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Standard/ Grade/ Class 10 Electricity Gurudatta K Wagh

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Page 1: Std10 Electricity

Standard/ Grade/ Class 10 Electricity

Gurudatta K Wagh

Page 2: Std10 Electricity

Electric current and circuit

Electric potential and potential difference

Ohm's Law

Factors responsible for the resistance of a conductor

Resistance of a system of resistors

• Resistors in series

• Resistors in parallel

Heating effect of electric current

• Practical applications of Joule's heating

Electric power

Page 3: Std10 Electricity

Electric current and circuitIf the electric charge flows through a conductor (a

metallic wire) we say that there is an electric current in the conductor.

A switch makes a conducting link between the cell and the bulb. A continuous and closed path of an electric current is called an electric circuit

If the circuit is broken anywhere (or the switch of the torch is turned off), the current stops flowing and the bulb does not glow

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Electric current The amount of charge flowing through a particular area in unit time, i.e. the rate of flow of electric charges

In metallic wires, electrons constitute the flow of charges

Electrons were not known at the time when the phenomenon of electricity was first observed. So, electric current was considered to be the flow of positive charges and the direction of flow of positive charges was taken to be the direction of electric current

Page 6: Std10 Electricity

Conventionally, in an electric circuit the direction of electric current (positive to negative) is taken as opposite to the direction of the flow of electrons

Electric current flows in the circuit from the positive terminal of the cell to the negative terminal of the cell through the bulb and ammeter

Page 7: Std10 Electricity

Electric circuit

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Current formulaIf a net charge Q flows across any cross-section of a conductor in time t, then the current I through the cross-section is

current I = net charge Q/ time t SI unit electric charge = coulomb 'C' equivalent to the charge contained in nearly 6 x 1018 electrons

An electron possesses a negative charge of 1.6 X 10-19 C

Page 9: Std10 Electricity

Electron/s Charge (C)1 1.6 x 10-19

6 x 1018 6 x 1018 x 1.6 X 10-19 = 9.6 x 10-1

Charles-Augustin de Coulomb

Page 10: Std10 Electricity

The chemical action within a cell generates the potential difference across the terminals of the cell, even when no current is drawn from it

In order to maintain the current in a given electric circuit, the cell has to expend its chemical energy stored in it

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SI unit electric current = ampere 'A'

One A is constituted by the flow of one C of charge per second

1A = 1C/ 1s

André-Marie Ampère

Small quantities of current

milliampere 1mA = 10-3A

microampere 1µA = 10-6A

Page 12: Std10 Electricity

Ammeter measures electric current in a circuit; always connected in series in a circuit•YouTube video explain working of ammeter. Add

Instruments used to measure smaller currents, in the milliampere or microampere range, are designated as milliammeters or microammeters

Page 13: Std10 Electricity

Flow of charges inside a wireElectrons are able to travel through a perfect solid crystal smoothly and easily, as if they were in a vacuum. The motion of electrons in a conductor is different from that of charges in empty space.

When a steady current flows through a conductor, the electrons in it move with a certain average drift speed. The drift speed of electrons for a copper wire carrying a small current is small, 1mm s-1

Page 14: Std10 Electricity

Electric potential and potential difference

What makes the electric charge to flow?The electrons move only if there is a difference

of electric pressure – potential difference – along the conductor

The potential difference may be produced by a battery consisting of one or more electric cells

Page 15: Std10 Electricity

Definition Electric potential difference between two points in an electric circuit carrying some current = work done to move a unit charge from one point to the other

Potential difference between two points (V) = Work done (W)/ Charge (Q)SI unit volt (V)

Page 16: Std10 Electricity

One volt is the potential difference between two points in a current carrying conductor when 1 joule of work is done to move a charge of 1 coulomb across one point to other

1 volt = 1 joule/ 1 coulomb

The potential difference is measured by means of an instrument called the voltmeter. The voltmeter is always connected in parallel across the points between which the potential difference is to be measured

Page 17: Std10 Electricity

Alessandro Giuseppe Antonio Anastasio Volta

A voltmeter is an instrument used for measuring electrical potential difference between two points in an electric circuit.

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One joule is the equivalent of one watt of power radiated or dissipated for one second

James Prescott Joule

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Ohm's LawDefinition The potential difference across the

ends of a given metallic wire in an electric circuit is directly proportional to the current flowing through it, provided its temperature remains same

V I, V/ I = constant (R), ∝ V = IR

Page 20: Std10 Electricity

Relationship between the potential difference across a conductor and the current through itV-I graph is a straight line passing through the origin. V/I is a constant ratio

Georg Simon Ohm

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R is a constant for the given metallic wire at a given temperature and is called resistance.

Resistance The property of a conductor to resist the flow of charges through it

SI unit = ohm ΩOhm's law R = V/ I

•If the potential difference across the two ends of a conductor is 1 V and the current through it is 1 A, then the resistance R of the conductor is 1 Ω•1 ohm = 1 volt/ 1 ampere

Page 22: Std10 Electricity

The current through a resistor is inversely proportional to its resistance. If the resistance is doubled the current gets halved

A component used to regulate current without changing the voltage source is called variable resistance. A rheostat is often used to change the resistance in the circuit

Page 23: Std10 Electricity

The word rheostat was coined about 1845 by Sir Charles Wheatstone. It is a two-terminal variable resistor. The term "rheostat" is becoming obsolete, with the general term "potentiometer" replacing it

The most common way to vary the resistance in a circuit is to use a rheostat

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Factors responsible for the resistance of a conductor

The current is different for different components. Certain components offer an easy path for the flow of electric current while the others resist the flow.

The ammeter reading decreases to one-half (half) when the length of the wire is doubled.

Page 25: Std10 Electricity

The ammeter reading increases when a thicker wire of the same material and of the same length is used

The ammeter reading changes when a wire of different material of the same length and the same cross-section is used

Page 26: Std10 Electricity

On applying Ohm's law, it is observed that,The resistance of the conductor depends 1)on its length, 2)on its area of cross-section, and 3)on the nature of its material

Resistance (R) of a uniform metallic conductor is directly proportional to its length (l) and inversely proportional to the area of cross-section (A)

Page 27: Std10 Electricity

R l and R 1/ A∝ ∝

Hence R l/ A = p l/ A∝

ρ (rho) = constant of proportionality = electrical resistivity of the material of the conductor

SI unit = Ω m

It is a characteristic property of the material

Page 28: Std10 Electricity

Metals and alloys have very low resistivity, range 10-8 – 10-6 Ω m = good conductors of electricity

Conductor tungsten (ρ = 5.20 x 10-8) is used almost exclusively for filaments of electric bulbs, whereas copper (ρ = 1.62 x 10-8) and aluminium (ρ = 2.63 x 10-8) are generally used for electrical transmission lines

Page 29: Std10 Electricity

Resistivity (ρ) of an alloy is generally higher than that of its constituent metals. Alloys do not oxidise (burn) readily at high temperatures. For this reason alloys are commonly used in electrical heating devices like electric iron, toasters, etc.

Nichrome (ρ = 100 x 10-6) = Alloy of nickel, chromium, manganese, and iron

The above values are at temperature 20 °C

Page 30: Std10 Electricity

Insulators

rubber, glass – high resistivity

1012 – 1017 Ω m

Resistance (R) and resistivity of a material (ρ) vary with temperature

Page 31: Std10 Electricity

Resistance of a system of resistorsCurrent through a conductor depends upon its

resistance and the potential difference across its ends.

Application of Ohm's law to combination of resistors

Two methods (series and parallel)

Page 32: Std10 Electricity

Series

Parallel

Page 33: Std10 Electricity

• Resistors in seriesHaving resistances R1, R2 and R3 connected end to

end in series

Value of the current in the ammeter is the same, independent of its position in the electric circuit

In a series combination of resistors the current is the same in every part of the circuit or the same current through each resistor

Page 34: Std10 Electricity

Potential difference is equal to the sum of potential differences V1, V2 and V3

The potential difference across a combination of resistors in series is equal to the sum of potential difference across the individual resistors,V = V1 + V2 + V3

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It is possible to replace the three resistors joined in series by an equivalent single resistor of resistance R, such that the potential difference across it, and the current I through the circuit remains the same,V = IR

Applying Ohm's law to the three resistors separately,V1 = IR1 V2 = IR2 V3 = IR3

Page 37: Std10 Electricity

Hence IR = IR1 + IR2 + IR3

OR

Rs = R1 + R2 + R3

When several resistors are joined in series, the resistance of the combination Rs equals the sum of their individual resistances R1, R2,

and R3 and is greater than any individual resistance

Page 38: Std10 Electricity

• Resistors in parallelTotal current I = sum of the separate currents

through each branch of the combinationI = I1 + I2 + I3

Rp is the equivalent resistance of the parallel combination of resistors

I = V/ Rp

Applying Ohm's law to each resistorI1 = V/ R1, I2 = V/ R2, I3 = V/ R3

V/ Rp = V/ R1 + V/ R2 + V/ R3

Page 39: Std10 Electricity

Resistors in parallel

Page 40: Std10 Electricity

The reciprocal of the equivalent resistance of a group of resistances joined in parallel = sum of the reciprocals of the individual resistances

Disadvantages of series circuitIn a series circuit the current is constant throughout the electric circuit. It is obviously impracticable to connect an electric bulb and an electric heater in series because they need currents of widely different values to operate properly

Page 41: Std10 Electricity

When one component fails the circuit is broken and none of the components works, e.g. fairy lights

Advantages of parallel circuit•Divides the current through the electrical gadgets•The total resistance is decreased •It is helpful particularly when each gadget has different resistance and requires different current to operate properly

Page 42: Std10 Electricity

Heating effect of electric currentA part of the source energy in maintaining the

current may be consumed into useful work (like in rotating the blades of an electric fan)

Rest of the source energy may be expended in heat to raise the temperature of the gadget

An electric fan becomes warm if used continuously for longer time

Page 43: Std10 Electricity

Heating effect of electric current If the electric circuit is purely resistive, i.e. a configuration of resistors only connected to a battery; the source energy continually gets dissipated entirely in the form of heat, e.g. electric heater, electric iron, boiler, geyser

Page 44: Std10 Electricity

Current I, Resistor of resistance R, Potential difference V, time t, charge QWork done P = VQPower input in time t, P = V x Q/t = VI

Energy supplied to the circuit by the source in time t = P x t = VI x t

Energy expended by the source gets dissipated in the resistor as heat

For a steady current I, the amount of heat H produced in time t, H = VIt

Page 45: Std10 Electricity

Applying Ohm's law,

H = I2Rt Joule's lawHeat produced in a resistor is 1) directly proportional to the square of current for a given resistance, 2) directly proportional to resistance for a given current, and 3) directly proportional to the time for which the current flows through the resistor

H = I2Rt is used after calculating the current through it, using the relation I = V/ R

Heat energy is expressed in calories, 4.18 J = 1 calorieH = I2Rt/4.18 cal = V2t/4.18R cal = VIt/4.18 cal

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• Practical applications of Joule's heatingThe generation of heat in a conductor is an

inevitable consequence of electric current. In many cases it is undesirable as it converts useful electrical energy into heat. The unavoidable heating can increase the temperature of the components and alter their properties

Heating effect of electric current has many useful applications. E.g. iron, toaster, oven, kettle, heater

Page 47: Std10 Electricity

Electrical heating is also used to produce light, as in a bulb. The filament must retain as much of the heat generated as is possible, so that it gets very hot and emits light. It must not melt

A strong metal with high melting point such as tungsten (melting point 3380 °C) is used for making bulb filaments. The filament should be thermally isolated as much as possible, using insulating support

Page 48: Std10 Electricity

The bulbs are usually filled with chemically inactive nitrogen and argon gases to prolong the life of the filament

Most of the power consumed by the filament appears as heat, but a small part of it is in the form of light radiated

Page 49: Std10 Electricity

Fuse used in electric circuits is a common application of Joule's heating. The fuse protects circuits and appliances by stopping the flow of any unduly high electric current. The fuse is placed in series with the device.

If a current larger than the specified value flows through the circuit, the fuse wire melts due to heating

Fuses for domestic purposes are rated 1 A, 2 A, 3 A, 5 A, 10 A etc. For an electric iron which consumes 1 kW electric power when operated at 220 V, a current 4.54 A flows in the circuit. Here a 5 A fuse must be used.

Page 50: Std10 Electricity

Electric powerRate of doing work is power = rate of

consumption of energy

H = I2Rt gives the rate at which electric energy is dissipated or consumed in an electric circuit = electric power

Power P is given by P = VIORP = I2R = V2/ RSI unit watt (W)

Page 51: Std10 Electricity

Watt Power consumed by a device that carries 1 A of current when operated at a potential difference of 1 V1 W = 1 VA

James Watt

Unit watt is very small

In actual practice a larger unit called kilowatt (kW = 1000 W) is used

Page 52: Std10 Electricity

Unit of electric energy watt hour (Wh)One watt hour is the energy consumed when 1 watt of power is used for 1 hour

The commercial unit of electric energy is kilowatt hour (kWh)

1 kWh = 1000 watt x 3600 second= 3.6 x 106 watt second= 3.6 x 106 joule (J)

Page 53: Std10 Electricity

THANK YOU

SSC Std 10th TextbookCBSE Std 10th Textbook

YouTubeGoogle

Wikipedia

Suggestions and Appreciations welcome

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