introduction to general chemistry

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Introduction to General Chemistry Ch. 1.6 - 1.9 Lecture 2 Suggested HW: 33, 37, 40, 43, 45, 46

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Introduction to General Chemistry. Ch. 1.6 - 1.9. Lecture 2 Suggested HW: 33, 37, 40, 43, 45, 46. Accuracy and Precision. - PowerPoint PPT Presentation

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Page 1: Introduction to General Chemistry

Introduction to General Chemistry

Ch. 1.6 - 1.9

Lecture 2Suggested HW:

33, 37, 40, 43, 45, 46

Page 2: Introduction to General Chemistry

Accuracy and Precision

• Accuracy defines how close to the correct answer you are. Precision defines how repeatable your result is. Ideally, data should be both accurate and precise, but it may be one or the other, or neither.

Accurate, but not precise. Reached the target, but could not reproduce the result.

Precise, but not accurate. Did not reach the target, but result was reproduced.

Accurate and precise.Reached the target and the data was reproduced.

Page 3: Introduction to General Chemistry

• Accuracy is calculated by percentage error (%E)

100% xvaluetrue

valuetruevalueaverageE

• We take the absolute value because you can’t have negative error.

• GROUP PROBLEM- A certain brand of thermometer is considered to be accurate if the %E is < 0.8%. The thermometer is tested using water (BP = 100oC). You bring a pot of distilled water to a boil and measure the temperature 5 times. The thermometer reads: 100.6o, 100.4o, 99.8o, 101.0o, and 100.4o. Is it accurate?

Measuring Accuracy

Page 4: Introduction to General Chemistry

• Precision is indicated by the number of significant figures. Significant figures are those digits required to convey a result.

– There are two types of numbers: exact and inexact– Exact numbers have defined values and possess an infinite

number of significant figures because there is no limit of confidence:

* There are exactly 12 eggs in a dozen * There are exactly 24 hours in a day * There are exactly 1000 grams in a kilogram

– Inexact number are obtained from measurement. Any number that is measured has error because:

• Limitations in equipment• Human error

Measuring Precision: Significant Figures

Page 5: Introduction to General Chemistry

• Example: Some laboratory balances are precise to the nearest cg (.01g). This is the limit of confidence. The measured mass shown in the figure is 335.49 g.

• The value 335.49 has 5 significant figures, with the hundredths place (9) being the uncertain digit. Thus, the (9) is estimated, while the other numbers are known.

• It would properly reported as 335.49±.01g

Measuring Precision: Significant Figures

- The actual mass could be anywhere between 335.485… g and 335.494… g. The balance is limited to two decimal places, so it rounds up or down. We use ± to include all possibilities.

Page 6: Introduction to General Chemistry

• All non-zeros and zeros between non-zeros are significant– 457 (3) ; 2.5 (2) ; 101 (3) ; 1005 (4)

• Zeros at the beginning of a number aren’t significant. They only serve to position the decimal.– .02 (1) ; .00003 (1) ; 0.00001004 (4)

• For any number with a decimal, zeros to the right of the decimal are significant– 2.200 (4) ; 3.0 (2)

Determining the Number of Significant Figures In a Result

Page 7: Introduction to General Chemistry

• Zeros at the end of an integer may or may not be significant– 130 (2 or 3), 1000 (1, 2, 3, or 4)

• This is based on scientific notation– 130 can be written as: 1.3 x 102 2 sig figs 1.30 x 102 3 sig figs – If we convert 1000 to scientific notation, it can be written

as: 1 x 103 1 sig fig 1.0 x 103 2 sig figs 1.00 x 103 3 sig figs 1.000 x 103 4 sig figs*Numbers that must be treated as significant CAN NOT disappear in scientific notation

Determining the Number of Significant Figures In a Result

Page 8: Introduction to General Chemistry

• You can not get exact results using inexact numbers

• Multiplication and division– Result can only have as many significant figures as the

least precise number

105.86643𝑚0.𝟗𝟖𝑠

=108.0269694𝑚𝑠

=110𝑚𝑠𝑜𝑟 1.1𝑥 102

𝑚𝑠

43270.0𝑘𝑔𝑥𝟒𝑚𝑠2

=173080𝑘𝑔𝑚𝑠2

=200000𝑘𝑔𝑚𝑠2

𝑜𝑟 2 𝑥105𝑘𝑔𝑚𝑠2

(3 s.f.)

(1 s.f.)

(2 s.f.)

Calculations Involving Significant Figures

Page 9: Introduction to General Chemistry

• Addition and Subtraction– Result is only as precise as the least precise

number.

20.4

1.322

83

+ 104.722

211.942 212

Calculations Involving Significant Figures

Limit of certain is the ones place

Page 10: Introduction to General Chemistry

• Using scientific notation, convert 0.000976392 to 3 sig. figs.• Using scientific notation, convert 198207.6 to 1 sig. fig.

H=10.000 cm

L = 31.00 cmW = .40 cm

• Volume of rectangle ?• Surface area (SA = 2WH + 2LH +

2LW) ?note: constants in an equation are exact numbers

Group Work

¿8.0 𝑐𝑚2+620.0𝑐𝑚2+2𝟒 .8𝑐𝑚2¿2 (4.0𝑐𝑚2 )+2 (310.0𝑐𝑚2)+2(1𝟐 .4𝑐𝑚2)

¿65𝟐 .8𝑐𝑚2=653𝑐𝑚2

Limit of certainty is the ones

place

Page 11: Introduction to General Chemistry

• Dimensional analysis is an algebraic method used to convert between different units

• Conversion factors are required – Conversion factors are exact numbers which are

equalities between one unit set and another.

– For example, we can convert between inches and feet. The conversion factor can be written as:

• In other words, there are 12 inches per 1 foot, or 1 foot per 12 inches.

inches

footor

foot

inches

12

1

1

12

Dimensional Analysis

Page 12: Introduction to General Chemistry

unitsdesiredunitsgiven

unitsdesiredxunitsgiven

conversion factor (s)

• Example. How many feet are there in 56 inches?• Our given unit of length is inches• Our desired unit of length is feet

• We will use a conversion factor that equates inches and feet to obtain units of feet. The conversion factor must be arranged such that the desired units are ‘on top’

𝟓𝟔 h𝑖𝑛𝑐 𝑒𝑠 𝑥1 𝑓𝑜𝑜𝑡12 h𝑖𝑛𝑐 𝑒𝑠

=4.6666 𝑓𝑡 4.7 ft

Dimensional Analysis

Page 13: Introduction to General Chemistry

• Answer the following using dimensional analysis. Consider significant figures.

– Convert 35 minutes to hours

– Convert 40 weeks to seconds

– Convert 4 gallons to cm3 (1 gal = 4 quarts, 1 quart = 946.3 mL)

– *35 to (1 mile = 5280 ft and 1 ft = 12 in)

Group Work

Page 14: Introduction to General Chemistry

• As we previously learned, the units of volume can be expressed as cubic lengths, or as capacities. When converting between the two, it may be necessary to cube the conversion factor

• Ex. How many mL of water can be contained in a cubic container that is 1 m3

1𝑚3𝑥 ( 𝑐𝑚10− 2𝑚 )𝑥 ( 𝒎𝑳

𝒄𝒎𝟑 )3

¿1𝑚3𝑥 𝒄𝒎𝟑

𝟏𝟎−𝟔𝒎𝟑 𝑥𝑚𝐿𝑐𝑚3 ¿𝟏 𝒙𝟏𝟎𝟔𝒎𝑳

Cube this conversion factor

Must use this equivalence to convert between cubic length to capacity

High Order Exponent Unit Conversion (e.g. Cubic Units)

Page 15: Introduction to General Chemistry

• Convert 10 mL to m3 (c = 10-2)

• Convert 100 L to µm3 (µ = 10-6)

• Convert 48.3 ft2 to cm2 (1 in. = 2.54 cm)

Group Work