o espectro de energia do átimo de hidrogênio
TRANSCRIPT
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xz
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b
c
a
b
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En 13.6n2
h 6.62 1034
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d2r
dt2 = k
r2r,
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a
b
t2 t1
S= t2
t1(K V) dt,
K
V
L(qi, qi) =K V
q (t)
q (t) q(t)+ q
q (t1) = q(t2) = 0
S= 0
b
c
a
b
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x= g
a
a
c
a
b
b
b
c
S =
t2t1
L(qi+qi, qi+qi) dt t2
t1
L(qi, qi) dt
=
t2t1
L
qiqi+
L
qiqi
dt=
t2t1
L
qiqi+
L
qi
d
dtqi
dt,
S =
t2t1
L
qiqi+
d
dt
L
qiqi
d
dt
L
qiqi
dt
= t2
t1 L
qiqi d
dt
L
qiqi +
t2
t1
d
dt L
qiqi dt
ddt
Lxi
xi
=
ddt
Lxi
xi + Lxi
ddtxi
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qi
t1
t2
S=
t2t1
L
qiqi d
dt
L
qiqi
dt= 0.
L
qi d
dt
L
qi= 0
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m1 m2 r 1
r 2
U(r 1,r 2) =1
2
2
a=bV(r 1,r 2),
a, b= 1, 2
K=1
2
2a=1
ma| r a|2,
| r a|2 = ijxiaxja
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L=1
2
2
a=1
ma| r a|2 V(r 1,r 2)
.
xia =xia+x
ia
L = L(xia,
xi
a) L(xia, xia) L
xiaxia+
L
xiaxia.
S= 0
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L = L
xiaxia+
L
xiaxia
= L
xiaxia+
d
dt
L
xiaxia
d
dt
L
xiaxia
=
L
xia d
dt
L
xia
xia+
d
dt
L
xiaxia
= 0 d
dt
L
xiaxia
= 0.
Q
xia=i
xia
L = L
xia
i
V(r 1,r 2) = V(|r 1 r 2|) V(r) rr 1 = rr 2 L = 0
Qi =
a
L
xiai.
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Pi = a
L
xia
P =m1 r 1+m2 r 2.
P
P= 0
r = r1 r2
L=1
2 | r |2 V(|r |)
= m1m2
m1+m2
r
V(r)
r a
R
r = Rr
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r
|r|2 = rTr = (Rr )T(Rr ) = r TRTRr.
r
RTR = I33
I
R3
R(1) =
1 0 0
0 cos 1 sen10 sen1 cos 1
R(2) =
cos 2 0 sen2
0 1 0
sen2 0 cos 2
R(2) =
cos 3 sen3 0sen3 cos 3 0
0 0 1
.
a a
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a = 0
R(1) =R(0) + dRd1
1=0
1=
1 0 0
0 1 0
0 0 1
+
0 0 0
0 0 1
0 1 0
1
R(2) =R(0) + dR
d2
2=0
2=
1 0 0
0 1 0
0 0 1
+
0 0 10 0 0
1 0 0
2
R(3) =R(0) +dR
d3
3=0
3=
1 0 0
0 1 0
0 0 1
+
0 1 0
0 0 0
1 0 0
3.
xi=Rji xj
Iji +a(Ja)
ji
xj =xi+a(Ja)
jixj
xi=a(Ja)jixj.
L
xixi = mx
ia(Ja)ji xj
Ja
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(Ja)ji =aij pi= mxi
Qa=aijpixj
Li= Qi
A
t =t .
L=r p
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xi = xi(t)
xi(t) =x
i(t
+)
xi(t)
xi(t) +xi(t) xi(t) xi(t)
L = L
xixi+
L
xixi=
L
xixi(t) +
L
xixi(t)
=
L
xixi(t) +
L
xixi(t)
=
dL
dt.
L = ddt
Lxi
xi
d
dt
L
xixi
=
d
dtL,
d
dt
L
xixi(t) L
= 0.
E= L
xixi L= m xi xi 1
2mxixi+V(|r |) =1
2m| r |2 +V(|r |)
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qi(t)
pi(t) = L
qi.
f
g
{f, g} = fxi
g
pi f
pi
g
xi
{f, g} = {g, f}
{f,gh} = g{f, h} + {f, g}h.
{f, {g, h}} + {g, {h, f}} + {h, {f, g}} = 0.
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{xj, pk
}=
xj
xi
pk
pi xj
pi
pk
xi=jiki = jk
{xi,
Lj}
={
xi, jkspkxs}
=jksikxs=jisxs
xi = aaijxj
xi = j{xi,Lj}.
pi=mxi
H=
L
xixi L
x=x(p)
=|p|2
2m+V(|r |)
{xi, H} = {xi,pjpj2m
+V |r |} = {xi,pjpj2m
}
= 12m
({xi, pj}pj+ pj{xi, pj}) = 1m
ijpj = 1m
pi= xi.
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xi=t xi
xi=t{xi, H}
qi(t)
qi=a{
qi, Qa}
.
dqi
dt = {qi, H} dpi
dt = {pi, H}.
q
p
= t
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{Li, Lj
}=
{irsxrps, jmnxmpn
}=irsjmn
{xrps, xmpn
}=irsjmn(xr{ps, xmpn} + {xr, xmpn}ps) =irsjmn(xrxm{ps, pn} +xr{ps, xm}pn++xm{xr, pn}ps+ {xr, xm}pspn) =irsjmn(xrsmpn+xmrnps) == irmjmnxrpn+irsjmrxmps=irmmjnxrpn+sirrjmxmps== (ijrn injr)xrpn+ (sjim ijsm)xmps= xnpnij xjpi+xipj xspsij ==xipj xjpi = ijkLk
ijkLk =ijkkrsxrps= (irjs isjr)xrps=xipjxjpi
{H, H} = 0.
{Li, H} =irsxrps, 1
2mpipi+V(|r |)
= irs
1
2mpipi+V(|r |), xrps
=
=irs
1
2mpipi, xrps
+irs {V(|r |), xrps} .
irs
1
2mpipi, xrps
=
1
2mirs(pi{pi, xrps} + {pi, xrps}pi) = 1
2mirs(pixr{pi, ps} +pi{pi, xr}ps
+xr{pi, ps}pi+ {pi, xr}pspi) = 0;
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irs{
V(
|r
|), xrps
}=xrirs
{V(
|r
|), ps
}+irs
{V(
|r
|), xr
}ps=xrirs V(|r |)
xi
ps
pi V(|r |)
pi
ps
xi
+irs
V(|r |)
xi
xr
pi V(|r |)
pi
xr
xi
ps=xrirs
V(|r |)xi
=xrirsV(|r |)
r
r
xi=
=xrirsV(|r |)
r
xi
r=irsxrxi
1
r
V(|r |)r
= 0.
{Li, H} = 0
{Li, H} = 0 {Li, Lj} = ijkLk
{H, H} = 0.
Li H
V r2
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p L
d(p L)dt
= dp
dt L +p d
L
dt =
dp
dt L= F(r)r (r p)
F(r)r
(r
p) = (rp)r
(rr )p.
d(p L)dt
= (F(r)r p)r (F(r)r r ) p
= m(F(r)r drdt
)r m(F(r)r r ) drdt
= mF(r)(dr
dtr r dr
dt).
d(rr
)
dt = 1
r2dr
dt+
1
r
dr
dt,
d(p L)dt
=
mF(r)r2
d(rr
)
dt
.
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F(r) =
k
r2
d(p L)dt
=mkd(r
r)
dt .
d
dt (p
L mkr
r ) = 0
A= p L mkrr
,
H
Li Ai {Li, H} =0 {Ai, H}
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{Li,
{Lj, H
}}+
{Lj,
{H, Li
}}+
{H,
{Li, Lj
}}= 0
{H, {Li, Lj}} = 0 {Li, Lj} {Li, Lj} =ijkLk
{Ai{Lj, H}}+ {Lj{H, Ai}} + {H{Ai, Lj}} = 0.
{Ai, Lj}
{Ai, Aj}
{Ai, Lj} = {imnpmLn mk xir
, Lj},
=imn{pmLn, Lj} mk{xir
, Lj}
=imnpm{Ln, Lj} +imn{pm, Lj}Ln mkxi{r, Lj} mkr {xi, Lj},
=imnnjkpmLk+imnmjrprLn mkr
ijkxk,
= (ijmk
ikmj)pmLk+ (njir
nrij)pnLr
mk
r ijkxk,
=piLj pjLi mkr
ijkxk,
=ijk(tukptLu mkxkr
),
=ijkAk.
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{Ai, Aj
}=
{irsprLs
mkxi
r
, jmnpmLn
mkxj
r },
= {irsprLs, jmnpmLn} mk{irsprLs,xjr} +mk{jmnpmLn,xi
r}.
{irsprLs, jmnpmLn} =irsjmn{prLs, pmLn},=irsjmn(pr
{Ls, pmLn
}+
{pr, pmLn
}Ls),
=irsjmn(prpm{Ls, Ln} +pr{Ls, pm}Ln+pm{pr, Ln}Ls++ {pr, pm}LnLs),=irsjmnsnoprpmLo irsjmnmstprLnpt+irsjmnrntpmLspt,=irs(joms jsom)prpmLo irs(nsjt ntjs)prLnpt++irs(jtmr jrmt)pmLspt,=irs(prpsLj
prpoLojs)
irs(prLspt
prLtptjs)+
+irs(prLspj pmLspmjr),= irsprpoLojs irsprLspt+irsprLtptjs +irsprLspj irspmLspmjr ,= irjprpoLo irsprLspt+irjprLtptirsprLspj ijspmLspm,= ijspmLspm,=
ijsp
2Ls.
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{irsprLs,
xj
r}=
{irsprLs,
xj
r},
=irs(prxj{Ls,1r} +pr{Ls, xj}1
r+xj{pr,1
r}Ls+ {pr, xj}Ls
r ),
=irspr
r{Ls, xj} +irsxj{pr,1
r}Ls+irs{pr, xj}Ls
r ,
= irsprr
jsuxu+irsxjxr
r3Ls irsrj Ls
r
{jmnpmLn,xir} =jmnpm
r invxv jmnxi xm
r3Ln+jmnmi
Ln
r .
= irsprr
jsuxu+irsxj xrr3
Ls irsrj + jmnpmr
invxv jmnxi xmr3
Ln+jmnmi
= (iujr ijru)prxur
+irsxjxrLs
r3 ijs Ls
r + (jvmi ijmv)pmxv
r jmn xixmLn
r3 +jin
Ln
r
= pjxir
+prxr
r ij+ irs
xjxrLs
r3 ijs Ls
r +
pixj
r pmxm
r ij jmn xixmLn
r3 +jin
Ln
r
= pjxir
+irsxjxrLs
r3 ijs Ls
r +
pixj
r jmn xixmLn
r3 +jin
Ln
r
=1
r(pixj pjxi) + 2ijk Lk
r +
1
r3(irsxjxrLs jmnxixmLn)
= 3ijkLk
r + 1
r3 (irsxjxrLs jmnxixmLn)= 3ijk
Lk
r +
1
r3(xjxir p xjpir2 xixjr p +xipjr2)
= 3ijkLk
r +
1
r(xjpi+xipj)
= 3ijkLk
r1
rijkLk
= 2ijkLk
r ,
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{Ai, Aj} = ijkp2Lk+ 2ijk Lkr
= 2mHijkLk.
{Li, Lj} =ijkLk{Li, H} = 0{Li, Aj} =ijkAk{Ai, H} = 0{Ai, Aj} = 2mHijkLk
E =|E|
Ai=
Ai2m|E| .
{Li, Lj} =ijkLk {Li, H} = 0 {Li, Aj} =ijk Ak {Ai, H} = 0 {Ai, Aj} =ijkLk {H, H} = 0
Li Ai
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Mi=1
2(Li+ Ai) Ni=
1
2(Li
Ai),
{Mi, Mj} = {12
(Li+ Ai),1
2(Lj+ Aj)}
=1
4{Li, Lj} +1
4{Li, Aj} +1
4{Ai, Lj} +1
4{Ai, Aj}
=1
4ijkLk+
1
4ijk Ak+
1
4ijk Ak
1
4+ijkLk =
1
2ijkLk+
1
2ijk Ak=ijkMk
{Ni, Nj
}=
{
1
2(Li
Ai),
1
2(Lj
Aj)
}=
1
4{Li, Lj} 1
4{Li, Aj} 1
4{Ai, Lj} +1
4{Ai, Aj}
=1
4ijkLk 1
4ijk Ak 1
4ijk Ak
1
4+ijkLk =
1
2ijkLk 1
2ijk Ak =ijkNk
{Mi, Nj} = {12
(Li+ Ai),1
2(Lj Aj)}
=1
4{Li, Lj} +1
4{Li, Aj} 1
4{Ai, Lj} 1
4{Ai, Aj}
=14
ijkLk+14
ijk Ak 14
ijk Ak 14 ijkLk= 0.
{Mi, Mj} = ijkMk {Ni, Nj} = ijkNk {Mi, Nj} = 0,
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| M|2 = MiMi |N|2 = NiNi
Mi Ni
| M|2 = | N|2
| M|2 | N|2 =14|(Li+ Ai)|2 1
4|(Li Ai)|2
=14
(Li|2 + Ai2 + 2 L| A|2) (Li|2 + Ai2 2L| A|2)
= L A= p L L mkr
r L= 0
| M|2 + | N|2
| M|2 + | N|2 =14|(Li+ Ai)|2 +1
4|(Li Ai)|2
=1
4(Li|2 + Ai2 + 2 L|A|2) + (Li|2 + Ai2 2L|A|2)
=1
2(L2 +
A2) =
mk2
4|E| .
|M
|2
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xixi pipi {, } 1i
[, ]
[xi,pj] =iij.
H=|p2|
2m+V(r).
H =H
Li = ijk xj pk.
Li =Li
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A = (p
L
mk
r
r
) = (p
L)
(mk
r
r
) = (ijkpjLk)
(mk
r
r
) =ijkLkpj
mkr
r A = A
A=1
2(p L L p) mk r
r
[H, Ai] = 0,
[H, Li] = 0.
[Ai, Aj] = 2imijkHLk [Ai, Lj] = iijkAk
[Li, Lj] = iijkLk.
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|E|
Ai= Ai2m|E|
[Ai, Aj] = iijk Ak Ai, Lj
= iijk Ak
[Li, Lj] = iijkLk.
Mi=1
2
Li+ Ai
Ni =
1
2
Li Ai
.
[Mi, Mj] = iijkMk
[Ni, Nj] = iijkNk
[Mi, Nj] = 0
[Mi, H] = 0
[Ni, H] = 0.
| M|2
| N|2
j(j+ 1)2
q(q+ 1)2
j, q= 0, 1
2, 1, . . .
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|M
|2
|N
|2 =LiAi= 0
| M|2 = | N|2
| M|2 + | N|2
| = 2j(j+ 1)2|.
|L|2
2
2 mk
2
4|E| .
Ej = mk2
22(2j+ 1)2, j = 0,
1
2, 1, . . .
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R
3 3
RTR= I33
A
R3
A(x,y,z) = (x, y cos zsen, y sen+zcos ).
u R3
u
= [r1, r2,...,rn] K K
= [r1, r2,...,rn] K u K
u= 1u1 + 2u2 + ... + nun
[1, 2,...,n]
u
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[u] =
1
2
n
.
[u] =
x
y
z
.
[u] =X
m n
T :Rm Rn
T :K K
= [u1, u2,...,un] K = [w1, w2,...,wn]
K
A(v1),...,A(vn) K
A(v1) =11w1+...+m1wm
A(vn) =1nw1+...+mnwm
[A]
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A
[A] =
11 . . . 1n
21 . . . 2n
n1 . . . nn
.
ij A
[A] =
11 12 13
21 22 23
31 32 33
.
A(u) =
11 12 13
21 22 23
31 32 33
x
y
z
A(u) = (11x +12y+13z, 21x+22y+23z, 31x+32y+33z)
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x = 11x+12y+13z
y cos zsen = 21x+22y+23zy sen +zcos = 31x+32y+33z.
11= 1, 22=33 = cos 23 = 32 = sen,
A(x,y,z) =
1 0 0
0 cos sen0 sen cos
A(x,y,z) = (x, yz)
(x , y , z )
(x, y, z)
[u] =
x
y
z
.
x
y
z
=
1 0 0
0 cos sen0 sen cos
x
y
z
,
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yz
R =
1 0 0
0 cos sen0 sen cos
.
xz
R3
B(x,y,z) = (x cos +zsen,y,x sen+zcos )
R3
R3
= [r1, r2,...,rn]
= [r1, r2,...,rn]
u= 1u1 + 2u2 + ... + nun [1, 2,...,n]
[u] =
1
2
n
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[u] =
x
y
z
[u] =X
T :Rm Rn
T : K
K
= [u1, u2,...,un] = [w1, w2,...,wn]
A(v1),...,A(vn)
B(v1) =11w1+...+m1wm
B(vn) =1nw1+...+mnwm
[B]
[B] =
11 . . . 1n
21 . . . 2n
n1 . . . nn
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ij
[B] =
11 12 13
21 22 23
31 32 33
B(x,y,z) = (x cos +zsen,y,
x sen+zcos )
B(u) =
11 12 13
21 22 23
31 32 33
x
y
z
B(u) = (11x+12y+13z, 21x+22y+23z, 31x+32y+33z)
(x cos +zsen,y,x sen+zcos ) = (11x+12y+13z, 21x+22y+23z, 31x+32y+33z)
x cos +zsen=
11x+
12y+
13z
y = 21x+22y+23z
x sen+zcos = 31x+32y+33z
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11 = 33= cos , 22 = 1 13 = 31= sen
B(x , y , z ) =
cos 0 sen
0 1 0
sen 0 cos
B(x,y,z) = (x, yz)
[u] =
x
y
z
x
y
z
=
cos 0 sen
0 1 0
sen 0 cos
x
y
z
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R =
cos 0 sen
0 1 0
sen 0 cos
R3
C(x,y,z) = (x cos y sen, x sen+y cos , z)
R3
R3
= [r1, r2,...,rn]
= [r1, r2,...,rn] u= 1u1 + 2u2 + ... + nun [1, 2,...,n]
[u] =
1
2
n
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[u] =
x
y
z
[u] =X
T :Rm Rn
T : K
K
= [u1, u2,...,un] = [w1, w2,...,wn]
A(v1),...,A(vn)
B(v1) =11w1+...+m1wm
C(vn) =1nw1+...+mnwm
[C]
[C]=
11 . . . 1n
21 . . . 2n
n1 . . . nn
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ij
[C]=
11 12 13
21 22 23
31 32 33
C(x,y,z) = (x cos
y sen, x sen+y cos , z)
C(u) =
11 12 13
21 22 23
31 32 33
x
y
z
C(u) = (11x +12y+13z, 21x+22y+23z, 31x+32y+33z)
(x cos y sen, x sen+y cos , z) = (11x+12y+13z, 21x+22y+23z, 31x+32y+33z)
x cos
y sen=
11x +
12y+
13z
x sen+y cos =21x+22y+23z
z= 31x+32y+33z
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7/24/2019 O espectro de energia do timo de Hidrognio
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11 = 22 = cos , 12 = 21= sen 33 = 1
C(x,y,z) =
cos sen 0sen cos 0
0 0 1
C(x,y,z) = (x, yz)
[u] =
x
y
z
x
y
z
=
cos sen 0sen cos 0
0 0 1
x
y
z
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R=
cos
sen 0
sen cos 0
0 0 1
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2
v =d(rr)
dt =
dr
dtr+r
dr
dt = rr+r
dr
d
d
dt = rr+r
d
dt.
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E=1
2
(rr)2 +
r
d
dt
2 Gm1m2
r .
L= r p= r v tangencial =rr ddt
=r2d
dt
E=1
2r2 +
L2
2r2Gm1m2
r .
r
dr
dt =
2
E L
2
2r2+
Gm1m2
r
1/2.
r()
ddtdrdt
=L2
r2
2
E L2
2r2 +
Gm1m2
r1/2 .
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7/24/2019 O espectro de energia do timo de Hidrognio
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d=L2
r2Er2 L2
2r2+ Gm1m2
r
1/2
1
2r2
1/2
dt= L
2 1
r2
E L2
2r2 + Gm1
m2
r dr
u= 1r
du= 1r2
d =
L
2 1
E L2u2
2
+Gm1m2u du
d= du
2EL2 u2 + 2 Gm1m2
L2 u
1/2.
r0= L2
Gm1m2
d = du2E
L2u2+2ur0
1/2 = du
2E
L2u2+ 2u
r0+ 1r20
1r20
1/2 = du
2E
L2+ 1
r20
u 1
r0
2
1/2
=
r0du
r0
2EL2
+ 1r20
u 1r0
21/2 =
r0du2Er
20
L2 +1(ur01)2
1/2 .
2 = 1 +
2Er20
L2
d= r0du
(2
(ur0 1)2
)1/2
.
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r0u= 1
cos
r0du=
sen
d= sen
(2 ( cos )2)1/2 = sen
(1 cos2 ))1/2 =d.
=
r0u= 1
cos
r0u= 1 cos( ) = 1 cos 1u
= r0
1 cos .
r= 1
u
r= r0
1 cos .
L= (Gm1m2r0)1/2
E= Gm1m2
2r0(2 1).
r= r0
1 cos =r0+r cos
r2 =x2 +y2
x= r cos
y= r sen
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x2 +y2 = (r0+x) =r20+ 2r0x+
2x2.
Ax2 +Bxy+C y2 +Dx+Ey+F = 0.
B2 4AC < 0
B2 4AC = 0
B2 4AC >0
= 0
r= r0 x2 +y2 =r20
0< 0
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= 1
x2 +y2 =r20+ 2r0x +2x2
y2
2r0x
r20 = 0
4.0.1 = 0
>1
x2 +y2 =r20+ 2r0x +2x2 (1 2)x2 +y2 2r0x r20 = 0
(1 2)
4.(1 2).1> 0
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b c= d di=
j,k=1
ijkbjck
a (b c) =ijkajkrsbrcs=ijkkrsajbrcs
ijkkrs = irjs isjr
(irjs
isjr)ajbrcs=asbics
arbrci= (ac )bi
(ab)ci
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ijklmn = 2il
ijkijk = 6
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{f, g} = fxi
g
pi f
pi
g
xi=
f
xi
g
pi+
f
pi
g
xi
= {g, f}
{f,gh} = fxi
(gh)
pi f
pi
(gh)
xi
= f
xi
g
h
pi+
g
pih
f
pi
g
h
xi+
g
xih
= f
xi
g
pi
h
f
pi
g
xi
h+gf
xi
h
pi g
f
pi
h
xi
{f,gh} =g{f, h} + {f, g}h
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{f,
{g, h
}}+
{g,
{h, f
}}+
{h,
{f, g
}}=
= f
xi
{g, h}pi
fpi
{g, h}xi
+ g
xi
{h, f}pi
gpi
{h, f}xi
+ h
xi
{f, g}pi
hpi
{f, g}xi
= f
xi
{g, h}pi
fpi
{g, h}xi
+ g
xi
{h, f}pi
gpi
{h, f}xi
+ h
xi
{f, g}pi
hpi
{f, g}xi
= f
xi
pi
g
xi
h
pi g
pi
h
xi
f
pi
xi
g
xi
h
pi g
pi
h
xi
+
g
xi
pi
h
xi
f
pi h
pi
f
xi
+
gpi
xi
h
xi
f
pi h
pi
f
xi
+
h
xi
pi
f
xi
g
pi f
pi
g
xi
h
pi
xi
f
xi
g
pi f
pi
g
xi
= 0
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7/24/2019 O espectro de energia do timo de Hidrognio
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r p
[xi, rj] =xixj xjxi= 0
[pi, pj] =pipj pjpi= 0
[xi, pj](f) = xi
if
xj
+
i
xif
xj
= i
xi
f
xj xi f
xj fxi
xj
=
= iij
[xi, pj](f) = xiif
xj
+
ix
ifxj
=
xi
if
xj
ix
ifxj
=
= [pj, xi](f)
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[Lk, xi](f) = [xipj
xjpi, xi](f) = [xipj, xi](f)
[xjpi, xi](f) =
= xi[pj , xi](f) + [xi, xi]pj(f) xj[pi, xi](f) [xj, xi]pi(f) == xi
i(xif)
xj+ixi
(f)
xj
xj
i(xf)
xi+i
(f)
xi
=
= xii
xi (f)
xj f(xi)
xj+xi
(f)
xj
xji
f(xi)
xi xi (f)
xi+xi
(f)
xi
= ixj
[Lk, pi](f) = [xipj xjpi, pi](f) = [xipj, pi](f) [xjpi, pi](f) =xi[pj , pi](f) + [xi, pi]pj(f) xj[pi, pi](f) [xj, pi]pi(f) = [xi, pi]pj(f) = i
xi
pjf
xi xipjf
xi
=
= ipj
[Lk, Li](f) = [Lk, xjpk xkpi](f) = [Lk, xjpk](f) [Lk, xkpi](f) == xj[Lk, pk] + [Lk, xj]pk xk[Lk, pj] [Lk, xk]pj = ixipk+ixkpi== ikijLj
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AiAi=
ijkpjLk mk xir
irsprLs mk xi
r
=ijkpjLkirsprLs
ijkpjLkmk
xi
rmk
xi
r
irsprLs+m2k2
ijkpjLkmk xir mk xirirsprLs= 2mkr |L|2
AiAi= | A|2 =ijkpjLkirsprLs 2mkr |L|2 +m2k2
= (jrks jskr)pjLkprLs 2mk
r |L|2 +m2k2= |p|2|L|2 (p L)2 2mk
r |L|2 +m2k2
= 2m
|p|22m
kr
|L|2 +m2k2
= 2mH|L|2 +m2k2
| A|2 2mH|L|2 =m2k2
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H= |E|
| A|2 + 2m|E||L|2 =m2k2
Ai=
Ai2m|E|
2m|E|||A|2 + 2m|E||L|2 =m2k2
|A|2 + |L|2 = mk2
2|E|
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7/24/2019 O espectro de energia do timo de Hidrognio
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A=
1
2(p L L p) mk r
r
ijk [pk, Lj ] =ijkpkLj ijkLjpk
Ai =
12(ijkpjLk ijkLjpk) mk xir
=
12(
ijkpjLk+ijk [pk, Lj] ijkpkLj) mk xir
[Lj, pk] = [pk, Lj ] = ijklpl
Ai = 1
2
(ijkpjLk
iijkjklpl
ijkpkLj)
mk
xi
r = 1
2
(2ijkpjLk
i2ilpl)
mk
xi
r =
(ijkpjLk ipi) mk xi
r
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7/24/2019 O espectro de energia do timo de Hidrognio
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AiAi= |A|2 =
(ijkpjLk ipi) mk xir
(irsprLs ipi) mk xi
r
=
= ijkpjLkirsprLs ijkpjLkipi ijkpjLkmk xir
+
ipiirsprLs+ipiipi+ipimk xir
+
mk xir
irsprLs+mkxi
ripi+m
2k2 =
= |p|2|L|2 + 2|p|2 2mkr |L|2 2mk
r
2 +m2k2
H= |p|
2
2m k
r
|A|2 = |p|2|L|2 +2|p|2 2mkr |L|2 2mk
r
2 +m2k2 = 2mH|L|2 +2|p|2 2mkr
2 +m2k2 =
= 2mH
|L
|2 + 2mH2 +m2k2 = 2mH(
|L
|2 + 2) +m2k2
|A|2 2mH(|L|2 + 2) = +m2k2
H= |E|
|A|2 + 2m|E|(|L|2 +2) = +m2k2
Ai= Ai2m|E|
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2m
|E
|
|A
|2
+ 2m
|E
|(
|L
|2 +2) = m2k2
|A|2 + (|L|2 + 2) = m2k2
2m|E|
|A|2 + |L|2 = mk2
2|E| 2
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[H, A] = [p2
2mk
r,1
2(p L L p) mk r
r] = 0
[p2
2m,1
2p L] = 1
2m
1
2ijk [p
2, pjLk] = 1
2m
2ijk([p
2, pj]Lk+ pj[p2, Lk])
p2
Lk
[p2, Lk] = 0
[p2
2m,1
2p L] = 0
[ p2
2m,1
2L p]
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p2
2m,
mk
r
r=
k
2p2,r
r =
k
2
([pj,xi
r
]pj+ pj[pj ,xi
r
]) =
k
2
([pj, xi]pi
r
+xi[pj,1
r
]pj
+pj[pj , xi]1
r+pj[pj ,
1
r]xi) = iij 1rpj+ ixixj 1r3pj ipjij 1r +ipjxj 1r3 xi
p
2
2m,mk r
r
= ipi 1
r+1
rpi
+i
xi xj
r3pj+ pj xj
r3xi
k
r
,
2
p
L =
k2 1r , p
L= ijkk2 1r , pjLk= ijk
k2 1r , pj Lk =
= ki2r3
ijkxjLk = ki2r3
x L
k
r,1
2L p
=
ki
2r3ijkxjLk =
ki
2r3L x
[H, A] = [p2
2mk
r,1
2(p L L p) mk r
r] =
k2
2r3x L k
2
2L x 1
r3
x L
L x
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x
L =ijkxjLk =ijkxjkrsxrps= (irjs
isjr)xjxrps=xjxipj
xjxjpi =
= (x (x p) r2p)
L x =ijkLjxk=ijkjrsLjxk= (kris ksir)xrpsxk== (p r2
(p
x ) x )
[H, A] =k2
2r3x L k
2
2L x 1
r3 =
k2
2r3(x (x p) r2p) k
2
2r3(p r2 (p x ) x ) = 0
[Lm, Ai] =
Lm,
(ijkpjLk ipi) mk xir
= ijk [Lm, pjLk] i[Lm, pi] mk
Lm,
xi
r
=
= pjijk [Lm, Lk] +ijk [Lm, pj]Lk i[Lm, pi] mk Lm,
xi
r = i
jnopnLoipr mk xr
r
= imirAr
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[Ja, Jb] =iabcJc
J2
J2
J2f=f Jzf= f
J=Jx iJy
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Jz
[Jz, J] = [Jz, jx]
[Jz, iJy] =iJy
i(
iJx) =
J
J2
[J2, J] = 0
J2
Jz Jf
J2(Jf) =JJ2f=Jf=(Jf)
Jz
Jz(Jf) = (LzJ JJz)f+JJzf= Jf+J(f) = (+ )(Jf)
J+
J
J+ft= 0
ft J+ft= 0 Jz j
Jzft=jft
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J2
JJ = (Jx iJy)(Jx iJy) =J2 J2z i(iJz) J2 =JJ+J2z Jz
J2ft = (JJ+J2z Jz)ft = (0 + 2j2 +2j)ft= 2j(j+ 1)ft
= 2j(j+ 1)
Jfb= 0
j
Jz
Jzfb= jfb
J2fb= (J+JJ2z Jz)fb= 2j (j 1)fb
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j (j
1) =j (j+ 1)
j =j + 1
j = j
Jzf=
mf
J2f= 2j(j+ 1)f
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