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SOAL SOAL DAN JAWABAN (PHYSICS) FISIKA (PHYSICS)

Di Buat Oleh :- Abdul Rahman Halim - Alfi Rahmah Santika - Amalia Hajar D.E. - Anis Fitriyah - Annisah Maharinda - Muhammad Fiqhi Ibad - Muhammad Rizqi Alfian - Nanda Pradana - Muhammad Fatkhul Arifian - Nandini candrika - Zumrotul Ulya - Yuli Lestari - Razan Miqdad Afifi - Azizah Ardyanti Putri - Azizah Handayani - Elma Elviana - Dimas Fasihatin - Inge Nindiana Irawan - Muhimmatus Syarifah - Veronika Prastiwi - Tika Aprilia - Muhammad Ainul Yaqin - Clarin Puspa - Devi Ratna Safitri - Asri Lindung Sari - Muhammad Tulus Subakti

SMA NAHDLATUL ULAMA 1 GRESIK

TAPEL 2010 - 2011

ALAT OPTIK1. Rani who suffer from nearsightedness has a focal point 50 cm. If you want to read with normal spacing (25 cm), then what is the point nearby?Diketahui : s = 25 cm f = 50 cm Ditanyakan: s = ... ? Jawab :

1

=

1

+

1

1 1 1 = + 50 25 1 1 1 = 25 50 1 2 1 = 50 50 s = 50cm = 0,5m

2. In experiments on optics, John uses convex lens that focuses 25 cm. In front of the lens is placed objects whose height 3 cm at a distance of 30 cm. Specify: a. shadow distance to the lens, b. magnification image, c. high shadow?

Completionf = + 25 cm (cembung) S = 30 cm dan h = 3 cm a. Jarak bayangan ke lensa S memenuhi:

1

=

1

+

1

1 1 1 = + 25 30 1 1 1 65 1 = = = 25 30 150 150 Berarti S = 150 cm b. Perbesaran bayangan sebesar :M= = 150 = 5x(nyata) 30

c. Tinggi bayangan benda sebesar: M= h=M.h = 5 . 3 = 15cm

SUHU DAN KALORKD 4.1 The result of water temperature measurements using the thermometer scale Celsius is 40 C. Determinethe number that is shown if the water temperature was measured with a thermometer Kelvin scale!

Answer: Diket : C = 40 C 100 40 = 100 K = 273 40 = 313K When the ice is melting, the thermometer scale showed the 20 X X and while it is boiling, thethermometer scale showed the 140 X X. This situation was measured at 1 atmosphere air pressure. Find The relationship between scale C and scale X Thermometer scale of C, if the thermometer scale showed 80 X X!

=

273 100 273 100

Answer: Diket : Pembagian skala X = (140-20) skala = 120 skala C : X = 100 : 120 = 5 : 6 a. Hubungan skala C dan X. 20 = 5 6 b. 80 X = ... C (80 20) = 5 6 60 5 = = 50 6 Jadi, skala C menunjukkan angka 50C If the scale Fahrenheit thermometer showed a temperature of 50 F. Find the scale indicated by theCelsius and Kelvin!

Answer: Diket : F = 50F 32 = 180 100 = 100 = C = 10C

32 = 180 = 100 = 10 =

273 100

273

273

10 + 273 = K K = 283 K A rectangular aluminum plate with the long side - side 50 cm and temperature 30 C. If the coefficientlength of aluminum miaui 25. 10-6 C-1, determine the aluminum square area if the temperature is raised to 150 C!

Answer: 32 = 180 100 = = C = 10 C 32 = 180 = 10 = K 273 10 + 273 = K K = 283 K A bullet-shaped ball made of copper with a radius of 3 mm at a temperature of 20 C. If the lengthexpansion coefficient of copper 17. 10-6 C-1, determine the volume of bullets if heated to 170 C!

273 100

Answer: Diket ro

= 3mm; = 17 . 10-6 C-1 To = 20 C; T1 = 170 C Vt = Vo (1+T) dengan = 3 = (51 . 10-6 C-1) = (170 -20) C = 150 Co

=

3

= (3,140(3

)3 = 113,04 mm3

Sehingga didapatkan Vt = 113,04 mm3 {1 + (51 . 10-6 C-1-(150 C)} = 113,04 (1 + 0,00765)mm3 Vt = 113,04 (1,00765) = 113,90 mm3

A gas when the pressure is 6 atmospheres volume 2 liters. For fixed temperature, if pressure is reduced to4 atmosphere, calculate the volume occupied by gas! (1 atm = 1.013. 105 Pa)

Answer: Vl = 2 L, P1 = 6 atm, dan P2 = 4 atm P1 v1 = p2 v2 ( 6 atm)( 2 L) = ( 4 atm )V2 62 = =3 4 A 4 meter long iron rod with cross-sectional area 25 cm2. The difference in temperature between both Answer:

ends of the iron 80 C. Also known coefficient of thermal conductivity of iron 46 Jm-1 C-1. Determine the amount of heat that crept in the iron per unit of time!

l

= 4 m;

= (T2 T1) = 80 C A = 25 cm = 25 . 10-4m2 k = 46 Jm-1 s-1 C-12

=

H = (46 Jm-1s-1 C-1)(25 . 10-4 m2)

= 2,3

= 2,3

KD 4.2 Determine the amount of heat needed to heat the water as much as 2 kg of a temperature of 20 C until itreaches its boiling point of 100 C. known to heat water type kJkg 4.2 C-1!

Answer: m = 2 kg, c = 4,2 kJkg-1C-1 T = 100 C - 20 C = 80 C = . . = (2kg)(4,2 kJ kg-1 C-1)(80 C) = 672 kJ An object has a heat capacity of 2000 J C-1. Determine the amount of heat required to raise thebody temperature of 10 C

Answer: Diket :

C = 2.000 JC-1 T = 10 C Q = C = (2.000 JC-1)(10 C) = 20.000 joule = 20kJ

KD 4.3 In a cup of tea there are as many as 60 mL of water with a temperature of 80 C. Then, into the glasswas added to 40mL of water temperature of 5 C. If known heat tea water type with heat cold water species, determine the temperature of the mixture of water!

Answer: Diket : mteh = 60mL, Tteh = 80 C mair = 40mL, Tair = 5 C cteh = cair jika suhu akhir camouran adalah Tc, diperoleh = Qterima(air es) Qlepas (teh) mteh cteh ( Tteh Tc ) = mair cair ( Tc Tair ) 60 mL ( 80 C Tc ) = 40mL ( Tc - 5 C ) 4800 C (60Tc) = ( 40 Tc ) - 200 C 100 Tc = 5.000 C Tc = 50 C A metal type X is determined heat put into a kalorima = ether. X metal mass is 0.2 kg. Temperature atfirst - first 98 C. Known also Caloriemeter made of polystyrene material, which material can absorb almost no heat. In the calorimeter contained as much as 1 kg of water temperature 25 C. After X Included metal into the calorimeter, then stirred, thermal equilibrium is reached a temperature of 28 C. From these observations, determine the heat of the metal type X, if you heat water type Jkg 4200 C-1!

Answer: ml cl (Tl Tt) = maca ( Tt Ta ) (0,2 kg)cl (98 28) C = (1 kg)(4.200 Jkg-1 C-1)(28 25) C cl =. , -1

C-1 = 900 Jkg-1 C-1

Know the melting heat of water 3.36. 105Jkg-1 and m = 0.1 kg, Determine the amount of heat required tomelt 100 grams of ice!

Answer: Diket : L = 3,36 . 105 Jkg-1 dan m = 0,1 kg Q = m . L = (0,1 kg)(3,36 . 105 Jkg-1) = 3,36 . 104 J Known heat frozen water 3.36 Jkg -1. Determine the amount of water which freezes when the temperatureis 0 C absorbed energy of 1.68. 104 J of water.

Answer: Q=m.L m= =, ,

= 0,05

= 500

By using steam heat, determine the amount of heat required to evaporate 0.5 kg of water at a temperatureof 100 C so that it becomes steam at 100 C!

Answer: Q = m . L = (0,5 kg)(2,26 . 106Jkg-1) = 1,13 . 106 Joule Diketahui 400 gram es bersuhun 0 C diberikan kalor sebesar 3,36 kJ. Jika kalor lebur es 3,36 . 105Jkg-1, tentukanlah berapa persen es yang melebur !

Jawab : Q=m.L , m=

= 0,01

;

=

,

,

100% =

= 25%

Determine the amount of heat required to raise the temperature of 0.2 kg of ice from -10 C until all thewater temperature of 50 C 1 is known heat melting ice 3.36. Jkg 105-1, heat type of ice Jkg 2100 C-11, and heat water type Jkg 4200 C-1-1.

Answer: Diket :

mes To T1

= 0,2 kg; = -10 C; = 4200 C;

Les ces cair

= 3,36 . 105 Jkg-1 = 2.100 Jkg-1 C-1 = 4.200 Jkg-1 C-1

Q = Q1 + Q2 + Q3 Q1 = mes ces es =(0,2 kg)(2.100 Jkg-1 C-1)(0-(-10)) C = 4,2 kJ Q2 = mes Les = ( 0,2 kg)(3,36 . 105 Jkg-1) = 67,2 kJ Q3 = mair cair air = (0,2 kg )(4.200 Jkg-1 C-1)(50 0) C = 42 kJ Qtotal = Q1 + Q2 +Q3 = 113,4 kJ The length of a rod of iron at a temperature of 20 C is 10 meters. If the length expansion coefficient of iron 11. 10-6 C-1, determine the length of iron bar was added if the temperature is raised to 100 C! Answer: Diket : To = 20 C; T1besi = 100 C

lol l

= 10 m ;

= 11 . 10-6 C-1

= lo ( T1 To )=(11 . 10-6 C-1)(10 m )(100 20)C= 8,8 . 10-3meter = 8,8 milimeter

( ABDURRAHMAN HALIM )

KD 4.1 1. At 30 C a metal plate breadth of 10 m2. If the temperature raised to 90 C and length expansion coefficient of iron 0.000012 / C, determine the area of iron plate! Diketahui : A1 = 10 m2 T1 = 30 C T2 = 90 C T = T2 T1 = 90 30 = 60 C = 0,000012/ C = 2 0,000012/ C = 0,000024 Ditanyakan : A2 = ... ? Jawab : A2 =A1(1 + x T) = 10(1 + 0,000024 60) = 10(1 + 0,00144) = 10 1,00144 = 10,0144 m2 Jadi, luas pelat besi setelah dipanaskan adalah 10,0144 m2. 2. How much heat is required to convert 2 grams of ice at 0 C to water vapor at a temperature of 100 C? (Liquid = 4200 J / kg C, L = 336J/Kg, and U = 2260 J / Kg) Diketahui : m = 2 g = 2 10-3 kg T = 100 0 = 100 C U= 2.260 J/Kg L = 336J/Kg Cair = 4.200 J/kg C Ditanya : Qtotal = ? Dijawab : Q1 = m x L = 2 x 336 J/Kg = 672 J

Q2 = m x Cair x T = 2.10-3 x 4200 x 100 = 840 J Q3 = m x U = 2 x 2260 = 4420 J Qtotal = Q1 + Q2 + Q3 = 672 + 840 + 4420 = 5932 J

3. A piece of iron which has a mass of 3 kg, is heated from temperature 20 C to 120 C. If heat is absorbed iron by 135 kJ. Determine the heat capacity of iron and heat type of iron? Diketahui : m = 3 kg T = 120 20 = 100 C Q = 135 kJ Ditanya : C = ..? c = ..? Dijawab : a. C =.

= = 1350 J/0C4. Ethyl alcohol move at 78.50 C and frozen at-1170C padatekanan 1 atm. Express this temperature in both a. Kelvin b. Fahrenheit Dijawab: K = C + 273 = 78,5 + 273 = 351,5 K K = -117+ 273 = 156 K F = 9/5C + 32 = 9/5(78,5) + 32 = 1730F F = 9/5(-117) + 32 = -1790F

5. A container made of aluminiumyang filled with 300mL of glycerin at a temperature of 200C. What is the amount of glycerin that tumpaah if the container is heated to suhu1100C? Length expansion coefficient of aluminum 2.55 x 10-5/0C and volume expansion coefficient of 5.3 x 10-4/0C glycerin.