m3

Mass of the object (kg)0.02 kg0.019 kg0.02 kg

Volume of water and object (m3)1.08 x 10-41.08 x 10-41.08 x 10-4

Volume of displaced water (m3)8 x 10-68 x 10-68 x 10-6

Density of the object (kg/m3)2500 kg/m32500 kg/m32500 kg/m3

Analysis

Discussion1. Shows the calculation of density and specific gravity for the object.

2. Is it suitable this procedures used to determine the density of object that can absorb the water? How to solve this problem?

CONCLUSION

Hypothesis is accepted. In the conclusion, fluid can be classified into two categories, liquid and gas. Each fluid has their own physical properties. The application of the fluid can be recognized or treasured by knowing the physical properties of the fluid.