half-life and practice problems
TRANSCRIPT
Half-Life and Radiometric Dating
Rate of Decay
The time required for half the nuclei in a sample of a radioisotope to undergo radioactive decay is called its half-life. This is the time required for half of the
nuclides in a sample to decay. Half-life of U-238 is 4.5 billion years Half-life of I-131 is 8.07 days Half-life of Po-194 is 0.7 second
Red dots are radioactive atoms
Blue dots are stable atoms that have undergone decay
Carbon-14 Dating
We have some radioactive materials in our bodies.
One of the isotopes is carbon-14.
Carbon-14 is an isotope of the carbon in CO2.
All living things take it in during respiration.
Carbon-14 Dating
Scientist use carbon-14 to date very old things were once alive.
Carbon-14 Dating
Decayed carbon-14 is continually being replaced in the body.
Once the organism dies the carbon-14 is no longer replaced, but that which remains continues to decay.
By examining the amount of carbon-14 left in the material, scientist can estimate the age of the subject.
Accurate to about 20,000-50,000 years.
Practice Problems
1) A fossilized tree killed by a volcano was studied. It had 6.25 percent of the amount of carbon-14 found in a sample of the same size from a tree that is alive today. When did the volcanic eruption take place?
Practice Problems
You need to find out how many times ½ (0.5) must be used as a factor to produce 0.0625.
The answer is 4 times because
0.5 X 0.5 X 0.5 X 0.5 = 0.0625
4 half-lives have gone by and each half-life is 5730 years.
5730 years X 4 = 22,920 years
Practice Problems
2) A rock was analyzed using potassium-40. The half-life of potassium-40 is 1.25 billion years. If the rock had only 25 percent of the potassium-40 that would be found in a similar rock formed today, calculate how long ago the rock was formed.
Potassium-40 Half-life is 1.25 billion years
Practice Problems
2) Convert 25% to a decimal --- 0.5 X 0.5 = 0.25
2 half-lives have gone by.
1.25 billion X 2 = 2.50 billion years
0.25
Practice Problems3) Ash from an early fire pit was found to have
12.5 percent as much carbon-14 as would be found in a similar sample of ash today. How long ago was the ash formed?
Convert 12.5% to a decimal ---
0.5 X 0.5 X 0.5 = 0.125
3 half-lives have gone by.
5730 X 3 = 17,190 years ago
0.125
Practice Problems4) A rock sample has 12.5% of the potassium-40
that would be present in a similar rock formed today. How old is the rock sample?
Convert 12.5% to a decimal ---
0.5 X 0.5 X 0.5 = 0.125
3 half-lives have gone by.
1.25 billion X 3 = 3.75 billion years old
0.125
Practice Problems5) How old is a piece of wood in which the
carbon-14 is 3.12% of that in wood formed today?
Convert 3.12% to a decimal ---
0.5 X 0.5 X 0.5 X 0.5 X 0.5 = 0.03125
5 half-lives have gone by.
5730 X 5 = 28,650 years old
0.0312
Half-life equation
Amount remaining = amount of original sample 2n
n = number of half-lives
1) An isotope of cesium (cesium-137) has a half-life of 30 years. If 1.0 mg of cesium-137 disintegrates over a period of 90 years, how many mg of cesium-137 would remain?
Amount remaining =amount of original sample
2n
1.0 mg
231 half life = 30 years
Therefore, 90 years is equal to how many half lives?
n = 3
4. Sodium-25 was to be used in an experiment, but it took 3.0 minutes to get the sodium from the reactor to the laboratory. If 5.0 mg of sodium-25 was removed from the reactor, how many mg of sodium-25 were placed in the reaction vessel 3.0 minutes later if the half-life of sodium-25 is 60 seconds?
Amount remaining =amount of original sample
232n5.0 mg =
1 half life = 60 seconds
Therefore, 3 minutes is equal to how many half lives?
n = 3