rotational motion (1) kinematics - texas a&m...
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Rotational Motion
(1) Kinematics
Everything’s analogous to linear kinematics
Define angular properties properly
and derive the equations of motionby analogy
Computer Hard Drive
A computer hard drive typically rotates at 5400
rev/minute
Find the: •
Angular Velocity in rad/sec
•
Linear Velocity on the rim (R=3.0cm)•
Linear Acceleration
It takes 3.6 sec to go from rest to 5400 rev/min, with constant angular acceleration.
•
What is the angular acceleration?
Examples
Consider two points on a rotating wheel. One on the inside (P) and the other at the end (b):
•
Which has greater angular velocity?
•
Which has greater linear velocity?
bR1R2
Rolling without Slipping
•
In reality, car tires both rotate and translate
•
They are a good example of something which rolls (translates, moves forward, rotates) without slipping
•
Is there friction? What kind?
Derivation
•
The trick is to pick your reference frame correctly!
•
Think of the wheel as sitting still and the ground moving past it with speed V.
Velocity of ground (in bike frame) = -ωR
=> Velocity of bike (in ground frame) = ωR
Bicycle comes to RestA bicycle with initial linear velocity V0
decelerates uniformly (without slipping) to rest over a distance d. For a wheel of radius R:
a)
What is the angular velocity at t0
=0?b)
Total revolutions before it stops?
c)
Total angular distance traversed by wheel?
(d) The angular acceleration?(e) The total time until it stops?
Vector Cross Product
A B vs.B A
A A
:CheckB" intoA Swing"
Rule-Hand-Right fromDirection SinB AC
B A C
rrrr
rr
rrr
××
×
Θ=
×=
Example of Cross ProductThe location of a body is length r from the origin and at an angle θ from the x-
axis. A force F
acts on the body purely in the y
direction.
What is the Torque on the body?
z
x
yθ
Rotational Dynamics
•
What plays the role of mass in rotation?
•
F = ma = mRα•
τ
= R F = mR2α
•
Rotational inertia: mR2
•
Στi
= (Σmi
Ri2) α
•
I = Σmi
Ri2
•
Στ
= I α•
(Στ)CM
= ICM
αCM
Calculating Moments of Inertia
( ) 233
2
121
24243
31 2
2
2
2
Mllll
Ml
MdRRl
MI Rl
l
l
l=⎟⎟
⎠
⎞⎜⎜⎝
⎛+===
−−∫
∫= dmRI 2 dRl
MdRdm l == ρ
A few helpful theorems
•
Parallel Axis TheoremI = ICM
+ M h2
•
Perpendicular Axis TheoremIz
= Ix
+ IyOnly valid for flat object!
Angular Momentum
Angular Momentum
MomentumL = Iω
p = mv
Στ
= Iα
= dL/dt
ΣF = ma = dp/dt
Στ=0 ⇒ L=const.
ΣF=0 ⇒ p=const.
Total Angular Momentum is conserved if Στ=0.
Note: L
= I ω, Angular Momentum is a vector
Rotating Kinetic Energy
•
K = Σ(1/2mi
vi2) = Σ(1/2 mi
Ri2 ω2)
= ½
Σ(mi
Ri2) ω2
= ½
I ω2
•
Rotational Kinetic Energy: ½
I ω2
•
W= F dl= F⊥Rdθ= τdθ
•
W=1/2 I ω22
-
1/2 I ω1
2
Rotation and Translation
•
Translation: K = ½
mv2
•
Rotation: K = ½
Iω2
•
Both (e.g. rolling): –
K = ½
mvCM
2
+ ½
Iω2
Atwood’s Machine Revisited
A pulley with a fixed center (at point O), radius R0
and moment of inertia I,
has a
massless rope wrapped around it (no slipping). The rope has two masses, m1
and m2 attached to its ends. Assume m2
>m1
A pulley with a fixed center (at point O), radius R0
and moment of inertia I,
has a
massless rope wrapped around it (no slipping). The rope has two masses, m1
and m2 attached to its ends. Assume m2
>m1
Or :
Angular Momentum
dtLdI
dtLd
dtLd
dtId
dtdII
rrr
rrrrrr
==
=====
∑
∑
ατ
ωωατ
)()(
ωrr
IL =Newton’s Law for rotational motion:
Angular Motion of a ParticleDetermine the angular momentum, L, of a particle,with mass m
and
speed v, moving in uniform circular motion with radius r.
Man on a Disk
A person with mass m
stands on the
edge of a disk with radius R
and
moment ½MR2. Neither is moving. The person then starts moving on the disk with speed V.Find the angular velocity of the disk.
A bullet strikes a cylinderA bullet of speed V
and mass m
strikes a solid cylinder of mass M
and inertia ½MR2,
at radius R
and sticks. The cylinder is anchored at point 0 and is initially at rest.
What is ω of the system after the collision?
Is energy Conserved?
Kepler’s
2nd
Law2nd
Law:
Each
planet moves so that an imaginary line drawn from the Sun to the planet sweeps out area in equal periods of time.