sensitivity analysis of the galaxy linear programming model
DESCRIPTION
Sensitivity Analysis of The Galaxy Linear Programming Model. Max 8X 1 + 5X 2 (Weekly profit) subject to 2X 1 + 1X 2 £ 1000 (Plastic) 3X 1 + 4X 2 £ 2400 (Production Time) X 1 + X 2 £ 700 (Total production) X 1 - X 2 £ 350 (Mix) - PowerPoint PPT PresentationTRANSCRIPT
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Max 8X1 + 5X2 (Weekly profit)subject to2X1 + 1X2 1000 (Plastic)
3X1 + 4X2 2400 (Production Time)
X1 + X2 700 (Total production)
X1 - X2 350 (Mix)
Xj> = 0, j = 1,2 (Nonnegativity)
Sensitivity Analysis of Sensitivity Analysis of The Galaxy Linear Programming ModelThe Galaxy Linear Programming Model
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– If a linear programming problem has an optimal solution, an extreme point is optimal.
Extreme points and optimal solutionsExtreme points and optimal solutions
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The Role of Sensitivity Analysis The Role of Sensitivity Analysis of the Optimal Solutionof the Optimal Solution
• Is the optimal solution sensitive to changes in input parameters?
• Possible reasons for asking this question:– Parameter values used were only best estimates.– Dynamic environment may cause changes.– “What-if” analysis may provide economical and
operational information.
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• Range of Optimality– The optimal solution will remain unchanged as long as
• An objective function coefficient lies within its range of
optimality • There are no changes in any other input parameters.
– The value of the objective function will change if the
coefficient multiplies a variable whose value is nonzero.
Sensitivity Analysis of Sensitivity Analysis of Objective Function Coefficients.Objective Function Coefficients.
5
500
1000
500 800
X2
X1Max 8X
1 + 5X2
Max 4X1 + 5X
2
Max 3.75X1 + 5X
2
Max 2X1 + 5X
2
Sensitivity Analysis of Sensitivity Analysis of Objective Function Coefficients.Objective Function Coefficients.
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500
1000
400 600 800
X2
X1
Max8X1 + 5X
2
Max 3.75X1 + 5X
2
Max 10 X
1 + 5X2
Range of optimality: [3.75, 10]
Sensitivity Analysis of Sensitivity Analysis of Objective Function Coefficients.Objective Function Coefficients.
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• Reduced costAssuming there are no other changes to the input parameters, the reduced cost for a variable Xj that has a value of “0” at the optimal solution is:
– The negative of the objective coefficient increase of the variable Xj (-Cj) necessary for the variable to be positive in the optimal solution
– Alternatively, it is the change in the objective value per unit increase of Xj.
• Complementary slackness At the optimal solution, either the value of a variable is zero, or its reduced cost is 0.
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• In sensitivity analysis of right-hand sides of constraints we are interested in the following questions:– Keeping all other factors the same, how much would the
optimal value of the objective function (for example, the profit) change if the right-hand side of a constraint changed by one unit?
– For how many additional or fewer units will this per unit change be valid?
Sensitivity Analysis of Sensitivity Analysis of Right-Hand Side ValuesRight-Hand Side Values
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• Any change to the right hand side of a binding constraint will change the optimal solution.
• Any change to the right-hand side of a non-binding constraint that is less than its slack or surplus, will cause no change in the optimal solution.
Sensitivity Analysis of Sensitivity Analysis of Right-Hand Side ValuesRight-Hand Side Values
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Shadow PricesShadow Prices
• Assuming there are no other changes to the input parameters, the change to the objective function value per unit increase to a right hand side of a constraint is called the “Shadow Price”
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1000
500
X2
X1
500
2X1 + 1x
2 <=1000
When more plastic becomes available (the plastic constraint is relaxed), the right hand side of the plastic constraint increases.
Production timeconstraint
Maximum profit = $4360
2X1 + 1x
2 <=1001 Maximum profit = $4363.4
Shadow price = 4363.40 – 4360.00 = 3.40
Shadow Price – graphical demonstrationShadow Price – graphical demonstrationThe Plastic constraint
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Range of FeasibilityRange of Feasibility
• Assuming there are no other changes to the input parameters, the range of feasibility is– The range of values for a right hand side of a constraint, in
which the shadow prices for the constraints remain unchanged.
– In the range of feasibility the objective function value changes as follows:Change in objective value = [Shadow price][Change in the right hand side value]
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Range of FeasibilityRange of Feasibility
1000
500
X2
X1
500
2X1 + 1x
2 <=1000
Increasing the amount of plastic is only effective until a new constraint becomes active.
The Plastic constraint
This is an infeasible solutionProduction timeconstraint
Production mix constraintX1 + X2 700
A new activeconstraint
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Range of FeasibilityRange of Feasibility
1000
500
X2
X1
500
The Plastic constraint
Production timeconstraint
Note how the profit increases as the amount of plastic increases.
2X1 + 1x
2 1000
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Range of FeasibilityRange of Feasibility
1000
500
X2
X1
5002X1 + 1X2 1100
Less plastic becomes available (the plastic constraint is more restrictive).
The profit decreases
A new activeconstraint
Infeasiblesolution
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– Sunk costs: The shadow price is the value of an extra unit of the resource, since the cost of the resource is not included in the calculation of the objective function coefficient.
– Included costs: The shadow price is the premium value above the existing unit value for the resource, since the cost of the resource is included in the calculation of the objective function coefficient.
The correct interpretation of shadow prices The correct interpretation of shadow prices
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The Process for Other Optimality Changes The Process for Other Optimality Changes
• Deletion of a constraint: The process: Determine if the constraint is a binding (i.e. active, important) constraint by finding whether its slack/surplus value is
zero. If binding, deletion is very likely to change the current optimal solution. Delete the constraint and re-solve the problem. Otherwise, (if not a binding
constraint) deletion will not affect the optimal solution.
• Addition of a variable: The coefficient of the new variable in the objective function, and the shadow prices of the resources provide information about marginal
worth of resources and knowing the resource needs corresponding to the new variable, the decision can be made, e.g., if the new product is profitable or not.
The process: Compute what will be your loss if you produce the new product using the shadow price values (i.e., what goes into producing the new product).
Then compare it with its net profit. If the profit is less than or equal to the amount of the loss then DO NOT produce the new product. Otherwise it is profitable
to produce the new product. To find out the production level of the new product resolves the new problem.
• Addition of a constraint: The process: Insert the current optimal solution into the newly added constraint. If the constraint is not violated, the new constraint
does NOT affect the optimal solution. Otherwise, the new problem must be resolved to obtain the new optimal solution.
• Deletion of a variable: The process: If for the current optimal solution, the value of the deleted variable is zero, then the current optimal solution still is optimal
without including that variable. Otherwise, delete the variable from the objective function and the constraints, and then resolve the new problem.
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• Infeasibility: Occurs when a model has no feasible point.
• Unboundness: Occurs when the objective can become
infinitely large (max), or infinitely small (min).
• Alternate solution: Occurs when more than one point
optimizes the objective function
One Must Not Do Any Sensitivity One Must Not Do Any Sensitivity Analysis one Models Without Analysis one Models Without
Unique Optimal SolutionsUnique Optimal Solutions
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1
No point, simultaneously,
lies both above line and
below lines and
.
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2 32
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Infeasible ModelInfeasible Model
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Unbounded solutionUnbounded solution
The feasible
region
Maximize
the Objective Function
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• This Solver does alert the user to the existence of alternate optimal solutions.
WinQBS Solver – An Alternate Optimal WinQBS Solver – An Alternate Optimal SolutionSolution
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Cost Minimization Diet Problem Cost Minimization Diet Problem • Mix two sea ration products: Texfoods, Calration.• Minimize the total cost of the mix. • Meet the minimum requirements of Vitamin A, Vitamin D, and Iron.
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• Decision variables– X1 (X2) -- The number of two-ounce portions of
Texfoods (Calration) product used in a serving.
• The ModelMinimize 0.60X1 + 0.50X2Subject to
20X1 + 50X2 100 Vitamin A 25X1 + 25X2 100 Vitamin D 50X1 + 10X2 100 Iron X1, X2 0
Cost per 2 oz.
% Vitamin Aprovided per 2 oz.
% required
Cost Minimization Diet Problem Cost Minimization Diet Problem
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10
2 44 5
Feasible RegionFeasible Region
Vitamin “D” constraint
Vitamin “A” constraint
The Iron constraint
The Diet Problem - Graphical solutionThe Diet Problem - Graphical solution
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• Summary of the optimal solution
– Texfood product = 1.5 portions (= 3 ounces)Calration product = 2.5 portions (= 5 ounces)
– Cost =$ 2.15 per serving. – The minimum requirement for Vitamin D and iron are met with
no surplus. – The mixture provides 155% of the requirement for Vitamin A.
Cost Minimization Diet Problem Cost Minimization Diet Problem
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• Linear programming software packages solve large linear models.
• Most of the software packages use the algebraic technique called the Simplex algorithm.
• The input to any package includes:– The objective function criterion (Max or Min).– The type of each constraint: .– The actual coefficients for the problem.
(WinQSB) Professional Computer Solution of (WinQSB) Professional Computer Solution of Linear Programs With Any Number of Decision Linear Programs With Any Number of Decision
VariablesVariables
, ,