StructuresStructured Programming 2012/2013

Problems

Calculate Distance

Write a program that represents the distance in the form of a structure containing meters, and

centimeters

Define 3 variables and input their values, as follows:The first value from the user.The second value from initialization.The third value is the result of addition of the other two values.

#include<iostream>using namespace std;

// Define distance structurestruct dist{

int meters;int centimeters;

};

int main(){

dist d1, d2, d3;

// Enter the values of the first variable memberscout << "Enter the values of the first variable: meters then centimeters" <<endl;cin >> d1.meters >> d1.centimeters;

// Initialize the second variable membersd2.meters = 15;d2.centimeters = 40;

// Add the first and second variable members adn put the result in the third variabled3.meters = d1.meters + d2.meters;d3.centimeters = d1.centimeters + d2.centimeters;

// Put the third variable in the correct meters and centimeters formatwhile (d3.centimeters >= 100){

d3.meters++;d3.centimeters -= 100;

}

//Display the third variable memberscout<< d1.meters << "." << d1.centimeters << " + "<< d2.meters << "." << d2.centimeters << " = "<< d3.meters << "." << d3.centimeters << endl;

}

Room Area

Write a program that creates a data structure that stores the 2 dimensions of a room (its

length and width), putting into account that the length and width are both members of the

distance struct represented in program1, and then outputs the area of the room in square

meters.

#include <iostream>using namespace std;

void main(){

//Distance struct that we have seen before!struct distance{

int meters;int centimeters;

};

//Define Room Structstruct room{

//member length is another struct !!distance length;distance width;distance height;

};

//Declare a main variable room living;

//initialize variable membersliving.length.meters = 10;living.length.centimeters = 17;living.width.meters = 12;living.width.centimeters = 10;

//Calculate approximate length and widthint approxLength = living.length.meters + living.length.centimeters / 100.0;int approxWidth = living.width.meters + living.width.centimeters / 100.0;

//calculate area and display it..cout<<"Area : "<< approxLength * approxWidth<<" square meters. "<<endl;

}

CodeTipBraces

Array of Student

Write a program that represents the students’ data by name (char array), id (int) and 6 grades.

The user should input the data of 3 students (array of struct), and then the program should

output the sum of grades of each student beside his name.

#include <iostream>#include<stdio.h>using namespace std;

void main(){

//Declare student structstruct student{int id;char name[30];int grades[6];};

//define array of 3 studentsstudent s[3];

for(int i = 0; i < 3; i++){

//read idcout<<"Enter the id of student"<<i + 1<<": ";cin>>s[i].id;cin.ignore();

//read name cout<<"Enter the name of student"<<i + 1<<endl;gets(s[i].name);

//read 6 gradescout<<"Enter the grades of student "<<i + 1<<": ";for(int j = 0 ; j < 6 ; j++){

cin>>s[i].grades[j];}

}

int sum;for(int i = 0 ; i < 3 ; i++){

sum = 0;cout<<"Sum of grades of student"<<s[i].name<<": ";

//calculate total grade for each studentfor(int j = 0 ; j < 6 ; j++){

sum += s[i].grades[j];}cout<<sum<<endl;

}}

Thanks!