slopes and equations of lines
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Chap 8. Slopes and Equations of Lines. Chin-Sung Lin. Distance Formula Midpoint Formula Slope Formula Parallel Lines Perpendicular Lines. Basic Geometry Formulas. Mr. Chin-Sung Lin. Distance Formula. Mr. Chin-Sung Lin. A (x 1 , y 1 ). B (x 2 , y 2 ). - PowerPoint PPT PresentationTRANSCRIPT
Slopes and Equations of Lines
Chin-Sung Lin
Chap 8
Basic Geometry Formulas
Mr. Chin-Sung Lin
Distance Formula
Midpoint Formula
Slope Formula
Parallel Lines
Perpendicular Lines
Distance Formula
Mr. Chin-Sung Lin
Distance Formula
Distance between two points A (x1, y1) and B (x2, y2) is given by distance formula
d(A, B) =√(x2 − x1 )2 + (y2 − y1 )2
A (x1, y1) B (x2, y2)
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Distance Formula - Example
Calculate the distance between A (4, 5) and B (1, 1)
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Distance Formula - Example
Calculate the length of AB if the coordinates of A and B are (4, 15) and (-1, 3) respectively
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Distance Formula - Example
Calculate the distance between A (9, 5) and B (1, 5)
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Midpoint Formula
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Midpoint Formula
If the coordinates of A and B are ( x1, y1) and ( x2, y2) respectively, then the midpoint, M, of AB is given by the midpoint formula
x1 + x2, y1+ y2
2 2M = ( )
A (x1, y1) B (x2, y2)M (x, y)
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Midpoint Formula - Example
Calculate the midpoint of AB if the coordinates of A and B are (2, 7) and (-6, 5) respectively
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Midpoint Formula - Example
M(1, -2) is the midpoint of AB and the coordinates of A are (-3, 2). Find the coordinates of B
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Slope Formula
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Slope Formula
If the coordinates of A and B are (x1, y1) and (x2, y2) respectively, then the slope, m, of AB is given by the slope formula
y2 - y1
x2 - x1
m =
A (x1, y1
)
B (x2, y2
)
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Slope Formula - Example
Calculate the slope of AB, where A (4, 5) and B (2, 1)
Mr. Chin-Sung Lin
Slope Formula - Example
Calculate the slope of AB, where A (4, 5) and B (2, 1)
5 - 1
4 - 2
= 2
m =
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Slope of Lines in the Coordinate Planes
Positive slope
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Slope of Lines in the Coordinate Planes
Negative slope
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Slope of Lines in the Coordinate Planes
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Zero slope
Slope of Lines in the Coordinate Planes
Undefined slope
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Slope and Parallel Lines
The straight lines with slopes (m) and (n) are parallel to each other if and only if m = n
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m n
Slope and Parallel Lines - Example
If AB is parallel to CD where A (2, 3) and B (4, 9), calculate the slope of CD
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Slope and Parallel Lines - Example
If AB is parallel to CD where A (2, 3) and B (4, 9), calculate the slope of CD
9 - 3
4 - 2
= 3
m = n =
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Slope and Perpendicular Lines
The straight lines with slopes (m) and (n) are mutually perpendicular if and only if m · n = -1
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mn
Slope and Perpendicular Lines - Example
If AB is perpendicular to CD where A (1, 2) and B (3, 6), calculate the slope of CD
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Slope and Perpendicular Lines - Example
If AB is perpendicular to CD where A (1, 2) and B (3, 6), calculate the slope of CD
6 - 2
3 - 1
= 2
since m · n = -1, 2 · n = -1, so, n = -1/2
m =
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Group Work
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Parallel and Perpendicular Lines
There are four points A (2, 6), B(6, 4), C(4, 0) and D(0, 2) on the coordinate plane.
Identify the pairs of parallel and perpendicular lines
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Equations of Lines
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Slope Intercept Form
Linear equation can be written in slope-intercept form:
y = mx + bwhere m is the slope
b is the y-intercept
slope: m
b
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Write Slope Intercept FormGiven: If the slope of a line is 3 and it passes
through(0, 2), write the equation of the line in slope-intercept form
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Write Slope Intercept FormGiven: If the slope of a line is 3 and it passes
through(0, 2), write the equation of the line in slope-intercept form
m = 3, b = 2y = 3x + 2
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Write Slope Intercept Form
Given: y-intercept b and a point (x1, y1)
(0, b)
(x1, y1)
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Write Slope Intercept Form
Given: y-intercept b and a point (x1, y1)
Step 1: Find the slope m by choosing two points (0, b) and (x1, y1) on the graph of the
lineStep 2: Find the y-intercept bStep 3: Write the equation
y = mx + b
(0, b)
(x1, y1)
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Write Slope Intercept FormGiven: Two points (0, 4) and (2, 0)
(0, 4)
(2, 0)
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Write Slope Intercept FormGiven: Two points (0, 4) and (2, 0)
Step 1: Find the slope by choosing two points on the graph of the line: m = (0-4)/(2-0)
= -2Step 2: Find the y-intercept: b = 4Step 3: Write the equation:
y = -2x + 4
(0, 4)
(2, 0)
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Write Slope Intercept Form - Example
A line passing through (2, 3) and the y-intercept is -5. Write the equation
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Point-Slope Form
Linear equation can be written in point-slope form:
y – y1 = m(x – x1)where m is the slope
(x1, y1) is a point on the line
slope: m
(x1, y1)
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Write Point-Slope FormGiven: If the slope of a line is 3 and it passes
through(5, 2), write the equation of the line in slope-intercept form
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Write Point-Slope FormGiven: If the slope of a line is 3 and it passes
through(5, 2), write the equation of the line in slope-intercept form
m = 3, (x1, y1) = (5, 2)
y - 2 = 3(x – 5)
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Write Point-Slope Form
Given: Two points (x1, y1) and (x2, y2)
(x1, y1)
(x2, y2)
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Write Point-Slope Form
Given: Two points (x1, y1) and (x2, y2)
Step 1: Find the slope m by plugging two points (x1, y1) and (x2, y2) into the slop formula m = (y2 – y1)/(x2 – x1)
Step 2: Write the equation using slope m and any point y – y1 = m(x – x1)
(x1, y1)
(x2, y2)
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Write Point-Slope Form Example
Given: Two points (3, 1) and (1, 4)
(1, 4)
(3, 1)
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Write Point-Slope Form Example
Given: Two points (3, 1) and (1, 4)Step 1: Find the slope m by plugging two
points (3, 1) and (1, 4) into the slop formula m = (4 – 1)/(1 – 3)
= -3/2Step 2: Write the equation
y – 1 = (-3/2)(x – 3)
(1, 4)
(3, 1)
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Write Point-Slope Form Example
Given: Two points (-2, 7) and (2, 3)
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Equations of Parallel & Perpendicular Lines
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Equation of a Parallel Line
Write an equation of the line passing through the point (-1, 1) that is parallel to the line y = 2x – 3
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Equation of a Parallel Line
Write an equation of the line passing through the point (-1, 1) that is parallel to the line y = 2x - 3
Step 1: Find the slope m from the given equation: since two lines are parallel, the slopes are
the same, so: m = 2
Step 2: Find the y-intercept b by using the m = 2 and the given point (-1, 1): 1 = 2(-1) + b, so, b
= 3Step 3: Write the equation: y = 2x + 3
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Equation of a Parallel Line - Example
Write an equation of the line passing through the point (2, 3) that is parallel to the line y = x – 5
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Equation of a Parallel LineWrite an equation of the line passing through the
point (2, 0) that is parallel to the line y = x - 2
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Equation of a Perpendicular Line
Write an equation of the line passing through the point (2, 3) that is perpendicular to the line y = -2x + 2
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Equation of a Perpendicular Line
Write an equation of the line passing through the point (2, 3) that is perpendicular to the line y = -2x + 2
Step 1: Find the slope m from the given equation: since two lines are perpendicular, the
product of the slopes is equal to -1, so: m = 1/2
Step 2: Find the y-intercept b by using the m = 2 and the given point (-1, 1): 3 = (1/2)(2) + b, so,
b = 2Step 3: Write the equation: y = (1/2)x + 2
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Equation of a Perpendicular LineWrite an equation of the line passing through the
point (1, 2) that is perpendicular to the line y = x + 3
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Equation of a Perpendicular LineWrite an equation of the line passing through the
point (4, 1) that is perpendicular to the line y = -x + 2
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Group Work
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Equation of a Perpendicular LineBased on the information in the graph, write the
equations of line P and line Q in both slope-intercept form and point-slope form
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(4, 3)
y = 2x -5
-2
K
P
Q
Coordinate Proof
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Coordinate Proof
Two types of proofs in coordinate geometry:• Special cases
Given ordered pairs of numbers, and prove something about a specific segment or polygon
• General TheoremsWhen the given information is a figure that represents a particular type of polygon, we must state the coordinates of its vertices in general terms using variables
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Coordinate Proof
Two skills of proofs in coordinate geometry:
• Line segments bisect each otherthe midpoints of each segment are the same point
• Two lines are perpendicular to each otherthe slope of one line is the negative reciprocal of the slope of the other
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Coordinate Proof – Special CasesIf the coordinates of four points are A(-3, 5), B(5,
1), C(-2, -3), and D(4, 9), prove that AB and CD are perpendicular bisector to each other
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Coordinate Proof – Special CasesThe vertices of rhombus ABCD are A(2, -3), B(5, 1),
C(10, 1) and D(7, -3). (a) Prove that the diagonals bisect each other. (b) Prove that the diagonals are perpendicular to each other.
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Coordinate Proof – Special CasesIf the coordinates of three points are A(-1, 4), B(4,
7), and C(1, 2), prove that ABC is an isosceles triangle
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Aim: Coordinate Proof DoNow:
If the coordinates of three points are A(-1, 4), B(4, 7), and C(1, 2), prove that ABC is an isosceles triangle
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Coordinate Proof – Special CasesIf the coordinates of three points are A(4, 3), B(6, 7),
and C(-4, 7), prove that ΔABC is a right triangle. Which angle is the right angle?
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Coordinate Proof – General Theorems
Vertices definition in coordinate geometry:
• Any triangle— (a, 0), (0, b), (c, 0)
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(0, b)
(a, 0) (c, 0)
(0, b)
(a, 0) (c, 0)
Coordinate Proof – General Theorems
Vertices definition in coordinate geometry:
• Right triangle— (a, 0), (0, b), (0, 0)
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(0, b)
(0, 0) (a, 0)
Coordinate Proof – General Theorems
Vertices definition in coordinate geometry:
• Isosceles triangle— (-a, 0), (0, b), (a, 0)
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(0, b)
(-a, 0) (a, 0)
Coordinate Proof – General Theorems
Vertices definition in coordinate geometry:
• Midpoint of segments— (2a, 0), (0, 2b), (2c, 0)
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(0, 2b)
(2a, 0) (2c, 0)
Coordinate Proof – General Theorems
Prove that the midpoint of the hypotenuse of a right triangle is equidistance from the vertices
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Coordinate Proof – General Theorems
Prove that the midpoint of the hypotenuse of a right triangle is equidistance from the vertices
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B (0, 2b)
A (2a, 0)
C(0, 0)
M
Given: Right triangle ABC whose vertices are A(2a, 0), B(0, 2b), and C(0,0). Let M be the midpoint of the hypotenuse AB
Prove: AM = BM = CM
Coordinate Proof – General Theorems
Prove that the midpoint of the hypotenuse of a right triangle is equidistance from the vertices
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B (0, 2b)
A (2a, 0)C(0, 0)
M
Concurrence of the Altitudes of a Triangle
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Altitude Concurrence - Orthocenter
Orthocenter: The altitudes of a triangle intersect in one point
Acute Triangle
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B(0, b)
A(a, 0) C(c, 0)
Altitude Concurrence - Orthocenter
Theorem: The altitudes of a triangle are concurrent (intersecting in one point— orthocenter)
Acute Triangle
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B(0, b)
A(a, 0) C(c, 0)
Altitude Concurrence - Orthocenter
Orthocenter: The altitudes of a triangle intersect in one point
Right Triangle
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B(0, b)
A(a, 0) C(c, 0)
Altitude Concurrence - Orthocenter
Theorem: The altitudes of a triangle are concurrent (intersecting in one point— orthocenter)
Right Triangle
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B(0, b)
A(a, 0) C(c, 0)
Altitude Concurrence - Orthocenter
Orthocenter: The altitudes of a triangle intersect in one point
Obtuse Triangle
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B(0, b)
A(a, 0) C(c, 0)
Altitude Concurrence - Orthocenter
Theorem: The altitudes of a triangle are concurrent (intersecting in one point— orthocenter)
Obtuse Triangle
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B(0, b)
A(a, 0) C(c, 0)
Orthocenter
The coordinates of the vertices of ΔABC are A(0, 0), B(-2, 6), and C(4, 0). Find the coordinates of the orthocenter of the triangle
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Orthocenter
The coordinates of the vertices of ΔABC are A(0, 0), B(-2, 6), and C(4, 0). Find the coordinates of the orthocenter of the triangle
Answer: (-2, -2)
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Orthocenter
The coordinates of the vertices of ΔABC are A(0, 0), B(3, 4), and C(2, 1). Find the coordinates of the orthocenter of the triangle
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Orthocenter
The coordinates of the vertices of ΔABC are A(0, 0), B(3, 4), and C(2, 1). Find the coordinates of the orthocenter of the triangle
Answer: (6, -2)
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The End
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