practice problems for real analysis

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  • 8/13/2019 Practice Problems for Real Analysis

    1/12

    Q Q R2

    Q Q R2

    A, B

    A

    B= Q Q

    QQ QQ

    E= R2

    A1= (, ) (, ) B1= (, ) (, ) A1 B1

    R R2 A1 B1

    A= (Q Q)

    A1 B= (Q Q)

    B1 A

    B Q Q A1 B1

    (, ) (, ) (, ) (, )

    R2 Q Q

    QQ =A

    B

    Q Q R2

  • 8/13/2019 Practice Problems for Real Analysis

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    C={(x, y) : x2 +y2 = 1} R2

    f p= [0, 2] R C={(x, y) : x2 + y2 = 1} R2

    f(p) = (cos(p),sin(p))

    R [0, 2]

    f f

    f(p) =cos(p) f(p) =sin(p)

    f(p) =cos(p) p [0, 2] >0

    >0 |f(p) f(p0)|< p [0, 2] |p p0|<

    p0 [0, 2] = 2

    cos(x) cos(y) =2 sin

    x+y

    2

    sin

    x y

    2

    |cos(p) cos(p0)|=

    2 sin

    p+p02

    sin

    p p0

    2

    sin(x) 1 sin

    p+p0

    2

    1

    2

    sin

    p p02

    2

    sin pp02

    < |p p0|< pp02 < |sin(x)| |x|

    2

    sin

    p p02

    2p p02

  • 8/13/2019 Practice Problems for Real Analysis

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    f(p) = sin(p) p [0, 2] > 0

    >0 |f(p) f(p0)|< p [0, 2] |p p0|<

    p0 [0, 2] = 2

    sin(x) sin(y) = 2 cos

    x+y

    2

    sin

    x y

    2

    |sin(p) sin(p0)|=

    2 cos

    p+p02

    sin

    p p0

    2

    cos(x) 1 cos

    p+p0

    2

    1

    2sin

    p p02

    2

    sin pp02

    < |p p0|<

    pp02

    < |sin(x)| |x|

    2

    sin

    p p02

    2p p02

  • 8/13/2019 Practice Problems for Real Analysis

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    (E, d) f, g : E R limpp0f(p) = q0

    limpp0g(p) = r0 limpp0(f g)(p) = q0r0

    limpp0f(p) = q0 > 0 1 > 0 |f(p) q0| <

    0< |p p0|< 1 p E

    limpp0g(p) =r0 > 0 2 > 0 |g(p) r0| <

    0< |p p0|< 2 p E

    >0 >0 |(f g)(p) q0r0|< 0< |p p0|<

    2 + (|qo| + |r0|) = = = min{1, 2}

    2 + (|qo| + |r0|)

    0 f(p)r0 f(p)r0

    |(f g)(p) q0r0|= |f(p)g(p) q0r0|= |f(p) (g(p) r0) +r0(f(p) q0)|

    |x y| |x| |y|

    |f(p)| |g(p) r0| + |r0| |f(p) q0|

    |f(p) q0|< = |g(p) r0|<

    =

    (|f(p)| + |r0|)

    0 |q0| | q0|

    (|f(p) q0+q0| + |r0|)

    (|f(p) q0| + |q0| + |r0|)

    |f(p) q0|< =

    (+ |q0| + |r0|) = 2 + (|qo| + |r0|)

  • 8/13/2019 Practice Problems for Real Analysis

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    2 + (|qo| + |r0|)

    = 0 0 e=

    0< 0 = min{1, 2} |(f g)(p) q0r0| < 0 0 1 > 0 |f(p) q0| <

    0< |p p0|< 1 p E

    limpp0h(p) = r0 > 0 2 > 0 |h(p) q0| <

    0< |p p0|< 2 p E

    f(p) g(p) h(p)

    |p p0|< r

    >0 >0 |g(p) q0|< 0< |p p0|< p E

    |f(p) q0| < |h(p) q0| < q0 < f(p) < q0 +

    q0 < h(p)< q0+

    p E = min{1, 2, r} q0 < f(p) g(p) h(p)< q0+

    0< |p p0|<

    q0 < g(p)< q0+ |g(p) q0|<

    >0 >0 |g(p) q0|< p E

    0< |p p0|< = min{1, 2, r}

    limpp0g(p) =q0.

  • 8/13/2019 Practice Problems for Real Analysis

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    f : R R 0

    f(x) =

    x if x Q

    0 if x / Q 0

    f 0

    f x >0 >0

    f(B(x)) B((f(x))

    x = 0 f(x) = 0 B(0) = (, ). = e f(B(0)) B(0)

    =

    0

    0

    f R

    a= 0 Q f(a) =a

    >0 > 0 xR |x a| < f(B(a))

    B((f(a)) f(B(a)) B(a)

    = |a|2

    B(a) 0

    B(a) R

    B(a) 0

    B(a)

    = |a|2

    >0 x R |xa|< f(B(a)) B(a)

    a= 0 / Q f(a) = 0

    >0 >0 x R |x a|< f(B(a))

    B((f(a)) f(B(a)) B(0)

    = |a|2

    B(0) a

    B(a) R

    B(a) a

    B(0)

    = |a|2

    >0 x R |x a|< f(B(a))

    B(0)

    f 0 x R

  • 8/13/2019 Practice Problems for Real Analysis

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    f : R R |f|

    f(x) =

    1 if x Q

    1 if x / Q |f(x)| = 1

    x R

    f

    a Q

    f(a) = 1

    >0 > 0 xR |x a| < f(B(a))

    B((f(a)) f(B(a)) B(1)

    = 12

    B(1) 1

    B(a) R

    B(a) 1

    B(1)

    = 12

    >0 x R |x a|< f(B(a)) B(1)

    a / Q f(a) =1

    >0 >0 x R |x a|< f(B(a))

    B((f(a)) f(B(a)) B(1)

    = 12

    B(1) 1

    B(a) R

    B(a) 1

    B(1)

    = 12

    > 0 xR |x a|< f(B(a))

    B(1)

    f

    |f(x)|= 1 x R

    > 0 = x R |x a| < f(B(a)) B(1)

    B(a) 1

    a R |f|

  • 8/13/2019 Practice Problems for Real Analysis

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    f : Z R

    p0 Z f(p0) =q0 R

    >0 >0 |f(p) q0|< p Z |p p0|<

    f(B(p0)) B(q0)

    = 12

    Z

    B(p0) =p0 B(p0)

    p0 p= p0

    |f(p) f(p0)|= |f(p0) f(p0)|= 0< >0

  • 8/13/2019 Practice Problems for Real Analysis

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    d(x, y) =|x y| R d

    R R = R2 d: R2 R

    p0= (x0, y0) R2 d(p0) =|x0 y0| R

    > 0 > 0 |d(p) d(p0)| < p = (x, y) R2

    d(p, p0)<

    d(p, p0)<

    (x x0)2 + (y y0)2 0 >0 |f(p) q0|< |p p0|< p R

    = f(x) = 0 x R

    |f(p) q0|= |0 0|= 0<

    >0

    f

    f U R

    {0} R

    {0} R\{0}

    a

    a

    R\{0}

  • 8/13/2019 Practice Problems for Real Analysis

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    f : R R S

    f1(S)

    f(x) =x2 S= {1}

    S

    {1}.

    f

    x0 R f(x0) =x20 R

    > 0 >0 |f(x) f(x0)|< |x x0|< x R

    = |x+x0|

    f

    |f(x) f(x0)|= |x2 x20|= |(x x0)(x+x0)|

    |x x0| |y y0|

    |x x0|<

    < |x+x0|=

    |x+x0||x+x0|=

    f R

    f1(S) f1(S) ={1, 1}= C

    C=A

    B A B

    C

    C C

    R

    A= C

    (, 0) B = C

    (0, ) (, 0) (0, )

    R A B C

    A = 1 B = 1 C

    C

    f1(S)