project finance (part 2) h. scott matthews 12-706/73-359 lecture 12 - oct. 8, 2003

37
Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Post on 21-Dec-2015

220 views

Category:

Documents


6 download

TRANSCRIPT

Page 1: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Project Finance (part 2)

H. Scott Matthews12-706/73-359Lecture 12 - Oct. 8, 2003

Page 2: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Admin Issues

Pipeline case out - read for Monday Brief discussion on preparing cases

HW 2 back todayProject groups/ideas due today

Short (1/2 page) description of project, client

Midterm

Page 3: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Notes on Notation

PV = $FV / (1+i)n = $FV * [1 / (1+i)n ] But [1 / (1+i)n ] is only function of i,n $1, i=5%, n=5, [1/(1.05)5 ]= 0.784 = (P|F,i,n) Would see tables like this in ‘old’ textbooks

As shorthand: Future value of Present: (P|F,i,n)

So PV of $500, 5%,5 yrs = $500*0.784 = $392

Present value of Future: (F|P,i,n) We’ll see similar notations for other types

Page 4: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Timing of Future Values

Noted last time that we assume ‘end of period’ values

What is relative difference?Consider comparative case:

$1000/yr (uniform) Benefit for 5 years @ 5%

Assume case 1: received beginning Assume case 2: received end

Page 5: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Timing of BenefitsDraw 2 cash flow diagramsNPV1 = 1000 + 1000/1.05 + 1000/1.052 +

1000/1.053 + 1000/1.054

NPV1 =1000 + 952 + 907 + 864 + 823 = $4,545

NPV2 = 1000/1.05 + 1000/1.052 + 1000/1.053 + 1000/1.054 + 1000/1.055

NPV2 = 952 + 907 + 864 + 823 + 784 = $4,329

NPV1 - NPV2 ~ $216Notation: (P|U,i,n)

Page 6: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Relative NPV AnalysisIf comparing, can just find ‘relative’ NPV

compared to a single option E.g. beginning/end timing problem Net difference was $216

Alternatively consider ‘net amounts’ NPV1 =1000 + 952 + 907 + 864 + 823 = $4,545 NPV2 = 952 + 907 + 864 + 823 + 784 = $4,329 ‘Cancel out’ intermediates, just find ends NPV1 is $216 greater than NPV2

Page 7: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Uniform Values - Theory

Assume ‘end of period’ valuesA = U/(1+i) +U/(1+i)2 + ..+ U/(1+i)n

A = U*[(1+i)-1+(1+i)-2 + ..+ (1+i)-n]A(1+i)=U*[1+(1+i)-1+(1+i)-2 + ..+

(1+i)1-n]A(1+i) - A = U*[1 - (1+i)-n]A = U*[1 - (1+i)-n] / i = U*(P|U,i,n)

Page 8: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Uniform Values - Application

Recall $1000 / year for 5 years example

Stream = U*(P|U,i,n) = U*[1 - (1+i)-n] / i(P|U,5%,5) = 4.329Stream = 1000*4.329 = $4,329 =

NPV2

Page 9: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Why Finance?

Time shift revenues and expenses - construction expenses paid up front, nuclear power plant decommissioning at end.

“Finance” is also used to refer to plans to obtain sufficient revenue for a project.

Page 10: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Borrowing

Numerous arrangements possible: bonds and notes bank loans and line of credit municipal bonds (with tax exempt

interest)Lenders require a real return -

borrowing interest rate exceeds inflation rate.

Page 11: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Issues

Security of loan - piece of equipment, construction, company, government. More security implies lower interest rate.

Project, program or organization funding possible. (Note: role of “junk bonds” and rating agencies.

Variable versus fixed interest rates: uncertainty in inflation rates encourages variable rates.

Page 12: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Issues (cont.)

Flexibility of loan - can loan be repaid early (makes re-finance attractive when interest rates drop). Issue of contingencies.

Up-front expenses: lawyer fees, taxes, marketing bonds, etc.- 10% common

Term of loanSource of funds

Page 13: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Borrowing

Sometimes we don’t have the money to undertake - need to get loan

i=specified interest rateAt=cash flow at end of period t (+ for loan

receipt, - for payments)Rt=loan balance at end of period tIt=interest accrued during t for Rt-1

Qt=amount added to unpaid balanceAt t=n, loan balance must be zero

Page 14: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Equations

i=specified interest rateAt=cash flow at end of period t (+ for

loan receipt, - for payments)It=i * Rt-1

Qt= At + ItRt= Rt-1 + Qt <=> Rt= Rt-1 + At + It Rt= Rt-1 + At + (i * Rt-1)

Page 15: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Option: Uniform payments

Assume a payment of U each year for n years on a principal of P

Rn=-U[1+(1+i)+…+(1+i)n-1]+P(1+i)n

Rn=-U[( (1+i)n-1)/i] + P(1+i)n

Uniform payment functions in ExcelSame basic idea as earlier slide

Page 16: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Example

Borrow $200 at 10%, pay $115.24 at end of each of first 2 years

R0=A0=$200

A1= - $115.24, I1=R0*i = (200)(.10)=20

Q1=A1 + I1 = -95.24

R1=R0+Qt = 104.76

I2=10.48; Q2=-104.76; R2=0

Page 17: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Repayment Options

Single Loan, Single payment at end of loan

Single Loan, Yearly PaymentsMultiple Loans, One repayment

Page 18: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Note on Taxes

Companies pay tax on net incomeIncome = Revenues - ExpensesThere are several types of expenses

that we care about Interest expense of borrowing Depreciation (can only do if you own

asset) These are also called ‘tax shields’

Page 19: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Depreciation

Decline in value of assets over time Buildings, equipment, etc. Accounting entry - no actual cash flow Systematic cost allocation over time

Government sets dep. Allowance P=asset cost, S=salvage,N=est. life Dt= Depreciation amount in year t Tt= accumulated (sum of) dep. up to t Bt= Book Value = Undep. amount = P - Tt

Page 20: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Depreciation Example

Simple/straight line dep: Dt= (P-S)/N Equal expense for every year $16k compressor, $2k salvage at 7 yrs. Dt= (P-S)/N = $14k/7 = $2k Bt= 16,000-2t, e.g. B1=$14k, B7=$2k

Page 21: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Accelerated Dep’n Methods

Depreciation greater in early yearsSum of Years Digits (SOYD)

Let Z=1+2+…+N = N(N+1)/2 Dt= (P-S)[N-(t-1)]/Z, e.g. D1=(N/Z)*(P-S) D1=(7/28)*$14k=$3,500, D7=(1/28)*$14k

Declining balance: Dt= Bt-1r (r is rate) Bt=P(1-r)t, Dt= Pr(1-r)t-1

Requires us to keep an eye on B Typically r=2/N - aka double dec. balance

Page 22: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Ex: Double Declining Balance

Could solve P(1-r)N = S (find nth root)

t Dt Bt0 - $16,0001 (2/7)*$16k=$4,571.43 $11,428.572 (2/7)*$11,428=$3265.31 $8,163.263 $2332.36 $5,830.904 $1,665.97 $4,164.935 $1,189.98 $2,974.956 $849.99 $2,124.967 $607.13** $1,517.83**

Page 23: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Notes on Example

Last year would need to be adjusted to consider salvage, D7=$124.96

We get high allowable depreciation ‘expenses’ early - tax benefit

We will assume taxes are simple and based on cash flows (profits) Realistically, they are more complex

Page 24: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Tax Effects of Financing

Companies deduct interest expenseBt=total pre-tax operating benefits

Excluding loan receipts

Ct=total operating pre-tax expenses Excluding loan payments

At=net pre-tax operating cash flow A,B,C: financing cash flowsA*,B*,C*: pre-tax totals / all sources

Page 25: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Notes

Mixed funds problem - buy computerBelow: Operating cash flows AtFour financing options in At

t At(Operation)

0 -22,000 10,000 10,000 10,000 10,0001 6,000 -2,505 -800 -2,8002 6,000 -2,505 -800 -2,6403 6,000 -2,505 -800 -2,4804 6,000 -2,505 -800 -2,3205 6,000 -14,693 -2,505 -10,800 -2,160

2,000

At(Financing)

Page 26: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Further Analysis (still no tax)t At

8% (Operation)0 -22,000 10,000 10,000 10,000 10,000 -12,000 -12,000 -12,000 -12,0001 6,000 -2,505 -800 -2,800 6,000 3,495 5,200 3,2002 6,000 -2,505 -800 -2,640 6,000 3,495 5,200 3,3603 6,000 -2,505 -800 -2,480 6,000 3,495 5,200 3,5204 6,000 -2,505 -800 -2,320 6,000 3,495 5,200 3,6805 6,000 -14,693 -2,505 -10,800 -2,160 -8,693 3,495 -4,800 3,840

2,000 2,000 2,000 2,000 2,000NPV 3317.427 0.1911 -1.7386 0 1E-12 3317.62 3315.69 3317.4 3317.43

At(Financing at 8%)

A*(Total pre-tax)

MARR (disc rate) equals borrowing rate, so financing plans equivalent.

When wholly funded by borrowing, can set MARR to interest rate

Page 27: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Effect of other MARRs (e.g. 10%)t At

10% (Operation)0 -22,000 10,000 10,000 10,000 10,000 -12,000 -12,000 -12,000 -12,0001 6,000 -2,505 -800 -2,800 6,000 3,495 5,200 3,2002 6,000 -2,505 -800 -2,640 6,000 3,495 5,200 3,3603 6,000 -2,505 -800 -2,480 6,000 3,495 5,200 3,5204 6,000 -2,505 -800 -2,320 6,000 3,495 5,200 3,6805 6,000 -14,693 -2,505 -10,800 -2,160 -8,693 3,495 -4,800 3,840

2,000 2,000 2,000 2,000 2,000NPV 1986.563 876.8 504.08 758.16 483.69 2863.37 2490.64 2744.7 2470.25

At A*(Financing at 8%) (Total pre-tax)

‘total’ NPV higher than operation alone for all options All preferable to ‘internal funding’ Why? These funds could earn 10% ! First option ‘gets most of loan’, is best

Page 28: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Effect of other MARRs (e.g. 6%)t At

6% (Operation)0 -22,000 10,000 10,000 10,000 10,000 -12,000 -12,000 -12,000 -12,0001 6,000 -2,505 -800 -2,800 6,000 3,495 5,200 3,2002 6,000 -2,505 -800 -2,640 6,000 3,495 5,200 3,3603 6,000 -2,505 -800 -2,480 6,000 3,495 5,200 3,5204 6,000 -2,505 -800 -2,320 6,000 3,495 5,200 3,6805 6,000 -14,693 -2,505 -10,800 -2,160 -8,693 3,495 -4,800 3,840

2,000 2,000 2,000 2,000 2,000NPV 4768.699 -979.46 -551.97 -842.5 -525.1 3789.23 4216.73 3926.2 4243.61

At A*(Financing at 8%) (Total pre-tax)

Now reverse is true Why? Internal funds only earn 6% ! First option now worst

Page 29: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

After-tax cash flows

Dt= Depreciation allowance in t

It= Interest accrued in t + on unpaid balance, - overpayment Qt= available for reducing balance in t

Wt= taxable income in t; Xt= tax rate

Tt= income tax in t

Yt= net after-tax cash flow

Page 30: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Equations

Dt= Depreciation allowance in tIt= Interest accrued in t

Qt= available for reducing balance in t So At = Qt - It

Wt= At-Dt -It (Operating - expenses)Tt= Xt Wt

Yt= A*t - Xt Wt (pre tax flow - tax) ORYt= At + At - Xt (At-Dt -It)

Page 31: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Simple example

Firm: $500k revenues, $300k expense Depreciation on equipment $20k No financing, and tax rate = 50%

Yt= At + At - Xt (At-Dt -It)

Yt=($500k-$300k)+0-0.5 ($200k-$20k)

Yt= $110k

Page 32: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

First Complex Example

Firm will buy $46k equipment Yr 1: Expects pre-tax benefit of $15k Yrs 2-6: $2k less per year ($13k..$5k) Salvage value $4k at end of 6 years No borrowing, tax=50%, MARR=6% Use SOYD and SL depreciation

Page 33: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Results - SOYD

D1=(6/21)*$42k = $12,000SOYD really reduces taxable income!

t At SOYD Tax Income Inc Tax Aft-Tax6% (Pre-tax) Dt Wt Tt Yt

0 -46,000 -46,0001 15,000 12,000 3,000 1,500 13,5002 13,000 10,000 3,000 1,500 11,5003 11,000 8,000 3,000 1,500 9,5004 9,000 6,000 3,000 1,500 7,5005 7,000 4,000 3,000 1,500 5,5006 5,000 2,000 3,000 1,500 3,500

4,000 4,000NPV 7661.004 285.02

Page 34: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Results - Straight Line Dep.

Now NPV is negative - shows effect of depreciation method on decision Negative tax? Typically a credit not cash back

t At SL Tax Income Inc Tax Aft-Tax6% (Pre-tax) Dt Wt Tt Yt

0 -46,000 -46,0001 15,000 7,000 8,000 4,000 11,0002 13,000 7,000 6,000 3,000 10,0003 11,000 7,000 4,000 2,000 9,0004 9,000 7,000 2,000 1,000 8,0005 7,000 7,000 0 0 7,0006 5,000 7,000 -2,000 -1,000 6,000

4,000 4,000NPV 7661.004 -548.9

Page 35: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Let’s Add in Interest - Computer Again

Price $22k, $6k/yr benefits for 5 yrs, $2k salvage after year 5 Borrow $10k of the $22k price Consider single payment at end and

uniform yearly repayments Depreciation: Double-declining balance Income tax rate=50% MARR 8%

Page 36: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

t At At Bt Dt Rt It Wt Tt Yt8% (Operation) (Loan 8%)

0 -22,000 10,000 22,000 10000 -12,0001 6,000 13,200 8,800 10800 800 -3,600 -1800 7,8002 6,000 7,920 5,280 11664 864 -144 -72 6,0723 6,000 4,752 3,168 12597 933 1,899 949.44 5,0514 6,000 2,851 1,901 13605 1,008 3,091 1545.7 4,4545 6,000 -14,693 2,000 851 14693 1,088 4,061 2030.3 -10,723

2,000 2,000NPV 3317.427 0.19109 1774.38

Single Repayment

Had to ‘manually adjust’ Dt in yr. 5Note loan balance keeps increasing

Only additional interest noted in It as interest expense

Page 37: Project Finance (part 2) H. Scott Matthews 12-706/73-359 Lecture 12 - Oct. 8, 2003

Uniform paymentst At At Bt Dt Rt It Wt Tt Yt

8% (Operation) (Loan 8%)0 -22,000 10,000 22,000 10000 -12,0001 6,000 -2,505 13,200 8,800 8295 800 -3,600 -1800 5,2952 6,000 -2,505 7,920 5,280 6453.6 664 56 28.2 3,4673 6,000 -2,505 4,752 3,168 4464.9 516 2,316 1157.9 2,3374 6,000 -2,505 2,851 1,901 2317.1 357 3,742 1871 1,6245 6,000 -2,505 2,000 851 -2.555 185 4,964 2481.8 1,013

2,000 2,000NPV 3317.427 -1.7386 974.707

Note loan balance keeps decreasingNPV of this option is lower - should

choose previous (single repayment at end).. not a general result