linear equations ax + by = c. identifying a linear equation ax + by = c ● the exponent of each...
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Linear Equations
Ax + By = C
Identifying a Linear EquationAx + By = C
● The exponent of each variable is 1. ● The variables are added or subtracted.● A or B can equal zero.● A > 0● Besides x and y, other commonly used variables
are m and n, a and b, and r and s.● There are no radicals in the equation.● Every linear equation graphs as a line.
Examples of linear equations 2x + 4y =8
6y = 3 – x
x = 1
-2a + b = 5 4
73
x y
Equation is in Ax + By =C form
Rewrite with both variables on left side … x + 6y =3
B =0 … x + 0 y =1
Multiply both sides of the equation by -1 … 2a – b = -5
Multiply both sides of the equation by 3 … 4x –y =-21
Examples of Nonlinear Equations
4x2 + y = 5
xy + x = 5
s/r + r = 3
The exponent is 2
There is a radical in the equation
Variables are multiplied
Variables are divided
4x
The following equations are NOT in the standard form of Ax + By =C:
x and y -intercepts
● The x-intercept is the point where a line crosses the x-axis.The general form of the x-intercept is (x, 0).
The y-coordinate will always be zero.
● The y-intercept is the point where a line crosses the y-axis.The general form of the y-intercept is (0, y).
The x-coordinate will always be zero.
Finding the x-intercept
● For the equation 2x + y = 6, we know that y must equal 0. What must x equal?
● Plug in 0 for y and simplify.
2x + 0 = 6
2x = 6
x = 3● So (3, 0) is the x-intercept of the line.
Finding the y-intercept
● For the equation 2x + y = 6, we know that x must equal 0. What must y equal?
● Plug in 0 for x and simplify.
2(0) + y = 6 0 + y = 6 y = 6● So (0, 6) is the y-intercept of the line.
To summarize….
● To find the x-intercept, plug in 0 for y.
● To find the y-intercept, plug in 0 for x.
Find the x and y- interceptsof x = 4y – 5
● x-intercept:● Plug in y = 0
x = 4y - 5
x = 4(0) - 5
x = 0 - 5
x = -5● (-5, 0) is the
x-intercept
● y-intercept:● Plug in x = 0
x = 4y - 5
0 = 4y - 5
5 = 4y
= y
● (0, ) is the
y-intercept
5
4
5
4
Find the x and y-interceptsof g(x) = -3x – 1*
● x-intercept● Plug in y = 0
g(x) = -3x - 1
0 = -3x - 1
1 = -3x
= x● ( , 0) is the
x-intercept
● y-intercept● Plug in x = 0
g(x) = -3(0) - 1
g(x) = 0 - 1
g(x) = -1● (0, -1) is the
y-intercept
*g(x) is the same as y
1
3
1
3
Find the x and y-intercepts of 6x - 3y =-18
● x-intercept● Plug in y = 0
6x - 3y = -18
6x -3(0) = -18
6x - 0 = -18
6x = -18
x = -3● (-3, 0) is the
x-intercept
● y-intercept● Plug in x = 0
6x -3y = -18
6(0) -3y = -18
0 - 3y = -18
-3y = -18
y = 6● (0, 6) is the
y-intercept
Find the x and y-intercepts of x = 3
● y-intercept
● A vertical line never crosses the y-axis.
● There is no y-intercept.
● x-intercept
● Plug in y = 0.
There is no y. Why?
● x = 3 is a vertical line so x always equals 3.
● (3, 0) is the x-intercept.x
y
Find the x and y-intercepts of y = -2
● x-intercept
● Plug in y = 0.
y cannot = 0 because
y = -2.● y = -2 is a horizontal
line so it never crosses
the x-axis.
●There is no x-intercept.
● y-intercept
● y = -2 is a horizontal line
so y always equals -2.
● (0,-2) is the y-intercept.
x
y
Graphing Equations● Example: Graph the equation -5x + y = 2
Solve for y first.-5x + y = 2 Add 5x to both sides y = 5x + 2
● The equation y = 5x + 2 is in slope-intercept form, y = mx+b. The y-intercept is 2 and the slope is 5. Graph the line on the coordinate plane.
x
y
Graph y = 5x + 2
Graphing Equations
Graph 4x - 3y = 12● Solve for y first
4x - 3y =12 Subtract 4x from both sides
-3y = -4x + 12 Divide by -3
y = x + Simplify
y = x – 4● The equation y = x - 4 is in slope-intercept form,
y=mx+b. The y -intercept is -4 and the slope is . Graph the line on the coordinate plane.
Graphing Equations
12-3
43
43
43
-4-3
Graph y = x - 4
x
y
43
Graphing Equations