power systems fundamentals

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Symmetrical Components David Castor, P.E.

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Page 1: Power Systems Fundamentals

Symmetrical

Components

David Castor, P.E.

Page 2: Power Systems Fundamentals

SYMMETRICAL COMPONENTS

AND EASYPOWER

– AN INTRODUCTION

David Castor, P.E.

Page 3: Power Systems Fundamentals

Why We Use them?

• Using standard single-line diagrams, complex impedances, and phasors, we can analyze steady-state conditions for all sorts of ac systems and configurations – as long as the three phase voltages and currents are equal in magnitude.

• For imbalanced conditions (ground faults) things get extremely complicated to analyze due to the coupling between the three phases.

Page 4: Power Systems Fundamentals

Symmetrical Components

• C. L. (Charles Legeyt) Fortescue (1918): Any

set of N unbalanced phasors can be

represented by N sets of balanced phasors.– Balanced system can be simulated with single phase. Easier to analyze and

compute.

– Three phase unbalanced vectors three balanced “sequence vectors.”

We still use this mathematical technique to this

day!

Page 5: Power Systems Fundamentals

Three Sets of “Sequence” Vectors

(Phasors)• Each set of sequence vectors is balanced – that is

what makes this approach easier to solve

• Positive Sequence (e.g. VA1) – this is the normal power system phase sequence quantities

• Negative Sequence (e.g. VA2) – Balanced phasorswith negative phase sequence

• Zero Sequence (e.g. VA0) – Three identical phasors– same phase angle.

Page 6: Power Systems Fundamentals

Sequence Vectors

o120

o120A1I

B1I

C1I

o120

o120

A2I

B2I

C2I

AoIBoI

CoI

Position of View

Position of View

Position of View

Positive SequenceVector Rotation Direction

Negative SequenceVector Rotation Direction

Zero SequenceVector Rotation Direction

Page 7: Power Systems Fundamentals

Symmetrical Components

Written in terms of sequence vectors (which are all symmetrical):

𝐼𝐴 = 𝐼𝐴0 + 𝐼𝐴1 + 𝐼𝐴2

𝐼𝐵 = 𝐼𝐵0 + 𝐼𝐵1 + 𝐼𝐵2

𝐼𝐶 = 𝐼𝐶0 + 𝐼𝐶1 + 𝐼𝐶2

AI

BI

CI

Page 8: Power Systems Fundamentals

Symmetrical Components MathSince sequence vectors are symmetrical and balanced, they have clearly defined relationships:

𝐼𝐵1 = 𝑎2 ∙ 𝐼𝐴1, 𝐼𝐶1 = 𝑎 ∙ 𝐼𝐴1

𝐼𝐵2 = 𝑎2 ∙ 𝐼𝐴2, 𝐼𝐶2 = 𝑎 ∙ 𝐼𝐴2

𝐼𝐴0 = 𝐼𝐵0 = 𝐼𝐶0

Where:

𝒂 = 𝟏∠𝟏𝟐𝟎°

Page 9: Power Systems Fundamentals

Symmetrical Components Math

𝐼𝐴 = 𝐼𝐴0 + 𝐼𝐴1 + 𝐼𝐴2

𝐼𝐵 = 𝐼𝐴0 + 𝑎2 ∙ 𝐼𝐴1 + 𝑎 ∙ 𝐼𝐴2

𝐼𝐶 = 𝐼𝐴0 + 𝑎 ∙ 𝐼𝐴1 + 𝑎2 ∙ 𝐼𝐴2

Page 10: Power Systems Fundamentals

Sequence Impedances

Transmission lines:– Pos. & Neg. sequence impedances are equal.

– Zero sequence impedance includes ground wires, shield wires, earth.

Cables, Busway, etc:– Pos. & Neg. sequence impedances are equal.

– Zero sequence similar to transmission line, but can be higher.

Page 11: Power Systems Fundamentals

Sequence Impedances

Generators:

– Pos. & Neg. similar except for impedances

and voltage induced by rotating machinery.

– Zero sequence varies, but generally smaller

than positive and negative sequence

impedances.

• MV generators normally impedance grounded.

Page 12: Power Systems Fundamentals

Sequence ImpedancesTransformers:

– Pos. & neg.

sequence

impedances

are equal.

– Zero sequence

depends on

transformer

connections

Page 13: Power Systems Fundamentals

Fault Calculation Example

BUS-1 12 kV

BUS-2 12 kV

UTIL-1

0.01 + j0.1

0.02 + j0.2

1-9

54

Mag

no

lia

AA

C,

5 m

i.

Look at Line-to-Ground Fault for this simple system

Page 14: Power Systems Fundamentals

Positive Sequence Network

Util 1R Util 1X Line 1R Line 1X

DriveV

Page 15: Power Systems Fundamentals

Negative Sequence Network

Util 2R Util 2X Line 2R Line 2X

Page 16: Power Systems Fundamentals

Zero Sequence Network

Util oR Util oX Line oR Line oX

Page 17: Power Systems Fundamentals

Combine Networks

• Once the sequence networks are defined, we need to determine how they are interconnected at the fault – this depends on the type of fault

• For a single line-to-ground fault on Phase A, IBand IC equal zero. It can be shown that to satisfy the fault conditions, the three sequence current for Phase A must be equal

• The only way this can happen is for the three sequence networks to be in series.

Page 18: Power Systems Fundamentals

Resulting Sequence Diagram

• Since the positive and negative sequence impedances are equal, this simplifies to :

Util 1R Util 1X Line 1R Line 1X

DriveV

Util 2R Util 2X Line 2R Line 2X

Util oR Util oX Line oR Line oX

FaultI

DriveFault pu

1 pu o pu

VI =

2Z + Z

Any fault impedance would show up as 3Zf in the sequence diagram since it will be each sequence

ONLY VALID FOR SLG FAULTS!

Page 19: Power Systems Fundamentals

Other Fault Types• Process is similar for other types of

unbalanced faults

• Sequence networks are the same.

• The difference is in how the sequence networks are interconnected based on the fault conditions.

• Standard references have tables of interconnection of networks for various faults types.

• This is all handled automatically in EasyPower

Page 20: Power Systems Fundamentals

Short Circuit in EasyPower

• One-line display options

Page 21: Power Systems Fundamentals

Short Circuit in EasyPower

Page 22: Power Systems Fundamentals

Short Circuit in EasyPower

Page 23: Power Systems Fundamentals

EasyPower Example

• We’ll look at doing unbalanced fault

calculations in EasyPower

• Look at symmetrical component results