maths studies topic 4

Upload: zabbyy

Post on 02-Jun-2018

218 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/10/2019 Maths Studies topic 4

    1/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    1

    Answers

    Skills check

    a y= 2.5x2+x 1

    whenx= 3,y= 18.5

    b h= 3 2t 1 when t= 0, h= 2

    c d= 2 t3 5t1+ 2 when t=1

    2, d= -31

    4

    a x2+x 3 = 0 x= 1.30, 2.30

    b 2t2 t= 2

    2t 2 t 2 = 0 t= 0.781, 1.28

    c x 2y= 3

    3x 5y= 2 x= 19,y= 11

    a A(7, 2) B(1, 4) m = = =+

    4 2

    1 7

    6

    8

    3

    4

    b A(3, 2) B(1, 8) m = = =++

    8 2

    1 3

    10

    4

    5

    2

    Exercise 4A a B

    Mrs. Urquiza

    Mr. Genzer

    A

    MickLucyLidia

    Diana

    This is a function since each student is in only

    one mathematics class.

    b B

    Mrs. Urquiza

    Mr. Genzer

    A

    MickLucyLidiaDiana

    This is not a function since each teachers

    teaches two of the student.

    a A3

    750

    B12

    1649100

    This is a function since each element of A is

    related to one and only one element of B.

    b B121649

    100

    A3750

    This is not a function since one element of

    B(16) is not related to any element of A.

    c C49

    100

    A3750

    This is a function since each element of C is

    related to one and only one element of A.

    Mathematical models4 a i A

    1234

    B246

    This is not a function since one element of

    A(4) is not related to any element of B.

    ii A1234

    C1246

    This is not a function since one element of

    A(4) is not related to any element of C.

    iii C1246

    A1234

    This is not a function since one element of

    C(1) is not related to any element of A.

    iv B246

    C1246

    This is a function since each element of Bis related to one and only one element of C.

    v C1246

    A1234

    This is a not a function since one element

    of C(6) is not related to any element of A.

    a y= 2x b y=x

    2

    c y=x

    3 dy

    x=

    3

    2 a Function

    b Function

    c not a function since negative elements in the

    first set are not related to any element in the

    second set

    d Function

    Exercise 4B

    a i

    ii domain is the set of all real numbers

    iii yes, sincey= 0 is the image of x= 0

    x1

    2

    0 1 3.5 6

    y = 2x 1 0 2 7 12

  • 8/10/2019 Maths Studies topic 4

    2/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    2

    b i

    ii domain is the set of all real numbers

    iii no, since there is no solution to the

    equation

    0 =x 2+ 1

    c i

    ii domain is the set of all real numbers except

    x= 1

    iii no, since there is no solution to the

    equation

    0 =

    1

    1x-

    d ix 3 0

    1

    4 1 9 100

    y x x 0 1

    2 1 3 10

    ii domain is the set of all non-negative real

    numbers

    iii yes,y= 0 is the image of x= 0

    a False, there is no solution to the equation

    0 =2

    x

    b true,y=x 2 0 for all values ofx

    c true,y=x 2 + 3 3 for all values ofx

    d true,y= 3 whenx= 2

    e true,y= -33

    1 = 2

    f false, the image ofx= 1 isy= 4

    Exercise 4C

    a y y= 2x 4

    x2 04 2 4 6

    2

    46

    8

    6

    8

    4

    26

    b i (2, 0)

    ii (0, 4)

    c A (250, 490) 490 2 250 4 no

    d B (3,y) y= 2 3 4 = 10 a i {x: 4 x 6} ii {y: 4 y 1}

    iii (4, 0) iv (0, 2)

    x 3 0 2 1

    4 2 x

    y = x 2+1 10 1 5 17

    16 5 5

    x 2 1 0 1

    2 3 5

    yx

    1

    11 x 1

    2

    3

    1

    4

    1

    6

    b i {x:x} ii {y:y 8}

    iii (4, 0), (0, 0) iv (0, 0)

    c i {x: 1 x 1} ii {y: 0 y 1}

    iii (1, 0), (1, 0) iv (0, 1)

    d i {x:x 1} ii {y:y 4}

    iii no points iv (0, 8)

    a i F ii F iii T b i F ii T iii F

    c i F ii T iii F

    d i F ii F iii T

    a yy= 2x+ 3

    x2 04 2 4 6

    2

    4

    6

    8

    6

    8

    4

    26

    b y

    y= x+ 2

    x2 04 2 4 6

    2

    4

    6

    8

    6

    8

    4

    26

    c yy= 3x 4

    x2 04 2 4 6

    2

    4

    6

    8

    6

    8

    4

    26

    Exercise 4D

    f (x) =x (x 1) (x+3)

    a f (2) = 2(1) (5) = 10

    b f1

    2

    =

    =

    12

    1

    2

    7

    2

    7

    8

    c f (3) = 3(4)(0) = 0

    d f (1) = 1(2)(2) = 4

    (1, 4) lies on the graph of f

    d(t) = 5tt 2

    a t

    b d (2.5) = 5(2.5) 2.52= 6.25

    c d (1) = 51 = 4

    d d (1) = 4 d(4) = 2016 = 4 d (1) = d(4)

    C (n) = 100 10n

    a C (2) = 100 20 = 80

    b b= C (3) = 100 30 = 70

    c C (a) = 0 100 10a= 0 a= 10

    a i v (1) = 3 ii v (3) = 3

    b 3m+ 6 = 9 m= 1 c t= 2

    d v (t) < 0 for t> 2

  • 8/10/2019 Maths Studies topic 4

    3/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    3

    f (x) = 0.5 (3 x)

    a yy= 0.5(3 x)

    x2 04 2 4 6

    2

    4

    6

    8

    6

    8

    4

    26

    b (3, 0)

    c (0, 1.5)

    d 0.5 (3 x) = 2 3 x= 4 x= 1

    h (x) = 3 22x

    a i h(0) = 3 ii h(1) = 3 21= 6

    b 3 2x= 24 2x= 8 x= 3

    Exercise 4E

    a i l= 30 2x ii w= 15 2x

    b V= (30 2x)(15 2x)x

    i V (3) is the volume of the box when the

    squares cut from each corner have side

    length 3 cm.

    ii V (3) = (24) (9) (3) = 643 cm 3

    iii V (3.4) = (23.2) (8.2) 3.4 = 646.816 cm 2

    iv No,x< 7.5 since the width of the card is

    only 15 cm a width = 12 x

    b A=x(12 x)

    c i A (2) is the area of the rectangle when the

    length is 2 cm

    ii A (2) = 2(10) = 20 cm2

    d No, ifx= 12 the width would be 0.

    a C= 300 + 150n

    b C (30) = 300 + 150(30) = 4800USD c i 300 + 150n< 2300

    ii 300 + 150(14) = 2400, no

    iii 150n< 2000, n< 13.3 13 days.

    C (x) = 0.4x 2+ 1500 I(x) = 0.6x 2+ 160x

    a P(x) = I(x) C(x) = 0.6x 2+ 160x

    (0.4x 2+ 1500) = x 2+ 160x 1500

    b P(6) = 62+ 160(6) 1500 = 576 AUD, a

    loss of 576 AUD

    c i P(40) = 402+ 160(40) 1500 = 3300 AUD

    ii I(40) = 0.6(40)2+ 160(40)

    = 5540

    Assuming all books have same price, one

    book costs

    I(40) 5540

    40 40 = 136 AUD

    d 10 or 150

    Exercise 4F

    a 50 kg = 110 pounds b y

    y= 2.2x

    Kilograms (kg)

    Pounds(lb)

    x0 20 40 60 80 100

    50

    100

    150

    200

    250

    c gradient = 2.2 p (x) = 2.2x

    d p (75) = 165 p (125) = 275 e y= 2.2x x= y

    2 2. k(x) =

    x

    2 2.

    f k(75) = 34.1 k(100) = 45.5

    1 = S$2.05

    a 50 = S$102.5

    b yy= 2.05x

    GBP ()

    S

    GD

    ($)

    x0 20 40 60 80 100

    50

    100

    150

    200

    250

    c gradient = 2.05 s(x) = 2.05x

    d s (80) = 164 s (140) = 287

    e p (x) =x

    2 05. p (180) = 87.8

    1 = $1.55

    a 60 GBP = 93 USD

    b y y= 1.55x

    GBP ()

    USD($)

    x0 20 40 60 80

    20

    40

    60

    80

    100

    120

    140

    c gradient = 1.55 u (x) = 1.55x

    d u(300) = 465 u (184) = 285.2 e p(x) =

    x

    1 55.

    f p (250) = 161 p (7750) = 5000

  • 8/10/2019 Maths Studies topic 4

    4/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    4

    Exercise 4G

    a

    0 21 3 5 7 94 6 8

    10050

    150200250300

    400350

    Temperature(C)

    Time (minutes)

    b 10C c T (x) = 40x+ 10

    a

    0 20 40 60 80 100

    20

    40

    60

    80

    Lengthofspring(mm)

    Weight (g)

    b 18 mm c 20g

    d 0.5 mm e L (x) = 0.5x+ 18

    b T (x) =2

    3x+ 10

    c 66.7C

    b 20 cm

    c 20 cm

    d 350 g

    e L (x) = 0.08x+ 20

    Exercise 4H

    a Flour = 80s+ 60f

    b Fat = 50s+ 90f

    c 80s+ 60f= 820

    50s+ 90f= 880

    s= 5 f= 7 5 sponge cakes, 7 fruit cakes

    8t+ 3c= 51

    100t+ 30c= 570

    t= 3 c= 9 3 tables, 9 chairs

    3v+ 5c= 59

    7v+ 3c= 70

    v= 6.65 c= 7.81 7 vans, 8 cars

    80p+ 50t= 620

    10p+ 25t= 190

    p= 4 t= 6 4 passenger planes, 6 transport planes

    70x+ 40y= 1440

    x= 2y

    140y+ 40y= 1440

    180y= 1440

    y= 8 x= 16

    16 volume 1, 8 volume 2

    Exercise 4I

    0 1 2 3123

    24

    6

    8

    10

    12

    14

    16

    18

    (0, 1)x

    y= 2x2+1

    y

    0 2 424

    2

    4

    2

    4(0, 3)

    y= x2+ 3

    x

    y

    (3, 0)(3, 0)

    0 2 424

    20

    10

    (0, 2)

    y= 3x2 2

    x

    y

    ( ) 23 , 0( )23

    , 0

    0 21 32 13

    10

    8

    6

    4

    2

    8

    6

    4

    2

    (0, 7)

    y= 2x2+ 7

    x

    y

    ( )72 , 0( )

    72 , 0

    Exercise 4J

    (3, 2) x= 2

    (5, 4) x= 5

    (4, 1) x= 4

    (5, 7) x= 5

    (3, 4) x= 3

    Exercise 4K

    y=x(x 4)

    a x= 2 b (0, 0) (4, 0) c (2, 4)

    y=x(x+ 6)

    a x= 3 b (0, 0) (6, 0) c (3, 9)

    y= 8xx 2=x (8 x)

    a x= 4 b (0, 0) (8, 0) c (4, 16)

    y= 3xx 2=x (3 x)

    a x= 32 b (0, 0) (3, 0) c 3 9,

    2 4

  • 8/10/2019 Maths Studies topic 4

    5/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    5

    y=x22x=x (x 2)

    a x= 1 b (0, 0) (2, 0) c (1, 1)

    y=x 2 x=x (x1)

    a x= 12 b (0, 0) (1, 0) c 1 1,

    2 4

    y=x 2 + 4x=x(x+ 4)

    a x= 2 b (0, 0) (4, 0) c (2, 4)

    y=x 2 +x=x(x+ 1)

    a x= 1

    2 b (0, 0) (1, 0) c 1 1,

    2 4

    y= (x+ 1) (x 3)

    a x= 1 b (1, 0) (3, 0) c (1, 4)

    y= (x 5) (x+ 3)

    a x= 1 b (5, 0) (3, 0) c (1, 16)

    y= (x 2) (x 6)

    a x= 4 b (2, 0) (6, 0) c (4, 4)

    y= (x+ 2) (x 4) a x= 1 b (2, 0) (4, 0) c (1, 9)

    Exercise 4L

    y=x 2 2x+ 3

    a x= 1 b no points c (1, 2)

    y=x 2+ 4x 5 = (x+ 5) (x 1)

    a x= 2 b (5, 0), (1, 0) c (2, 9)

    y=x 2+ 6x+ 4

    a x= 3 b (0.764, 0), (5.24, 0)

    c (3, 5)

    y= 3x 2 6x+ 2

    a x= 1 b (0.423, 0), (1.58, 0)

    c (1, 1)

    y= 2x 2 8x 1

    a x= 2 b ( 0.121, 0), (4.12, 0) c (2, 9)

    y= 2x 2+ 6x 7

    a x= 3

    2

    b (0.898, 0), (3.90, 0) c3 23

    ,2 2

    y= 0.5x 2x+ 2

    a x= 1 b no points c 32

    1,

    y= 0.5x 2+ 3x 4

    a x= 3 b (1.12, 0), (7.12, 0) c17

    23,

    Exercise 4M

    f (x) =x 2+ 2x 3 = (x+ 3) (x 1)

    a i (0, 3)

    ii x= 1

    iii (1, 4)

    iv (3, 0), (1, 0)

    v y 4

    b

    0 21 32 135 4 2

    4

    6

    10

    8

    4

    2

    6

    (1, 4)

    y=x2+ 2x 3

    x

    y

    f (x) =x 2+ 8x+ 7 = (x+ 1) (x+ 7)

    a i (0, 7) ii x= 4

    iii (4, 9) iv (7, 0), (1, 0)

    v y 9

    b

    0 12139 8 7 6 5 42

    4

    10

    8

    6

    10

    8

    4

    2

    6

    (4, 9)

    y=x2+ 8x + 7

    x

    y

    f (x) =x 2 6x 7 = (x 7) (x+ 1)

    a i (0, 7) ii x= 3

    iii (3, 16) iv (1, 0), (7, 0)

    v y 16

    b

    04 4 8 124

    8

    16

    12

    20

    16

    8

    4

    12

    (3, 16)

    y=x2 6x 7

    x

    y

    f (x) =x 2 3x 4 = (x 4) (x+ 1)

    a i (0, 4) ii x=3

    2

    iii3

    2

    25

    4,

    iv (1, 0), (4, 0)

    v y 254

    b

    02 2 4 644

    8

    8

    12

    4

    y=x2 3x 4

    ( )32254

    ,

  • 8/10/2019 Maths Studies topic 4

    6/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    6

    f (x) =x 2 3x 10 = (x 5) (x+ 2)

    a i (0, 10) ii x=3

    2

    iii 3 49,2 4

    iv (2, 0), (5, 0)

    v y 494

    b

    02 2 4 644

    8

    12

    4

    16

    12

    8

    y=x2 3x 10

    ( )32494

    ,

    x

    y

    f (x) = 2x 2+x 3 = (2x+ 3) (x 1)

    a i (0, 3) ii x= 14

    iii 1 25,4 8

    iv3

    40,

    , (1, 0)

    v y 258

    b

    02 2 4 644

    8

    12

    4

    16

    y= 2x2+x 3

    ( )14 258, x

    y

    f (x) = 2x 2+ 5x 3 = (2x 1) (x+ 3)

    a i (0, 3) ii x= 54

    iii 5 49,4 8

    iv 12

    0,

    , (3, 0)

    v y 498

    b

    02 2 448

    8

    4

    8

    12

    4

    16y= 2x2+ 5x 3

    ( )54498

    ,

    x

    y

    f (x) = 3x 2x 4 = (3x 4) (x+ 1)

    a i (0, 4) ii x= 16

    iii1

    6,

    49

    12

    iv 3

    40,

    , (1, 0)

    v y 4912

    b

    02 2 44

    10

    20

    10

    y= 3x2x 4

    ( )1

    6

    49

    12,

    x

    y

    Exercise 4N

    02 2

    (1,3)

    (3,0)(1,0)

    44

    2

    4

    4

    2

    x

    x= 1

    y

    02 2

    (1,2)

    44

    4

    8

    12

    4

    x

    y

    x= 1

    02 2 44

    4

    8

    4

    x

    y

    (0,1)

    x= 0

    02 2 4 x

    y

    2

    4

    2

    (1.5,1)(3,0)(0,0)

    x= 1.5

    0

    (2,2)

    (4,2)(0,2)2 2 4 x

    y

    4

    8

    12

    4x= 2

  • 8/10/2019 Maths Studies topic 4

    7/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    7

    0 x

    y

    2 4 6 8

    4

    6

    8

    2

    (5,0)(2,0)

    (0,4)

    x= 3.5

    Exercise 4O

    f (x) =x 2+ 3x 5 =g (x)x 2

    a (3, 5), (1, 1)

    b x 2+ 3x 5 =x 2

    x 2+ 2x 3 = 0

    (x+ 3) (x 1) = 0

    x= 3 or 1 (Same as part a)

    c h(x) = 2x 3 x 2+ 3x 5 = 2x 3

    x 2+x 2 = 0

    (x+ 2) (x 1) = 0

    x= 2 or 1

    (2, 7), (1, 1)

    f (x) =x 2+ 3x 5 5 x 2

    a x+y+ 5 = 0

    y= 5 x

    x 2+ 3x 5 = 5 x

    x2

    + 4x= 0 x(x+ 4) = 0

    x= 0 or 4 (0, 5) (4, 1)

    a f (x) = 5 + 3xx 2 g(x) = 1

    5 + 3xx 2= 1

    x 2 3x 4 = 0

    (x 4)(x+ 1) = 0

    x= 4 or 1 (4, 1), (1, 1)

    b f (x) = 5 + 3xx 2 h(x) = 2x+ 3

    5 + 3xx 2= 2x+ 3

    x 2x 2 = 0

    (x 2)(x+ 1) = 0

    x= 2 or 1 (2, 7), (1, 1)

    b f: range = {y: 3.125 y 18}

    g: range = {y: 2 y 4}

    c x= 1 or 2

    e f (x) = h(x)

    2x 2x 3 = 2x+ 2

    2x 2 3x 5 = 0

    (2x 5)(x+ 1) = 0

    x= 52or 1

    f (2, 7), (2, 3)

    a (2.12, 1.5), (2.12, 1.5)

    f (x)

  • 8/10/2019 Maths Studies topic 4

    8/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    8

    f (x) = ax 2+ bx+ 2

    b

    a2= 1 b= 2a

    (1, 5) 5 = a b+ 2

    a b= 3

    a= 3

    a= 3 b= 6 f (x) = 3x 2 6x+ 2

    g(x) = ax 2+ bx 3

    ba2

    = 2 b= 4a

    (2, 5) 5 = 4a 2b 3

    2a b= 4

    2a= 4

    a= 2 b= 8 g(x) = 2x 2 8x 3

    f (x) = ax2+ bx

    b

    a2=

    12

    b= a

    1 1 1 1 1,2 2 2 4 2

    a b

    2 = a 2b

    2 = a

    a= 2 b= 2 f (x) = 2x 2+ 2x

    g(x) = ax 2+ bx+ 3

    b

    a2= 0 b= 0

    (1, 2) 2 = a+ 3

    a= 1 g(x) = x 2+ 3

    Exercise 4Q

    a 2l+ 2w= 170

    l+ w= 85

    l= 85 w

    A= lw= w(85 w)

    A= w(85 w)

    For maximum area, w= 42.5, l= 42.5

    length = 42.5 m, width = 42.5 m

    b 2l+ w+ (w 15) = 110 2l+ 2w= 125

    l= 62.5 w

    A= w(62.5 w)

    For maximum area, w= 31.25, l= 31.25

    length = 31.25 m, width = 31.25 m

    p (u) = 0.032u 2+ 46u 3000

    a 13531.25 riyals

    b 3000 riyals

    c 69 units

    H (t) = 37t t2

    a 270 m

    b 342.25 m

    c 37 s

    Exercise 4R

    For all questions:yintercept is (0, 1), horizontal

    asymptote isy= 0

    Exercise 4S

    f (x) = 2x a (0, 1) b y= 0

    0 x

    y

    y =2x

    1 1 322

    8

    2

    4

    6

    f (x) = 6x a (0, 1) b y= 0

    0 x

    y

    y =6x

    1 1 22

    10

    20

    30

    f (x) =1

    3

    x

    a (0, 1) b y= 0

    0 x

    y

    1 1 22

    8

    2

    4

    6

    y = ( )x13

    f (x) = 15

    x

    a (0, 1) b y= 0

    0 x

    y

    1 1 22

    20

    5

    10

    15

    y = ( )x15

  • 8/10/2019 Maths Studies topic 4

    9/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    9

    f (x) = 3(2)x+ 4 a (0, 7) b y= 4

    0 x

    y

    1 1 2 323

    20

    5

    15

    25

    10

    y =3(2)x+ 4

    f (x) = 2(4)x 1 a (0, 3) b y= 1

    0 x

    y

    2 211

    10

    30

    20

    y =2(4)x 1

    f (x) = 1(2)x

    + 3 a (0, 2) b y= 3

    0 x

    y

    2 2

    2

    4

    2y =1(2)x+ 3

    f (x) = 4(3)x 2 a (0, 2) b y= 2

    0 x

    y

    23 21 31

    30

    10

    20

    y =4(3)x 2

    f (x) = 0.5(2)x+ 3 a (0, 3.5) b y= 3

    0 x

    y

    1 1 2 3 423

    8

    2

    6

    10

    4y =0.5(2)x+ 3

    f (x) = 2(0.5)x+ 1 a (0, 3) b y= 1

    0 x

    y

    1 1 2 323

    15

    3

    12

    18

    69

    y = 2(0.5)x+ 1

    f (x) = 0.4x+ 1 a (0, 2) b y= 1

    y =0.4x+ 1

    0 x

    y

    1 1 223

    15

    3

    12

    18

    6

    9

    f (x) = 2(0.1)x 1 a (0, 1) b y= 1

    0 x

    y

    1 1 2 323

    40

    10

    30

    60

    50

    20

    y =2(0.1)x 1

    Exercise 4T

    f (x) = 4(2)x+ 2 a (0, 6) b y= 2

    0 x

    y

    1 1 223

    15

    3

    12

    18

    6

    9y =4(2)x+ 2

    f (x) = 4x+ 1 a (0, 0) b y= 1

    0 x

    y

    2123 1

    15

    12

    3

    3

    9

    6y =4x+ 1

    f (x) = 2(2)x+ 3 a (0, 1) b y= 3

    0 x

    y

    2123 1

    12

    3

    3

    9

    6

    y =2(2)x

    + 3

    f (x) = 3(2)x 2 a (0, 1) b y= 2

    0 x

    y

    2 1 21 3 4

    2

    1

    3

    4

    2

    1

    3

    y =3(2)x 2

  • 8/10/2019 Maths Studies topic 4

    10/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    10

    f (x) = 0.5(3)x+ 2 a (0, 2.5) b y= 2

    0 x

    y

    23 1 21 3 44

    8

    10

    12

    14

    4

    2

    6

    y =0.5(3)x+ 2

    f (x) = 0.5x+ 1 a (0, 2) b y= 1

    0 x

    y

    2 2 44

    4

    6

    8

    2

    y =0.5x+ 1

    f (x) = 2(0.1)x 1 a (0, 1) b y= 1

    0 x

    y

    2 2 44

    8

    12

    16

    4

    4

    y =2(0.1)x 1

    f (x) = 0.4x+ 2 a (0, 3) b y= 2

    0 x

    y

    2 2 44

    8

    12

    16

    4y =0.4x+ 2

    f (x) = 3(0.2)x+ 4 a (0, 7) b y= 4

    0 x

    y

    23 1 214

    812

    16

    20

    24

    28

    32

    4

    y = 3(0.2)x+ 4

    f (x) = 5(3)x 2 a (0, 3) b y= 2

    0 x

    y

    23 1 21 3 44

    8

    12

    16

    20

    4

    4

    8

    y = 5(3)x 2

    Exercise 4U

    0 x

    y

    2 2 44

    2

    4

    6

    8

    g(x)= 2x+ 0.5

    f(x)= 2x+ 0.5

    a (0, 1.5)

    b y= 0.5

    v(t) = 26000x t

    a 26000 euros

    b 26000x= 22100 x= 0.85

    c v (t) = 26000 (0.85)t

    v (9) = 6022.04 v(10) = 5118.73 10 years

    M(t) = 150(0.9)

    t

    a

    0

    M(t)

    t4020 60 80 100

    40

    80

    120

    160

    M(t)= 150(0.9)t

    b M = 0

    c M(20)= 18.2g

    d M(6) = 79.7 M(7) = 71.7 7 years

    A (t) = 50(1.06)t

    a

    A(t)= 50(1.06)t

    0

    A(t)

    t44 8 16 2012

    40

    80

    120

    160

    b days before 1st June.

    c A (14)= 113 m2

    d A (8) = 79.7 A (9) = 84.5 t= 8

  • 8/10/2019 Maths Studies topic 4

    11/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    11

    k+ c = 5 and 0 = 2k+ c, so c= 10 k= 5

    T (t) = 18 + 60(2)t

    a

    T(t)= 18 + 60(2)t

    0

    T(t)

    t4 8 10

    20

    40

    60

    80

    b 78C

    c T (5)= 19.875C

    d T (1.4) = 40.7 T (1.5) = 39.2 1.5 minutes

    e 18C As tincreases Tgets closer to 18C

    (T= 18 is an asymptote). D (t) = 18000 (0.9)t

    a 18000 USD

    b D (5) = 10628.82 USD

    c D (6) = 9565.94 D (7) = 8609.34 7 years

    f (x) =2x

    a (0, 6) (2, 0.8)

    b=1a 0.8 =

    4a a= 5 b= 0.2

    y= 2x+ 3 A (0, a) B (1, b)

    a a= 20+ 3 a= 4

    b= 21+ 3 b= 5

    b y= 3

    a a= 1.667 b= 19

    b

    0 x

    f(x)

    2 2

    4

    8

    12

    16

    f(x)= 2(3)x

    + 1

    c range = {y:y> 1} (orf (x) > 1)

    Exercise 4V

    a f (x) = 0.0015x4+ 0.056x3 0.60x 2+ 1.65x+ 4

    b 8.77 hours

    c 1.80 hours, 17.4 hours

    a 6

    b (x 2)4+ 6 = 6

    (x 2)4= 0

    x= 2

    c f (x) 6

    Exercise 4W

    b 28.9C

    c 50 = 21 +79

    x

    29 =79

    x x= 2.72 minutes

    d x= 0

    e y= 21

    f 21C

    f (x) = 100 100

    x

    b 90C

    c 100 100

    x = 30

    100

    x = 70 x= 1.43 minutesd 100C

    b 8 = 25

    x x 2=

    5

    8 x= 0.791

    c x= 0,y= 0

    d f(x) > 0

    b 3.75

    c 5 = 3 +6

    x

    6

    x= 2 x= 3

    d x= 0,y= 3

    e range is all real numbers except 3

    {y:x,y 3}

    Exercise 4X

    b minimum value = 17.5 (whenx= 1.71)

    c 75.3 ms1

    d 50 =20

    x+2x2

    2x 3 50x+ 20 = 0

    x= 0.403s, 4.79s

    a v=x (2x)y= 2x 2y

    b y= 2 2300 50

    2x x

    A= 2x 2+xy+xy+2xy+ 2xy

    A= 2x 2+ 6xy

    A= 2x 2+ 6x1

    = +

    50 9002

    22x x

    x

    d For minimum area,x= 6.0822,y=2

    50

    6.0822

    = 4.0548length = 6.08 cm, breadth = 12.2 cm,

    height = 4.05 cm

  • 8/10/2019 Maths Studies topic 4

    12/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    12

    a v x h= 13

    2

    b

    hl

    x

    2

    l 2= h 2+2 2

    2

    2 2

    x xhl

    c A=x 2+4

    2

    xl=x 2+ 2xl= x x h x2

    22 2

    2

    + +

    d 1500 =2

    3

    x h h= 2

    4500

    x

    l=2 2

    4

    4500

    4

    x

    x A=x 2+ 2x

    2 2

    4

    4500

    4

    x

    x

    f For minimum area,x= 14.7084, h=2

    4500

    14.7084

    = 20.8009

    side length = 14.7 m, height = 20.8 m

    Let width =x, length = 2x, height = h

    320 = 12x+ 4h

    h= 80 3x

    viewing area = 2xh+ 2xh+xh

    = 5xh

    A= 5x(80 3x)

    maximum viewing area = 2666.67

    = 2670 cm 2

    Exercise 4Y

    f(x) = 1 +2

    x,x 0

    a {x:x,x 0}

    b x 10 5 4 2 1 0.5 0.2 0

    f (x) 0.8 0.6 0.5 0 1 3 9

    x 0.2 0.5 1 2 4 5 10

    f (x) 11 5 3 2 1.5 1.4 1.2

    c

    0 x

    y

    4 26 42 6 8 10810

    2

    4

    6

    810

    8

    10

    6

    4

    2

    y = 1 +2x

    d x= 0

    e y= 1

    f(x) = 8x 1+ 3,x 0

    a {x:x,x 0}

    x 10 8 5 4 2 1 0

    f (x) 2.2 2 1.4 1 1 5 0

    b x 1 2 4 5 8 10

    f (x) 11 7 5 4.6 4 3.8

    c

    0 x

    y

    4 26 42 6 8 10810

    2

    4

    6

    8

    10

    8

    10

    6

    4

    2

    y = + 38x

    d x= 0

    e y= 3

    Exercise 4Z

    Sketch graphs

    Range :y 1.81

    y

    y

    y 1.25

    y< 0 or y 2.98

    Exercise 4AA

    a

    0 x

    y

    4 26 42 6 88

    2

    2

    4

    6

    8 y =x2

    y = 4 1x)(

    b (0.254, 0.0646), (1.86, 3.46), (2.11, 4.47)

    a, c

    0 x

    y

    4 26 42 6 88

    2

    2

    4

    6

    8

    6

    4

    g(x)= 3x

    f(x)= 1 +4x

    b y= 1,x= 0

  • 8/10/2019 Maths Studies topic 4

    13/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    13

    d 1 +4

    x= 3x x= 1 or 1.33

    e {y:y,y 1}

    a (0.366, 0.669), (0.633, 2.01)

    b y= 0

    a

    0 x

    y

    2 13 21 3 44

    1

    1

    2

    3

    4

    3

    4

    2

    g(x)=x3

    f(x)=3x

    b3

    xx 3= 0

    3

    x=x 3 2 solutions

    c 1.32 or 1.32

    0 x

    y

    2 1 21 3

    2

    2

    4

    6

    8

    6

    4

    y =x3 3x2+ 2x

    y = 3x 4

    (1.11, 7.34), (1.25, 0.238), (2.86, 4.58)

    0 x

    y

    2 13 21 3 44

    2

    2

    4

    6

    8

    6

    8

    4

    y =x3+x2 6x

    y = 2x

    (2.99, 0.126), (0.147, 0.903), (2.41, 5.31)

    0 x

    y

    2 13 21 3 44

    1

    1

    2

    3

    4

    3

    4

    2

    y =x+ 2

    y =5x

    a x= 1.45 or 3.45b y= 0

    c x= 0

    Exercise 4AB

    a time in hours, water consumption in litres

    b 0700 2000

    c 0700 1200, 1400 1600

    d 1200 1400, 1600 2000

    e 1200 (local maximum at 1600)

    f 0700, 2000 (local minimum at 1400)

    a time in minutes, temperature in C

    b 100C

    c 35C

    d1

    2minute

    e no

    f approximately 22C

    at 0 5 10 15 20

    N 1 2 4 8 16

    b 13s

    c 2(60 5)= 212= 4096

    a 45 m

    b 1.5 s and 5.5 s

    c 0 3.5 s

    d 3.5 s 7 s

    e 90 m, 3.5 s

    f ball returns to ground level

    a i 3.8 m ii 2.2 m iii 0200 and 0600b 2 < t< 6

    a twice

    b 0400 0900

    c 1600

    d 5C

    e 1100 1600

    f 1300 and 1930

    g no, the temperature at the start of the

    following day is 1C whereas it was 3C at the

    start of this day.

    a x 2y= 16 y x=16

    2

    b x 0.5 1 2 4 8 10

    y = f (x) 64 16 4 1 0.25 0.16

    c

    0 x

    y

    1 2 3 4 5 6 7 8 9

    40

    10

    30

    60

    50

    20y =

    16

    x2

    d tends to zero

  • 8/10/2019 Maths Studies topic 4

    14/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    14

    a 3000 cm3

    b x 2y= 3000 yx

    = 30002

    c A=x 2+ 4xy=x 2+ 4x2

    3000

    x

    212000

    xA x

    d

    x(m) 5 10 15 20 25 30 35

    A(x)(cm2)

    (2sf )2400 1300 1000 1000 1100 1300 1600

    e

    0 x

    A

    5 10 15 20 25 30 35

    2000

    500

    1500

    1000

    A=x2+12000

    x

    f x= 18.2

    Review exercisePaper 1 style questions

    a 0000 0600

    b 1130 1700

    c 13 C

    c= nr+s

    a 35000 = 6r+s

    116000 = 24r+s

    18r= 81000

    r= 4500 SGDb 35000 = 6 4500 +s

    s= 8000 SGD

    a x 2+ 5x=x(x+ 5)

    b

    0

    (0, 0)(5, 0)

    (2.5, 6.25)

    x= 2.5

    y=x2+ 5x

    x

    y

    2 13 216 5 4

    2

    8

    10

    6

    4

    2

    h(t) = 30t 5t2 0 t 6

    a h(4) = 40 m

    b 45 m

    c from t= 1 to t= 5, 4 s

    a f (x) =2x

    m

    (3, 1.6) 1.6 = 23

    m m=

    8

    1.6= 5

    b f (x) =2

    5

    x

    (0, n) n= 15

    f(2) =2

    5

    2

    = 45

    a x 2 2x 15 = (x 5)(x+ 3)

    b i At A,x= 3 A = (3, 0)

    ii At B,x= 1 B = (1, 16)

    a ii

    b i

    c iii

    d iv a i A (1.68, 1.19)

    ii B (2.41, 1.81)

    b f (x)

  • 8/10/2019 Maths Studies topic 4

    15/16

    Worked solutions: Chapter 4 Oxford University Press 2012: this may be reproduced for class use solely for the purchasers institute

    WORKED SOLUTIONS

    15

    b y= 0,x= 0

    c

    0 x

    y

    2 13 21 3 44

    2

    2

    4

    6

    8

    6

    8

    4

    g(x)= 2x

    d x= 1.41

    e {y:y,y 0}

    f (x) = 2(1.5)x+ 3

    a a= 4.33 b= 7.5

    b

    0 x

    y

    2 13 21 3

    1

    1

    2

    3

    4

    5

    7

    6

    2

    f(x)= 2(1.5)x+ 3

    c f (x) > 3

    d x= 3.09

    e y= 3

    f (t) = 21 + 77(0.8)t

    a f (0) = 21 + 77 = 98C

    b y= 21

    c 21C

    d f (8) = 33.9C

    a

    0 x

    y

    4 26 42 6 8 10810

    2

    2

    4

    6

    8

    6

    8

    4

    f(x)=x2x 6

    g(x)= 1 2x

    b (0.5, 6.25)

    c 2

    d (0, 1)

    e (2.19, 3.39),

    (3.19, 7.39)

    f x= 2.19, 3.19

    a

    0 x

    y

    2 13 21 3 44

    2

    2

    4

    6

    8

    10

    6

    4

    f(x)=x2

    3x

    b x= 0

    c

    0 x

    y

    2 13 21 3 44

    2

    2

    4

    6

    8

    10

    6

    4 y = 3(2)x+ 9

    d y= 9

    e (2.73, 8.55), (0.454, 6.81), (1.53, 0.362)

    P =2

    10

    x+ 10x 60

    a x 0 10 20 30 40 50 60 70 80 90

    P 60 30 100 150 180 190 180 150 100 30

    b

    0x

    y

    20 40 60 80

    50

    50

    100

    150

    200

    P = + 10x 60x2

    10

    c i 190 euros ii 50 iii 33 or 67

    iv 60 euros

    a

    0 x

    y

    2 134 21

    (2.65, 0) (2.65, 0)

    (0, 7)

    3 4

    2

    2

    4

    68

    6

    8

    4

    y =x2 7

    (0, 7), (2.65, 0), (2.65, 0)

  • 8/10/2019 Maths Studies topic 4

    16/16

    WORKED SOLUTIONS

    b

    0 x

    y

    2 134 21

    (2.65, 0) (2.65, 0)

    3 4

    2

    2

    4

    6

    8

    6

    8

    4

    (0, 7)

    y = 7 x2

    c x= 2.65

    d c= 1, 2, 3, 4, 5, 6

    a2 2

    2 2

    x x +2x

    x2 2x= 0

    x(x 2) = 0

    x= 0 or 2 (0, 0), (2, 2)

    b x=

    =b

    a2

    2

    1= 2 x= 2

    c k= 2

    d

    0(0, 0)(4, 0)

    x

    y

    2 13 21 3 4 5

    1

    1

    2

    3

    4

    3

    4

    2

    f(x)=x2

    2

    g(x)= + 2xx2

    2

    e f(x)