production
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production paperTRANSCRIPT
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Subject: MELanguage: English
Q.1
achieve directional solidification
reduce possibility of blow holes
reduce the freezing time
increase the smoothness of cast surface
Solution
A chill is used to promote solidification in a specific portion of castingmould. It can be strategically placed to help in directionalsolidification.
Chills are used in hole plates can be used
Correct
Your Ans a
Correct Ans a
Time (Secs) 5
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Q.2
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5 litre
10 litre
15 litre
20 litre
Solution
The neutral flame is commonly used for welding of mild steel. Inneutral flame, the ratio of oxygen to acetylene is oneacetylenemixture is one. So, oxygen consumption = 10 litre
In gas welding of mild steel using an oxyacetylene flame, the totalamount of acetylene consumed was 10 litre. The oxygenconsumption from the cylinder is
Unattempted
Your Ans
Correct Ans b
Time (Secs) 24
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Q.3
Lower nucleation rate
Higher nucleation rate with lower growth rate
Higher nucleation rate with higher growth rate
Lower growth rate
Solution
Sol. (b)
Fine grain size during solidification of metal is achieved by
InCorrect
Your Ans c
Correct Ans b
Time (Secs) 49
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Q.4
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Lower hardness by transforming austenite to pearlite
Lower hardness by transforming martensite to pearlite
High hardness by transforming austenite to martensite
High hardness by transforming martensite to pearlite
Solution
Sol. (b)
Tempering process is used in steels to achieve
Correct
Your Ans b
Correct Ans b
Time (Secs) 19
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Q.5
Makes the tool stronger
Increases shear angle
Makes the cutting edge sharper
Increases the chip thickness
Solution
Sol. (c)
Cutting force is reduced if rake angle is positive because positiverake angle
Unattempted
Your Ans
Correct Ans c
Time (Secs) 25
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Q.6
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Solution
Clearance angle = 90 – (60 + 20)
In the figure shown below. The clearance angle (in degree) is______
Correct
Your Ans 10
Correct Ans 10
Time (Secs) 16
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Q.7
Solution
MRR = TdV = 0.8 × 1.2 × 60 × 10MRR = 57600 mm /min
A steel workpiece is turned on a lathe at 60 m/min cutting speed,0.8 mm/rev feed and 1.2 mm depth of cut. The metal removal rate(in mm /min) is ______ .3
3
3
Correct
Your Ans 57600
Correct Ans 57500 | 57700
Time (Secs) 44
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Q.8
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Relief face of tool
Rake face
Nose of tool
Cutting edge
Solution
Sol. (a)
Flank wear mainly occurs on
InCorrect
Your Ans b
Correct Ans a
Time (Secs) 12
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Q.9
400%
300%
200%
100%
Solution
In Taylor tool life equation VT = C, n = 0.5 and C = 300. Thepercentage increase in tool life when the cutting speed is reducedby 50% is
n
Unattempted
Your Ans
Correct Ans b
Time (Secs) 11
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Q.10
Solution
Tolerance = 0.05 – (–0.05) = 0.1 mmTolerance = 1000 microns
Unattempted
Your Ans
Correct Ans 100
Time (Secs) 3
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Q.11
Solution
A shaper having length of 200 mm has 30 number of doublestrokes per minute with ratio of cutting time to time of return equalto 3/2. The cutting speed is _____ m/min.
Unattempted
Your Ans
Correct Ans 9.9 | 10.1
Time (Secs) 8
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Q.12
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small components
large components
identical components in large number
medium size components
Solution
Sol. (a)
Drop forging is used to produce
Unseen
Your Ans
Correct Ans a
Time (Secs) 0
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Q.13
BCC form of iron
FCC form of iron
Pure iron with very low carbon
Intermetallic compound iron carbide
Solution
Sol. (b)
Austenite is the
Unseen
Your Ans
Correct Ans b
Time (Secs) 0
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Q.14
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1.26
2.51
48
151
Solution
The cutting velocity in m/sec., for turning a work piece or diameter100 mm at the spindle speed of 480 RPM is
Unseen
Your Ans
Correct Ans b
Time (Secs) 0
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Q.15
0.2%
6.67%
2%
1.2%
Solution
Sol. (c)
Maximum carbon content in steels is up to
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.16
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small components
large components
identical components in large numbers
mediumsize components
Solution
Droping forging is used to produce large number of identicalcomponents. In this process, a shaped die is used, with one halfbeing attached to the hammer and the other half to the axvil . It is amass production technique.
Drop forging is used to produce
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.17
30 s
36 s
1 minute
45 s
Solution
A 150 mm long, 12 mm diameter 304 stainless steel rod is beingreduced in diameter to 11.5 mm by turning on a lathe. The spindlerotates at N = 400 rpm and the tool is travelling at an axial speed of200 mm/min. The time taken for cuttiing is given by
Unseen
Your Ans
Correct Ans b
Time (Secs) 0
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Q.18
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6 mm
12 mm
25 mm
44 mm
Solution
The amount of offset of tail stock for turning taper on full length of ajob 300 mm long which is to have its two diameters at 50 mm and38 mm ultimately is
Unseen
Your Ans
Correct Ans a
Time (Secs) 0
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Q.19
110 mm/min
35 mm/min
6 mm/min
60 mm/min
Solution
A milling cutter of 70 mm diameter with 12 teeth is operating at acutting speed of 22 m/min and a feed of 0.05 mm/ tooth. The feedper minute is
Unseen
Your Ans
Correct Ans d
Time (Secs) 0
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Q.20
poor casting design
faculty mould flask
lower strength of the solidified metal
higher moisture in the moulding sand
Solution
Sol. (d)
Blow holes in sandcasting are caused by
Unseen
Your Ans
Correct Ans d
Time (Secs) 0
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Q.21
Pouring hot metal into the mould
Non uniform thickness of walls joining in a casting
Poor refractory property of the moulding sand.
Low thermal conductivity of the moulding sand.
Solution
Sol. (b)
Hot tear is sand casting is caused by
Unseen
Your Ans
Correct Ans b
Time (Secs) 0
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Q.22
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Solution
In an orthogonal turning of mild steel. The cutting velocity, feed anddepth of cut were 120 m/min, 0.25 mm/rev, and 2 mm respectively.When the cutting force of 800 N was applied. The specific energyconsumption for the turning operation (in J/mm ) is_____.3
Unseen
Your Ans
Correct Ans 1.6
Time (Secs) 0
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Q.23
Solution
Sol. [2]
In ASA, the tool nomenclature is 88561023 mm, then the sidecutting edge angle for the tool (in degree) is _________.
Unseen
Your Ans
Correct Ans 2
Time (Secs) 0
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Q.24
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Solution
A molten liquid metal having spherical shape with 2 mm radiustakes 8 seconds to solidify. The same molten metal drop withdouble the radius will take ______ seconds to solidify.
Unseen
Your Ans
Correct Ans 32
Time (Secs) 0
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Q.25
Any complex shape can be obtained
Cost of the pattern is low
Very thin sections can be readily made
Any size of casting can be obtained.
Solution
Sol. (c)
Main advantage of using shell moulding is
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.26
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The use of AC welding with nonconsumable electrodes
The use of DC welding with consumable electrodes
The use of AC welding with consumable electrodes
none of the above
Solution
Sol. (b)
Arc blow in manual metal arc welding is caused by
Unseen
Your Ans
Correct Ans b
Time (Secs) 0
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Q.27
Solution
In a wire drawing operation, diameter of steel wire is reduced from8mm to 7 mm. The mean flow stress of material is 250 MPa. Theideal force required for drawing (in kN) is _____.
Unseen
Your Ans
Correct Ans 2.55 | 2.59
Time (Secs) 0
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Q.28
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Solution
A blank of width 15 mm width and 25 mm length is cut from a 2 mmthick strip., if the ultimate shear strength of metal strip is 300 MPa.The blanking force required is _____ kN.
Unseen
Your Ans
Correct Ans 48
Time (Secs) 0
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Q.29
Solution
A cup of 120 mm diameter and 50 mm height is to be drawn usinga blank. The required blank diameter will be _____ mm.
Unseen
Your Ans
Correct Ans 195 | 197
Time (Secs) 0
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Q.30
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Lowcarbon steels
Alloy steels
Mediumcarbon steels
Highcarbon steels
Solution
Sol. (b)
Nitriding process is used to increase surface hardness for
Unseen
Your Ans
Correct Ans b
Time (Secs) 0
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Q.31
(1 0 0)
(1 1 0)
(1 1 1)
(1 0 1)
Solution
Miller indices for the hatched plane in the below unit cell will be
Unseen
Your Ans
Correct Ans b
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Time (Secs) 0
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Q.32
Solution
During an orthogonal cutting with rake angle of 12°, the chipthickness ratio was found to be 0.4 and width of cut and uncut chipthickness were 2 mm and 0.5 m respectively. If the yield shearstress of work material is 250 MPa, the shear force on total is_____ N.
Unseen
Your Ans
Correct Ans 630 | 645
Time (Secs) 0
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Q.33
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Solution
Sol. (d)
Unseen
Your Ans
Correct Ans d
Time (Secs) 0
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Q.34
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15 mm
20 mm
25 mm
30 mm
Solution
A hole is to be punched in a 15 mm thick plate having ultimateshear strength of 2.5 N/mm . If the allowable crushing stress in thepunch is 6 N/mm , the diameter of the smallest hole which can bepunched is equal to
2
2
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.35
Solution
A metallic sheet is reduced from an initial thickness of 10 mm to afinal thickness of 7 mm in a single pass rolling with rollers ofdiameter 300 mm. The angle of bit (in degrees) would be _____.
Unseen
Your Ans
Correct Ans 8.0 | 8.2
Time (Secs) 0
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Q.36
Solution
The casting shown in figure is to be made using steel which has ashrinkage allowance of 21 mm/m. Assuming shrinkage allowanceonly, the dimension of the pattern will be. (All dimensions in mm).
Unseen
Your Ans
Correct Ans a
Time (Secs) 0
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Q.37
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Solution
A sprue is to be designed for a casting to feed the molten metal ata rate of 10 kg/sec. The density of liquid metal is 8000 kg/m andthe height of pouring basin and height of sprue are 6 cm and 9 cmrespectively. Assuming sprue to be conical shape, the diameter ofsprue at top end i.e. larger diameter will be _____ cm.
3
Unseen
Your Ans
Correct Ans 3.7 | 3.9
Time (Secs) 0
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Q.38
Solution
A sprue is to be designed for a casting to feed the molten metal ata rate of 10 kg/sec. The density of liquid metal is 8000 kg/m andthe height of pouring basin and height of sprue are 6 cm and 9 cmrespectively. Assuming sprue to be conical shape. The diameter ofsprue at lower end will be _____ cm.
3
Unseen
Your Ans
Correct Ans 2.95 | 3.15
Time (Secs) 0
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Q.39
43 mm
38.2 mm
36.1 mm
35.7 mm
Solution
A strip of metal of dimension 40 mm × 25 mm × 100 mm is reducedto 10 mm × 100 mm × 100 mm between two flat dies in a forgingprocess. If the coefficient of friction is 0.25, the length from thecentre of strip along length upto which stricking exist is
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.40
4 and 12
6 and 6
6 and 12
6 and 9
Solution
Sol. (c)
Average number of atoms and coordination number for a crystalhaving HCP structure are respectively
Unseen
Your Ans
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Correct Ans c
Time (Secs) 0
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Q.41
Solution
During an orthogonal turning process with a tool designated as : 7 ? 6 6 8 20 1 mm, the tangential and thrust cutting forcewere 1200 N and 500 N respectively. The side rake angel (indegrees) is _____.
Unseen
Your Ans
Correct Ans 18.4 | 18.9
Time (Secs) 0
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Q.42
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Solution
During an orthogonal turning process with a tool designated as : 7 ? 6 6 8 20 1 mm, the tangential and thrust cutting forcewere 1200 N and 500 N respectively. The coefficient of friction atthe rake face is _____
Unseen
Your Ans
Correct Ans 0.89 | 0.93
Time (Secs) 0
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Q.43
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Solution
Sol. (a)
Unseen
Your Ans
Correct Ans a
Time (Secs) 0
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Q.44
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400 A and 100 V
200 A and 100 V
400 A and 50 V
200 A and 50 V
Solution
Assuming a straight line V – I characteristics for a dc weldingsgenerator, shortcircuit current as 400 A and open circuit voltageas 100 V, which one of the following is the correct voltage andcurrent setting for maximum arc power?
Unseen
Your Ans
Correct Ans d
Time (Secs) 0
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Q.45
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39.5º
42.25º
47.75º
50.5º
Solution
In an orthogonal cutting, rake angle of the tool is 20º and frictionangle is 25.5º. Using Merchant’s shear angle relationship, thevalue of shear angle will be
Unseen
Your Ans
Correct Ans b
Time (Secs) 0
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Q.46
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Solution
Sol. (c)
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.47
Solution
Sol. (c)
Which of the following is clearance fit
Unseen
Your Ans
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Correct Ans c
Time (Secs) 0
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Q.48
Drilling, reaming and grinding
Drilling, boring and grinding
Drilling, reaming and lapping
Drilling, reaming and electroplating
Solution
Drilling, reaming and grinding are machining processes used forgiving final shape to the component, whereas lapping andelectroplating are surface finishing processes used to provided agood surface finish to the machine component.Reaming is a sizing operation that removes a small amount of metalfrom a hole already drilled.
Which one of the following processing sequences will give the bestaccuracy as well as surface finish?
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.49
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Solution
EDM is used for shapping alloying steel and tungsten carbide dies,used for moudling, forgin, extension, wire drawing or suitable mouldcavities, press tools and to given any intricate shape or profile.ECM is used for machinary difficult to machine materials andcomplex shaped parts. Laser can make holes in a wide variety ofmaterials such as plastics, ceramics and many metals and alloys.USM can be used for drilling circular or noncircular holes in veryhard materials.
Match List I (Unconventional machining process) with List II(Typical application) and select the correct answer:
Unseen
Your Ans
Correct Ans b
Time (Secs) 0
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Q.50
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0°
30°
45°
90°
Solution
Angle between directions having miller indices [1 0 0] and [1 1 0] is
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.51
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Solution
In an orthogonal metal cutting process. The chip thickness ratiowas found to be 0.35, the rake angle was 10° and the chip flowvelocity as 2.5 m/s. If the mean thickness of primary shear zone is20 microns, the shear strain rate (in s ) is _____ × 10 .–1 4
Unseen
Your Ans
Correct Ans 35.0 | 36.5
Time (Secs) 0
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Q.52
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1.04 min
1.96 min
2.00 min
2.09 min
Solution
The time required to turn a mild steel rod from 5 cm diameter to 4.9cm a length of 10 cm if the cutting speed is 30 m/min and feed is0.25 mm/revolution is
Unseen
Your Ans
Correct Ans d
Time (Secs) 0
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Q.53
Solution
A hollow casting has to be produced by a cylindrical core of 120mm diameter and 180 mm height. The density of liquid metal is11300 kg/m and the density of core material is 1300 kg/m . Theupward lifting force on the core will be _____ N.
3 3
Unseen
Your Ans
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Correct Ans 198 | 201
Time (Secs) 0
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Q.54
Solution
Sol. (a)
Unseen
Your Ans
Correct Ans a
Time (Secs) 0
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Q.55
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Solution
Two steel sheets of 1 mm thickness are resistance welded in a lapjoint with a current of 800 amp. for 0.2 seconds. The effectiveresistance of the joint is 120 micro ohm. The joint can beconsidered as cylinder of diameter 10 mm and 1.5 mm height. Theheat required to melt steel is 0.1 J/mm .Heat lost to surrounding is _____ Joules.
3
Unseen
Your Ans
Correct Ans 3.5 | 3.7
Time (Secs) 0
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Q.56
Solution
A since bar has a length of 250 mm. Each roller has a diameter of25 mm. During taper angle measurement of a component, theheight from the surface plate to the centre of roller was measuredas 100 mm. The taper angle (in degrees) is_____
Unseen
Your Ans
Correct Ans 20.0 | 21.0
Time (Secs) 0
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Q.57
1.31 mm
2.62 mm
5.25 mm
6.00 mm
Solution
The arc lengthvoltage characteristic of a D.C. arc is given by theequation, V = 24 + 4L, where V’ is arc voltage in volts and ‘L’ is arclength in mm. The static voltampere characteristic of the powersource is approximated by a straight line with a no load voltage of90 volts and short circuit current of 600 Amp. The optimum arclength for maximum power is
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.58
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13 ± 0.07 mm
13 ± 0.11 mm
12.99 ± 0.11 mm
12.99 ± 0.07 mm
Solution
Sol. (c)
Unseen
Your Ans
Correct Ans c
Time (Secs) 0
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Q.59
Solution
4.5 mm thick sheet is rolled with 250 mm diameter rolls to reducethickness without any change its width. The friction coefficient atthe workroll interface is 0.1. The minimum possible thickness ofsheet that can be produced in a single pass is _____ mm.
Unseen
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Your Ans
Correct Ans 3.20 | 3.30
Time (Secs) 0
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Q.60
Solution
Unseen
Your Ans
Correct Ans b
Time (Secs) 0
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Q.61
Solution
A gating ratio of 1 : 3 : 4 is used to design a gating system. If thesprue area is 3 mm , then the gate area will be _____ mm .2 2
Unseen
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Your Ans
Correct Ans 12
Time (Secs) 0
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Q.62
Solution
Unseen
Your Ans
Correct Ans 3.8 | 3.9
Time (Secs) 0
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Q.63
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Solution
In a blanking operation to produce steel washer, the maximumpunch load used is2 × 10 N. The plate thickness is 4mm and percentage penetrationis 25. The work done during this shearing operation is
5
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Correct Ans a
Time (Secs) 0
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Q.64
Solution
A hole of 40 mm diameter and 50 mm depth is to be drilled in mildsteel component. The cutting speed can be taken as 65 m/min andthe feed rate as 0.25 mm/rev. Assuming lip angle of drill is 118°.The machining time___minutes.
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Correct Ans 0.5
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Q.65
Normal time + Allowances
Observed Time + Allowances
Observed time × Rating factor
Normal time × Rating factor
Solution
Normal time = observed time × Rating factorStandard time = Normal time + Allowances
In Industrial engineering, the standard time is equal to
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Q.66
process charts
flow diagrams
manmachine operation charts
therbligs
Solution
Sol. (d)
A SIMO chart should be used with
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Correct Ans d
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