introduction + chapter no 1
TRANSCRIPT
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IntroductionBUSINESSMATHEMATICS
BA(M) 531
MBA - I
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Important Notes
Maintain a separate register forMathematics
Probability of having a Quiz in eachclass is very high
No late assignments will be
accepted
Switch off cell phones
Late comers will be marked absent
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Division of Marks [ 40 ]
Internal finals = 20
Hourly Exam = 8 (average)
Quiz = 2 Assignment = 2
Attendance = 2
Past papers = 4 Register = 2
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Basic Algebra
Rules
1. - , - = +
2. + , - = -3. - , + = -
4. + , + = +
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Some Preliminaries
Chapter No 1
Pg no 4
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Terms
A variable is a letter which represents anunknown number. Any letter can be used asa variable. such as x , y,z
An algebraic expression contains at leastone variable.
Examples: a, x+5, 3y 2z
An equation is a sentence that states thattwo mathematical expressions are equal.
Example: 2x-16=18
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FirstDegree Equations in
One Variable Three types of equations
Identity equation
Conditional equation False statement
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Steps to Solving Equations
Simplifyeach side of the equation, if needed, by
distributing or combining like terms.
Move variables to one side of the equation by using
the opposite operation of addition or subtraction.
Isolate the variable by applying the opposite
operation to each side.
First, use the opposite operation of addition or subtraction.
Second, use the opposite operation of multiplication ordivision.
Checkyour answer.
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Examples
y is the variable.
Add 6 to each side to isolatethe variable.
Now divide both sides by 3.
The answer is 5.
Check the answer bysubstituting it into theoriginal equation.
3 6 9
6 6
3 15
3 3
5
Check: 3(5)-6=9
15-6=9
y
y
y
!
!
!
!
!
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Try this. . .
Did you getx = - 4?You were right!
4 8 24x !
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Second Degree Equations inone Variable
Quadratic Equations
Generalized form
ax2 +bx + c
Where a,b and c are constantsand
a 0
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Solving QuadraticEquations
Types of roots No real root
One real root
Two real roots
Discriminant = b2 4ac if b2 4ac < 0 no real root
if b2 4ac = 0 One real root if b2 4ac > 0 Two real roots
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Two methods
Factoring Method
Example
X2 -4x =0
X( x 4 ) = 0
Either x =0 or x -4=0x = 4
Quadratic Formula
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An inequality is like an equation, but instead of
an equal sign ( ) it has one of these signs:
< : less than : less than or equal to
> : greater than
: greater than or equal to
Section 1.3 Inequalities
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Types of Inequalities
Absolute Inequality
Which is always true
Conditional Inequality Is true under certain conditions x >
100
Double Inequality
Is an interval 0< y < 100
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Interval Notation
Open interval (a,b)
a < x < b
Closed interval [a,b]
a x b
Half open interval (a,b] or [a,b)
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-5 50 10-10
A number line is a line with marks on it that are placed at
equal distances apart.
One mark on the number line is usually labeled zero and then
each successive mark to the left or to the right of the zero
represents a particular unit such as 1 or .
On the number line above, each small mark represents
unit and the larger marks represent 1 unit.
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-5 50 10-10
Number lines can be used to represent:
A. Whole numbers The set {0, 1, 2, 3, }.
B. Positive numbers any number that is greater than
zero.
C. Negative numbers any number that is less than zero.
D. Integers The set of numbers represented as
{, -3, -2, -1, 0, 1, 2, 3, }
The arrows at the ends of the number line show that the
number line continues in both directions without ending.
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-5 50 10-10
A number can be graphed on a number line by placing a point
at the appropriate position on the number line.
Example
a) {4} (blue point)
b) {integers between 10 and 5} (purple)
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x < 5
means that whatevervalue x has, it must be
less than 5.
Try to name ten numbersthat are less than 5!
line and Inequality
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Numbers less than 5 are to the left
of 5 on the number line.
0 5 10 15-20 -15 -10 -5-25 20 25
If you said 4, 3, 2, 1, 0, -1, -2, -3, etc., you are right.
There are also numbers in between the integers, like2.5, 1/2, -7.9, etc.
The number 5 would notbe a correct answer,
though, because 5 is not less than 5.
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x -2
means that whatevervalue x has, it must begreater than or equal to
-2.
Try to name ten numbersthat are greater than or
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Numbers greater than -2 are to the
right of 5 on the number line.
0 5 10 15-20 -15 -10 -5-25 20 25
If you said -1, 0, 1, 2, 3, 4, 5, etc., you are right.
There are also numbers in between the integers,like -1/2, 0.2, 3.1, 5.5, etc.
The number -2 would alsobe a correct answer,
because of the phrase, or equal to.
-2
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k> 5
A. k+3 > 2
Subtract 3 from both sides.3 3
k+3 > 2
Solve and graph.
Example : Adding and Subtracting to Solve
Inequalities
5 0
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B.r 9 u 12
ru 21
Add 9 to both sides.r 9 + 9 u 12 + 9
r 9 u 12
21 2415
Example 1B: Adding and Subtracting to Solve
Inequalities Continued
Solve and graph.
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C.u 5 e 3
u e 8
Add 5 to both sides.u 5 + 5 e 3 + 5u 5 e 3
8 1050
Solve and graph.
Additional Example 1C: Adding and Subtracting to
Solve Inequalities Continued
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ce 4
D.
c
+ 6e
2
Subtract 6 from both sides.6 6c+ 6 e 2
0 47 4
Solve and graph.
Additional Example 1D: Adding and Subtracting to
Solve Inequalities Continued
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yu 8
A. y+ 7 u 1
Subtract 7 from both sides.7 7y+ 7 u 1
Try This: Example 1A
011 8
Solve and graph.
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5 1
5 is greater than 1.
Sometimes youmustmultiply or dividetoisolatethevariable. Multiplyingor dividingbothsidesofaninequality by anegativenumbergivesa
surprisingresult.
5 > 1
Multiplyboth sides by1.1 5 1 (1) > or < ?
You know 5 islessthan 1, so youshould use 1
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3 > 1
4 e 12
Multiply by 2
Divide by 4 1 u 3
6 < 2
MULTIPLYINGINEQUALITIESBYNEGATIVEINTEGERS
Words Original
Inequality
Multiply/
Divide
Result
Multiplyingordividingby anegative
numberreverses theinequalitysymbol.
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The directionoftheinequality changesonly ifthenumber youareusingtomultiply or divideby isnegative.
HelpfulHint
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A.3yu 15
ye 5
Divide each side by
3;u
changes toe
.
B.7 < 21
m < 3
Divide each side by7.
Additional Example 2: Multiplying and Dividing to
Solve Inequalities
Solve and graph.
0 33 5
3ye 153 3
7m < 21
7 7
7 5 0 4
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A. 8yu 24
ye 3
Divide each side by
8; changes > to 45
f> 5
Divide each side by9.
Try This: Example 2
8y u 248 8
9f> 459 9
3 07 4
0 5 10
Solve and graph.
t
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o v ng so ute a ue
Inequalities
Section 1.4 Solving absolute value inequalities is acombination of solving absolute value
equations and inequalities.
Rewrite the absolute value inequality.
For the first equation, all you have to do is drop
the absolute value bars.
For the second equation, you have to negate theright side of the inequality and reverse the
inequality sign.
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Solve: |2x + 4| > 12
2x+ 4 > 12 or 2x+ 4 < -12
2x> 82x< -16
x> 4 or x< -8
x< -8 orx> 4
0 4-8
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Solve: 2|4 -x| < 10
4 -x< 5 and 4 -x> -5
-x< 1 -x> -9x> -1 and x< 9
|4 -x| < 5
0 9-1
-1
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Assignment # 1
Section 1.1 [5,15,19 ]
Section 1.2 [ 9,27]
Section 1.3 [23,27,35,41 ] Section 1.4 [11,21,24,25,]
Section 1.5 [3,23 ]
Submission Date :Feb 08,2010,to be done on sheets