soal program linier
DESCRIPTION
proglinTRANSCRIPT
9. Solve the following transportation problem by the uv-method, using any one of the available methods for finding an initial solution.D1D2D3D4D5D6D7ai
O18
610129 11540
O23
76987850
O35
426393 90
O417
1211139101230
O57
114565760
bj20304080602515270
Penyelesaian:Berdasarkan tabel diatas, disusun dengan menggunakan metode modi sebagai berikut:
820 -6 20 +10 -612 -49 -411 -75 1
405
3 + 6 7 10 -6 -19 408 -27 -28 -1506
5 14 02406403109 -73 1903
17 -512 -211 -313 -19 3010 -212 -2309
7 211 -44 15 4620525715606
20304080602515270
31-130-11
810 -63010 012 29 211 15 7 + 4011
310
+7 -66 -1940 -8 -27 -28 -1506
5 -54 -6240640
+310 -9 -73 1903
17- 11
12 -811 -313 -1930 10 -212 -2309
7 -411-104 15 -2620 + 5 25715 -606
20304080602515270
-3-5-130-11
8 -7630 10 -712 -59 -511 -85 10
404
320
7 16 -19308 -27 -28 -1506
5 -54 12 406 50 -3 0 +9 -73 1903
17 -1112 111 -313 193010 -212 -2309
7 -411 -34 15 + 4630 - 52575606
20304080602515270
-32-130-11
8-116 30 10-1112 -99-911 -85 10
405
3 20
7 56 -1930
8 -27 28 3506
5 -54 52 406 20 -3309 -33 + 5903
17 -1112 311 -313 -193010 212 -2309
7 -811 -34 -3530+6 -45257 5 -606
20304080602515270
31-130-11
8 -6
6 30 10 -612 -49 -411 -35 10
405
320
7 06 -19 30-8 -27 2 +8 -2506
5 -54 02 406 15 3309 -33 5903
17 -1212 -211 -313 -19 3010 212 -3309
7
-811 -84
-3535+
6 -4525 -7 -560 6
20304080602515270
31-130-11
8 -6
630 10 -612 -49 -411 -55 10
408
320
7 06 -19 5
8 -27 258 -2509
5 -54 02 406 15 3309 -53 5906
17- 1112 -211 -313 -193010 0123012
7 -811 -84 -3560
6 -45 -27 -5605
20304080602515270
-6-2-40-3-2-3
Karena maka tabel sudah optimum sehingga:Fmin = 30(6) + 10(5) + 20(3) + 5(9) + 25(7) + 40(2) + 15(6) + 30(3) + 5(3) + 30(9) + 60(5) = 180 + 50 + 60 + 45 + 175 + 80 + 90 + 90 + 15 + 270 + 300 = 1355