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Page 1: Test Doc

- 145 -

Ajith Wimanga Wijesinghe

07

07

Page 2: Test Doc

- 146 -

Ajith Wimanga Wijesinghe

1 + (1 + ) + (1 + ) + … … … … … . (1 + ) m%idrKfha ys ix.=Klh ( )!( )!( )! nj

fmkajkak'

− ( − 3) + = 0 j¾. iólrKfha uQ, ;d;aúl ùu i|yd ∈ (−∞, 1) ∪ (9, ∞) nj o

uQ, 2 u Ok ùu i|yd ∈ [9, ∞) nj o fmkajkak' wd.kaâ igyk u; olajd we;s j¾.M,h fokq ,nk mrdih fidhkak'

log (2 + 1) < 1 wkqrEm l=vdu Ok ksÅ,h fidhkak'

mrdñ;shla úg" = 2 cos , = sin uÕska fokq ,nk jl%fha = g wkqrEm ,CIHfha §

we¢ wNs,ïNh jl%h kej; = wkqrEm ,CIHfha § yuqfõ'

2 sin − 8 cos + 3√2 = 0 nj fmkajkak'

+ − 1 = 0 yd + − 6 + 8 + 9 = 0 jD;a; iam¾Y jk ,CIHfha LKAvdxl fidhkak'

= jk ;%sfldaKfha (1 , 3 ) yd (−2, 7) fõ' ,CIHfha LKAvdxl 6 − 8 + 43 = 0 ;Dma; lrk nj fmkajkak'

w.hkak'

(2) = 4 yd (2) = 1 úg" [ hkq ys wjl,Hhhs] → 2 ( ) ( ) = 2 nj fmkajkak'

= cos sin , = asin cos kï , ksÅ, úg ( ) hkak f.ka iajdh;a; úg 4 = 5 nj fmkajkak'

1.

1

07

2.

3.

4.

5.

6.

7.

8.

9.

10.

AB −2 0 4

C (1 + 3√3 )

Page 3: Test Doc

11. (i)

(ii)

(iii)

(a)

(b)

(c)

(a)

(b)

11.

12.

13.

yd g

w.h .; o fmkajka

yd fidhkak' fidhkak' |5 − 3 | ≥ , , kï

m%Yak 12 k

(i) tla

(ii) ´kE

(iii) tla

m%Yak 06la3( + )wdldrfhk

i|yd 3 +

wNHqykfh= (1fidhkak'

wd.kaâ i

lrhs' y

iu

ixlS¾K ifidhkak' = 12 +(i) =

m%;súreoaO

yels nj o ak' + +tfiau , ,tkhska >kc≥ 2 − 3 jk

ï fldgia ;=k

ka m%Yak yhl

tla fldgfi

Eu fldgilsk

tla fldgisk

la f;dard.; y

m%ldYkfha

ka m%ldY l<+ 2 +. …

hka idOkh + √3) hhs

igyk u;

yd yryd h

udka;rdi%hla

ixLHdj +5 ys j¾. uQ00 0

,l=Kq we;s

yd g i= 0 ys uQ,, + hkq c iólrK ú

k mßÈ jQ y

klska iukaú

lg ms<s;=re i

ia m<uq m%Yak

ka m%Yak ;=k

ka tla m%Yakh

yels wdldr

yd i|

< yels nj f

hkak 7 ka … … … … … … .lrkak'

.ksuq' 2 uQ, ,CIH

hk f¾Ldj u

la jk fia + ldàiSh

uQ, fol + iy =

- 147 -

;s kï ys ;

iudk ,l=Kq

, fõ' fuys 36 − 12úi|kak'

ys w.h mrd

ú; m%Yak m;%

iemhsh hq;=h

kh wksjd¾h

klg jvd jeä

hlgj;a ms<s

fidhkak'

|yd iqÿiq w

fmkajkak' f

fnfok nj . . + ( ), ixlS¾

Hh o hkak

u; ksrEmK

,CIHh f;

h wdldrfhk+ wdldrf1 −00 0

;d;aúl w.

we;akï ±2√ yd ksh− 11 + 2

dih fidhkak

;%hl tla fl

h'

kï"

äfhka Tyqg

<s;=re iemhSu

w.hka f;dar

uys yd

fmkajkak'

=

¾K ixLHd

k 2 ' h

Kh lrkq ,

;dardf.k we

ka ks¾Kh

hka fidhkak−− hhs .

Aj

.h i|yd √ lsisu w

h; fõ' ,2 = 0 iólr

k'

ldgil m%Yak

g ms<s;=re iem

u wksjd¾h k

rd .ksñka 3Ok ksÅ, f

− ( )

tl tll

hkak ixl

,nk ,CIHh

e;' u.ska

lrkak'

k'

.ksuq'

Ajith Wimang

+ g ish

w.hla .; f

weiqßka

rKfha uQ,

k 04 ne.ska w

mhsh fkdye

kï" 3 hkak

fõ' tkhska O

− ( )udmdxlh y

lS¾K ixLH

h msysgkafkao

ka ksrEmKh

ys úl

ga Wijesingh

h¿ ;d;aúl

fkdyels nj+ yd

kï yd

wvx.=h' tu

els kï"

7 + 3(2 )Ok ksÅ,uh

nj .Ks;

yd úia;drh

Hd ksrEmKh

o@

lrkq ,nk

l¾Kj, È.

1

07

he

l

j

u

h

;

h

h

k

.

Page 4: Test Doc

- 148 -

Ajith Wimanga Wijesinghe

fuys , yd hkq ≠ 1 jk mßÈ jQ ;d;aúl ksh; fõ' = = nj

fmkajkak' hkq 3 jk >kfha talc kHdihhs' tkhska" = jk mßÈ kHdihla fidhkak'

(ii) = kHdih = imqrd,hs kï" = 0 kï = 0 nj fmkajkak'

(a) ( +1) 1+ 2 = nj fmkajkak'

fuys = tan fõ'

sin = (sin + cos ) + (cos − sin ) jk mßÈ yd fidhd wkql,kh w.hkak'

(b) i. ( ) w.hkak'

ii. ln(sec + tan ) = sec nj fmkajd

we.hSug th Ndú;d lrkak'

( )√ we.hSï i|yd = √

wdfoaYh fhdokak'

(a) = (1 + sin ) sin−1 kï" (1 − ) − hkak flfrka iajdh;a; nj

fmkajkak' tkhska = 1, 2, 3, 4 i|yd = 0 § fidhkak'

(b) ( ) = , , ;d;aúl ksh; fõ' (−2, −1) ,CIHh ( ) ys yereï ,CIHhla kï ,

fidhkak' m<uq jHq;amkakh ie,lSfuka = ( ) ys m%ia:drh w¢kak' ( ) = iólrKhg

m%Nskak ;d;aúl uQ, mej;Sug mej;sh hq;= w.h o fidhkak'

(c) ksh;hla o ≠ 0, cos ≠ 0 o úg" = (cos + sin ), = (sin − cos ) kï

ys Y%s; f,i yd fidhkak'

(a) + + = 0 ir, f¾Ldj u; ( ) ,CIHfha m%;sìïNfha LKavdxl fidhkak'

;%sfldaKhl , , YS¾I msysgd we;af;a ms<sfj,ska = , = 2 , = 3 f¾Ld u;h

,ïN iuÉfþolfha iólrKh 3 + − 18 = 0 fõ' f¾Ldj + = 0 ir,

f¾Ldjg iudka;rh' ;%sfldaKfha mdoj, iólrK ,nd.kak'

(b) + = 25 jd;a;fha;a − + 1 = 0 f¾Ldfõ;a fþμ ,CIHh yryd , jD;a; folla

we| we;af;a , jD;a; folu + = 25 f¾Ldj iam¾Y lrk mßÈh' yd ys ixlrk fidhkak'

yd ys fmdÿ iam¾Yl fþokh fkdjk nj o fmkajkak'

(a) = tan + cot − f,i .ksuq' 1 + = 2( − 1) sin 2 nj idOkh lrkak'

tkhska ys ´kEu ;d;aúl w.hla i|yd tan + cot − m%ldYh 1/3 yd 3 w;r

w.hla fkd.kakd nj fmkajkak' (b) i|yd úi|kak' 4 − 4(cos sin ) − sin 2 = 0

cos − sin = 6⁄ ' fuys 0 ≤ cos ≤ yd − ≤ sin ≤ '

(c) ;%sfldaKfha , fldaKhkaf.a ihsk − ( + ) + = 0 iólrKfha uQ, fõ' cos = sin nj fmkajkak'

∫ ∫ 2

-1

∫ 1

0 ∫

0 14.

15.

16.

17.

Page 5: Test Doc

- 149 -

Ajith Wimanga Wijesinghe

1 + (1 + ) + (1 + ) + … … … … … . (1 + ) m%idrKfha ys ix.=Klh ( )!( )!( )!

nj fmkajkak'

1 + (1 + )(1 + ) +. … … + (1 + ) = ( ) ( ) → .=fKda;a;r fY%aKshla f,i

.;aúg'

= [(1 + ) − 1] = +

+ 1∑= 0 − 1]

= + 1∑= 1

= + 1 úg ys ix.=Klh = =

( )!( )!( )! − ( − 3) + = 0 j¾. iólrKfha uQ, ;d;aúl ùu i|yd ∈ (−∞, 1) ∪ (9, ∞) nj

o uQ, 2 u Ok ùu i|yd ∈ [9, ∞) nj o fmkajkak'

− ( − 3) + = 0

∆ = ( − 3) − 4 = − 6 + 9 − 4 = ( − 1)( − 9) wd.kaâ igyk u; olajd we;s j¾.M,h fokq ,nk mrdih fidhkak'

= 6

1 + 3√3 = −2 + 3 + 3√3

= −2 + 6 + √

= −2 + 6 cos + sin

ixhqla; .Ks;h - I Combined Mathematics - I úi÷ï - 07 A fldgi

1.

+ + − +1 9

A B−2 0 4

uQ, ;d;aúl ùu i|yd" ∆ ≥ 0 úh hq;=h'

< 1 fyda > 9 úh hq;=h'

uQ, ;d;aúl ùug" (−∞, 1) ∪ (9, ∞) úh hq;=h'

uQ, fol yd kï" + = − 3

=

uQ, folu Ok ùu i|yd ∆ ≥ 0

− 3 > 0

> 0

th > 0, > 3, ≥ 9 úh hq;=h'

uQ, fol u ;d;aúl ùug ∈ [ 9, ∞)

2.

C (1 + 3√3 )

3.

5

10

5

5

5

5

5

5

5

5

5

Page 6: Test Doc

- 150 -

Ajith Wimanga Wijesinghe

=

§ we;s j¾,M,h" | + 2| ≥ 6 yd 0 < | | ≤ uÕska ±lafõ'

log (2 + 1) < 1 wkqrEm l=vdu Ok ksÅ,h fidhkak'

log (2 + 1) < 1

≠ 0 yd ≥ −2

;jo" 2 + <

− − 2 > 0

( − 2)( + 1) > 0

< −1 fyda > 2

wiudk;djg wkqrEm l=vd u ksÅ,h = 3

mrdñ;shla úg" = 2 cos , = sin uÕska fokq ,nk jl%fha = g wkqrEm ,CIHfha §

we¢ wNs,ïNh jl%h kej; = wkqrEm ,CIHfha § yuqfõ'

2 sin − 8 cos + 3√2 = 0 nj fmkajkak'

= 2 cos

= sin

+ = 1 jl%h b,smaihls'

+2 = 0

= = −

= úg" = √2 , = √ , =

= úg

wNs,ïNfha iólrKh" √√ = 2

√2 − 1 = 2√2 − 4

(2 cos , sin ) fuu f¾Ldj u; ksid"

√2 sin − 1 = 4√2 cos − 4

√2 sin − 4√2 cos = −3

2 sin − 8 cos = −3√2

2 sin − 8 cos + 3√2 = 0

= úg" 2 sin − 8 cos + 3√2 = 0

+ + − −1 2

4.

5.

5

10

5

5

5

5

5

5

5

5

5

5

Page 7: Test Doc

- 151 -

Ajith Wimanga Wijesinghe

+ − 1 = 0 yd + − 6 + 8 + 9 = 0 jD;a; iam¾Y jk ,CIHfha LKAvdxl fidhkak'

≡ + = 1 ≡ (0, 0) = 1 ≡ + − 6 + 8 + 9 = 0 ≡ ( − 3) + ( + 4) = 4 ≡ (3, −4) = 4 = √4 + 3 = 5 = 5 = 4 + 1 = + jD;a; fol ndysrj iam¾Y fõ'

iam¾Y ,CIHh = ,

= jk ;%sfldaKfha (1 , 3 ) yd (−2, 7) fõ' ,CIHfha LKAvdxl 6 − 8 + 43 = 0 ;Dma; lrk nj fmkajkak'

= ksid

( − 1) + ( − 3) = ( + 2) + ( − 7)

10 = −2 − 6 = 4 − 14 + 53

6 − 8 + 43 = 0

w.hkak'

=

= 2

= 2

(3, −4) (0, 0)= 41

( , )

(1, 3) (−2, 7)

6.

7.

8.

5

5

5

5

5

5

10

5

5

5

5

Page 8: Test Doc

- 152 -

Ajith Wimanga Wijesinghe

= 2 cot − 3 + cot

= 2 ln sin − 3 + 2 ln|sin | + − wNsu; ,CIHhls'

(2) = 4 yd (2) = 1 úg" [ hkq ys wjl,Hhhs ] → 2 ( ) ( ) = 2 nj

fmkajkak'

→ 2 ( ) ( ) = → 2 ( ) ( ) ( ) ( )

= → 2 ( ) ( ) −

( ( ) ( ))

= → 2 (2) −2 → 2 ( ) ( )

= 4 − 2 (2) = 4 − 2 × 1 = 2

= cos sin , = asin cos kï , ksÅ, úg ( )( ) hkak f.ka

iajdh;a; úg 4 = 5 nj fmkajkak'

+ = cos sin + sin cos

= cos sin [cos + sin ] = cos sin

, = (cos sin )(sin cos ) = cos sin

( )( ) =

( )( )

= ( )( )

f.ka iajdhla; ùug" 4 = 5

9.

10.

5

5

5

5

5

5

5

5

5

5

10

Page 9: Test Doc

- 153 -

Ajith Wimanga Wijesinghe

(i) yd g m%;súreoaO ,l=Kq we;s kï ys ;d;aúl w.h i|yd + g ish¿ ;d;aúl

w.h .; yels nj o yd g iudk ,l=Kq we;akï ±2√ lsisu w.hla .; fkdyels nj

o fmkajkak'

(ii) yd + + = 0 ys uQ, fõ' fuys yd ksh; fõ' , weiqßka + yd

fidhkak' tfiau , , + hkq 36 − 12 − 11 + 2 = 0 iólrKfha uQ, kï yd

fidhkak' tkhska >kc iólrK úi|kak'

(iii) |5 − 3 | ≥ 2 − 3 jk mßÈ jQ ys w.h mrdih fidhkak'

(i) = +

= +

− + = 0

ys ;d;aúl w.h i|yd

∆= − 4

yd ,l=Kq wiudk kï" < 0

−4 > 0

− 4 > 0

∆ > 0

tkï ys ;d;aúl w.h i|yd g ish¿ ;d;aúl w.h .; yel'

yd ys ,l=kq iudk kï"

> 0

túg" ∆= − 4

= − 2√ ( − 2√ )

−2√ < < 2√ úg ∆< 0 fõ'

tkï ;d;aúl w.h g −2√ yd 2√ w;r w.hla .; fkdyel'

(ii) + + = 0 ys uQ, yd kï"

+ = −

=

36 − 12 − 11 + 2 = 0 ys

uQ, , yd ( + ) kï"

+ + + =

2( + ) = → −2 =

= −

( + ) =

ixhqla; .Ks;h - II Combined Mathematics - II úi÷ï - 07 B fldgi

11.

+ +− −2√ 2√

5

5 5

5

5

5

5

5

5

5

5

5

10

10

Page 10: Test Doc

- 154 -

Ajith Wimanga Wijesinghe

(− ) =

= → =

+ = −

=

− + = 0

6 − + 2 = 0

= ± ( )( )×

= ± √

= √

, = √

+ =

§ we;s iólrKfha uQ, jkqfha"

, √ , √

h'

(iii) = 2 − 3

= |5 − 3 | = 5 − 3 ≤ 5 3⁄−5 + 3 >

ish¿ i|yd |5 − 3 | > 2 − 3 fõ'

tfukau ish¿ ;d;aúl i|yd |5 − 3 | > 2 − 5 fõ'

5

5

5

5

5

5

5

10

20

10

Page 11: Test Doc

- 155 -

Ajith Wimanga Wijesinghe

(a) , , kï fldgia ;=klska iukaú; m%Yak m;%hl tla fldgil m%Yak 04 ne.ska wvx.=h' tu

m%Yak 12 ka m%Yak yhlg ms<s;=re iemhsh hq;=h'

(i) tla tla fldgfia m<uq m%Yakh wksjd¾h kï"

(ii) ´kEu fldgilska m%Yak ;=klg jvd jeäfhka Tyqg ms<s;=re iemhsh fkdyels kï"

(iii) tla tla fldgiska tla m%Yakhlgj;a ms<s;=re iemhSu wksjd¾h kï"

m%Yak 06la f;dard.; yels wdldr fidhkak'

(b) 3( + ) m%ldYkfha yd i|yd iqÿiq w.hka f;dard .ksñka 3 hkak 7 + 3(2 ) wdldrfhka m%ldY l< yels nj fmkajkak' fuys yd Ok ksÅ, fõ' tkhska Ok ksÅ,uh

i|yd 3 + 2 hkak 7 ka fnfok nj fmkajkak'

(c) + +. … … … … … … . . + ( ) = − ( ) − ( ) nj .Ks;

wNHqykfhka idOkh lrkak'

(a) (i)

4 4 4 − 12 m<uq m%Yakh wksjd¾h úg m%Yak 06 f;dard.; yels wdldr'

m%Yak f;dard .; yels wdldr m%Yak f;dard .;

yels fldgia

fldgilska m%Yak

f;dard .ekSu

´kEu fldgilska m%Yak 03 la

03

01

03

tla fldgilska m%Yak 02 la

fjk;a fldgilska m%Yak 01 la = 6 = 9 54

tla fldgilska tla m%Yakhla

ne.ska

01 = 27 27

tla tla fldgiska m<uq m%Yakh wksjd¾h úg m%Yak f;dard .ekSï = 3 + 54 + 27 = 84

(ii) ´kEu fldgilska m%Yak 03 lg jvd jeäfhka f;dard .; fkdyels kï"

m%Yak f;dard .; yels

wdldr

m%Yak f;dard .;

yels fldgia

fldgilska m%Yak f;dard

.ekSu

m%Yak 03la fldgia 02

lska = 3 = 16 48

tla fldgilska m%Yak 03

la o ;j;a fldgilska

m%Yak 02 la o wjika

fldgiska m%Yak 01 la

3! = 6 = 96 576

tla fldgilska m%Yak 02

ne.ska

01 = 216 216

´kEu fldgilska m%Yak 03 jvd jeäfhka f;dard .; fkdyels kï l< yels f;dard

.ekSï = 48 + 576 + 216 = 840

12.

5

5

5

5

5

5

5

5

Page 12: Test Doc

- 156 -

Ajith Wimanga Wijesinghe

(iii) tla fldgilska tla m%Yakhla j;a wksjd¾h kï"

m%Yak f;dard .; yels

wdldr

m%Yak f;dard .;

yels fldgia

fldgilska m%Yak f;dard

.ekSu

tla fldgilska m%Yak 4

la o wfkla fldgia j,ska

01 m%Yakh ne.ska

= 3 = 16 48

tla fldgilska m%Yak 03

la o ;j;a fldgilska

m%Yak 02 la o wjika

fldgiska m%Yak 01 la

3! = 6 = 96 576

tla fldgilska m%Yak 02

ne.ska

01 = 216 216

tla fldgilska tla m%Yakhla j;a wksjd¾h kï"= 48 + 576 + 216 = 840

(b) 3 = 3(3 ) = 3(9) = 3( + ) f,i .ksuq' = 7 yd = 2 f,i .;a úg"

3 = 3(2 + 7)

= 3(2 ) + 3 7 2

= 3 7 2 ∈ f,i .ksuq' túg"

3 = 3(2 ) + 7

3 + 2 = 7 + 32 + 2

= 7 + 32 + 42

= 7 + 2 (3 + 4) = 7 + 7 ∙ 2

= 7( + 2 ) tkï" 3 + 2 hkak 7 ka fnfoa'

(c) + +. … … … … … … . . + ( ) = − ( ) − ( ) = 1 úg j'me' = =

o'me' = − − = − =

= 1 úg m%;sM,h i;H fõ'

= úg m%;sM,h i;H hhs .ksuq'

+ +. … … … … … … . . + ( ) = − ( ) − ( ) fomigu ( ) tl;= lruq'

∑ − 1

= 0 ∑ − 1

= 0

5

5

5

5

5

5

5

5

5

5

5

5

5

5

5

Page 13: Test Doc

- 157 -

Ajith Wimanga Wijesinghe

+ ( ) + 1( +2)2−1 = − ( ) − ( ) + ( ) = − ( ) − ( ) + ( )( ) = − ( ) − ( ) + ( ) + ( ) = − ( ) − ( ) tkï" = + 1 úgo m%;sM,h i;H fõ' tneúka ish¿ Ok mQ¾K i|yd"

+ +. … … … … … … . . + ( ) = − ( ) − ( ) fõ'

(a) = (1 + √3) hhs .ksuq' 2 , ixlS¾K ixLHd tl tll udmdxlh yd úia;drh

fidhkak'

wd.kaâ igyk u; uQ, ,CIHh o hkak 2 ' hkak ixlS¾K ixLHd ksrEmKh

lrhs' yd yryd hk f¾Ldj u; ksrEmKh lrkq ,nk ,CIHh msysgkafkao@

iudka;rdi%hla jk fia ,CIHh f;dardf.k we;' u.ska ksrEmKh lrkq ,nk

ixlS¾K ixLHdj + ldàiSh wdldrfhka ks¾Kh lrkak' ys úl¾Kj, È.

fidhkak'

= 12 + 5 ys j¾. uQ, fol + wdldrfhka fidhkak'

(b) (i) = 00 0 iy = 1 − −0 −0 0 hhs .ksuq'

fuys , yd hkq ≠ 1 jk mßÈ jQ ;d;aúl ksh; fõ' = = nj

fmkajkak' hkq 3 jk >kfha tall kHdihls' tkhska" = jk mßÈ kHdihla

fidhkak'

(ii) = kHdih = imqrd,hs kï" = 0 kï = 0 nj fmkajkak'

(a) = (1 + √3)

= + √

= cos + sin

| | = 1, =

= cos + sin

= cos − sin + 2sin cos

= cos + sin

2 = 2 cos + sin

|2 | = 2

(2 ) = 23

= cos + sin

13.

2

10

5

5

5

5

5

5

5

5

10

10

Page 14: Test Doc

- 158 -

Ajith Wimanga Wijesinghe

= 3 cos − sin = 3 cos + sin

= 3, =

1' = − + −

= 2 −

=

, , tal f¾Çh fõ'

ys ixlS¾K ixLHdj ≡ 2 + 3⁄

= 2 cos − sin +3 cos + sin

= 5 cos 23 − sin = −

= 2 − = + √

= + = = √7

= 2 2 − 32

= −1 + √3 + 1 + √3

= + √ = +

= = √19

ys j¾. uQ, + kï"

( + ) =

( − ) + 2 = 12 + 5

− = 12

2 = 5

− = 12

4 − 25 = 48 4 − 48 − 25 = 0

(2 + 1)(2 − 25) = 0

2 + 1 ≠ 0 ksid 2 − 25 = 0

=

= ± 5 √2

30

(2 ) /32 /3

/6 0/3/3 /3

5

20

5

55

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Page 15: Test Doc

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Ajith Wimanga Wijesinghe

túg = ± √ ∙

= ±1/√2

ys j¾. uQ, → √ + √ fyda √ − √

(b) (i) = 100 0 = 1 − −0 −0 0

= 100 0 1 − −0 −0 0

= 1 0 00 1 00 0 9

= 1 − −0 −0 0 100 0

= 1 0 00 1 00 0 1

= =

( ) =

=

= 1 0 00 1 00 0 1

=

= = 1 0 0− 0− −

(ii) =

=

=

= + ++ +

= = 1 00 1

+ = 1 1

+ = 0

= 0 kï = 1

= 0

+ = 0

= 0

(a) ( +1) 1+ 2 = nj fmkajkak'

fuys = tan fõ'

sin = (sin + cos ) + (cos − sin ) jk mßÈ yd fidhd wkql,kh w.hkak'

∫ 1

0 ∫

0 14.

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Page 16: Test Doc

- 160 -

Ajith Wimanga Wijesinghe

(b) ( ) w.hkak'

ln(sec + tan ) = sec nj fmkajd

we.hSug th Ndú;d lrkak'

( )√ we.hSï i|yd = √

wdfoaYh fhdokak'

(a) = tan úg"

= tan → = sec

= 0 úg = 0

= 1 úg = 4

( )( ) = ( )( ) sec

= ( )

sin = (sin + cos ) + (cos − sin ) sin ys ix.=' → 1 = − 1

cos ys ix.=' → 0 = + 2

2 = 1 → = 1/2

= −1/2

sin = (sin + cos ) − (cos − sin ) = −

= −

= 2 − ln|sin + cos | = − ln √2

(ln ) = (ln )

= (ln ) − (ln )

= (ln ) −

= (ln ) − ln

= (ln ) − ln ( )

∫ ∫ 2

-1

∫ 1

0 ∫0 ∫

0

0 ∫

0 ∫

0

∫ ∫ ∫∫∫∫

5

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Page 17: Test Doc

- 161 -

Ajith Wimanga Wijesinghe

= (ln ) − ln + (ln ) = (ln ) − ln +

= (ln ) − ln + +

[ln(sec + tan )] = × sec tan + sec

= [ ]

= sec

= sec ''''' = sec tan

= √

= sec

= [ln(sec + tan )]

= ln(sec + tan ) +

(b) = √

= ( )( )/√ √( )

= ( )( ) ( )( ) √

= ( ) √ 1

= ( )

− 1 = ( ) ( )

= ( )

= ( )( )

− 1 = ( + 1)/( + 2) 1 ka" =

( )( ) ( )√

= ( )√

( )√ =

= log [sec + tan ] fuys sec = 1 o sec = fõ'

∫∫ ∫ ∫ ∫

∫ 2

-1 ∫2

-1

∫ 5

5

5

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Page 18: Test Doc

- 162 -

Ajith Wimanga Wijesinghe

(a) = (1 + sin ) sin−1 kï" (1 − ) − hkak flfrka iajdh;a; nj

fmkajkak' tkhska = 1, 2, 3, 4 i|yd = 0 § fidhkak'

(b) ( ) = , , ;d;aúl ksh; fõ' (−2, −1) ,CIHh ( ) ys yereï ,CIHhla kï ,

fidhkak' m<uq jHq;amkakh ie,lSfuka = ( ) ys m%ia:drh w¢kak' ( ) = iólrKhg

m%Nskak ;d;aúl uQ, mej;Sug mej;sh hq;= w.h o fidhkak'

(c) ksh;hla o ≠ 0, cos ≠ 0 o úg" = (cos + sin ), = (sin − cos ) kï

ys Y%s; f,i yd fidhkak'

(a) = (1 + sin ) sin kï"

= (1 + sin ) √ + sin 11− 2

= (1 + sin ) √ + √

= (1 + 2 sin ) √

√1 − = 1 + 2 sin 1

kej; úIfhka wjl,kfhka"

√1 − − √ = √

(1 − ) − = 2 2

tkï" (1 − ) − hkak flfrka iajdhla; fõ'

kej; úIfhka wjl,kfhka"

(1 − ) −2 − − = 0

(1 − ) −3 − = 0 3

kej; úIfhka wjl,kfhka"

(1 − ) −2 −3 −3 − = 0

(1 − ) −5 −4 = 0 4 ka"

= 0 úg 1 ka = 1

= 0 úg 2 ka = 2

= 0 úg 3 ka = = 1

= 0 úg 4 ka = 4 = 4 × 2 = 8

15.

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Page 19: Test Doc

- 163 -

Ajith Wimanga Wijesinghe

(b) ( ) =

( ) = ( ) ( )( )

= −2 úg (−2) = 0

( )

= 0 → −3 + 4 = 0 1

= −2 úg (−2) = −1

= −1

−2 + = −5 2

5 = 20

= 4

= 3

( ) =

( ) = ( ) ( )( )

= ( )

= ( )( )

= ( )( )( )

( ) = 0 úg (2 + )(1 − 2 ) fõ'

= −2 fyda = 1/2

< 2 −2 < < 1/2 1/2 <

( ) − + −

= −2 § Y%s;h wjuhls' wjuh ≡ −1 ⇒ (−2, −1) = 1/2 § Y%s;h Wmßuhls' Wmßuh ≡ 4 ⇒ (1/2, 4) = 0 úg (0) = 3 ⇒ (0, 3) = 0 úg 4 + 3 = 0 → = −3/4 ⇒ (−3/4,0) → ±∞ úg → 0

5

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5

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Page 20: Test Doc

- 164 -

Ajith Wimanga Wijesinghe

( ) = i,luq'

= ( ) o = o úg

( ) = g m%Nskak úi÷ï i|yd yd fþok ,CI úh hq;=hs' ta i|yd"

−1 ≤ ≤ 4 úh hq;=hs' (c) = (cos + sin )

= ( cos + sin − sin ) = cos = (sin − cos )

= (cos − cos + sin ) = sin

= ×

= sin × = tan

=

= ×

= tan ×

= sec ×

=

(a) + + = 0 ir, f¾Ldj u; ( ) ,CIHfha m%;sìïNfha LKavdxl fidhkak'

;%sfldaKhl , , YS¾I msysgd we;af;a ms<sfj,ska = , = 2 , = 3 f¾Ld u;h

,ïN iuÉfþolfha iólrKh 3 + − 18 = 0 fõ' f¾Ldj + = 0 ir,

f¾Ldjg iudka;rh' ;%sfldaKfha mdoj, iólrK ,nd.kak'

(b) + = 25 jd;a;fha;a − + 1 = 0 f¾Ldfõ;a fþμ ,CIHh yryd , jD;a; folla

we| we;af;a , jD;a; folu + = 25 f¾Ldj iam¾Y lrk mßÈh' yd ys iólrK

fidhkak'

yd ys fmdÿ iam¾Yl fþokh fkdjk nj o fmkajkak'

(a) + + = 0

wkql%uh = − /

( , ) yryd § we;s f¾Ldj ,ïN f¾Ldj u; ´kEu ( ) ,CIHhla ie,l+ úg"

= 1

= = f,i .ksuq' mrdñ;shls'

= +

( , )

( , ) + + =

16.

10

5

5

5

5

5

5

5

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Page 21: Test Doc

- 165 -

Ajith Wimanga Wijesinghe

= +

ys m%;sìïNh ( ) kï"

= + , = + fõ'

ys uOH ,laIHh ≡ +

,CIHh = 0 u; ksid

+ [ ]

+ = 0

( + ) = −2[ + + ] = −2

[ ]

tuÕska" , ys m%;sìïNh = − 2 ( )

= − 2 ( )

≡ + 3 − 18 = 0

= + = 0

≡ ( , ) f,i .ksuq'

túg = 0 u.ska ys m%;sìïNh ksid

= − [ ]

= − . [ ]

,CIHh = 2 u; ksid

− [ + 3 − 18] = 2 − ( + 3 − 18) − [4 − 18] = 2 − [4 − 18] 5 − 12 + 54 = 10 − 8 + 36

9 = 18

= 2

≡ 2 + (10) , 2 + (10) ≡ (4, 8)

≡ (2, 2) f¾Ldj ksid"

^ f¾Ldfõ wkq& × (− ) = −1

f¾Ldfõ wkql%uKh = 3

f¾Ldfõ iólrKh

= 3

3 − − 4 = 0

∥ + = 0 f¾Ldj ksid"

ys wkql%uKh = 1

ys iólrKh

= 1

− 8 = − + 4

=

C

B A

= =

= =

5

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Page 22: Test Doc

- 166 -

Ajith Wimanga Wijesinghe

+ − 12 = 0

≡ ( ) kï" + = 12 1

= 3 2

4 = 12 → = 3

= 9

≡ (3, 9) ys iólrKh +

− 3 = 7( − 3) 7 − − 18 = 0

(b) = + − 25 = 0 = − − 1 = 0

yd ys fþok ,CIHh yryd jk ´kEu jD;a;hls'

+ − 25 + ( − − 1) = 0

+ + − − 25 − = 0

flakaøh = " wrh = 2⁄ + 25 +

fuu jD;a; + − 25 = 0 f¾Ldj iam¾Y lrhs'

^flakaøfha isg ÿr& = ^wrh&

√ = + 25 +

+25 + =

+ 2 − 575 = 0

( + 25)( − 23) = 0

= −25 fyda

= 23

= −25 úg ≡ + − 25 + 25 = 0

= 23 úg ≡ + + 23 − 23 − 48 = 0

= 0 yd = 0 fþokh jk ksid yd g we;af;a fmdÿ iam¾Yl folls'

;jo yd ys wrhka iudkh'

tneúka yd ys fmdÿ iam¾Yl fþokh fkdfõ'

(a) = tan + cot − f,i .ksuq' 1 + = 2( − 1) sin 2 nj idOkh lrkak'

tkhska ys ´kEu ;d;aúl w.hla i|yd tan + cot − m%ldYh 1/3 yd 3 w;r

w.hla fkd.kakd nj fmkajkak'

(b) i|yd úi|kak'

4 − 4(cos sin ) − sin 2 = 0

cos − sin = 6⁄ ' fuys 0 ≤ cos ≤ yd − ≤ sin ≤ '

(c) ;%sfldaKfha , fldaKhkaf.a ihsk − ( + 5) + = 0 iólrKfha uQ, fõ' cos = sin nj fmkajkak'

=

17.

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5 5

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Page 23: Test Doc

- 167 -

Ajith Wimanga Wijesinghe

(a) = tan + cot −

= ×

=

= sin 2 − sin 2 + (2 sin 2 − 1) = 2 sin 2 + 1

2 sin 2 ( − 1) = 1 +

sin 2 = ( )

ish¿ i|yd −1 ≤ sin 2 ≤ 1 ksid

−1 ≤ ( ) ≤ 1

= ( ) +1 ≥ 0 = ( ) −1 ≤ 0

= ( )( ) ≥ 0 =

( )( ) ≤ 0

= ( ) ≥ 0 = ( )( ) ≤ 0

yd m%ldYk folu i;H ùug"

< 1/3 yd > 3 úh hq;=h'

tneúka 1/3 < < 3 w;r w.hla .; fkdyel'

(b) 4 − 4(cos sin ) − sin 2 = 0 (cos − sin ) = 1 − sin 2 ksid

4 − 4(cos − sin ) + (cos − sin ) − 1 = 0

= cos − sin f,i fhdouq'

3 − 4 + = 0

( − 3)( − 1) = 0

= 3 fyda = 1 fõ' ≠ 3 ksid"

= 1 úg cos − sin = 1

√ cos − √ sin = √

cos − = √

cos − = cos

+ = 2 ± " ksÅ,hls'

= 2 ± −

= 2 fyda = 2 −

+ + − 1/3 1

− − +1 3

1/3 3 1

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5

5 5

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5 5

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Page 24: Test Doc

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Ajith Wimanga Wijesinghe

cos − sin =

= cos o = sin f,i .ksuq'

cos = o sin =

− =

= +

cos = cos +

= cos − sin sin

= √

∙ cos −

3 = √3 cos

√3 = cos

3 = (1 − ) 4 = 1

= → = ±

fojk jD;a; mdolfha;a 4 jk jD;a; mdolfha;a kï"

= úh fkdyel'

∴ = fõ'

(c) − ( + ) + = 0

uQ, sin yd sin kï"

sin + sin =

sin + sin =

sin + sin ≠ 0 kï"

sin = 1

= 2

+ + =

+ = 2

= 2 −

cos = cos 2 −

cos = sin

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