section 6.5 notes

43
Section 6.5 Notes

Upload: cicely

Post on 21-Mar-2016

41 views

Category:

Documents


1 download

DESCRIPTION

Section 6.5 Notes. 1 st Day. Today we will learn how to change from rectangular (standard) complex form to trigonometric (polar) complex form and vice versus. A complex number z = a + bi can be represented as a point ( a , b ) in a coordinate plane called the complex plane . - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Section  6.5 Notes

Section 6.5 Notes

Page 2: Section  6.5 Notes

1st Day

Today we will learn how to change from rectangular (standard) complex form to trigonometric (polar) complex form and vice versus.

Page 3: Section  6.5 Notes

A complex numberz = a + bi

can be represented as a point (a, b) in a coordinate plane called the complex plane.The horizontal axis is called the real axis and the vertical axis is called the imaginary axis.

Page 4: Section  6.5 Notes

real axis

imaginary axis

Page 5: Section  6.5 Notes

Example 1

Graph.a. 2 + 3ib. -1 – 2i

Page 6: Section  6.5 Notes

I

R

(2, 3)2 + 3i

(-1, -2)

-1 - 2i

Page 7: Section  6.5 Notes

In Algebra II you learned how to add, subtract, multiply, and divide complex numbers.In Pre-Calculus you will learn how to work with powers and roots of complex numbers.To do this you must write the complex numbers in trigonometric form (or polar form).

Page 8: Section  6.5 Notes

On the next slide you will see how we change a rectangular (standard) complex number into a trigonometric (polar) complex number.

Page 9: Section  6.5 Notes

θ

(a, b)

ab

r

I

R

cos ar

a cosr

sin br

b sinr

2 2a b

a + bi

r

Page 10: Section  6.5 Notes

The trigonometric form of the complex number z = a + bi is

z = r(cos θ + i sin θ)where a = r cos θ, b = r sin θ,

In most cases 0 ≤ θ < 2π or 0° ≤ θ < 360°.

2 2 , and tan . br a ba

Page 11: Section  6.5 Notes

There is a shortcut for writing a trigonometric complex number. The shortcut is

z = rcis θ = r(cos θ + i sin θ)

Page 12: Section  6.5 Notes

Example 2

Write the complex number z = 6 – 6i in trigonometric (polar) form in radians.1. The point is in what quadrant?

4th quadrant

Page 13: Section  6.5 Notes

226 6 r 6 2

6tan 16

2. Find r.

3. Find θ.

74

Remember θ is in the 4th quad.

7 76 2 cos sin4 4

z i 76 2cis

4

Page 14: Section  6.5 Notes

Example 3Represent the complex number graphically and then find the rectangular (standard) form of the number. No rounding.

z = 6(cos 135° + isin 135°)

Page 15: Section  6.5 Notes

135°

6

Page 16: Section  6.5 Notes

Find a and b.

6cos135 a 262

6sin135 b 262

3 2 3 2 z i

3 2

3 2

Page 17: Section  6.5 Notes

Now we will learn how to multiply and divide complex numbers in trigonometric (polar) form.

Page 18: Section  6.5 Notes

Product of Complex Numbers

1 1 1 1 2 2 2 2Let cos sin and cos sin

be complex numbers.

z r i z r i

1 2 1 2 1 2 1 2

1 2 1 2

cos sin where

0 2 or 0 360

z z r r i

Page 19: Section  6.5 Notes

Example 4

Find the product z1z2 of the complex numbers. Write your answer in standard form.

1 26 cos sin and 4 cos sin3 3 6 6

z i z i

Page 20: Section  6.5 Notes

1 2 z z 6 4 cos sin3 6 3 6

i

24 cos sin2 2

i

24 0 1 i

24 i

Page 21: Section  6.5 Notes

Quotient of Complex Numbers

1 1 1 1 2 2 2 2Let cos sin and cos sin

be complex numbers.

z r i z r i

1 11 2 1 2

2 2

1 2 1 2

cos sin

where 0 2 or 0 360

z r iz r

Page 22: Section  6.5 Notes

Example 5

1

2

Find the quotient of the complex numbers.

Write your answer in standard form.

zz

1 26 cos40 sin 40 and 2 cos10 sin10 z i z i

Page 23: Section  6.5 Notes

1

2

6 cos40 sin 402 cos10 sin10

iz

z i

6 cos 40 10 sin 40 102

i

3 cos 30 sin 30 i

3 132 2

i

3 3 32 2

i

END OF 1ST DAY

Page 24: Section  6.5 Notes

2nd DayToday we will learn to:1. Raise complex numbers to a power.2. Find the roots of complex numbers.

Page 25: Section  6.5 Notes

Multiply:(4 + 2i)10

Page 26: Section  6.5 Notes

DeMoivre’s Theorem

If z = r(cos θ + isin θ) is a complex number and n is a positive integer, then

cos sin nnz r i

cos sin n nz r n i n

Page 27: Section  6.5 Notes

Example 6

12Use DeMoivre's Theorem to find 1 3 .

Write your answer in standard form.

i

In what quadrant is this complex number?2nd Quadrant

Page 28: Section  6.5 Notes

1. Change to polar form.

2. Find θ.

221 3 r 2

3tan 31

23

Page 29: Section  6.5 Notes

12

12 2 21 3 2 cos sin3 3

i i

12 12 2 12 22 cos sin

3 3

i

4096 cos8 sin8 i

4096 1 0 i

4096

Page 30: Section  6.5 Notes

The nth Root of a Complex Number

The complex number u = a + bi is an nth root of the complex number z if

z = un = (a + bi)n

Page 31: Section  6.5 Notes

Finding the nth Root of a Complex Number

Page 32: Section  6.5 Notes

For a positive integer n, the complex number z = r(cos θ + i sin θ)

has exactly n distinct nth roots given by

2 2cos sin

where 0,1,2,..., 1

n k kr in n

k nor

360 360cos sin

where 0,1,2,..., 1

n k kr in n

k n

Page 33: Section  6.5 Notes

Example 7

Find all the fourth roots of 1.This means: x4 = 1.1. Change 1 into a polar complex number.

1 = cos(0π) + isin(0π)r = 1, n = 4 and k = 0, 1, 2, 3

Page 34: Section  6.5 Notes

k = 0

0 2 0 0 2 01 cos sin

4 4

x i

1

1 cos0 sin 0 i

1 1 0 i

Page 35: Section  6.5 Notes

k = 1 0 2 1 0 2 1

1 cos sin4 4

x i

i

1 cos sin2 2

i

1 0 i

Page 36: Section  6.5 Notes

k = 2

0 2 2 0 2 21 cos sin

4 4

x i

1

1 cos sin i

1 1 0 i

Page 37: Section  6.5 Notes

k = 3

0 6 0 61 cos sin4 4

x i

i

3 31 cos sin2 2

i

1 0 i

Page 38: Section  6.5 Notes

Notice that the roots in example 2 all have a magnitude of 1 and are equally spaced around the unit circle. Also notice that the complex roots occur in conjugate pairs.The n distinct nth roots of 1 are called the nth roots of unity.

Page 39: Section  6.5 Notes

Example 8

Find the three cube roots of z = -6 + 6i to the nearest thousandth.This means x3 = -6 + 6i.

Page 40: Section  6.5 Notes

1. Change to polar complex form in degrees.

2. Now find the three cube roots.

72cis 135 z

Page 41: Section  6.5 Notes

k = 0

6 135 072cis3

x

6 72cis 45

1.442 1.442 i

Page 42: Section  6.5 Notes

k = 1

6 135 36072cis3

x

6 72cis 165

1.970 0.528 i

Page 43: Section  6.5 Notes

k = 2

6 135 72072cis3

x

6 72cis 285

0.528 1.970 i