section 2.2 1. by imagining tangents at he indicated points state whether the slope is positive,...

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Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

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Page 1: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

Section 2.2

1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point.

P 1P 2

P 3

Page 2: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

2. Use the red tangent lines shown to find the slopes of the curve at the points of tangency.

..

Page 3: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

3. Find the average rate of change of f (x) = x 2 + x between the following pairs of x-values.

a. x=1 and x=3b. x=1 and x=2c. x=1 and x=1.5d. x=1 and x=1.1e. x=1 and x= 1.01f. What number do your answers seem to be approaching

Page 4: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

3. Find the average rate of change of f (x) = x 2 + x between the following pairs of x-values. a. x=1 and x=3 Note h = 2b. x=1 and x=2 Note h = 1c. x=1 and x=1.5 Note h = 0.5d. x=1 and x=1.1 Note h = 0.1e. x=1 and x= 1.01 Note h = 0.01f. What number do your answers seem to be approaching

You may do this problem using the 4-step procedure.

Step 1: f (x + h) = (x + h) 2 + ( (x + h) = x 2 + 2xh + h 2 + x + h

Step 2: f (x) = x 2 + x

Step 3: f (x + h) – f (x) = 2xh + h 2 + h

1hx2h

hhxh2

h

)x(f)hx(f.4Step

2

Note the beginning x vale is 1 for all parts and only the h changes. Plug in those values to step 4.

2x + h + 1 = 2 + h + 1 = 3 + h = ?? part a yields 5, b yields 4, c yields 3.5, d yields 3.1 and e yields 3.01

Page 5: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

4. Find the average rate of change of f(x) = 5x +1 between the following pairs of x-values. a. x=3 and x=5b. x=3 and x=4 c. x=3 and x=3.5d. x=3 and x=3.1e. x=3 and x=3.01f. What number do your answers seem to be approaching?

Page 6: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

You may do this problem using the 4-step procedure.4. Find the average rate of change of f(x) = 5x +1 between the following pairs of x-values. a. x=3 and x=5 Note h = 2b. x=3 and x=4 Note h = 1c. x=3 and x=3.5 Note h = 0.5d. x=3 and x=3.1 Note h = 0.1e. x=3 and x=3.01 Note h = 0.01f. What number do your answers seem to be approaching?

Step 1: f (x + h) = 5(x + h) + 1 = 5x + 5h + 1

Step 2: f (x) = 5x + 1

Step 3: f (x + h) – f (x) = 5h

f (x h) f (x) 5hStep 4. 5

h h

Note that by using this method you do not need to do the problem several time (parts a thru g) to get the value of 5.

Page 7: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

5. Find the instantaneous rate of change of f (x) = x 2 + x at x = 1. Use the five step procedure.

h 0 h 0

f (x h) f (x)Step 5. lim lim 2x h 1 2x 1

h

Step 1: f (x + h) = (x + h) 2 + (x + h) = x 2 + 2xh + h 2 + x + h

Step 2: f (x) = x 2 + x

Step 3: f (x + h) – f (x) = 2xh + h 2 + h

1hx2h

hhxh2

h

)x(f)hx(f.4Step

2

f ’ (1) = 2 (1) + 1 = 3

Page 8: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

6. Find the slope of the tangent of 2x 2 + x – 2 at x = 2

Graph this on your calculator and use “draw” “tangent” to get the answer. Remember the slope of the tangent is the number in front of the x in the tangent equation. In this case the slope is 9.

Page 9: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

7. Use the definition of derivative (5-step procedure) to find f ‘ (x) of f (x) = 2x 2 – 3x + 5

Step 1: f (x + h) = 2(x + h) 2 - 3(x + h) + 5 =2 x 2 + 4xh + 2h 2 - 3x – 3h + 5Step 2: f (x) = 2x 2 - 3x + 5

Step 3: f (x + h) – f (x) = 4xh + 2h 2 – 3h

2f (x h) f (x) 4xh 2h 3xhStep 4. 4x 2h 3

h h

h 0 h 0

f (x h) f (x)Step 5. lim lim 4x 2h 3 4x 3

h

Page 10: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

Step 1: f (x + h) = 9(x + h) – 2 = 9x + 9h - 2

Step 2: f (x) = 9x - 2

Step 3: f (x + h) – f (x) = 9h

f (x h) f (x) 9hStep 4. 9

h h

h 0 h 0

f (x h) f (x)Step 5. lim lim 9 9

h

8. Use the definition of derivative (5-step procedure) to find f ‘ (x) of f (x) = 9x - 2

Page 11: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

Step 1: f (x + h) = 4

Step 2: f (x) = 4

Step 3: f (x + h) – f (x) = 0

f (x h) f (x) 0Step 4. 0

h h

h 0 h 0

f (x h) f (x)Step 5. lim lim 0 0

h

9. Use the definition of derivative (5-step procedure) to find f ‘ (x) of f (x) = 4

Page 12: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

Step 1: f (x + h) = 2/(x + h)

Step 2: f (x) = 2/x

Step 3: f (x + h) – f (x) = 0

h 0 h 0 h 0

f (x h) f (x)Step 5. lim lim lim

h h

- 2h- 2x (x h)

x (x h)

10. Use the definition of derivative (5-step procedure) to find f ‘ (x) of f (x) = 2/x

h)(xx

2h-

x

2-

hx

2 (x) f– h) (x f:4 Step

22 x2

x

2

Page 13: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

11. Use the definition of derivative (5-step procedure) to find f ‘ (x) of f (x) = √x

Step 1: f (x + h) = √(x + h)

Step 2: f (x) = √x

Step 3: f (x + h) – f (x) = √(x + h) - √x

x h x x h x x h xf (x h) f (x)Step 4.

h h h x h x

12

h 0 h 0

f (x h) f (x) 1 1 1Step 5. lim lim x

h 2x h x 2 x

Hint Multiply the numerator or denominator of the difference quotient by √(x + h) + √x and then simplify.

h 1

h ( x h x) x h x

Page 14: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

12. Find the equation to the tangent line to the curve f (x) = x 2 – 3x + 5 at x = 2, writing the equation in slope intercept form.

b. Use a graphing calculator to graph the curve together with the tangent line to verify your answer.

See problem 6.

Page 15: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

13. a. Find f’(x) using the definition of the derivative. b. Explain, by considering the original function, why the derivative is a constant.

f (x) = 3x - 4

b.

Use the five step procedure. See problem 8.

f ‘ (x) = 3.

Page 16: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

14. Business: Temperature The temperature in an industrial pasteurization tank is f (x) = x 2 – 8x + 110 degrees centigrade after x minutes (for 0 ≤ x ≤ 12)

a. Find f’(x) by using the definition of the derivative.b. Use your answer to part (a) to find the instantaneous rate of change of the temp.after 2 minutes. Be sure to interrupt the sign of your answer.c. Use your answer to part (a) to find the instantaneous rate of change after 5 minutes.

a. Use the five-step procedure (See problem 7) to get

f ’ (x) = 2x – 8.

b. f ’ (2) = 2 (2) – 8 = - 4 After two minutes the temperature is decreasing at a rate of 4 degrees per minute.

c. f ’ (5) = 2 (5) – 8 = 2 After five minutes the temperature is increasing at a rate of 2 degrees per minute.

Page 17: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

15. Behavioral Science: Learning theory In a psychology experiment, a personcould memorize x words in 2x 2 -x seconds (for 0 ≤ x ≤ 10 )a.Find f’(x) by using the definition of the derivative.b.Find F’(5) and interpret it as an instantaneous rate of change in the proper units.

a. Use the five-step procedure (See problem 7) to get

f ’ (x) = 4x – 1.

b. f ’ (5) = 4 (5) – 1 = 19 it will take 19 seconds to memorize the next, sixth, word..

Page 18: Section 2.2 1. By imagining tangents at he indicated points state whether the slope is positive, zero or negative at each point. P 1 P 2 P 3

16. Social Science: Immigration The percentage if people in the United Stateswho are immigrants (that is, born elsewhere) for different decades is approximated by the function f (x) = ½ x 2 – 3.7 x + 12, where x stands for the number of decades since 1930 (so that, for example x=5 would stand for 1990).

a. Find f ’(x) using the definition of the derivative.b. Evaluate the derivative at x=1 and interpret the resultc. Find the rate of change if the immigrant percentage in the year 2000.

a. Use the five-step procedure (See problem 7) to get

f ’ (x) = x – 3.7.

b. f ’ (1) = 1 – 3.7 = - 2.7 During the 1940’s the percentage of immigrants was decreasing by 2.7 %.

c. f ’ (7) = 7 – 3.7 = 3.3 During the 2000’s the percentage of immigrants was increasing by 3.3 %.