heat load calculation.xls

8/10/2019 Heat Load Calculation.xls

1/20

FICHTNERIndia

Annexure-1: Estimation of Heat load calculation for proposed MV Switchgear

Building & Control Room Building for Electrical equipments

1.1 33 KV Switchgear

This Swotchgear having four Nos. of 33 KV switchgears

(a). Incomer module with 2500A breaker:

2 Nos. Incomers of 2500A VCB, having 2 CT's of 15VA burden, 5 indicating lamps, 4 meters,

1 PT-100 VA burden, 4 auxiliary contactors & 4 relays & width of panel is 1200 mm

Breaker loss = 3x25002x60x10

-6 = watts

CT+PT = (2x15+100)x0.1 = watts

Indicating lamps = = watts Negligible, since the type

Meters = 4x3 = watts of indication lamp is

Aux. contactors = 4x4 = watts assumed as LED type

Relays = 4x2 = watts

Busbars = 0.0724x2500x3x1.2 = watts

The heat loss one incomer feeder = wattsTherefore, total heat loss for 2 incomer feeders = watts

= KW

(b). Outgoing module with 1250A breaker:

2 Nos. outgoing feeders of 1250A VCB, having 2 CT's of 15VA burden, 5 indicating lamps,

4 meters, 1 PT-100 VA burden, 4 auxiliary contactors & 4 relays & width of panel is 1200 mm


-6 = watts

CT+PT = (2x15+100)x0.1 = watts






The heat loss one outgoing feeder = watts

Therefore, total heat loss for 2 outgoing feeders = watts= KW

1.2 Lighting Load = KW Assumed

1.3 Power Cable = KW Assumed

Therefore Total Heat Load For MV Building = KW

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SHORT CIRCUIT TEST

FACILITY AT BINA (MP)

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ETHS&PS/620P-

90801/ED2.131.001.BHEAT LOAD CALCULATION

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SHORT CIRCUIT TEST


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ETHS&PS/620P-


Description

2. Control Room Building

2.1 CRP Panels = watts Assumed

Therefore, total heat loss for 11 CRP = KW

2.2 MLDB & ELDB = watts Assumed

Therefore, total heat loss for 3 ACDBs = KW

2.3 Lighting Load = KW Assumed

2.4 Power Cable = KW Assumed

2.5 AC Automatic Transfer Switch (ATS)

This Switchgear having four Nos. of 415V switchgears

Incomer & Outgoing module with 2000A breaker:

2 Nos. Incomers & 2 Nos. Outgoing feeders of 2000A ACB, having 2 CT's of 15VA burden,

5 indicating lamps, 4 meters, 1 PT-100 VA burden, 4 auxiliary contactors & 4 relays


-6 = watts

CT+PT = (2x15+100)x0.1 = watts






Therefore, total heat loss for ATS = KW

2.6 AC Normal Supply Panel

(a). Incomer module with 2000A breaker:

1 No. Incomer of 2000A ACB, having 2 CT's of 15VA burden, 5 indicating lamps, 4 meters,

1 PT-100 VA burden, 4 auxiliary contactors & 4 relays


-6 = watts

CT+PT = (2x15+100)x0.1 = watts





The heat loss one incomer feeder = watts

Therefore, total heat loss for 1 incomer feeder = KW

(b). Outgoing module with 1000A MCCB:

1 No. outgoing feeder of 1000A MCCB, having 2 CT's of 15VA burden, 5 indicating lamps,

4 meters, 1 PT-100 VA burden, 4 auxiliary contactors & 4 relays

Breaker loss = watts

CT+PT = (2x15+100)x0.1 = watts






Therefore, total heat loss for 1 outgoing feeder = KW

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NHPTL HIGH POWER

SHORT CIRCUIT TEST


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ETHS&PS/620P-


Description

(c). Outgoing module with 630A MCCB:

3 Nos. outgoing feeders of 630A MCCB, having 2 CT's of 15VA burden, 5 indicating lamps,



CT+PT = (2x15+100)x0.1 = watts






Therefore, total heat loss for 3 outgoing feeders = KW

(d). Outgoing module with 400A MCCB:




CT+PT = (2x15+100)x0.1 = watts







(e). Outgoing module with 300A MCCB:




CT+PT = (2x15+100)x0.1 = watts







(f). Outgoing module with 200A MCCB:




CT+PT = (2x15+100)x0.1 = watts


Meters = 4x3 = watts of indication lamp isAux. contactors = 4x4 = watts assumed as LED type




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HEAT LOAD CALCULATIONETHS&PS/620P-

90801/ED2.131.001.B

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SHORT CIRCUIT TEST


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ETHS&PS/620P-


Description

(g). Outgoing module with 160A MCCB:




CT+PT = (2x15+100)x0.1 = watts







(h). Outgoing module with 125A MCCB:




CT+PT = (2x15+100)x0.1 = watts







(i). Outgoing module with 100A MCCB:




CT+PT = (2x15+100)x0.1 = watts







(j). Outgoing module with 80A MCCB:




CT+PT = (2x15+100)x0.1 = watts



Aux. contactors = 4x4 = watts assumed as LED typeRelays = 4x2 = watts



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-HEAT LOAD CALCULATION Sheet No.


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ETHS&PS/620P-


Description

(k). Outgoing module with 63A MCCB:




CT+PT = (2x15+100)x0.1 = watts







(l). Outgoing module with 32A MCCB:




CT+PT = (2x15+100)x0.1 = watts







(m). Outgoing module with 16A MCCB:




CT+PT = (2x15+100)x0.1 = watts







Busbars with 1 No. of 2000A horizontal & 3 Nos. of Vertical drop inside the panel

(i). Horizontal Busbars = 0.0724x2000x3x5.050 = watts

(ii). Vertical Busbars = 0.0724x2000x3x3x1.8 = watts

Therefore, total heat loss for Busbars = KW

Therefore, total heat loss for AC Normal = KW

Supply Panel

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SHORT CIRCUIT TEST


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ETHS&PS/620P-


Description

2.7 AC Preferred Supply Panel

(a). Incomer module with 1000A MCCB:

1 No. incomer feeder of 1000A MCCB, having 2 CT's of 15VA burden, 5 indicating lamps,



CT+PT = (2x15+100)x0.1 = watts






Therefore, total heat loss for 1 incoming feeder = KW





CT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts




Relays = 4x2 = wattsThe heat loss one outgoing feeder = watts


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SHORT CIRCUIT TEST


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Section

ETHS&PS/620P-


Description


(i). Horizontal Busbars = 0.0724x1000x3x4.250 = watts(ii). Vertical Busbars = 0.0724x1000x3x3x1.8 = watts


Therefore, total heat loss for AC Preferred = KW

Supply Panel

2.8 ACGE Preferred Supply Panel

(a). DG side Incomer module with 500A MCCB:

2 Nos. incomer feeders of 500A MCCB, having 2 CT's of 15VA burden, 5 indicating lamps,



CT+PT = (2x15+100)x0.1 = watts



Aux. contactors = 4x4 = watts assumed as LED typeRelays = 4x2 = watts


Therefore, total heat loss for 2 incoming feeders = KW

(b). Outgoing module with 1000A breaker:

2 Nos. outgoing feeders of 1000A ACB, having 2 CT's of 15VA burden, 5 indicating lamps,



-6 = watts

CT+PT = (2x15+100)x0.1 = watts

Indicating lamps = = watts

Meters = 4x3 = watts

Aux. contactors = 4x4 = watts








Therefore, total heat loss for ACGE Preferred = KW

Supply Panel

2.9 Battery Charger

Heat loss (watts) = 0.05 x Rated output (Assuming Efficiency of Charger as 0.95)

Rated output of Charger = KW

(As per DC System sizing calculation)

Therefore, heat loss for Battery Charger = KW

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Doc. No.

FORM T9-P REV-A

Sheet No.

Rev. SectionNHPTL HIGH POWER

SHORT CIRCUIT TEST


HEAT LOAD CALCULATION


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Sheet No.


NHPTL HIGH POWER

SHORT CIRCUIT TEST


A

Section

ETHS&PS/620P-


Description

2.10 Control Room DCDB


3 Nos. incoming feeders & 1 No. Bus-coupler feeder of 400A MCCB, having 2 CT's of15VA burden, 5 indicating lamps, 4 meters, 1 PT-100 VA burden, 4 auxiliary contactors &

4 relays


CT+PT = (2x15+100)x0.1 = watts






Therefore, total heat loss for 4 feeders = KW

(b). Outgoing module with 32A MCB: = KW Assumed


(i). Horizontal Busbars = 0.0724x400x2x3.6 = watts(ii). Vertical Busbars = 0.0724x1000x2x2x1.8 = watts


Therefore, total heat loss for Control Room = KW

DCDB

Therefore Total Heat Load For Control Room = KW

Building

Therefore Total combined Heat Load For = KW

MV & Control Room Building

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Annexure-2: Estimation of Heat load calculation for proposed Marshalling

KIOSK Building MK-1 for Electrical equipments

Marshalling KIOSK - 1

1 CRP Panels = watts Assumed


2 Lighting Load = KW Assumed

3 Power Cable = KW Assumed

4 AC Normal Supply Panel


1 No. Incomer of 125A MCCB, having 2 CT's of 15VA burden, 5 indicating lamps, 4 meters,


Breaker loss = = wattsCT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts










CT+PT = (2x15+100)x0.1 = watts





The heat loss one outgoing feeder = wattsTherefore, total heat loss for 5 outgoing feeders = KW

Rev. Section

NHPTL HIGH POWER

SHORT CIRCUIT TEST



90801/ED2.131.001.BA Sheet No.

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SHORT CIRCUIT TEST



90801/ED2.131.001.BA Sheet No.








Supply Panel

5 AC Preferred Supply Panel




Breaker loss = = watts

CT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts






Project Subject Doc. No. Rev. Section

NHPTL HIGH POWER


HEAT LOAD CALCULATION ETHS&PS/620P-90801/ED2.131.001.B

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SHORT CIRCUIT TEST



90801/ED2.131.001.BA Sheet No.







CT+PT = (2x15+100)x0.1 = watts







(e). Outgoing module with 63A MCCB:




CT+PT = (2x15+100)x0.1 = watts







(f). Outgoing module with 32A MCCB:




CT+PT = (2x15+100)x0.1 = watts












Supply Panel

6 Battery Charger





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SHORT CIRCUIT TEST



90801/ED2.131.001.BA Sheet No.



7 Marshalling KIOSK-1 DCDB


3 Nos. incomingfeedwers & 1 No. Bus-coupler feeder of 400A MCCB, having 2 CT's of

15VA burden, 5 indicating lamps, 4 meters, 1 PT-100 VA burden, 4 auxiliary contactors &

4 relays


CT+PT = (2x15+100)x0.1 = watts












Therefore, total heat loss for Marshalling = KW

KIOSK-1 DCDB

Therefore Total Heat Load For Marshalling = KW

KIOSK-1

SHORT CIRCUIT TEST


HEAT LOAD CALCULATION90801/ED2.131.001.B

- Sheet No.


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90801/ED2.131.001.BA Sheet No.







Supply Panel






CT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts







NHPTL HIGH POWER


HEAT LOAD CALCULATION ETHS&PS/620P-90801/ED2.131.001.B

- Sheet No.


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SHORT CIRCUIT TEST



90801/ED2.131.001.BA Sheet No.






CT+PT = (2x15+100)x0.1 = watts












Supply Panel

6 Battery Charger









4 relays


CT+PT = (2x15+100)x0.1 = watts








Busbars with 1 No. of 400A horizontal & 2 Nos. of Vertical drop inside the panel(i). Horizontal Busbars = 0.0724x400x2x3.6 = watts




KIOSK-2 DCDB


KIOSK-1

NHPTL HIGH POWER

SHORT CIRCUIT TEST



90801/ED2.131.001.B

- Sheet No.


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Annexure-3: Estimation of Heat load calculation for proposed Marshalling

KIOSK Building MK-2

Marshalling KIOSK - 2

1 CRP Panels = watts Assumed


2 Lighting Load = KW Assumed

3 Power Cable = KW Assumed

4 AC Normal Supply Panel




Breaker loss = = wattsCT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts










CT+PT = (2x15+100)x0.1 = watts





The heat loss one outgoing feeder = wattsTherefore, total heat loss for 6 outgoing feeders = KW


NHPTL HIGH POWER

SHORT CIRCUIT TEST


HEAT LOAD CALCULATION 3112133-PB-EL-690-001 - Sheet No.


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NHPTL HIGH POWER

SHORT CIRCUIT TEST









Supply Panel






CT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts











CT+PT = (2x15+100)x0.1 = watts







NHPTL HIGH POWER




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NHPTL HIGH POWER

SHORT CIRCUIT TEST








CT+PT = (2x15+100)x0.1 = watts












Supply Panel

6 Battery Charger









4 relays


CT+PT = (2x15+100)x0.1 = watts








Busbars with 1 No. of 400A horizontal & 2 Nos. of Vertical drop inside the panel(i). Horizontal Busbars = 0.0724x400x2x3.6 = watts




KIOSK-2 DCDB


KIOSK-1

NHPTL HIGH POWER

SHORT CIRCUIT TEST




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The heat load dissipation of electrical equipment as follows.

Sl. No. Description of Building/Room Load In KW

1 MV Building

2 Control Room

3 Marshlling KIOSK-1 8.814 Marshlling KIOSK-2 10.84

5 Comressor Room 1.30

Total heat load dissipation Load 59.16

38.21

heat load calculation.xls

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